s <- paste("'chain:",j,"'" ,sep="")
You don't want the single quotes around the string you are constructing.
Try
s <- paste0("chain:", j)
which will give you, e.g.,
"chain:1"
instead of
"'chain:1'"
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Fri, Aug 28, 2015 at 6:08 PM, Andrea L
I am noticing that there is a difference between the fitted.values returned
by train.kknn, and the values returned using predict with the same model and
dataset. For example:
> data (glass)
> tmp <- train.kknn(Type ~ ., glass, kmax=1, kernel="rectangular",
> distance=1)
> tmp$fitted.values
[[1]]
Hello all,
For a study I want to find E|X1/3+X2/3+X3/3-X4| for variables following
lognormal distribution. To get the value we need to use four integrals. This is
the code which I is used
fx<-function(x){
dlnorm(x,meanlog=2.185,sdlog=0.562)
}
U31<-integrate(function(y1) { sap
Hi Angela,
It depends upon what you want to illustrate. If you are just interested in
the relative values, you can suppress the labels. One solution is to create
a very high PDF to look at the colors, which you could then expand and
scroll around to see the labels.
Jim
On Sat, Aug 29, 2015 at 6:0
tf <- vector("list", numberofchains)
for (j in 1:numberofchains){
s <- paste("'chain:",j,"'" ,sep="")
tf[[j]] = mi.control.i@data$s@variables$y.obs.tx@parameters[30,]
}
If you want the component whose name is the value of the variable 's'
use data[[s]].
The syntax 'data$s' mea
Hi Jim,
Thank you, that definitely reduced it but there are still about 600 genes, so
too many to label. It does make the heat map itself look cleaner. Maybe
labeling isn't necessary for the heat map?
-Angela
On Fri, 8/28/15, Jim Lemon wrote:
Subj
Hi,
DrawDensity3D-function in package VecStatGraphs3D utilizes
rgl.points-function {rgl}:
function (vectors, Div = 40, Layers = 3, DrawAxes = FALSE)
{
open3d(windowRect = c(100, 100, 800, 800))
bg3d("white")
Cx = vectors[, 1]
Cy = vectors[, 2]
Cz = vectors[, 3]
Cr <- kd
Have you looked at the help for mlogit.optim? At the minimum you need a
likelihood function and starting value(s). If you don’t understand the
function syntax you may have difficulty interpreting any output that you do get.
> On Aug 28, 2015, at 11:26 AM, Alaa Sindi wrote:
>
> Dear All,
> ca
I am running a simulation and need to refer to a matrix of parameters from
a large object. Here is a snippet of the object structure itself:
Formal class 'mi' [package "mi"] with 3 slots
..@ call : language .local(y = y, n.chains = ..2, max.minutes = 2)
..@ data :List of 100
On Aug 28, 2015, at 11:26 AM, Alaa Sindi wrote:
> Dear All,
> can anybody help me with an example on how to use mlogit.optim?
That is just a helper function. The examples are all on the mogit help page.
>
>> On Aug 28, 2015, at 9:00 PM, Alaa Sindi wrote:
>>
>> Dear all,
>>
>> Can anyone he
Thank you Michael :)
S
On 28 August 2015 at 12:09, Michael Dewey wrote:
> Dear Suparna,
>
> See below
>
> On 28/08/2015 10:22, Suparna Mitra wrote:
>
>> Hello,
>>Can anybody please help me with mvabund package installation?
>> I downloaded and installed it. It seems installed, but I can't l
I am running a simulation and need to refer to a matrix of parameters from
a large object. Here is a snippet of the object structure itself:
Formal class 'mi' [package "mi"] with 3 slots
..@ call : language .local(y = y, n.chains = ..2, max.minutes = 2)
..@ data :List of 100
Dear All,
can anybody help me with an example on how to use mlogit.optim?
Regards
> On Aug 28, 2015, at 9:00 PM, Alaa Sindi wrote:
>
> Dear all,
>
> Can anyone help me to change the maximum likelihood of multinomial logic
> model in R?
>
> Thanks
__
Dear all,
Can anyone help me to change the maximum likelihood of multinomial logic model
in R?
Thanks
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide htt
On 27 Aug 2015, at 17:40 , Dirk Eddelbuettel wrote:
> Michael Meyer via R-help r-project.org> writes:
>
>> I am an (very) grateful user of Rcpp.
>
> Glad to hear that!
>
> But you are on the wrong mailing list. Please ask on rcpp-devel.
But for the benefit of the rest of us: A NumericVecto
peter dalgaard gmail.com> writes:
> But for the benefit of the rest of us: A NumericVector is a pointer, right?
