Thanks Dave.
What I actually want is to obtain say 10, different sets of (n=50) data for
every 10,000 iterations I run. You will realise that the current code produces
one set of data (n=50). I want 10 different sets of 50 observations at one run.
I hope this makes sense.
Chris Guure
On
I'm not sure I understand your question. Both functions return CD
because they perform exact string matching. The first demonstrates how string
or character replacements can be vectorized, while the second merely
demonstrates how Rcpp can accelerate this type of operation.
Cheers,
Adam
On
On Jul 31, 2015, at 6:36 PM, Christopher Kelvin via R-help wrote:
Dear All,
I am performing some simulations for a new model. I run about 10,000
iterations with a sample of 50 datasets and this returns one set of 50
simulated data.
Now, what I need to obtain is 10 sets of the 50
Dear All,
I am performing some simulations for a new model. I run about 10,000 iterations
with a sample of 50 datasets and this returns one set of 50 simulated data.
Now, what I need to obtain is 10 sets of the 50 simulated data out of the
10,000 iterations and not just only 1 set. The model
Dear all,
when I am running the code attached below, it seems that no results are
returned, only the predefined NAs. What mistake do I make?
Any comments and help is highly appreciated.
Thanks and best,
Martin
Simpar3 - function(n1) {
L2distance - matrix(NA, ncol=n1, nrow=n1)
data -
Martin,
I think the main problem is that you are trying to assign your results
to the result matrix inside the foreach loop. Parallel functions in R
are generally not good at updating parts of matrices from the different
workers in this way. Instead, using e.g. foreach, each loop of the
Dear Sir/MadamPlease provide me with the information how to implement R, what
is a steps of implementation and obligations, difficulties and etc.
thank you in advance Mr. Beka Biashvili
Quality Management System
ISO 9001:2008 Lead Auditor
18 Lortkipanidze street, Tbilisi, Georgia.
mob:
I am working in China for a month and needed to download an earlier version of
R in order to use Deseq2 and its requirements. The download got to the last few
seconds and hung up. A trojan was found. It could be coincidence that it
happened when I was downloading R, or perhaps a man in the
Try this chance to actually return values:
library(doParallel)
Simpar3 - function(n1) {
L2distance - matrix(NA, ncol=n1, nrow=n1)
data - rnorm(n1)
diag(L2distance)=0
cl - makeCluster(4)
registerDoParallel(cl)
x - foreach(j=1:n1) %dopar% {
library(np)
datj - data[j]
Daniel,
Basically just responding to your last paragraph (the others are
interesting, but I think that you are learning as much as anyone and I
don't currently have any other suggestions).
I am not an expert on copulas, so this is a basic understanding, you
should learn more about them if you
On Jul 31, 2015, at 8:38 AM, Beka Biashvili via R-help r-help@r-project.org
wrote:
Dear Sir/MadamPlease provide me with the information how to implement R, what
is a steps of implementation and obligations, difficulties and etc.
thank you in advance Mr. Beka Biashvili
Quality Management
On Jul 31, 2015, at 5:55 AM, tom walk rootsw...@yahoo.co.uk wrote:
I am working in China for a month and needed to download an earlier version
of R in order to use Deseq2 and its requirements. The download got to the
last few seconds and hung up. A trojan was found. It could be
Hi Adam,
Possibly subset() or would be helpful. Or even aggregate(),
depending on your ultimate goal.
Without a reproducible example that includes some sample data provided
using dput() (fake is fine), the code you used, and some clear idea of
what output you expect, it's impossible to figure
This is very basic. Have you made **any** effort to learn R -- e.g. by
going through an R tutorial? If not, please do this before posting
further. This will save you -- and foks on this list, probably -- a
lot of grief in the long (or even short) run.
Also, if/when you do post further, post in
On Jul 31, 2015, at 2:22 PM, Steven Backus bac...@whimsy.med.utah.edu wrote:
I'm on RHEL 6.6, R version 3.2.1 Patched (2015-07-30 r68761) --
World-Famous Astronaut. Issuing the x11() command hangs R and
does not complete. A window is partially drawn then freezes.
Does anyone know of a
On Jul 31, 2015, at 1:49 PM, Adam Jauregui adm...@gmail.com wrote:
Hello R-help,
I am trying to compute the mean of a quarterback's career fantasy football
stats, but I wish to exclude his 2014 stats from the mean, as that will be
the test data for the model I am trying to build for my
I'm on RHEL 6.6, R version 3.2.1 Patched (2015-07-30 r68761) --
World-Famous Astronaut. Issuing the x11() command hangs R and
does not complete. A window is partially drawn then freezes.
Does anyone know of a solution?
Thanks,
Steve
--
Steven J. BackusComputer Systems
Hello R-help,
I am trying to compute the mean of a quarterback's career fantasy football
stats, but I wish to exclude his 2014 stats from the mean, as that will be
the test data for the model I am trying to build for my academic undergrad
research.
The code for figuring out the mean of his Yds
Thanks David,
I was hoping for something a little bit more generic and less
case-by-case basis.
Sebastien
On 7/30/2015 3:51 PM, David Winsemius wrote:
On Jul 30, 2015, at 8:37 AM, sbihorel wrote:
Hi,
When the as.layer function is used to overaly 2 lattice plots, there seems to be an
On Fri, 31 Jul 2015, Marc Schwartz wrote:
Can you run:
capabilities()
FWIW, on Slackware-14.1 I've had no issues with X11().
capabilities()
jpeg pngtiff tcltk X11aqua
TRUETRUETRUETRUETRUE FALSE
Hi
I am not an expert but the problem seems to me that
(den1/R1+den2+den3+den4+den5/R5)-1
gives you sometimes value 0 and sometimes negative. In these cases the value of
log(1/result) is NA or Inf and nls can not handle this.
I do not search vhere is nls2 from so I used nls and removed -1
Hi
Your question is a bit cloudy. Simple loop can be realised to populate lists
res-vector(100, list)
for (i in 1:100) {
lll - do something based on i value
res[[i]] - put lll in ith place of the list
}
Cheers
Petr
-Original Message-
From: R-help
Thank you very much for your help.
I tried it under Unix and then the parallel version was faster than under
Windows (but still slower than the non parall version). This is an important
point to keep in mind. Thanks for this.
Best,
Martin
Gesendet: Donnerstag, 30. Juli 2015 um 14:56
Dear All,
Was trying to study similar kind of this and found out a post on one of stack
overflow site:
http://stackoverflow.com/questions/8438903/open-source-projects-for-email-scrubbing-generating-structured-data-from-unstruc
I guess this is not really answered yet. But wanted to check the
Thank you very much to you both for your help.
I knew that parallelizing has some additional overhead costs, but I was
surprised be the order of magnitude (it was 10 times slower.) Therefore I
thought I made some mistake or that there is a more clever way to do it.
Best,
Martin
Gesendet:
marc_schwa...@me.com writes:
First, just an FYI, that this would be better posted to R-SIG-Fedora:
https://stat.ethz.ch/mailman/listinfo/r-sig-fedora
Thanks, I'll give it a try.
Can you run:
capabilities()
in a terminal session and see what it shows for X11:
Yes, here is the output:
Hi April,
You need nested loops for something like this
qs- c(0,0.25,0.5,1,2,4,8,16,32,64)
nrows-dim(Data)[1]
nqs-length(qs)
D.mat-SE.mat-matrix(NA,nrow=nrows,ncol=nqs)
for(row in 1:nrows) {
for(qval in 1:nqs) {
# perform your calculation and set D.mat[row,qval] and
SE.mat[row,qval] to the
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