Dear Sir,
Thanks for your great guidance. Made me realize that I need to think out of
box.
As regards the low losses, BASEL guidelines do say to get rid of such low
losses which create noise in analysing the losses caused by Operational Loss
events.
Its the right tail events do matter which
I would start by looking at the "Graphics" and "Web Technologies" entries
in "Task Views" on CRAN. In addition, I suspect there might be some
packages listed in the Spatial task view that could do this.
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore,
Hello,
I am trying to build a map of a country which shows informations to its
regions in a popup window as soon as someone clicks on a region.
Thank you
--
View this message in context:
http://r.789695.n4.nabble.com/interactive-Map-Popups-tp4710226.html
Sent from the R help mailing list archi
I think that the Cox model still works well when the only information
in the censoring is conditional on variables in the model. What you
describe could be called non-informative conditional on x.
To really see the difference you need informative censoring that
depends on something not included i
On 23/07/15 01:15, Therneau, Terry M., Ph.D. wrote:
3. Should you ever use it [i.e. Type III SS]? No. There is a very strong
inverse
correlation between "understand what it really is" and "recommend its
use". Stephen Senn has written very intellgently on the issues.
Terry --- can you pl
So - as you can see, your data can be modelled.
Now the interesting question is: what do you do with that knowledge. I know
nearly nothing about your domain, but given that the data looks log-normal, I
am curious abut the following:
- Most of the events are in the small-loss category. But most
Hello, everyone!
I'm new to R, so I'm sorry in advance if it's something obvious, but I still
can't figure it out.
I've started experimenting with apriori and everything was working fine,
i.e. I changed support and confidence and results were different depending
on combination.
But on the next a
Amelia Marsh yahoo.com> writes:
> Hello! (I dont know if I can raise this query here on this forum,
> but I had already raised on teh finance forum, but have not received
> any sugegstion, so now raising on this list. Sorry for the same. The
> query is about what to do, if no statistical distr
Try this:
ggplot(mydf,aes(x)) +
geom_line(aes(y = y1, colour = "y1")) +
geom_line(aes(y = y2, colour = "y2")) +
scale_color_manual(values = c(y1 = "green4", y2 = "blue2"))
Note that you don't need to use `mydf` and names in the manual scale
should match the values in the aes() calls.
Alsoi
Try:
qqnorm(log(mydat))
That doesn't look too bad, does it? Now: where is the problem?
Cheers,
B.
On Jul 22, 2015, at 12:41 PM, Amelia Marsh wrote:
> Hello!
>
> (I dont know if I can raise this query here on this forum, but I had already
> raised on teh finance forum, but have not receive
matthewjones43 kellogg.ox.ac.uk> writes:
>
> Hi, I am not a statistician and so I am sure whatever it is I
> am doing wrong
> must be an obvious error for those who are...Basically I can
> not understand
> why I get NA for variable 'CDSTotal' when running a glm?
> Does anyone have an
> idea o
Hi,
Given a data frame, I'm trying to graph multiple lines on one graph, each
line being a different color and each colored line corresponding to a
specific name in the legend. Here is a very basic data sample to work with:
x <- seq(0,40,10)
y1 <- sample(1:50,5)
y2 <- sample(1:50,5)
mydf <-
Hello!
(I dont know if I can raise this query here on this forum, but I had already
raised on teh finance forum, but have not received any sugegstion, so now
raising on this list. Sorry for the same. The query is about what to do, if no
statistical distribution is fitting to data).
I am into
Hello,
I am trying to figure out if there is a way to order the left side of a Sankey
diagram from most frequent to least frequent. I am using R version 3.2.1 and
using googleVis version 0.5.9 for the Sankey. I've tried sorting, but that does
not work. Is there anyway to force it to arrange the
On Wed, 22 Jul 2015, Boris Steipe wrote:
According to ...
http://info.ngwa.org/gwol/pdf/721000139.PDF (Graphical Interpretation of
Water Quality Data)
... a Langelier-Ludwig plot is simply a scatterplot of cations vs. anions (in
percent).
Surely that would be beyond trivial to produce in R.
Please reply to the list, not me. The list doesn't allow most
attachments (and most of the list recipients are highly unlikely to
open unsolicited binary files anyway). Do see the link I provided for
the appropriate way to create reproducible examples, including
providing data (hint: use dput(), an
forgot the reply to all:
These are serial dates within EXCEL. Here is a way of converting them:
> as.Date(c(42460, 42426), origin = '1899-12-30')
[1] "2016-03-31" "2016-02-26"
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how
On Jul 22, 2015, at 12:50 AM, JIALU YAO wrote:
> Hello,
>
> When I type the code *rownames(gene_exp_matrix)<-levels(geneidfactor)*,the
> error happens: Error in "rownames<-(*tmp*,value=character(0)):can not set
> object to 'rownames'.
>
> I am using Mac OS X10.10.2.
>
> How can I fix this prob
Those numbers are a "serial" number of days. A value of 1 maps to Jan 1,
1900. ref:
https://support.office.com/en-za/article/DATE-function-e36c0c8c-4104-49da-ab83-82328b832349
A formula such as: as.Date('1900-01-01')+excel_date-1 should convert the
serial value to a date value.
On Wed, Jul 22, 20
According to ...
http://info.ngwa.org/gwol/pdf/721000139.PDF (Graphical Interpretation of
Water Quality Data)
... a Langelier-Ludwig plot is simply a scatterplot of cations vs. anions (in
percent).
Surely that would be beyond trivial to produce in R. Or am I missing a subtle
something?
Che
Hi Antony,
I am not sure it could work easily with package xlsx. Try using the
function read_excel() from package readxl. This function allows for
Dates to be read.
