On Oct 15, 2015, at 3:10 PM, William Dunlap wrote:
> C can tell when it hits the end of input. Reading the lines with
> readLines and passing them to scan() does not help - it is the
> same as having scan read the original file.
>
> My problem is that the file (or other connection) has a variab
I don't know what OS-independent function you use in C that performs the
way you describe. I would write the below function in C myself in order to get
this functionality in that language.
readListOfVectors <- function( input ) {
lines <- readLines( input )
if ( "" == lines[ length( lines ) ]
C can tell when it hits the end of input. Reading the lines with
readLines and passing them to scan() does not help - it is the
same as having scan read the original file.
My problem is that the file (or other connection) has a variable number
of fields on each "line", and perhaps no fields on so
Hi Jim,
Yes, your Java versions need to match bit width.
As for drivers, I do not use the Microsoft one; it used to be hard to
obtain for Linux users; I don't know if it still is. I currently use
"jtds" from Sourceforge:
http://jtds.sourceforge.net/
>From their site:
> jTDS is an open source
This is a problem in C as well... and the solution is to read the lines
yourself and then give those lines to scan.
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#.
scan(nlines=) does this post-processing, which is why I'm using it
instead of readLines.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Thu, Oct 15, 2015 at 2:06 PM, Sarah Goslee wrote:
> Thus the post-processing, which I assume you'd have to do with scan() as well.
>
>> tcon <- file(tfile, "r"
Hi,
I'm trying to use rvest to scrape a page and I am having difficulty excluding
child element superscripts via a CSS selector. For example, here I've read the
html and selected nodes.
p <- read_html(targetUrl)
p %>% html_nodes("td.xyz")
The result looks something like this:
{xml_nodeset
I have the following differential equations and return list:
dCgd.dt = -kad*y[1]-kgd*y[1] # PK model equation gut d
dCld.dt= kad*y[1]-rhyd-rmetd #pk model equation liver d
dCgl.dt = -kal*y2[1]-kgl*y2[1] # PK model equation gut l
dCll.dt= kal*y2[1]-rhyl-rmetl #pk model
Dear R family,I am trying to develop a 3D Scatterplot for the following data>
dput(fer)structure(c(1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 1, 2, 3, 4, 5, 1, 2, 3, 4,
5, 54.682478566783, 73.7179265155391, 56.0442812544372, 123.944575771864,
81.6715941711683, 51.7551364274066, 64.017245155324, 73.3252689749
Dear R family,
I am trying to develop a 3D Scatterplot for the following data
> dput(fer)
structure(c(1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5,
54.682478566783, 73.7179265155391, 56.0442812544372, 123.944575771864,
81.6715941711683, 51.7551364274066, 64.017245155324, 73.32526897
Thus the post-processing, which I assume you'd have to do with scan() as well.
> tcon <- file(tfile, "r") # or tcon <- textConnection(t)
> allfile <- readLines(tcon, n=1)
> strsplit(paste(allfile, collapse="\n"), "\"")
[[1]]
[1] "A " "Two line\nentry""\n\n"
"Three\nline\ne
Mark,
Thanks for the suggestion. I will have to look into that option. I assume
that if I am running on a 64-bit system, I also have to use the 64-bit
version of Java. We have had some problems in the past because the company
standard is a 32-bit version of Java and we had to also load in the 6
readLines() does not work for me since it breaks up
multiline fields that are enclosed in quotes. E.g., the
text file line
A "Two line\nentry"
should be imported as 2 strings, the second being
"Two line\nfield", not "\"Two line" with the next call to
readLines bringing in "fentry\"".
Bill Dunla
I've always used system("wc -l myfile") to get the number of lines in
advance. But here are two other R-only options, both using readLines
instead of scan. There's probably something more efficient, too.
Your setup:
t <- 'A "Two line\nentry"\n\n"Three\nline\nentry" D E\n'
tfile <- tempfile()
cat(t
> On 15 Oct 2015, at 13:45 , jpara3 wrote:
>
> I have tried:
>
> tktitle(tt) <- iconv("¡GUI estadística", from="latin1",to="UTF8")
> tktitle(tt) <- iconv("¡GUI estadística", from="",to="UTF8")
> tktitle(tt) <- iconv("¡GUI estadística", to="UTF8")
>
>
> But there are no good results.
