Hi
in line
> -Original Message-
> From: Val
> Sent: Wednesday, November 6, 2019 3:24 AM
> To: PIKAL Petr
> Cc: r-help@R-project.org (r-help@r-project.org)
> Subject: Re: [R] File conca.
>
> Thank you Petr and Jeff fro your suggestions.
>
> I made some improvement but still need some
Thank you Petr and Jeff fro your suggestions.
I made some improvement but still need some tweaking. I could not
get correctly the folders names added to each row. Only the last
forename was added.
table(Alldata$oldername) resulted
week2
25500
Please see the complete,
Agree, especially there is an "Urgent" on the title. He must be too
"urgent" to think about your answer. I will wonder if your effort will be
in vain.
Best,
Jiefei
On Tue, Nov 5, 2019 at 4:52 PM Rolf Turner wrote:
>
> Richard: I know that you mean well, but *please* don't do people's
>
For the record, I left out a key word in my prior "explanation", which I
have corrected below. I also needed to clarify something, as my original
wording is confusing. Sorry about that.
Bert
On Tue, Nov 5, 2019 at 11:09 AM Bert Gunter wrote:
> Lattice functions pass down their
Richard: I know that you mean well, but *please* don't do people's
homework for them!!! (They are *cheating* by asking R-help to do their
homework.)
cheers,
Rolf Turner
On 6/11/19 4:27 AM, Richard O'Keefe wrote:
This looks vaguely like something from exercism.
Let's approach it
A simplified example of what you wish to do might help to clarify here.
Here's my guess. Feel free to dismiss if I'm off base.
Suppose your model is:
y = exp(a*x) + b
and you wish the b to be constant but the a to vary across expts. Then can
you not combine the data from both into single x, y
Here's how you pass an argument down to the panel function.
foo <- runif(30,0,5)
y <- rnorm(30, mean = 10)
xyplot(y~foo,
panel = function(x,...) {
panel.xyplot(x,..., col = "red")
panel.rug(x, col="black")
})
Cheers,
Bert
Bert Gunter
"The trouble with having
This question is off-topic for rhelp despite your use of an R package
because it is a request for advice for statistical issues, rather than
about R coding. You should read the Posting guide where you are advised
of this concern. You are also asked to post in plain text and include an
Dear All,
Thanks for all the support and help and I think I was able to solve my
problem.
Thanks a ton.
Best Regards,
Chandeep Kaur
On Tue, 5 Nov 2019, 8:57 pm Richard O'Keefe, wrote:
> This looks vaguely like something from exercism.
> Let's approach it logically.
> xa xb xc ya yb zc
> We
> set.seed(1)
> m <- matrix(rnorm(500),ncol=2)
> cor(m)
# [,1] [,2]
# [1,] 1. 0.04060113
# [2,] 0.04060113 1.
> options(digits=12)
> cor(m)
# [,1][,2]
# [1,] 1.0 0.0406011304584
# [2,] 0.0406011304584 1.0
DeaR users,
A new package called 'funprog' is now on CRAN :
https://CRAN.R-project.org/package=funprog
'funprog' contains high-order functions to manipulate data, given one or more
auxiliary functions.
Functions are inspired by other pure functional programming languages (Haskell
mainly).
Hello
I am trying to determine least-squares estimates of the parameters of a
nonlinear model, where I expect some parameters to remain constant across
experiments, and for others to vary. I believe this is typically referred
to as global curve fitting, or the presence of shared/nested parameters.