HTH,
Ivan
--
Ivan Calandra, ATER
University of Reims Champagne-Ardenne
GEGENAA - EA 3795
CREA - 2 esplanade Roland Garros
51100
My web search for an R package producing Langelier-Ludwig plots found no
hits. Has this been implemented in base graphics, lattice, ggplot2, or
another package?
The reference:
Langelier, W., and Ludwig, H., 1942, Graphical methods for indicating the
mineral character of natural waters: J. Am
Without a reproducible example that includes some sample data (fake is
fine), the code you used, and some clear idea of what output you
expect, it's impossible to figure out how to help you. Here are some
suggestions for creating a good reproducible example:
http://stackoverflow.com/questions/59632
Hi,
Here i am having a ".xlsx" file and it contains various columns including
date-column[mm/dd/yy]-but it is not in the date format. I have to read this
excel[.xlsx] file and need to get in dataframe. So i used "xlsx"-liabrary
and it was fine to read data. But the problem is, values in the date c
Package SDR for subgroup discovery data mining is available on CRAN now.
More info of the package on the CRAN page:
https://cran.r-project.org/web/packages/SDR/index.html
Ángel.
[[alternative HTML version deleted]]
___
R-packages mailin
Hello,
When I type the code *rownames(gene_exp_matrix)<-levels(geneidfactor)*,the
error happens: Error in "rownames<-(*tmp*,value=character(0)):can not set
object to 'rownames'.
I am using Mac OS X10.10.2.
How can I fix this problem?
Thank a lot.
Yao
--
View this message in context:
http:/
I wish to simulate event times where the censoring is informative, and to
compare parameter estimator quality from a Cox PH model with estimates
obtained from event times generated with non-informative censoring. However
I am struggling to do this, and I conclude rather than a technical flaw in
my
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
and http://adv-r.had.co.nz/Reproducibility.html
John Kane
Kingston ON Canada
> -Original Message-
> From: l.shul...@hotmail.com
> Sent: Tue, 21 Jul 2015 10:39:45 -0700 (PDT)
> To: r-help@r-project.org
On 7/21/2015 11:14 AM, Michael Friendly wrote:
More generally, for an I x J x K table, where the last factor is the
response, my desired result
is a data frame of IJ(K-1) rows, with adjacent log odds in a 'logodds'
column, and ideally, I'd like
to have a general function to do this.
Note that if
Hi,
In addition to Terry’s great comments below, as this subject has come up
frequently over the years, there is also a great document by Bill Venables that
is valuable reading:
Exegeses on Linear Models
http://www.stats.ox.ac.uk/pub/MASS3/Exegeses.pdf
Regards,
Marc Schwartz
> On Jul 2
Dear Terry,
I am very grateful to you for such a detailed and helpful answer.
Following your recommendation then I will skip the method presented at
http://www.ats.ucla.edu/stat/r/faq/type3.htm
So far, based on my understanding of R I arrived to the conclusion that the
correct way to see if ther
On Wed, Jul 22, 2015 at 9:50 AM, Jomy Jose wrote:
> How to calculate the sensitivity,specificity,Youden index for 18 factors
> and their combination (6 factors in each) with an outcome measure.
www.rseek.org turns up a bunch of references to Youden index,
including packages.
Without a reproducib
How to calculate the sensitivity,specificity,Youden index for 18 factors
and their combination (6 factors in each) with an outcome measure.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
"Type III" is a peculiarity of SAS, which has taken root in the world. There are 3 main
questions wrt to it:
1. How to compute it (outside of SAS). There is a trick using contr.treatment coding that
works if the design has no missing factor combinations, your post has a link to such a
descri
Sent from my iPhone
Begin forwarded message:
> From: Maram SAlem
> Date: July 21, 2015 at 11:40:56 PM GMT+2
> To: Arne Henningsen
> Cc: "r-help@r-project.org"
> Subject: Re: [R] Warning message with maxLik()
>
> Dear Arne,
>
> The elements of the theta vector are indeed strictly positive.
On Jul 21, 2015 9:30 PM, wrote:
>
> Dear Ladies and Gentlemen,
> as a beginner in R, I encountered a sort of "naturally given
limits"concerning the process of amending R with packages.
> I apparently own version 3.0.2 and I principally decided to use R via
> the RKWard GUI on Linux Kubuntu Trusty
Thanks Thierry
What if I don't know the n in the offset term?
On Wednesday, July 22, 2015, Thierry Onkelinx
wrote:
> If you know the number of counts (n) used to calculate the average then you
> can still use a poisson distribution.
>
> Total = average * n
> glm(total ~ offset(n), family = poiss
> On 22 Jul 2015, at 06:48 , Don McKenzie wrote:
>
> Sorry. Central limit theorem.
Or some sort of vegetarian sandwich. Celery, Lettuce, Tomato sounds almost
edible with sufficient mayo. ;-)
> Enough averaging and you get a normal distribution (simply stated, perhaps
> too simply). If so oth
Hi lstat,
The problem may be that as you are adding your connector triangles
there is a fill color. Try reprogramming with col=NA if you are using
"polygon" to draw the connectors.
Jim
On Wed, Jul 22, 2015 at 12:49 PM, David Winsemius
wrote:
>
> On Jul 21, 2015, at 10:39 AM, lstat wrote:
>
>> H
Hi Pierre,
I get a reasonable plot using the following code:
par(mar=c(6,4,4,2))
barpos<-barplot(unlist(GEP.data2),
main="Global Portfolio Weights",
col.main="gray", col=blues9,
cex.axis=1, ylim=c(-1,1), las=2,
cex.lab=1, cex=0.8)
axis(1,at=barpos,labels=rep("",8))
For one thing, you don't ne
If you know the number of counts (n) used to calculate the average then you
can still use a poisson distribution.
Total = average * n
glm(total ~ offset(n), family = poisson)
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie &
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