>
Hmm,
I would like to read a connection line by line with scan but
don't know how to tell when to quit trying. Is there any
way that you can ask the connection object if it is at the end?
E.g.,
t <- 'A "Two line\nentry"\n\n"Three\nline\nentry" D E\n'
tfile <- tempfile()
cat(t, file=tfile)
tcon <- file
Hi Jim,
No answers over the course of 24 hours so I'll give it a shot.
First, I always work under Linux, so my answers may well be worthless
for your Windows scenario.
Second, I don't know if my workaround works as I don't actually have a
SQL Server DB using float.
Now the workaround:
I have h
On Oct 15, 2015, at 4:07 AM, Wiebke Ullmann wrote:
> Dear everyone.
>
> I have a data frame with relocation data of several animals
>
>> head(data)
It would be better to post output of dput(head(data))
>
>timestamp
>
>
> individual
>
>
> easting
>
>
> nor
My strategy is to be specific about the names of columns at the top level. As I
see it, letting functions internally come up with their own column names makes
fragile code.
foo <- function(df, newColName ) {
x <- setNames( df[, 1, drop = FALSE], newColName )
dfOut <- data.frame(df, x)
dfOut
}
Tried compiling all previous version of R 3.x.x. Compilations went fine.
Code works, but every version throws the 'graphics problem' (basically,
spawns the X1 window, which more or less becomes a static screen capture
of the desktop under the spawned window.
What I think is related (cause?) is
Axel,
The solution you propose looks fine to me, if an error is the outcome that
you want in such a situation. Were you hoping for a different outcome?
Would you, for example, prefer that the "x" in the data frame be given a
different name, rather than the "x" in the function?
Jean
On Thu, Oct
May this be fine ?
foo <- function(df) {
x <- df[, 1, drop = FALSE]
available <- rev(letters[(letters %in% colnames(df)) == FALSE])
colnames(x) <- available[1]
dfOut <- data.frame(df, x)
dfOut
}
Data <- data.frame(x = c(1, 2), y = c(3, 4))
foo(Data)
x y z
1 1 3 1
2 2 4 2
--
GG
Hello,
I have a variable named 'x' defined inside a function, which may conflict
with a variable name supplied in the argument to the function. What is the
best practice to avoid this conflict?
foo <- function(df) {
x <- df[, 1, drop = FALSE]
dfOut <- data.frame(df, x)
dfOut
}
Data <- da
Doing enumerative combinatorics with rejection methods rarely
works well. Try mapping your problem to the problem of choosing
m-1 items from n-1. E.g., your code was
f0 <- function(n, m) {
stopifnot(n > m)
D<-matrix(0,nrow=n-m+1,ncol=m-1)
for (i in 1:m-1){
D[,i]<-seq(0,n-m,1)
}
Boris Steipe writes:
> Sorry - two typos coorected:
>
> If you need x[,"a"] + x[,"b"] equal to 1, then replace any non-zero initial
> value of x[,b] with 1-x[,a].
> But if you really need "less than" h, you'll need to specify what your
> desired distribution of h - (x[,"a"] + x[,"b"]) should loo
>From ?rq.fit.pfn I see:
Details:
Preprocessing algorithm to reduce the effective sample size for QR
problems with (plausibly) iid samples. The preprocessing relies
on subsampling of the original data, so situations in which the
observations are not plausibly iid, are likely
Hello All,
I am looking for any package/function which can give processing time for
each line of a given function. I came through the package "profr" but don't
know how to find line number.
Any help will be appreciated.
Thanks
--
Sheila
[[alternative HTML version deleted]]
__
I am using R in my project for analysis of data, and I have generated SVM
model using kernlab package with the dataset (3000 rows and 281 columns).
Now I want to generate this model for dataset containing 8000 rows and 281
column, but here I am getting an error saying that "cannot allocate vector
Dear everyone.
