Hey :)
W2MH = y[43]; #number of infected vaccinated males high risk
infected with
non-vaccine strain
length(y0)
[1] 42
As a sidenote, would you mind sharing the flow diagram with me, so I can
show it to my students doing a practical with DeSolve, as example of a
contemporary
Hi Livia,
You can convert the time of day fields using strptime like this:
strptime(sapply(strsplit(time: 08:14:22, ),[,2),%H:%M:%S)
This will give you the times as seconds in the current day. If you
then wish to divide the day into morning, afternoon and night, you
could create three time
Hi thuksu,
Would defining the factor in your training set with all the levels
that occur in the test set solve the problem? That is, there would be
at least one factor level in the training set even though there were
no instances of that factor.
Jim
On Thu, Apr 30, 2015 at 8:05 AM, thuksu
- Mensaje original -
De: javier ruben marcuzzi javier.ruben.marcu...@gmail.com
Para: R-help-es@r-project.org r-help-es@r-project.org
Enviados: Jueves, 30 de Abril 2015 4:07:35
Asunto: [R-es] predict nlme
Estimados
Tengo un error que me desconcierta, es un código que simplifiqué de
Hi Olufemi,
I sounds like you have a data frame (let's call it mydata) with at
least three elements (columns). You may be trying to use c() in this
way:
y1to3-c(y1,y2,y3)
in which case it won't work. However:
y1to3-c(mydata$y1,mydata$y2,mydata$y3)
might do what you want, substituting whatever
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
John Kane
Kingston ON Canada
-Original Message-
From: lutipilo...@yahoo.com.br
Sent: Wed, 29 Apr 2015 18:45:26 -0700
To: r-help@r-project.org
Subject: [R] help - hoslem.test
Hello,
I'm
Hola a tod@s, explico lo que estoy intentando hacer...
Tengo un listado de url comprimidas de twitter, entre las cuales hay muchas
repetidas, por lo que el número de registros llega a más de 15K.
Por otro lado tengo otra lista de esas url únicas con su equivalente ya
descomprimido llegando a un
Hola,
Salvo que lo esté entendiendo mal, con un merge() podrías solucionar el
problema.
urlGood - merge(url.origen, url.des, by.x=V1, by.y=url1)
urlGood sería un data.frame de 15K filas y como columnas todas las que
tuviera url.origen y url.des pero pareadas la columna que las vincula:
V1 y
-Original Message-
From: lutipilo...@yahoo.com.br
Sent: Thu, 30 Apr 2015 04:24:32 -0700
To: r-help@r-project.org, jrkrid...@inbox.com
Subject: RE: [R] help - hoslem.test
load(id3.rda)
And what is this?
We do not have access to your office or computer hard disc.
Please read
Kevin Thorpe pointed out to me that there is a dropbox link at the very bottom
of the post that I missed. :(
I just downloaded it, read it in and it looks fine.
John Kane
Kingston ON Canada
-Original Message-
From: petr.pi...@precheza.cz
Sent: Thu, 30 Apr 2015 14:25:23 +
To:
Genial !! Gracias Carlos, voy a leer la vignette.
A todo esto, alguien se acuerda de esas paginas para buscar paquetes y
funciones de R ? Se que una estaba en CRAN, pero las otras tambien eran
muy buenas porque las use un par de veces, pero no las puedo encontrar
en los mails de la lista.
Eric,
Tienes estas dos no oficiales:
http://crantastic.org/
http://www.rdocumentation.org/
Un saludo,
Emilio
*Emilio L. Cano*
Mobile: +34 665 676 225
skype: emilopezcano
twitter: @emilopezcano
http://emilio.lcano.com
El 30 de abril de 2015, 15:52, eric ericconchamu...@gmail.com escribió:
Estimado Oliver Nuñez
Envío un ejemplo reproducible.
Javier Marcuzzi
# de donde tomo datos, y tiene el modelo (en el pdf)
library(MCMCglmm)
# librería con las funciónes que voy a usar
library(nlme)
datos0-ChickWeight
# creo algunos datos que agrego a los origonales
I must correct myself,
attach does not prevent from modifying the object but can be confusing see
?attach example
x-1:5
y-NA
xx-data.frame(x,y)
attach(xx)
The following objects are masked _by_ .GlobalEnv:
x, y
rm(x,y)
x
[1] 1 2 3 4 5
yy-x3
xx-cbind(xx,yy)
xx
x yyy
1 1 NA
2015-04-30 10:52 GMT-03:00 eric ericconchamu...@gmail.com:
alguien se acuerda de esas paginas para buscar paquetes y funciones de R ?
¿Sería esta: http://rseek.org/?