Effectively even though it is not treated as one by the users. But you
know what P in SEXP stands for, and Rcpp objects really are what we call
"proxy objects" for the respective unde
Dear Agrima
As well as Sarah's seven possibilities an eighth occurs to me: you have
not yet read it into R in the first place. If that is the case you may
be able to use read.table to get it into a data frame with columns
corresponding to your words.
?read.table may be your friend here.
On 2
Nice and interesting! Something to remember.
Lesson (for me):
Always first look in Task Views on CRAN.
Choose Optimization and look at Mathematical Programming Solvers.
Berend
> On 28 Aug 2015, at 12:56, Hans W Borchers wrote:
>
> I got interested in enabling the full funcionality that MATL
Hi,
On Fri, Aug 28, 2015 at 7:49 AM, agrima seth wrote:
> i have a text file with data of the given format:
>
> white snow
> lived snow
> in snow
> lived place
> in place
> a place
> called place
> as place
That doesn't specify the format. I can think of at least seven things
that could be:
a ch
Hi
Without a reproducible example I am only guessing
Try this
xyplot(threshold ~ age |frequency.a, data=subset(rage !is.na(threshold} &
!is.na(age)),
groups = HL,
cex=0.5,
layout=c(7,4),
par.strip.tex=list(cex=0.8),
xlab="Age (years)",
ylab="Threshold
i have a text file with data of the given format:
white snow
lived snow
in snow
lived place
in place
a place
called place
as place
here i have to find the frequency of the terms only in the first column
(i.e.)
white - 1
lived- 2
in -2
a-1
called - 1
as -1
Could you please guide me how to do the
do that (Error: unexpected '>' in ">").
So, for me the following works (and it should also for you) and gives the
shown output (after a very short while):
Trapz <- as.matrix( read.table( "w.txt", head = T, row.names = "Traps"))
set.seed( 2
I perhaps should have added a stronger warning here; note that the model
fitting in my previous post (below) uses explicit initial breakpoints for
segmented (specifically, c(30,60) at line 1 of the get.segments() ). if you
know where yours are, substitute them there. Otherwise, you'd need to us
Dear Suparna,
See below
On 28/08/2015 10:22, Suparna Mitra wrote:
Hello,
Can anybody please help me with mvabund package installation?
I downloaded and installed it. It seems installed, but I can't load the
package.
Here is what I tried:
install.packages("/Users/smitra/Documents/Soft/mva
There isn't an abline method for segmented, and even if there were you'd need
segments() for a segmented line plot. You're going to have to roll your own.
That will need a function to extract the break locations and predicted values
at those points
I don't have your data, so I can't do one spe
I got interested in enabling the full funcionality that MATLAB's
lsqlin() has, that is with equality and bound constraints. To replace
an equality constraint with two inequality constraints will not work
with solve.QP() because it requires positive definite matrices. I will
use kernlab::ipop() inst
Hi,
Thank you for comments.
Yes it is a vector an not a list ;).
I need to round also the input Value (Value <- round(Value, digits=0). If
not Matching is not possible. The vector is a real number and the color.df
are Integer.
Thanks for sapply is better than lapply in my case.
Karim
On Fri, Aug 2
Hi Karim,
I'm not sure that this is what is causing the error, but your "list" is
actually a vector. The following runs, but the function is obviously not
working:
sapply(list,
function(x)
as.character(attriColorValue(x,list,colors=c("blue","white","red"),feet=1)))
There is probably a better nam
Hi,
attriColorValue works with one value. I would like to get the color of a
list with lappy but in input I have two variables (the value and the list).
attriColorValue <- function(Value, list, colors=c(a,b,c, d,e),feet){
list <- round(list, digits = 0)
Max <- max(list, na.rm=TRUE)
Hi Angela,
Assuming the above data frame is named angela.df:
angela.mat<-as.matrix(angela.df[,2:3])
angela.mat<-angela.mat[apply(angela.mat,1,function(x) all(x) > 0),]
will remove all of the rows that have contain at least one zero.
Jim
On Fri, Aug 28, 2015 at 9:00 AM, Angela via R-help
wrote
Hello,
Can anybody please help me with mvabund package installation?
I downloaded and installed it. It seems installed, but I can't load the
package.
Here is what I tried:
> install.packages("/Users/smitra/Documents/Soft/mvabund_3.10.4.tgz", repos
= NULL, type="source")
* installing *binary* p
t the help page, but it presumably
# won't work because of your sample size.
set.seed( 20150828) # for reproducibility
fisher.test( W, simulate.p.value = TRUE, B = 1e5)
# For B look at the help page.
Finally: Did Minitab really report "p > 0.001"? ;-)
Hth -- Gerrit
32 matches
Mail list logo
