Re: [R] Latin Hypercube Sampling when parameters are defined according to specific probability distributions

Nell, I still might not be interpreting your question correctly, but I will try. When you say that the sum of the probabilities of all distance classes must equal one, I am going to treat distance as a class, instead of as a continuous variable. distance_class_probabilities <- c(9, 11, 10, 8.9,

Re: [R] Need Help - R Programming - Using iteration value to change field names for processing for every iteraion

Refer to columns by position rather than name and everything is simpler: for (i in 2:4 ) { test[, i] <- test[, i] + test[, i-1] } Note your approach fails on the first line since you start with i=1 and there is no Day0. Another approach that is simpler: t(apply(test, 1, cumsum)) David L.

Re: [R] (no subject)

> On May 30, 2017, at 11:18 AM, Pedro páramo wrote: > > I have seen that the vector of dates could be: > > itemizeDates(startDate="12-30-11", endDate="1-4-12") > > How can I say "today" without having to declare the endDate? > > Finally, if you can help mi with the

Re: [R] seek non-black box alternative to randomForest

I’m interested in the subject. If you send the question to another platform, please share the link here to follow up. Also, I wish to see the manuscript and rejected parts and detailed reasons. Most of the time, scientists want to reveal/discuss underlying physical process in an event and it’s

Re: [R] Differentiate values in a plot by colour or symbol

> On 30 May 2017, at 21:44, Tobias Christoph wrote: > > Okay;) > > First of all many thanks to you, Ismail, that you really try to help me. I am > really not an expert with R and try to learn. > You’re welcome. > I just checked: All columns in my data frame are

Re: [R] seek non-black box alternative to randomForest

Barry, This is mostly a mailing list about R - you have have more luck with statistical questions on www.stat.stackexchange.com. That said - the editor is wrong. The limitations of trees that random forests “solves” is overfitting. The mechanism by which a random forest classifier is built

Re: [R] (no subject)

I have seen that the vector of dates could be: itemizeDates(startDate="12-30-11", endDate="1-4-12") How can I say "today" without having to declare the endDate? Finally, if you can help mi with the plot would be very helpfull 2017-05-30 19:41 GMT+02:00 Pedro páramo :

[R] (no subject)

Hi all, I get started with R till many time ago. I want to make a function that makes a plot with several inputs. First of all, the first input is a date 01/01/2014. I make a plot of a calculated series from 01/01/2014 till TODAY. How can I make this vector authomatically without calculating

[R] seek non-black box alternative to randomForest

I've recently had a research manuscript rejected by an editor. The manuscript showed that for a real life data set, random forest outperformed multiple linear regression with respect to predicting the target variable. The editor's objection was that random forest is a black box where the random

Re: [R] Differentiate values in a plot by colour or symbol

Okay;) First of all many thanks to you, Ismail, that you really try to help me. I am really not an expert with R and try to learn. I just checked: All columns in my data frame are numeric. The range of years is from 2005 to 2016. Please find attached the result of "data.frame(data)". I

Re: [R] Differentiate values in a plot by colour or symbol

> On 30 May 2017, at 21:23, Tobias Christoph wrote: > > Ahh, okay. > > I think now I understand what you exactly mean. But the plot is stil not > working /differentiate the dots by color. I used the following formula. > "plot(data$stations, data$revenue,

Re: [R] Differentiate values in a plot by colour or symbol

Ahh, okay. I think now I understand what you exactly mean. But the plot is stil not working /differentiate the dots by color. I used the following formula. "plot(data$stations, data$revenue, xlab="stations", ylab="revenue", col = findInterval(data$year, c(2005, 2010, 2015))" I think the

Re: [R] Differentiate values in a plot by colour or symbol

> On 30 May 2017, at 20:48, Tobias Christoph wrote: > > Hi Ismael, > > thanks for your quick reply. > > I was now able to esmitate two intervals with the "findInterval"-Function. > > x > [1,] 2005 1 > [2,] 2006 1 > [3,] 2007 1 > [4,] 2008 1 > [5,] 2009 1 >

Re: [R] Differentiate values in a plot by colour or symbol

Hi Ismael, thanks for your quick reply. I was now able to esmitate two intervals with the "findInterval"-Function. x [1,] 2005 1 [2,] 2006 1 [3,] 2007 1 [4,] 2008 1 [5,] 2009 1 [6,] 2010 1 [7,] 2011 2 [8,] 2012 2 [9,] 2013 2 [10,] 2014 2 [11,] 2015 2 [12,] 2016 2 But I was

Re: [R] Differentiate values in a plot by colour or symbol

> On 30 May 2017, at 19:02, Tobias Christoph wrote: > > Hey Guys, > > I just try to differentiate certain values in my plot by colour or symbol. > > I have panel data with three dimensions (number of stations, revenue, > years). To integrate the third dimension

