Yes, but colMeans, rowMeans, pmax, pmin , etc. are *much* faster.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Fri, Feb 12, 2016 at 9:15 PM, J
Hi Ashta,
Surely you are aware of the "apply" family of functions that return the
numbers you want:
ashmat<-matrix(c(117,12,13,21,21,32,11,1,65,43,23,7,58,61,78,95 ),
nrow=4,byrow=TRUE)
apply(ashmat,2,mean)
[1] 65.25 37.00 31.25 31.00
apply(ashmat,1,which.max)
[1] 1 2 1 4
Jim
On Sat, Feb 13, 2
hi all,
I have a square matrix (1000 by 1000),
1. I want calculate mean, min and max values for each column and row.
2, I want pick the coordinate value of the matrix that has the max
and min value for each row and column.
This an example 4 by 4 square matrix
It can also happen if you use colClasses, since that applies as.factor to the
input column without first converting it to numeric. To wit:
> read.table(text="
+ 9
+ 10", colClasses="factor")$V1
[1] 9 10
Levels: 10 9
-pd
> On 12 Feb 2016, at 22:43 , Jim Lemon wrote:
>
> It depends upon what g
It depends upon what goes into the "data reshaping pipeline". If there is a
single non-numeric value in the data read in, it will alpha sort it upon
conversion to a factor:
x<-factor(c(sample(6:37,1000,TRUE)," "))
z<-factor(x)
levels(z)
[1] " " "10" "11" "12" "13" "14" "15" "16" "17" "18" "19" "
Thanks Greg. Worked perfectly!!!
cheers,
Rolf
On 13/02/16 09:22, Greg Snow wrote:
One option is to call `legend` twice and do some manual positioning.
This worked for me:
plot(1:10)
legend('topleft', lty=1:3, bty="n", legend=c('','','') )
legend('topleft', pch=c(20,8,1), bty="n",
legend=c('
> On 12 Feb 2016, at 17:44 , C W wrote:
>
> On a side note, is it ok to do?
>
> > which(max(p_x))
> and use that instead of numerical integration to get E[X]?
Now THAT makes absolutely no sense. max() is a number, so which(max()) usually
returns 1.
If you mean whether the mode is equal to t
One option is to call `legend` twice and do some manual positioning.
This worked for me:
plot(1:10)
legend('topleft', lty=1:3, bty="n", legend=c('','','') )
legend('topleft', pch=c(20,8,1), bty="n",
legend=c('clyde','irving','melvin'), inset=c(0.1,0))
You may need to fiddle with the amount of ins
Dear R list users,
I have three lists of data frames, respectively temp_list, wind_list and
snow_list.
The elements of these three lists are
temp_list$station1, temp_list$station2 and temp_list$station3 with columns date
and temp;
wind_list$station1, wind_list$station2 and wind_list$station3 wit
Not an answer
But note that your several stopifnot() statements can be combined into
1. See ?stopifnot .
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic
> On Feb 12, 2016, at 10:33 AM, Jacob Wegelin wrote:
>
> To check that a regression object comes from logistic regression, I employ
> the following two lines:
>
> stopifnot(glmObject$family$family=="binomial")
>
> stopifnot(glmObject$family$link=="logit")
>
> For instance:
>
> t
Define "truncated." (It is often confused with "censored".) As
stated, it seems to me that you already have the answer. Do you have
data? -- i.e. what do you mean by "parameters" ?
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking thin
On a side note, is it ok to do?
> which(max(p_x))
and use that instead of numerical integration to get E[X]?
I will try both and report back! Thank you expeRts
On Fri, Feb 12, 2016 at 11:29 AM, C W wrote:
> Hi Peter,
>
> Great, let me try that and get back to you on my findings in a few hours
Since this is due to a throttle in Twitter's API, I would assume that attempts
to bypass this will violate Twitter's TOS. You'll either have to purchase the
data you need, or build your own in-house data set, going forward.
