Dear Robert,
Although you don't say so, it sounds as if you may be using the Anova()
function in the car package, which is what the R Commander uses for ANOVA. If
so, in most cases, Anova() returns an object of class c("anova", "data.frame"),
which can be manipulated as a data frame. To see
On Wed, 25 Jul 2018, David Winsemius wrote:
# create a list from these files
list.filenames<-list.files(pattern=".CSV$") # This gets a list of all CSV files
It would get all the files with all caps "CSV" anywhere within the file
name, but it would not get any files with an extension ".csv",
> On Jul 25, 2018, at 2:54 PM, Rich Shepard wrote:
>
> On Wed, 25 Jul 2018, Shawn Way wrote:
>
>> To get you start, here's a script I used to combine any number of files
>> into one data.frame.
>>
>> library(knitr)
>> library(tidyverse)
>> library(xlsx)
>> library(xtable)
>>
On Wed, 25 Jul 2018, Shawn Way wrote:
To get you start, here's a script I used to combine any number of files
into one data.frame.
library(knitr)
library(tidyverse)
library(xlsx)
library(xtable)
library(lubridate)
# create a list from these files
list.filenames<-list.files(pattern=".CSV$") #
Pemissions settings on your target directory (which is a Windows not an R
issue)??
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Wed, Jul 25, 2018
I just installed R 3.5.1 on a new Windows 10 computer. R tries to set a
personal library to C:/Users/jackp/OneDrive/Documents/R/win-lib/3.5. I want to
store R packages on my local hard drive, not OneDrive. I tried placing the
line of code:.libPaths(c(.libPaths(),
On Wed, 25 Jul 2018, Bert Gunter wrote:
Eric may have more to say, but the straightforward answer is: use
functions to do what you want and pass any file specific info to them as
parameters of function calls.
Bert,
I was considering that functions would be the way to go. The functions can
Eric may have more to say, but the straightforward answer is: use functions
to do what you want and pass any file specific info to them as parameters
of function calls.
If this seems arcane to you, then you have some homework to do, as using
functions is a (maybe the) central programming paradigm
On Wed, 25 Jul 2018, Eric Berger wrote:
You should be able to do all this within R. From what you have written I
don't see a compelling reason to use scripts at the shell level.
Eric,
The source() help page's last example calls a set of scripts to run
sequentially. I assume this is used to
You should be able to do all this within R.
>From what you have written I don't see a compelling reason to use scripts
at the shell level.
Best,
Eric
On Wed, Jul 25, 2018 at 9:41 PM, Rich Shepard
wrote:
> On Wed, 25 Jul 2018, Eric Berger wrote:
>
> 1. For R scripts you should also consider
In general, analysis functions in R return objects. When returned alone on an
interactive console the default print method for that object gets printed.
However, you can put it into a variable with the <- assignment operator, and
use the str function to see what values are inside the object,
On Wed, 25 Jul 2018, Eric Berger wrote:
1. For R scripts you should also consider the package littler developed by
Dirk Eddelbuettel, Highly recommended. For info
http://dirk.eddelbuettel.com/code/littler.html or the github repository.
Eric,
I'll definintely look at that package.
2.
On Wed, 25 Jul 2018, MacQueen, Don wrote:
From my perspective, which is a unix-alike perspective, Rscript makes R
useable in exactly the same way as other unix style scripting languages
such as perl, tcsh, bash, etc. This is useful, and a good thing. If I
remember (and understood) correctly, it
If you need to make a list of long but unknown length you can save time by
adding the items to an environment, with names giving the order, then
converting the environment to a list when you are done filling the
environment. E.g.,
> makeData
function (container, n)
{
for (i in seq_len(n))
Dear Jeff, it is a precious help and a fabulous suggestion. I will slowly
go over the R code that you have sent. Thanks a lot !
On Wed, Jul 25, 2018 at 10:43 AM, Jeff Newmiller
wrote:
> The code below reeks of a misconception that lists are efficient to add
> items to, which is a confusion with
The code below reeks of a misconception that lists are efficient to add
items to, which is a confusion with the computer science term "linked
list". In R, a list is NOT a linked list... it is a vector, which means
the memory used by the list is allocated at the time it is created, and
Some additional comments that might be relevant to people interested in
these topics.
1. For R scripts you should also consider the package littler developed by
Dirk Eddelbuettel, Highly recommended.
For info http://dirk.eddelbuettel.com/code/littler.html or the github
repository.
2. Scripts can
I've studied R a little bit, although I haven't used it in some time
(except via RCommander). I'm working on my dissertation project and
have spectrometer data that I need to evaluate. I need to find a way to
simplify the output from multi-way ANOVA so I can reduce the areas of
the spectrum
Dear Thierry and Juan, thank you for your help. Thank you all.
Now, if I would like to add an element to the empty list, how shall I do :
for example, shall i = 2, and j = 1, in a bit of more complex R code :
x <- data.frame(TYPE=c("DEL", "DEL", "DUP", "TRA", "INV", "TRA"),
CHRA=c("chr1",
From my perspective, which is a unix-alike perspective, Rscript makes R useable
in exactly the same way as other unix style scripting languages such as perl,
tcsh, bash, etc. This is useful, and a good thing. If I remember (and
understood) correctly, it is why Rscript was introduced, later in
The Export option from the interactive Plots view is a terrible option for any
publication-quality graphics.
There are many [1] ways to make publication-quality graphics in R, and there
can be some operating-system-specific downstream tools considerations that
affect what works best for you. I
On Wed, 25 Jul 2018, Rich Shepard wrote:
That's a given. Why would I prefer Rscript over R CMD BATCH, or
vice-versa? I did not see much difference between the two in their help
files.