[R] Differentiate values in a plot by colour or symbol

Hey Guys, I just try to differentiate certain values in my plot by colour or symbol. I have panel data with three dimensions (number of stations, revenue, years). To integrate the third dimension (years) in the plot, I want to differentiate the values(number of stations, revenue) by a certain

[R] (Somewhat?) Off topic: Containerization software

Folks: This is **off topic**, but I thought it might be informative to this community. Consequently: please **no on list public comments or discussion**. Feel free to respond to me privately, if you like; but I have neither knowledge nor opinions, so why bother? This is just FYI. My apology if it

Re: [R] R package recommendation - recursively partition data frame, calculate summaries of node data frames, plot and print summaries

Hello Ross, > On 30 May 2017, at 14:51, Ross Gayler wrote: > > I am after R package recommendations. > > I have a data frame with ~5 million rows and ~50 columns. (I could do what > I want with a sample of the rows, but ideally i would use all the rows.) Very nice question

Re: [R] Fw: Need Help - R Programming - Using iteration value to change field names for processing for every iteraion

Your fields are adjacent, right? If so, you do not need to refer to them by name to accomplish this. Please spend some (more) time with an R tutorial or two as Rolf suggested, especially with "indexing". -- Bert Bert Gunter "The trouble with having an open mind is that people keep coming along

Re: [R] R package recommendation - recursively partition data frame, calculate summaries of node data frames, plot and print summaries

1. Generally this sort of thing (statistical issues) is OT here. 2. Have you tried googling? "recursive partitioning R" . 3. Have you looked at the CRAN "Machine Laearning" Task View? https://cran.r-project.org/web/views/MachineLearning.html -- Bert Bert Gunter "The trouble with having an

Re: [R] Latin Hypercube Sampling when parameters are defined according to specific probability distributions

Thanks a lot Rob for your answer. I need to add a condition for the parameter “dispersal distance”. The sum of the probabilities of all distance classes must be equal to 1: y <- c(9, 11, 10, 8.9, 8, 7, 6, 5.8, 5.1, 4, 3.9, 3.7, 3.4, 3.1, 2, 1.9, 1.6, 1.4, 1, 0.9, 0.8, 0.7, 0.4, 0.3, 0.1) x <-

Re: [R] ggplot: Pie Chart with correct labels

>1. get the order of the labels right You need to order your labels in the Land factor correctly when you create it with the factor function, which was (not) done here but rather before you used dput to generate this code. >2. Why I need to reference "breaks" and "labels" completely? Read

[R] ggplot: Pie Chart with correct labels

Hi All, I would like to do the following pie chart using ggplot from an official data source ( http://www.deutscheweine.de/fileadmin/user_upload/Website/Service/Downloads/Statistik_2016-2017-neu.pdf , Tab 8, Page 14): -- cut -- cat("# weinimport_piechart.R\n") # -- Input

[R] Fw: Need Help - R Programming - Using iteration value to change field names for processing for every iteraion

Hi All, I have tried in different ways. Finally I got the solution this way : for(i in 2:4) { test[,paste0("Day",i,".Prod.balc")] <- test[,paste0("Day",i,".Prod.balc")] + test[,paste0("Day",i-1,".Prod.balc")] } Please save it for references, if needed in future. Thanks all for your

Re: [R] Need Help - R Programming - Using iteration value to change field names for processing for every iteraion

Hi Manjusha, Thank you for the response. That surely helps. But the major issue in my case is not how we can apply sum fn, but how we can change field names based on iteration number. I cant skip loop in my case, because in real situation I have to deal with say around 100 fields, the only

[R] R package recommendation - recursively partition data frame, calculate summaries of node data frames, plot and print summaries

I am after R package recommendations. I have a data frame with ~5 million rows and ~50 columns. (I could do what I want with a sample of the rows, but ideally i would use all the rows.) (1) I want to recursively partition the rows of the data frame in a way that I manually specify. That is, I

Re: [R] Need Help - R Programming - Using iteration value to change field names for processing for every iteraion

Hello Vijaya, On Tue, May 30, 2017 at 12:32 PM, Vijaya Kumar Regati < vijayakumar.reg...@m3bi.com> wrote: > Hi, > > I am new to R programming, I am trying to work on below requirement. But > could not achieve desired result. > Appreciate if someone can help me on this : > > test dataframe : >

Re: [R] [FORGED] Need Help - R Programming - Using iteration value to change field names for processing for every iteraion

On 30/05/17 19:02, Vijaya Kumar Regati wrote: Hi, I am new to R programming, I am trying to work on below requirement. But could not achieve desired result. Appreciate if someone can help me on this : test dataframe : Day1.balc Day2.balc Day3.balc Day4.balc x 1002030

[R] Need Help - R Programming - Using iteration value to change field names for processing for every iteraion

Hi, I am new to R programming, I am trying to work on below requirement. But could not achieve desired result. Appreciate if someone can help me on this : test dataframe : Day1.balc Day2.balc Day3.balc Day4.balc x 100203040 y 1001010