I have a data frame with relocation data of several animals
>head(data)
timestamp
individual
easting
northing
25.03.2014
07:00
animal1
410712.5
5913542
25.03.2014
08:00
Dear All,
I'm trying to do a simple task (which is in fact a tiny part of a larger
code).
I want to create a matrix, D, each of its columns is a sequence from 0 to
(n-m), by 1. Then, using D, I want to create another matrix ED, whose rows
represent all the possible combinations of the elements of
Sorry - two typos coorected:
If you need x[,"a"] + x[,"b"] equal to 1, then replace any non-zero initial
value of x[,b] with 1-x[,a].
But if you really need "less than" h, you'll need to specify what your desired
distribution of h - (x[,"a"] + x[,"b"]) should look like.
On Oct 15, 2015, at 9:5
If you need h equal to 1, then replace any non-zero initial value of x[,b] with
1-x[,a].
But if you really need "less than", you'll need to specify what your desired
distribution of h - x[,"a"] + x[,"b"] should look like.
No?
B.
On Oct 15, 2015, at 9:27 AM, Rainer M Krug wrote:
> Boris St
Boris Steipe writes:
> I don't think the problem is well defined. Otherwise you could just
> pick very small numbers from a range that is guaranteed to keep the
> sum < h.
What further information is missing? That the variables should be
covering the whole range from 0 to 1?
OK - forgotten to s
I don't think the problem is well defined. Otherwise you could just pick very
small numbers from a range that is guaranteed to keep the sum < h.
B.
On Oct 15, 2015, at 8:48 AM, Rainer M Krug wrote:
> Hi
>
> I need a Latin Hypercube with the following conditions:
>
> 0 < x[,"a"] < 1
> 0 < x
Hi
I need a Latin Hypercube with the following conditions:
0 < x[,"a"] < 1
0 < x[,"b"] < 1
0 < x[,"c"] < 1
but also
x[,"a"] + x[,"b"] < h
The first three are easy:
--8<---cut here---start->8---
n <- 1000
lhc <- lhs::randomLHS(n=n, k=3
colnames(lhc) <- c("a
We have to install R 3.2.2 on machines with too old libcurl to be able
to use https when installing packages, etc.
When a user tries to use install.packages() (with the default value of
the "repos" option), she is presented with a list of https-repos, which
is not very useful. She also gets an er
I have tried:
tktitle(tt) <- iconv("¡GUI estadística", from="latin1",to="UTF8")
tktitle(tt) <- iconv("¡GUI estadística", from="",to="UTF8")
tktitle(tt) <- iconv("¡GUI estadística", to="UTF8")
But there are no good results.
Can maybe exist a code to insert after the special characters, as \´i f
Read more carefully! That is what I did to _reproduce_ your problem.
Try
tktitle(tt) <- iconv("¡GUI estadística", to="UTF8", from="latin1")
or maybe from="", or from=, depending on how confused your
system is about the current encoding,
> On 15 Oct 2015, at 11:59 , jpara3 wrote:
>
> Hi P
Hi Peter,
Thanks for your help, but the problem is still happening.
I have done this:
funcion<-function(){
tt<-tktoplevel(bg="white")
x<-iconv("¡GUI estadística",to="latin1")
Encoding(x) <- "UTF8"
tktitle(tt)<-x
}
-
Guided Tours Basque Country
Guided tours in the three ca
> On 15 Oct 2015, at 09:52 , jpara3 wrote:
>
> Hi,
>
> I want to create my own package with a very simple GUI. The problem is that
> I need to use special latin characters, as ¿,¡,ñ...
>
> The function i have made is:
>
> funcion<-function(){
> tt<-tktoplevel()
> tktitle(tt)<-"¡GUI de estadí
Hi,
I want to create my own package with a very simple GUI. The problem is that
I need to use special latin characters, as ¿,¡,ñ...
The function i have made is:
funcion<-function(){
tt<-tktoplevel()
tktitle(tt)<-"¡GUI de estadística"
}
The problem is that when i run this function, instead est
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