Hello,
I have a large dataframe (windHW) of wind speeds (ws) at each hour
from many days over a set of years. Some of these values are
obviously wrong (600 m/s) and I want to get rid of all the values that
are larger than 5*sigma for each hour. The 5*sigma (variable name
sigma5) values are
.
Thanks,
Alexandra
On Fri, Apr 10, 2015 at 1:07 PM, Alexandra Catena amc5...@gmail.com wrote:
Hello,
I have a large dataframe (windHW) of wind speeds (ws) at each hour
from many days over a set of years. Some of these values are
obviously wrong (600 m/s) and I want to get rid of all
begins at 1, there is no element 0. Try using:
for(i in 1:24) {
...
and see what happens.
Jim
On Sat, Apr 11, 2015 at 7:06 AM, Alexandra Catena amc5...@gmail.com wrote:
Update:
I have this so far. * The first column of windHW is the wind speed.
The 5th column of the dataframe, spring
Hello,
I am trying to plot the hourly standard deviation of wind speeds from
13 different measured locations over many years. I imported the data
using readLines and into a dataframe called finalData. Using tapply, I
determined the standard deviation of the windspeed (ws) for each hour
(hour)
Hello All,
I have a data frame called windSFO of four columns, wind speed, wind
direction, station number, and date (mmdd). I downloaded the gz
data from a site online and then unzipped it using readLines. I then
concatenated these four columns from the unzipped data into a
dataframe using
Hello All,
I have a data frame of two columns for wind. The first column is for wind
speed and the second wind direction. I'm trying to replace the values
in the first column and the 999 values in the second column with NA. I
tried to use the function ltdl.fix.df but it doesn't seem to do
Hi,
I need help with a for loop and printing data. I want to loop through a
few years and print the data from each year stacked on top of each other.
For example,
for (i in 2000:2003){
#script for downloading each year
Data = readLines(sprintf('file/%4i,i))
}
It only prints out the data from
Hello,
Can someone help me with unzipping a .gz file. I used:
readLines(gzfile('/home/file.gz'))
I also found that I could use gunzip, but after trying to install it, it
says:
package ‘gunzip’ is not available (for R version 2.15.1)
Thanks,
Alexandra
[[alternative HTML version
you want to do, not how you want to do it.
On Wed, Feb 4, 2015 at 5:24 PM, Alexandra Catena amc5...@gmail.com
wrote:
Hi All,
I need to loop through and download the past 10 years of met data to a
temporary directory. I then need to unzip it and place it into another
directory.
year
Hi All,
I need to loop through and download the past 10 years of met data to a
temporary directory. I then need to unzip it and place it into another
directory.
year = (2005:2015)
for (i in year)
tmpdir = tempdir()
file[i] = file.path(tmpdir, sprintf('724927-23285-%4i.gz', i))
url =
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