Hi,
I am running this function:
library(psych)
corr.test.col.1to3 <- corr.test(allF[1:3], method = "spearman", use =
"complete.obs")
names(corr.test.col.1to3)
corr.test.col.1to3$p
and my result looks like this:
> corr.test.col.1to3$p
B_NoDB_DwoC B_DwC
B_NoD 0.000 0.000
I think your code is a bit buggy. Try this
for(i in 2:length(l)) {
allF <- merge(allF, l[[i]], by= "row.names", all.x= F, all.y= F)
rownames(allF) <- allF$Row.names
allF <- allF[,-1]
}
HTH,
Eric
On Tue, Nov 5, 2019 at 6:16 PM Ana Marija
wrote:
> Hi,
>
> I have 3 data frames like this:
The following produces a scatterplot with rugs on both the vertical and
horizontal axes.
library(dplyr)
library(stringr)
library(lattice)
library(latticeExtra)
## .
xyplot(scheduleInterval ~ calledForApptDate, data = dd.2, xlab = "Date
patient called for appointment", ylab = "Days in the
Hi,
I have 3 data frames like this:
> head(s11)
B_NoD
Ebfrl.7uOZfnjp_E7k 7.583709
ueQUrXd5FH554RlhZc 5.177791
0Uu3XrB6Bd14qoNeuc 4.680306
0t7nhVLii6tSAxtLhc 4.565023
fSUyR.vR7Xu0iR4nUU 2.885992
0Tm7hdRJxd9zoevPlA 2.866847
> head(s22)
B_DwoC
I'm trying to modernize my way of thinking, and my coding, into the
dplyr/tidyverse way of doing things.
To get basic summary statistics on a variable in a dataframe, with the
output also being a dataframe. I previously would do something like this,
using other packages:
library(doBy)
This looks vaguely like something from exercism.
Let's approach it logically.
xa xb xc ya yb zc
We see two patterns here:
A: x x x y y z
B: a b c a b c
If only we had these two character vectors, we could use
paste(A, B, sep = "")
to get the desired result. So now we have reduced the
problem
In other words... read the Posting Guide.
On November 5, 2019 2:52:34 AM PST, Jim Lemon wrote:
>Homework Chandeep, homework.
>
>Jim
>
>On Tue, Nov 5, 2019 at 9:40 PM Chandeep Kaur
>wrote:
>>
>> Dear Team,
>>
>> Could you please help me with the below question? How can I get the
>desired
>>
Greetings,
I have collected the data based on 5 point likert scale(very low, low,
neutral, high,very high) on the factor considered by individual before
making investment decision. There are five factors (D.Vs) Influencing
investment decisions. I am interested in knowing whether there is
Homework Chandeep, homework.
Jim
On Tue, Nov 5, 2019 at 9:40 PM Chandeep Kaur wrote:
>
> Dear Team,
>
> Could you please help me with the below question? How can I get the desired
> output?
>
> Produce the following sequence using only rep(), seq() and potentially
> other functions/operators.
Dear Team,
Could you please help me with the below question? How can I get the desired
output?
Produce the following sequence using only rep(), seq() and potentially
other functions/operators. You must not use c() nor explicit loops
“xa” “xb” “xc” “ya” “yb” “zc”
Thanks & Regards,
Chandeep
Thank you. the factor approach worked all right. Thank you for Likert
also: I already used it but here I wanted to run with lattice only.
Best regards
On Mon, Nov 4, 2019 at 6:57 PM Richard M. Heiberger wrote:
>
> ## The likert function would work well for this example.
> ## Continuing from your
OK.
Mira esta otra ayuda..
https://stackoverflow.com/questions/51858379/how-to-link-s3-bucket-to-sagemaker-notebook
Gracias,
Carlos Ortega
www.qualityexcellence.es
El mar., 5 nov. 2019 a las 7:53, Mabel Garcia ()
escribió:
> Muchas gracias por el enlace Carlos, me da error en el otro sentido,
I recommend not using setwd unless you have to (e.g at the beginning of a
script run by cron or another task scheduler). It is much simpler to build
paths to directories and files using file.path.
On November 5, 2019 12:13:19 AM PST, PIKAL Petr wrote:
>Hi
>
>Help with such operations is rather
Hi
Help with such operations is rather tricky as only you know exact structrure
of your folders.
see some hints in line
> -Original Message-
> From: R-help On Behalf Of Val
> Sent: Tuesday, November 5, 2019 4:33 AM
> To: r-help@R-project.org (r-help@r-project.org)
> Subject: [R] File
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