B.
On Feb 12, 2016, at 8:18 AM, SHIVI BHATIA wrote:
> Dear Team,
>
To check that a regression object comes from logistic regression, I employ the
following two lines:
stopifnot(glmObject$family$family=="binomial")
stopifnot(glmObject$family$link=="logit")
For instance:
toyfunction<-function(glmObject) {
stopifnot(inherits(glmObject, "
Hi Peter,
Great, let me try that and get back to you on my findings in a few hours!
:)
On Fri, Feb 12, 2016 at 11:09 AM, peter dalgaard wrote:
> I don't see here FAQ 7.31 comes in either (for once!...)
>
> However, either the density is unnormalized and the integral is not 1, or
> the integral
Dear Team,
Kindly refer to the error below while generating a Twitter Analysis for my
firm:
# Warning message:
# In doRppAPICall("search/tweets", n, params = params, retryOnRateLimit =
retryOnRateLimit, :
As I checked on forums such as StackOverflow and other r related literature
it
Hello,
Do you know how to obtain the parameters of a theoretical normal
distribution knowing the parameters of the same truncated normal
distribution? Is there in R any function that can do it?
Thanks in advance
[[alternative HTML version deleted]]
___
I don't see here FAQ 7.31 comes in either (for once!...)
However, either the density is unnormalized and the integral is not 1, or the
integral is 1 and it is normalized. The one in the picture clearly does not
integrate to one. You can fit a rectangle of size 0.1 by 1e191 under the curve
so th
Hi Bert,
Yay fantasyland!
In all seriousness, You are referring to this?
https://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-doesn_0027t-R-think-these-numbers-are-equal_003f
In particular, you mean this: .Machine$double.eps ^ 0.5?
Thanks!
On Fri, Feb 12, 2016 at 10:53 AM, Bert Gunter
wrote:
>
You are working in fantasyland. Your density is nonsense.
Please see FAQ 7.31 for links to computer precision of numeric calculations.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in
Dear Federico,
> -Original Message-
> From: Federico Calboli [mailto:federico.calb...@helsinki.fi]
> Sent: February 12, 2016 10:27 AM
> To: Fox, John
> Cc: R Help
> Subject: Re: [R] why is 9 after 10?
>
> Dear John,
>
> that is fortunatey not the case, I just managed to figure out that
Hi David,
This is the Gaussian looking distribution I am trying to integrate.
https://drive.google.com/file/d/0B2xN0-A6iTB4NThIZ2tYdGxHc00/view?usp=sharing
Notice the unnormalized density goes up as high as 2.5*101^191.
I tried to create small intervals like
> seq(0.5, 1.3, by = 10^(-8))
but th
Dear John,
that is fortunatey not the case, I just managed to figure out that the problem
was that in the data reshaping pipeline the numeric column was transformed into
a factor.
Many thanks for your time.
BW
F
> On 12 Feb 2016, at 17:22, Fox, John wrote:
>
> Dear Federico,
>
> Might m
Dear Federico,
Might my.data[, 2] contain character data, which therefore would be sorted in
this manner? For example:
> x <- sample(6:37, 1000, replace=TRUE)
> table(x)
x
6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31
32 33 34 35 36 37
29 30 35 29 41 33 27 21 38
Hi All,
I have some data, one of the columns is a bunch of numbers from 6 to 41.
table(my.data[,2])
returns
10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
26 27 28 29 30 31 32 33 34 35 36 37
1761 1782 1897 1749 1907 1797 1734 1810 1913
>
>
> Date: Wed, 10 Feb 2016 15:19:21 +
> From: Lila Collet
> To: r-help@R-project.org
> Subject: [R] MonteCarlo sampling on profile log likelihood - package
> extRemes
>
>
> Hi
>
>
> I am using the package extRemes to assess 100-year return period
> runoffs with the GEV and GP dist
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