--
«No soy aquellas sombras tutelares
que honré con versos que no olvida el tiempo.»
JL Borges
[[alternative
Hi
I agree with John
Just small refinements in lines
-Original Message-
-Original Message-
From: lutipilo...@yahoo.com.br
Sent: Thu, 30 Apr 2015 04:24:32 -0700
To: r-help@r-project.org, jrkrid...@inbox.com
Subject: RE: [R] help - hoslem.test
load(id3.rda)
And
Hi,
Given that a data frame is a list:
unlist(mydata[, 1:3])
For example:
all(unlist(iris[, 1:3]) == do.call(c, iris[, 1:3]))
[1] TRUE
Also, note that the returned result in both cases above retains names:
unlist(iris[, 1:3])
Sepal.Length1 Sepal.Length2 Sepal.Length3
load(id3.rda)
attach(id3)
#transformando q13 em binária
q131-ifelse(q13==1,1,ifelse(q13==2,2,ifelse(q13==3,2,
ifelse(q13==4,2,ifelse(q13==5,2,NA)
id3-cbind(id3,q131)
id3$q131 - as.factor(id3$q131)
tp1 - glm(q131 ~ q11 + q10+q12+edcat + q08+q06+ q14, family = binomial(link =
logit),
Hi All,
This is my first post in the community.
I am currently working on finding some inferences from my sample data and
the code I have used is:
inference(y = nc$weight, x = nc$habit, est = mean, type = ht, null = 0,
method = theoretical). While researching more on the code as I have just
Hello guys,
thanks for your quick reply
I will try and specific my problem
I have over 300.000 observations for different petrol pumps in all of Denmark
fra 1. november 2014 - 31 january 2015
for example I have:
petrol pump number: / date: 1. november 2014 / time: 08:14:22 / price:
On 30/04/2015 2:12 PM, Anirudh Jayaraman wrote:
I recently upgraded to *R-3.2.0* from *R-2.14.1* on *Ubuntu 12.04 LTS.*
I have been *trying to install some add-on packages* (that weren't
installed in the earlier version of R) to R-3.2.0. *but to no avail*,
getting repeated error messages. For
Thank you. your suggestions all worked.
Best Regards
On Thursday, 30 April 2015, 11:52, Bert Gunter gunter.ber...@gene.com
wrote:
... and if this is what is wanted, somewhat cleaner and more
generalizable for programming would be:
do.call(c, mydata[,1:3])
## where the column
Yes, I think unlist() is still better.
One caution (for all): make sure the columns are all of the same
type/class/mode or you may be in for nasty surprises.
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And
Dear All,
First of all, many thanks to all R contributors for a fantastic
program, and especially to Hadley Wickham for creating ggplot2. The
following is intended to be a warning that, if the apparently
superficial problems described are not sorted out, R could well find
itself being superceded.
hello dears
I have Search to compare the results between the three types of cluster
k-maen ,Em and Hierarchal clusters
How i figured the number of iterations , the time required to build each
Cluster ,accuracy and sum square error SSE for each cluster in the R
programming
[[alternative
LO QUE SE QUIERE REALIZAR ES LA GRAFICA PARA DIFERENTES VALORES DE DE N.
i.e. N=1,N=2,...,
UN POSIBLE ALGORITMO SERIA, bueno es una idea baga mia
les pido una colaboracion alrespecto para poder consolidar
fdens - function(n,z)
{
c - 1/factorial(n-1)
for(j in 0:n-1)
{ z - seq(i,i+1,0.1)
Hi, Thanks for the reply!
I did try this...
# res is a data frame
levels(res$mytypeid.f) - c(levels(res$mytypeid.f),mynewlevel)
logreg - glm(yesno ~ mytypeid.f + amount, data=res, family=binomial)
exp(coef(logreg))
# this result shows that the new level is not included in the regression.
it's
Hello,Kindly assist me on how to make the plot from the following programm to
be editable
x-c(0.84,1.03,0.96)y-c(1.30,1.46,1.48)z-c(1.32,1.47,1.5)w-c(0.07,0.07,0.07)r-c(500,1000,2000)
# Graph cars using a y axis that ranges from 0 to 12plot(r,x, type=o,
col=blue, ylim=c(0,1.5),lwd= 2, xlab =
Dear R users,
The lfactors package is now available from CRAN. It provides a class
lfactor that is similar to the class factor but can be referred to by level
or label.
This package is best explained with an example
flips - lfactor(c(0,1,1,0,0,1), levels=0:1, labels=c(Tails, Heads))
# Tails
I recently upgraded to *R-3.2.0* from *R-2.14.1* on *Ubuntu 12.04 LTS.*
I have been *trying to install some add-on packages* (that weren't
installed in the earlier version of R) to R-3.2.0. *but to no avail*,
getting repeated error messages. For example, *I tried installing swirl*.
