Thank you so much Marc,
that is exactly what I need. That will save me weeks of work and additionally I
learned a lot.
:-)
Have a great day!
Dagmar
Hi,
Given that your original data frame example is:
myframe <- data.frame (Timestamp=c("24.09.2012 09:00:00", "24.09.2012
10:00:00","25.09.2012
"Other than correlation, how to check ressemblence between these two curve"
(As Ted Indicated) Graph them... and look!
There is nothing magical about statistics, which seems to be what you seek.
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking
Thanks a lot for this reply
'a' is a simulated data while 'b' is empirical data.
Other than correlation, how to check ressemblence between these two curve
in terms of :
Amplitude in each row 1...12
Evolution and variability from 1 to 12
Thanks !
Le lundi 10 décembre 2018, Ted Harding a écrit
On Mon, 2018-12-10 at 22:17 +0100, Fatma Ell wrote:
> Dear all,
> I'm trying to use ks.test in order to compare two curve. I've 0 values i
> think this is why I have the follonwing warnings :impossible to calculate
> exact exact value with ex-aequos
>
> a=c(3.02040816326531, 7.95918367346939,
Hello,
That is a warning, not an error.
And it documented. In ?ks.test, section Details, the relevant part is
The presence of ties always generates a warning, since continuous
distributions do not generate them. If the ties arose from rounding the
tests may be approximately valid, but even
Dear all,
I'm trying to use ks.test in order to compare two curve. I've 0 values i
think this is why I have the follonwing warnings :impossible to calculate
exact exact value with ex-aequos
a=c(3.02040816326531, 7.95918367346939, 10.6162790697674, 4.64150943396226,
1.86538461538462, 1.125,
Thank you very much.
This is exactly what I needed.
Isaac.
-Mensaje original-
De: peter dalgaard [mailto:pda...@gmail.com]
Enviado el: lunes, 10 de diciembre de 2018 15:10
Para: Subirana Cachinero, Isaac
CC: Rui Barradas; r-help@r-project.org
Asunto: Re: [R] repeating the same variable
Estimado Carlos Córcoles
Mire la imagen en stackoverflow, habría que mirarlo un poco mejor, pero a
simple vista pienso que hay un problema al escribirlo.
Sweave tiene código dentro del archivo, algo latex y algo R, el código R
debe importar los datos o el código para ejecutar, lo que está en
You might be looking for this:
> all.vars(~chol+age+age, unique=FALSE)
[1] "chol" "age" "age"
-pd
> On 10 Dec 2018, at 11:35 , Subirana Cachinero, Isaac
> wrote:
>
> Thank you for your response.
> In fact, I use the formula environament to select variables, as part of the
> code of
Hol, Carlos;
No sé si entiendo tu problema, así que le contesto a lo que entiendo; no sé
si a tu pregunta.
Yo no soy tan valiente y no uso Latex, pero sí LyX, que para el caso
funcionan igual.
Vos no das un ejemplo de tu problema, así que le contesto al del link que
mandás, el resto te toca a
Hi,
Given that your original data frame example is:
myframe <- data.frame (Timestamp=c("24.09.2012 09:00:00", "24.09.2012
10:00:00","25.09.2012 09:00:00",
"25.09.2012 09:00:00","24.09.2012 09:00:00",
"24.09.2012 10:00:00"),
Thank you for your response.
In fact, I use the formula environament to select variables, as part of the
code of another function.
I would like to allow the user to select the same variable more than once.
The use of I() may partly solve the problem. However, I would like
Hello,
The formulas
y ~ cholesterol + age + age
and
y ~ cholesterol + age
are the same formula.
If you want 'age' twice, maybe
g <- y ~ cholesterol + I(age + age)
attr(terms(g), "term.labels")
#[1] "cholesterol" "I(age + age)"
Hope this helps,
Rui Barradas
Às 06:49 de 10/12/2018,
Hola!
Soy Carlos Córcoles Benavides. Os escribo porque tengo una duda. Estoy
aprendiendo a usar Swave (Latex para R) y no consigo saber como puedo hacer
para que este framework me reconozca los objetos de una archivo de
extensión .R. ¿Sabeis algo de esto?
Esta función fue planteada en este link.
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