Às 05:17 de 12/08/2023, Thomas Subia via R-help escreveu:
Colleagues,
Here is my reproducible code for a graph using geom_smooth
set.seed(55)
scatter_data <- tibble(x_var = runif(100, min = 0, max = 25)
,y_var = log2(x_var) + rnorm(100))
library(ggplot2)
Colleagues,
Here is my reproducible code for a graph using geom_smooth
set.seed(55)
scatter_data <- tibble(x_var = runif(100, min = 0, max = 25)
,y_var = log2(x_var) + rnorm(100))
library(ggplot2)
library(cowplot)
ggplot(scatter_data,aes(x=x_var,y=y_var))+
geom_point()+
No tuve tiempo de mirarlo, pero, ¿es coherente lo que dice?
El vie, 11 ago 2023 a las 21:02, Griera-yandex ()
escribió:
> Muchas gracias, Manuel:
>
> Que bueno! No se me había ocurrido lo de GPT!
>
> Lo pruebo.
>
> Saludos.
>
> On Fri, 11 Aug 2023 18:15:18 +0200
> Manuel Mendoza wrote:
>
> >
Thank you Bert and Ivan,
I was building the SVM model in hopes of applying it to future cases and hoped
that the model would be able to deal with new words it hadn't encountered
during training. But I tried Bert's suggestion by converting all of the data
to tokens, creating a DTM,
Muchas gracias, Manuel:
Que bueno! No se me había ocurrido lo de GPT!
Lo pruebo.
Saludos.
On Fri, 11 Aug 2023 18:15:18 +0200
Manuel Mendoza wrote:
> Esta es la respuesta que te da ChatGPT-4:
>
> Entiendo tu pregunta y, aunque no hay una función nativa en R que te
> permita hacer exactamente
Esta es la respuesta que te da ChatGPT-4:
Entiendo tu pregunta y, aunque no hay una función nativa en R que te
permita hacer exactamente lo que estás pidiendo, puedes lograr el mismo
resultado utilizando una función. Una función te permitiría encapsular la
lógica de la expresión que quieres
В Fri, 11 Aug 2023 10:20:27 +
James C Schopf пишет:
> > train_text_dtm <-
> > DocumentTermMatrix(Corpus(VectorSource(all_train_tokens)))
> > test_text_dtm <-
> > DocumentTermMatrix(Corpus(VectorSource(all_test_tokens)))
I understand the need to prepare the test dataset separately
(e.g.
I know nothing about tf, etc., but can you not simply read in the whole
file into R and then randomly split using R? The training and test sets
would simply be defined by a single random sample of subscripts which is
either chosen or not.
e.g. (simplified example -- you would be subsetting the
Hello, I'd be very grateful for your help.
I randomly separated a .csv file with 1287 documents 75%/25% into 2 csv files,
one for training an algorithm and the other for testing the algorithm. I
applied similar preprocessing, including TFIDF transformation, to both sets,
but R won't let me
Thank you for your hints.
All of them have been useful, and you solved my problem.
I understood the role of rle, but I think that for my task its use is not
fundamental.
I will put more attention on looking for the existing documentation.
Thank you again
Stefano
(oo)
--oOO--(
I have entered values into Excel, and sorted them. I am assuming you are asking
why the value 3 in x2 is ranked 4.5 versus in x5 it has a rank of 5.
X2 looks like this
Value RankOrder
1 1.5 1
1 1.5 2
2 3 3
3 4.5 4
3 4.5 5
4 6 6
Gracias, Isidro, por la ayuda:
On Fri, 11 Aug 2023 09:16:34 +
Isidro Hidalgo Arellano wrote:
> A ver... con que xfunc() esté preparada para tomar un parámetro de tipo
> "carácter" y evaluarlo, claro que se puede hacer...
> Si el problema lo tienes en evaluar la expresión, la función
A ver... con que xfunc() esté preparada para tomar un parámetro de tipo
"carácter" y evaluarlo, claro que se puede hacer...
Si el problema lo tienes en evaluar la expresión, la función "eval()" te lo
hace.
Si no te he entendido bien, explícate más
Saludos
Isidro
-Mensaje original-
Dear Chris,
the members of the triplet would be ranked 4, 5 and 6 (in your example),
so the *mean of their ranks* is correctly 5.
For any set of k tied values the ranks of its elements are averaged (and
assigned to each of its k members).
Hth -- Gerrit
Às 08:20 de 11/08/2023, Sigbert Klinke escreveu:
Hello,
I have defined a function 'equations(...)' which returns an object with
class 'equations'. I also defined a function 'print.equations' which
prints the object. But I did not use 'equations <- function(x, ...)
UseMethod("equations"). Two
I understand that the default ties.method is "average". Here is what I
get, expanding a bit on the help page example. Running R 4.3.1 on Ubuntu
22.04.2.
> x2 <- c(3, 1, 4, 1, 5, 9, 2, 6, 5, 3, 5)
> rank(x2)
[1] 4.5 1.5 6.0 1.5 8.0 11.0 3.0 10.0 8.0 4.5 8.0
OK so the ties, each of
On Fri, 11 Aug 2023 09:20:03 +0200
Sigbert Klinke wrote:
> I have defined a function 'equations(...)' which returns an object
> with class 'equations'.
> But I did not use 'equations <- function(x, ...)
> UseMethod("equations"). Two questions:
>
> 1.) Is this a sensible approach?
Quite. If
Hello,
I have defined a function 'equations(...)' which returns an object with
class 'equations'. I also defined a function 'print.equations' which
prints the object. But I did not use 'equations <- function(x, ...)
UseMethod("equations"). Two questions:
1.) Is this a sensible approach?
2.)
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