Here's my
Jeremy:
I suggest you have a look at the latest edition of Paul Murrell's
book, R Graphics, as you seem to be unaware that ggplot2 (as well as
a 3rd graphics paradigm, the lattice package) and base graphics are
built on 2 different and incompatible graphics engines.
Obviously, you are entitled
On 30/04/2015 3:20 PM, Anirudh Jayaraman wrote:
In that case, it seems that *libcurl* is not available for R-3.2.0 as I
get a message for
** *install.packages(libcurl)*
It's not an R package, it's a library that you'll need on your system.
package ‘libcurl’ is not available (for R
Perfecto, muchas gracias por las opciones :)
Slds, eric.
On 4/30/15, Carlos Ortega c...@qualityexcellence.es wrote:
O puedes instalarte la ayuda directamente en R con el paquete sos..
sos: Search contributed R packages, sort by package
Search contributed R packages, sort by package
More useful to the r-help list would be a reproducible example of the data you
are using and a clear statement of what you are trying to accomplish. It is
likely that all of your requirements can be easily met, but you spent most of
your message talking about what you have tried without telling
Hola,
La función que adjuntas es inconsistente:
- z, es para ti un parámetro , pero en la función es un valor
calculado.
- i, ¿qué valor ha de tomar?. ¿no será function(n,i) en vez de
function(n,z).
- dentro del bulce, f va incrementándose, pero has de inicializarla.
Antes de
After hours of looking for the reason why one data set plots correctly and
another one does not I am still not seeing the reason. The only differences
I see between the two data sets is the number of discrete variables (one has
6 years, the other 7 years) and one contains zeros. I wonder if the
Do not post in html. You need to change your email software so that it sends
messages in plain text only. Look below to see why.
Your plot is edited by modifying the code you gave us to change the graph. Save
the code in a script file, change it in any way you want and then run the code
again
In that case, it seems that *libcurl* is not available for R-3.2.0 as I get
a message for
** *install.packages(libcurl)*
package ‘libcurl’ is not available (for R version 3.2.0)
Or if on Terminal I run
*sudo apt-get install libcurl4-openssl-dev*
Package libcurl4-openssl-dev is not
I keep getting the same error message when trying to install R Commander.
My operating system is Mac OS Yosemite 10.10
I have installed R 3.2, Rstudio, XQuartz (X11), and tcltk-8.x.x-x11.dmg.
But I keep getting the following error:Loading required package: splinesLoading
required package:
Hi Ishaq,
Well, you could do something absolutely ridiculous like this:
edit_my_plot-function(x,y,z,w,r) {
npoints-length(r)
index-1
while(length(index)) {
matplot(x=matrix(r,nrow=3,ncol=4),y=cbind(x,y,z,w),
xlab=Number of iteration,ylab=Bias,
type=b,pch=c(1,22,22,22),lwd=2,
Hi Shiv82,
This doesn't look like it comes from the SharpeR, iBATGCH, inference
packages and there are too many other packages using the term to
easily identify it. As Rolf pointed out, alternative hypotheses are
typically framed as:
two-sided - non-directional, only specifies that the comparison
On 30/04/15 23:22, Shivi82 wrote:
Hi All,
This is my first post in the community.
I am currently working on finding some inferences from my sample data and
the code I have used is:
inference(y = nc$weight, x = nc$habit, est = mean, type = ht, null = 0,
method = theoretical). While researching
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Duncan
Murdoch
Sent: Thursday, April 30, 2015 1:33 PM
To: Anirudh Jayaraman
Cc: r-help@r-project.org
Subject: Re: [R] 'Installation of package package had non-zero exit
status' on R-3.2.0 (RStudio
... and if this is what is wanted, somewhat cleaner and more
generalizable for programming would be:
do.call(c, mydata[,1:3])
## where the column indices might have to be adjusted to get the
desired columns.
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is
O puedes instalarte la ayuda directamente en R con el paquete sos..
sos: Search contributed R packages, sort by package
Search contributed R packages, sort by package
Saludos,
Carlos Ortega
www.qualityexcellence.es
El 30 de abril de 2015, 16:04, Emilio L. Cano emilopezc...@gmail.com
escribió:
Here are two correct uses of the stack command, if by that you mean the
stack() function.
stack( data.frame(a=1:3, b=4:6, c=7:9) )
values ind
1 1 a
2 2 a
3 3 a
4 4 b
5 5 b
6 6 b
7 7 c
8 8 c
9 9 c
stack( list(a=1:3, b=4:6, c=7:9)
46 matches
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