Digging deeper into the Web I read that R CMD BATCH is an older approach
to automating R processing from
https://rviews.rstudio.com/2017/10/18/database-queries-with-r/
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Wed, Jul 25, 2018 at 7:57 AM,
On Wed, 25 Jul 2018, Bert Gunter wrote:
"Within R one can use source() to run a batch file of R commands, while R
CMD BATCH and Rscript are run from the command line. Is this correct?"
Yes.
Bert,
Thanks for confirming.
I think your query answers your query: You use Rscript when you want
I'm doing some work now to learn which SQL database package is the most optimal
for the task I am working on. There are many packages, and I'm reviewing the
documentation on some of them now. I am seeking advice from those of you who
might suggest a package to use for the task I am currently
"Within R one can use source() to run a batch file of R commands, while R
CMD BATCH
and Rscript are run from the command line. Is this correct?"
Yes.
I think your query answers your query: You use Rscript when you want to use
R in the command environment, perhaps as part of an analytical
Within R one can use source() to run a batch file of R commands, while R CMD
BATCH
and Rscript are run from the command line. Is this correct?
Given these choices, when would I want to run a script within R using
source(), and when would it be better for me to run it from the command
line?
Is anyone using DiagrammeR and grViz?
I made a nice grViz but when I use RStudio to export quality looks bad
(need high resolution figure).
I can't quite figure out how to use DiagrammeR to export the grViz I made.
Any suggestions?
Thank you, Evan
[[alternative HTML version deleted]]
Hi Bogdan,
Does the following do what you expect?
x$intersectA[[i]] <- c(x$intersectA[[i]], x$labA[j])
Note the difference between `[[` and `[`
On Wed, Jul 25, 2018 at 9:26 AM, Bogdan Tanasa wrote:
> Dear Thierry and Juan, thank you for your help. Thank you very much.
>
> Now, if I would
Dear Thierry and Juan, thank you for your help. Thank you very much.
Now, if I would like to add an element to the empty list, how shall I do :
for example, shall i = 2, and j = 1, in a bit of more complex R code :
x <- data.frame(TYPE=c("DEL", "DEL", "DUP", "TRA", "INV", "TRA"),
CHRA=c("chr1",
Thank you Juan.
On Wed, Jul 25, 2018 at 12:56 AM, Juan Telleria Ruiz de Aguirre <
jtelleria.rproj...@gmail.com> wrote:
> Check tidyverse's purrr package:
>
> https://github.com/rstudio/cheatsheets/raw/master/purrr.pdf
>
> In the second page of the cheatsheet there is info on how to create list
>
Hi
maybe
ii<-TRUE
while(ii) {
do something
if(some condition of two variables is met) {ii <- FALSE}
}
But in R such constructions are seldom necessary.
Cheers
Petr
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of tembe-
> atanasio...@ynu.jp
>
Hello,
Is there somebody who can demonstrate how to code a while loop that ends when a
convergence between the values of two or more variables (say vectors) is
reached? Thank you
Regards
[[alternative HTML version deleted]]
__
On 07/25/2018 10:23 AM, Ivan Calandra wrote:
Just for my understanding:
Is a data.frame with list columns still a data.frame? Isn't it then a list?
A data.frame is a list of equally sized vectors - that is, each vector
must be of the same length. It is not required that the vector is an
At first I was actually thinking about this situation, which cannot work:|
data.frame(x = 1:3, y = list(1:2, 1:3, 1:4))
|But I had never thought about this:|
df$y <-list(1:2, 1:3, 1:4)|
And it actually makes sense. The final requirement here is that all
columns must have the same length!
I'm
By the way, this also works:
dfl <- data.frame(x = 1:3, y = I(list(1:2, 1:3, 1:4)))
As indicated in "Advanced R" book:
http://adv-r.had.co.nz/Data-structures.html#data-frames
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> Just for my understanding:
> Is a data.frame with list columns still a data.frame? Isn't it then a list?
* A data.frame (or tibble) is a list of columns.
* In which each column must be from the same data type, in this case list().
__
Just for my understanding:
Is a data.frame with list columns still a data.frame? Isn't it then a list?
Ivan
--
Dr. Ivan Calandra
TraCEr, laboratory for Traceology and Controlled Experiments
MONREPOS Archaeological Research Centre and
Museum for Human Behavioural Evolution
Schloss Monrepos
56567
Dear Bogdan,
You are looking for x$intersectA <- vector("list", nrow(x))
Best regards,
ir. Thierry Onkelinx
Statisticus / Statistician
Vlaamse Overheid / Government of Flanders
INSTITUUT VOOR NATUUR- EN BOSONDERZOEK / RESEARCH INSTITUTE FOR NATURE AND
FOREST
Team Biometrie & Kwaliteitszorg /
Check tidyverse's purrr package:
https://github.com/rstudio/cheatsheets/raw/master/purrr.pdf
In the second page of the cheatsheet there is info on how to create list
columns within a data.frame :)
[[alternative HTML version deleted]]
__
Dear all,
assuming that I do have a dataframe like :
x <- data.frame(TYPE=c("DEL", "DEL", "DUP", "TRA", "INV", "TRA"),
CHRA=c("chr1", "chr1", "chr1", "chr1", "chr2", "chr2"),
POSA=c(10, 15, 120, 340, 100, 220),
CHRB=c("chr1", "chr1", "chr1", "chr2", "chr2", "chr1"),
POSB=c(30, 100, 300, 20, 200,
> On 25 Jul 2018, at 08:17, Naresh Gurbuxani
> wrote:
>
> I have a list whose components are data frames. My goal is to construct a
> data frame by merging all the list components. Is it possible to achieve
> this using apply and without a for loop, as used below?
>
> Thanks,
> Naresh
>
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