Mike,
There may be a more efficient way to do this, but this works on your
example.
# mix up the order of the rows
mix - dat[order(runif(dim(dat)[1])), ]
# get rid of duplicate x1s and x2s
sub - mix[!duplicated(mix[, x1]) !duplicated(mix[, x2]), ]
sub
Jean
On Mon, Jun 22, 2015 at 11:42 AM, C
R users,
Abstracts are now being accepted for the
2016 ASA Conference on Statistical Practice,
February 18-20,
San Diego, CA, USA.
Past conference attendees have shown particular interest in R,
reproducibility, and data visualization.
The deadline for submission is June 25.
You could apply na.omit() to just the columns you are using:
dcast(na.omit(df[,1:2]), v1 ~ v2, length, margins = TRUE)
Using v2 as value column: use value.var to override.
v1 X Y Z (all)
1 A 1 2 2 5
2 B 1 2 1 4
3 (all) 2 4 3 9
-
Hello R list,
I am have question about sampling unique coordinate values.
Here's how my data looks like
dat - cbind(x1 = rep(1:5, 3), x2 = rep(c(3.7, 2.9, 5.2), each=5))
dat
x1 x2
[1,] 1 3.7
[2,] 2 3.7
[3,] 3 3.7
[4,] 4 3.7
[5,] 5 3.7
[6,] 1 2.9
[7,] 2 2.9
[8,] 3 2.9
2015-06-22 12:38 GMT-03:00 jbetancourt jbetanco...@iscmc.cmw.sld.cu:
Gracias funcionó
si , efectivamente , así se eliminan, pero es que son casos diarios de una
enfermedad y no qusiera que el espacio se eliminara ?como tratarlo de
manera que se evalue el día sin tener en cuenta el valor,
I have the following code which creates a spline function
x - c(1, 12, 24, 36, 60, 120, 200, 240, 300, 360)
y - c(.2, 8, 8, 8, 8, 8, 8, 8, 18, 50)
Baseline - cbind(x,y)
Turnover - splinefun(Baseline[,1], Baseline[,2], method = natural)
plot(Turnover(seq(1, 360, 1)), type = l)
If I change the
Hi Jean,
Thanks!
Daniel,
Yes, you are absolutely right. I want sampled vectors to be as different
as possible.
I added a little more to the earlier data set.
x1 x2 x3
[1,] 1 3.7 2.1
[2,] 2 3.7 5.3
[3,] 3 3.7 6.2
[4,] 4 3.7 8.9
[5,] 5 3.7 4.1
[6,] 1 2.9 2.1
[7,] 2
On Jun 22, 2015, at 10:46 AM, synapse 123 wrote:
Hi
I wanted to know if I cn use Random Forest in R for time to event data. I
cannot use Random Survival Forest since my data is not censored. Any
suggestions.
I'm not sure why that should be a problem for RandomSurvivalForests. It's not a
On Mon, 22 Jun 2015, My List wrote:
All:
I am trying to implement CHAID decision tree. Can anyone please help me to
know which package can be used for it or lead me to the documentation to
the same.
A CHAID implementation is available on R-Forge at:
Por boxplot circular, ¿te refieres a esto? (sunburst)
http://bl.ocks.org/mbostock/4063423
Parece que hay alguna posibilidad de replicarlo con ggplot2 con coord polares
http://stackoverflow.com/questions/12926779/how-to-make-a-sunburst-plot-in-r-or-python
Saludos,
Pedro
All:
I am trying to implement CHAID decision tree. Can anyone please help me to
know which package can be used for it or lead me to the documentation to
the same.
I did read a web page says that only the source for the CHAID package is
available. Kindly,advice on the package to be used.
Thanks
Version 0.8.5 of metricsgraphics is now on CRAN.
It provides an 'htmlwidgets' interface to the 'MetricsGraphics.js'
('D3'-based) charting
library which is geared towards displaying time-series data. There are
routines for scatterplots, histograms and even 'grid.arrange'-like
functionality for
On Jun 22, 2015, at 1:09 PM, Glenn Schultz wrote:
I have the following code which creates a spline function
x - c(1, 12, 24, 36, 60, 120, 200, 240, 300, 360)
y - c(.2, 8, 8, 8, 8, 8, 8, 8, 18, 50)
Baseline - cbind(x,y)
Turnover - splinefun(Baseline[,1], Baseline[,2], method = natural)
On 6/22/2015 9:42 AM, C W wrote:
Hello R list,
I am have question about sampling unique coordinate values.
Here's how my data looks like
dat - cbind(x1 = rep(1:5, 3), x2 = rep(c(3.7, 2.9, 5.2), each=5))
dat
x1 x2
[1,] 1 3.7
[2,] 2 3.7
[3,] 3 3.7
[4,] 4 3.7
[5,] 5 3.7
Hi
I wanted to know if I cn use Random Forest in R for time to event data. I
cannot use Random Survival Forest since my data is not censored. Any
suggestions.
Thanks
Azi
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R-help@r-project.org mailing list
Hi Petr,
Thanks for the mail. Please find below the required information
Version: R-3.1.1 console
sessionInfo(): Attached the session info for your reference
Did you install new packages/R version? No
Did you load the package by library(xts)? Yes. I was able to run all the
functions related
Hi,
I am working on a problem which I think can be handled as a repeated measures
analysis, and I have read many tutorials about how to do this with R. This part
goes well, but I get stuck with the multiple comparisons I'd like to run
afterward. I tried two methods that I have seen in my
Hi,
I am trying to run packages timeseries, forecast, xts packages to execute some
task. I was using this R-console for 8months. I had never faced any issue. Now,
It's throwing an error saying 'Error: could not find function forecast
Similarly for other packages as well. Could you please
Hi,
I am a developer and I code 'R'. We have some project tasks and
durations(Expected, 50% - Average Case and 90% - Worst Case ) and I am trying
to understand how a simulation of this using monte carlo would help. Most of
the websites deal with either the math or some commercial
Hi,
I am relatively new to Bayesian statistics and am trying to apply a
non-linear hierarchical model using R2winBUGS on some tree stocking density
data. I am hoping someone may be able to help me find the reason why
R2winBUGS is giving me the following error:
*gen.inits cannot be executed (is
Hi
Please some aditional info:
version
sessionInfo()
Did you install new packages/R version?
Did you load the package by library(xts)?
And preferably no HTML post.
Cheers
Petr
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of
With so little to go on, we are not likely to be much help. A reproducible
example and output of sessionInfo would be the minimum information that the
Posting Guide would tell you to provide.
A wild guess is that you need to have a conversation with your system
administrator. If your R version
Estimados
En el presente script quisiera que me mostraran la manera de que los valores
cero que aparecen en la serie de casos diarios no se lean, es decir que no se
tengan en
cuenta para el análisis de la serie. Adjunto la serie
rm(list = ls())
x-scan('D:/Public/Documents/R/EPICALC/e.csv')
I'm using the dcast function from Hadley's reshape2 package to do some
tabulations. I can't get it to exclude NA's in the variables being
tabulated. Here's a simple example.
v1 - c(rep(A, 5), rep(B, 5), NA)
v2 - c(X, Y, Y, Z, Z, X, Y, Y, Z, NA, Z)
v3 - c(rep(a, 4), c, a, b, NA, c, b, c)
df -
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