Thank you John for spending time on this query and helping out.
It really helped me and finally i am able to achieve the desired results.
Thanks a ton to all others as well to spending time and furbishing solution.
Regards, Shivi
--
View this message in context:
Hi
I (wrongly) understood that Shivi82 wanted to summarise on month values.
Therefore
format(test$CR_DT,%m)
shall give you month number and list is required by aggregate.
All the problem was in
test$CHG_WT
which seems to be a factor (for whatever reason)
Cheers
Petr
-Original
Thanks a lot Rainer
On Thu, Jun 11, 2015 at 4:24 PM, Rainer M Krug rai...@krugs.de wrote:
Again: please keep this on r-help!
AROONALOK PYNE aroonalok.p...@gmail.com writes:
Hi,
My system has 4GB memory. On running htop command on linux terminal, for
c(999), a() rug on
Again: please keep this on r-help!
AROONALOK PYNE aroonalok.p...@gmail.com writes:
Hi,
My system has 4GB memory. On running htop command on linux terminal, for
c(999), a() rug on single cpu core showed stats for 100% cpu
utilization. On reaching b(), the entire system hanged (no
AROONALOK PYNE aroonalok.p...@gmail.com writes:
Please check this code :
library(parallel)
workerFunc - function(n) { return(n^2) }
a - function(){
CurrentTime - Sys.time()
res - lapply(values, workerFunc)
TimeTaken - Sys.time() - CurrentTime
print(TimeTaken)
}
b - function(){
Please keep this on the r-help mailing list.
AROONALOK PYNE aroonalok.p...@gmail.com writes:
R version 3.0.2 (2013-09-25)
Large value : 999
I rerun the code as c(1000) for which your machine works fine but
my code still hangs on reaching b(). I am running it from Linux
Terminal.
-- Forwarded message --
From: AROONALOK PYNE aroonalok.p...@gmail.com
Date: Thu, Jun 11, 2015 at 2:25 PM
Subject: Re: Issue with mcapply
To: Rainer M Krug rai...@krugs.de
R version 3.0.2 (2013-09-25)
Large value : 999
I rerun the code as c(1000) for which your machine
-- Forwarded message --
From: AROONALOK PYNE aroonalok.p...@gmail.com
Date: Thu, Jun 11, 2015 at 3:49 PM
Subject: Re: Issue with mcapply
To: Rainer M Krug rai...@krugs.de
Hi,
My system has 4GB memory. On running htop command on linux terminal, for
c(999), a() rug on
Frank,
I'm not sure what is going on. The following test function works for me in both 3.1.1
and 3.2, i.e, the second model matrix has fewer columns. As I indicated to you earlier,
the coxph code removes the strata() columns after creating X because I found it easier to
correctly create
The main effect trend seems rather dangerous, why not just estimate the f’s in
a loop?
url:www.econ.uiuc.edu/~rogerRoger Koenker
emailrkoen...@uiuc.eduDepartment of Economics
vox: 217-333-4558University of Illinois
fax: 217-244-6678
Do you already have an R package that will do a Spearman
Correlation Volcano plot ?
What do the data look like?
Have a look at
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
and http://adv-r.had.co.nz/Reproducibility.html
for some suggestions on how to
In addition to the other answers, I would suggest that the next time you
get the could not find function message, try like this:
help.search('Boxplot')
Among the output from that you should see
graphics::boxplot Box Plots
which should lead you to boxplot instead of
Well it might have worked for your supervisor but I don't see how.
As was mentioned it is boxplot , not Boxplot and the rest of the syntax looks
dodgy to say the least.
Try
boxplot(Acc_S$Subj ~ Acc_S$Acc)
I don't see how label = will work , ?boxplot says it should be names = and as
the
Dear Brittany,
There is an essentially perfect linear dependency among the variables in your
data (note the last eigenvalue, which is 0 within rounding error):
eigen(cor(problem.data.boxcox[,-1]), only.values=TRUE)
$values
[1] 3.644257e+00 1.821582e+00 1.712152e+00 1.205091e+00
I'm trying, and so far failing, to extract data from a very large
SharePoint list.
