It is time to end these queries and start your homework by consulting the
references you have already been given. Wickham's goes into all of this;
the R Language Definition that ships with R covers all of your questions
and more in detail; and numerous online references and tutorials -- A
search on
Afternoon, Peter,
Thank you for your concise but informative reply, and for a link to the source
code. These complex concepts do answer my question spot on, so thank you for
taking the time to put them all together and summarizing them for me.
Is the standard nomenclature for arguments in funct
Um... Let's get the concepts straight:
The "function" function doesn't evaluate anything. It just takes the list of
formal arguments (including default expressions), the function body, and the
current evaluation environment, and stiches them together into a function
object, known as a "closure"
Afternoon, David,
Thank you for your suggestions and insight. I have previously utilized parse,
but in my exploration to improve my coding technique I came across this comment
in stackoverflow.com
(https://stackoverflow.com/questions/1743698/evaluate-expression-given-as-a-string
- comment left
On 9/6/19 1:07 PM, Golden, Shelby wrote:
Thank you all for your reply. I should clarify, that I am looking to understand
why the keyword function can take a logical argument (eg: x<4) and use that
later inside the function's definition for logical evaluations.
Consider this example, which is
Possibly. However, this is not a a question about R but about statistical
theory, so is off-topic on this mailing list. Try Stack Exchange or consult a
local statistician.
On September 5, 2019 9:58:56 AM PDT, Paul Bernal wrote:
>Dear friends,
>
>Hope you are all doing great. If I am not mistake
John
Indeed, this was the issue. I needed to modify my windows path to include both
Rtools and the version of R I am using.
Thank you.
-Original Message-
From: Fox, John
Sent: Friday, September 6, 2019 9:35 AM
To: Doran, Harold
Cc: r-help@r-project.org
Subject: Re: [R] Help Installi
Hello Jiefei,
Missed this in the subsequent emails. That is a very intriguing article, but I
do not believe that it quite answers my question. Regardless, I will review it,
so thank you for sending it my way!
Respectfully,
Shelby
From: Wang Jiefei
Date: Friday, September 6, 2019 at 11:10 AM
Thank you all for your reply. I should clarify, that I am looking to understand
why the keyword function can take a logical argument (eg: x<4) and use that
later inside the function's definition for logical evaluations.
Consider this example, which is a simplification of
getAnywhere(subset.data
You might also want to look at the codetools package, for example the
showTree function " Prints a Lisp-style representation of R
expression."
> library(codetools)
> showTree(quote(x %*% x))
(%*% x x)
> showTree(quote(a+b))
(+ a b)
> showTree(quote(y ~ a+b))
(~ y (+ a b))
On Fri, Sep 6, 2019 at
The following may be of use (it gives the parse tree of the text):
> z <- as.list(parse(text = "function(x)x %*% x"))
> z[[1]]
function(x) x %*% x
> z[[c(1,1)]]
`function`
> z[[c(1,2)]]
$x
> z[[c(1,3)]]
x %*% x
> z[[c(1,3,1)]]
`%*%`
> z[[c(1,3,2)]]
x
> z[[c(1,3,3)]]
x
Bert Gunter
On Fri, Sep
If you are looking for an R code parser, I think the `parse` and `eval`
function might be a good start point. See the example below.
> parse(text="function(x)message(x)")
expression(function(x)message(x))
> eval(parse(text="function(x)message(x)"))
function(x)message(x)
Best,
Jiefei
On Fri, Sep
Hi Shelby,
Not quite sure what you are trying to do. Mine might be off-topic but have
you seen this document?
http://adv-r.had.co.nz/Functions.html#function-components
It illustrates the components of a function.
Best,
Jiefei
On Fri, Sep 6, 2019 at 11:52 AM Golden, Shelby wrote:
> Hi all,
>
Hello Bert,
Thank you for the reply and your clarifications. Yes, it might be helpful to
look into R’s formal grammar to see how “function” parses input to delegate
correct syntax. Is that accessible online?
Thank you,
Shelby
From: Bert Gunter
Date: Friday, September 6, 2019 at 10:44 AM
To:
1. This is a plain text list; all html is stripped. So there is no red
highlighting.
2. There is no "source code" for "function" -- it is a reserved keyword.
Or are you looking for R's formal grammar -- e.g. how it parses input to
determine correct syntax?
Bert Gunter
"The trouble with having
Hi all,
I have been attempting to access the source code for the keyword “function” to
better understand how it assigns and stores logical inputs, like in the
subset() [base] function. Does anyone know how I can access the source code for
this?
For example, if I have
norm <- function(x){
Dear Harold,
Have you checked that the Rtools directory is on the Windows path? If not, you
could try rerunning the Rtools installer and allow it to modify the path, or
simply add the Rtools directory to the path yourself.
I hope that this helps,
John
-
John Fo
Many thanks, as you suggest that does allow the program to run.
As does (no pun intended) as.character()
If anyone knows what causes this I would be still keen to know.
Cheers Paul
-Original Message-
From: peter dalgaard [mailto:pda...@gmail.com]
Sent: 06 September 2019 14:04
To: Paul Jo
I have no clue about the internals of fmodel() (and no real intention of
getting one...), but pragmatically and to avoid getting sidetracked, how about
converting the bogus variable to zero-one:
CPS85$bogus <- as.numeric(rnorm(nrow(CPS85)) > 0)
-pd
> On 6 Sep 2019, at 11:57 , Paul Johnston
>
Hi
Anyone able to help me with this.
I'm doing a datacamp course and the effect of adding a "bogus variable" to a
linear model.
I make a model and initially fmodel works fine.
When I have a second model which uses this "bogus variable" it complains about
the type of this variable.
The code belo
On 6/09/19 5:30 PM, pusuluri madhu wrote:
Please unsubscribe me
Go unsubscribe yourself! :-)
See the footer at the bottom of every r-help posting:
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
HTH
cheers,
Rolf Turner
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