I have a URL for getting XML from sharepoint:
http://
site/_vti_bin/owssvr.dll?Cmd=DisplayList={GUID}Query=*XMLDATA=TRUE
When I do something like the following:
require(XML)
require(RCurl)
URL - http://
On Jun 11, 2015, at 2:19 PM, John Kane wrote:
Well it might have worked for your supervisor but I don't see how.
As was mentioned it is boxplot , not Boxplot and the rest of the syntax looks
dodgy to say the least.
There is a Boxplot function in package 'car' and it has a labels
On Jun 11, 2015, at 12:25 PM, Kevin Kowitski wrote:
Hey,
I am having an issue with a for loop that is intended to read index values
by row and column so that it can pull out the valuable information. My issue
is that I am using a data.frame(which(df==1, arr.ind=TRUE))
That would be
On Jun 11, 2015, at 2:44 PM, MacQueen, Don wrote:
In addition to the other answers, I would suggest that the next time you
get the could not find function message, try like this:
help.search('Boxplot')
Spencer Graves uses RSiteSearch() as the underlying function for sos::findFn
--
Hi John,
That does help, thanks!
Brittany
On Jun 11, 2015, at 4:02 PM, John Fox j...@mcmaster.ca wrote:
Dear Brittany,
There is an essentially perfect linear dependency among the variables in your
data (note the last eigenvalue, which is 0 within rounding error):
Hey,
I am having an issue with a for loop that is intended to read index values by row and
column so that it can pull out the valuable information. My issue is that I am using a
data.frame(which(df==1, arr.ind=TRUE)) to find the index of the values in my data frame
that are equal to 1.
Hello,
I am familiar with the basics of statistical regression models, including
GAMs, but I am stumped on a particular implementation issue.
I am constructing a GAMM to fit to data that is autocorrelated. On of my
covariates (covariate 4) is a sin function the represents time of day. It
is
Cross-posting to SO and Rhelp is deprecated.
On Jun 11, 2015, at 8:40 PM, Bogdan Tanasa wrote:
Dear all,
please could you please with a simple question : I do have an array of 32
elements, where each element is indexed by a name : eg :
list_triplet_wells -c(A1:A2:A3, A4:A5:A6 ,
I did not realize that there is a coursers assignment similar to this. I am
running this for data analysis at work, not for coursers. However I will look
through the link you provided and see if it is applicable.
Thanks,
Kevin
Sent from my iPhone
On Jun 10, 2015, at 3:21 PM, David Winsemius
Dear Don, thank you very much.
I really wasn’t being able to figure the problem.
You were a big (huge) help.
Seeing the graphs, I think I’ll try to put the 3 settings (sample size) in
different graphs.
I’ll try to use trellis graphs :) using sample size as the “factor”
Thank you very much
Oh I see, I'm sorry I just plopped it in GitHub for ease of help, I didn't
notice I put it under coursera work. This task is not related to coursera, I
will separate it out.
-Kevin
Sent from my iPhone
On Jun 10, 2015, at 3:21 PM, David Winsemius dwinsem...@comcast.net wrote:
On Jun 10,
Dear all,
I would like to estimate a quantile regression model including a bivariate
nonparametric term which should be interacted with a dummy variable, i.e.,
log p ~ year + f(a,b):year.
I tried to use Roger Koenker's quantreg package and the functions rqss and qss
but it turns out that
Thanks John! My eyes aren't good enough to see that. I actually checked (I
thought). This was the default window on Mac console, for others who might care.
Sent from my iPad
On Jun 10, 2015, at 6:17 PM, John Kane jrkrid...@inbox.com wrote:
You have curly quotes rather than plain ones here
Dear all,
please could you please with a simple question : I do have an array of 32
elements, where each element is indexed by a name : eg :
list_triplet_wells -c(A1:A2:A3, A4:A5:A6 , A7:A8:A9, A10:A11:A12
)
xxx -array(0, dim=4)
dimnames(xxx) = list(list_triplet_wells)
From another script, I
Thanks Don,
I suspected there was a Boxplot() out there by was too lazy to look. I still
don't see how the original code would work if label only had onevalue but I
must admit what Boxplot() is actually doing is still confusing me.
John Kane
Kingston ON Canada
-Original Message-
Oh, Swami, gazing into the crystal ball one can see ...
;-}
Cheers,
Bert
Bert Gunter
Data is not information. Information is not knowledge. And knowledge is
certainly not wisdom.
-- Clifford Stoll
On Thu, Jun 11, 2015 at 4:48 PM, David Winsemius dwinsem...@comcast.net
wrote:
On Jun 11,
Hi Kevin,
I don't even pretend to try to read it. If David is having a problem I am
going for tea.
I think we need some sample data (see ?dput for the best way to supply it) and
an succinct description in English of what the problem is and what you need to
get out of the data.
I suspect
Muchas gracias por tu respuesta y el código Olivier, me es de mucha ayuda.
Un saludo,
Guillermo
Guillermo,
me temo que en tu simulación, el enfoque multinivel carezca de sentido.
Ten en cuenta que en este tipo de modelo la agrupación de los datos,
es decir el segundo nivel en la jerarquía,
Please check this code :
library(parallel)
workerFunc - function(n) { return(n^2) }
a - function(){
CurrentTime - Sys.time()
res - lapply(values, workerFunc)
TimeTaken - Sys.time() - CurrentTime
print(TimeTaken)
}
b - function(){
CurrentTime - Sys.time()
numWorkers - detectCores()
Dear Sirm/Madam,
Just wondering if someone could help me. I've tried running a code on R
and the code includes the following:
Boxplot(~Acc_S$Acc, label=Acc_S$Subj)
But I receive the following error message:
*Error: could not find function Boxplot*
I have tried installing all the packages
Rosa Oliveira wrote:
Dear Jim,
when I run your code (even the one you send me, not in my data), I get:
Don't know how to automatically pick scale for object of type function.
Defaulting to continuous
Error in data.frame(x = c(0.1, 0.2, 0.1, 0.2, 0.1, 0.2, 0.1, 0.2, 0.1, :
arguments
The idea is to move from regional dummies interacted with time dummies (model
1) to a smooth spline (defined on longitudes and latitudes) interacted with
time dummies (model 2), i.e.,
Model 1: Log p ~ X\beta + REGION*YEAR
Model 2: Log p ~ X\beta + f(long, lat)*YEAR
Estimating the f's in a loop
This is the script i am working from.
library(poLCA) f -
cbind(bq70,bq72_1,bq72_2,bq72_3,bq72_4,bq72_5,bq72_6,bq72_7,bq73a_1,bq73a_2,bq73a_3,bq73a_4)~
zq88+zq89+dm_zq101_2+dm_zq101_3+dm_zq101_4+dm_zq101_5+dm_zq101_6+dm_zq101_7+dm_zq101_8+dm_zq101_9
for(i in 2:14){max_II--100 min_bic-10
Hi all,
I have a data frame composed by 25 numerical variables. I want to do a Spearman
Correlation Volcano plot (i. e. x = correlation coefficient and y = -log10(p
value))
I'm a begginer in R, so how can I do this ?
PS : Sorry for my English, this is not my mother tongue.
Thank you !
Dear all,
I am using ksvm in R for SVM classification. I trained the SVM classifier
with prob.model=TRUE. I have the two following outputs when I predicted.
1) label-predict(model, TestData)
I have classification accuracy about 93%, where as in another mode
2) Probvalues-predict(model,
R is case sensitive.
try boxplot not Boxplot
On Thu, Jun 11, 2015 at 7:20 AM, Kris Singh
kris.si...@research.uwa.edu.au wrote:
Dear Sirm/Madam,
Just wondering if someone could help me. I've tried running a code on R
and the code includes the following:
Boxplot(~Acc_S$Acc,
Start by going through an R tutorial or two? You need to do some minimal
homework BEFORE posting here.
Cheers,
Bert
Bert Gunter
Data is not information. Information is not knowledge. And knowledge is
certainly not wisdom.
-- Clifford Stoll
On Thu, Jun 11, 2015 at 8:05 AM, Pierlot Gabin
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