On 18.04.2014 13:02, petre...@unina.it wrote:
Prof. Dewey, sorry for the trivial question and many thank for the replay.
Using which package?
In this case I used the meta package, but I know that for all but the
DerSimonian-Laird method the R function rma.uni of R package metafor is
Dear all,
I am struggling to add a prediction interval to a forest plot that was
created with forest.meta(), package meta.
I checked the source of forest.meta() and realized that it is heavily
relying on grid. I am lacking any experience with grid graphics. So, I
am having difficulties to find
Am 24.08.2011 07:50, schrieb Paola Tellaroli:
My script is the following:
library(metafor)
yi-c(-0.1, 0.2, 0.3, 0.4)
sei-c(0.4, 0.2, 0.6, 0.1)
vi-sei^2
studi-c(A, B, C, D)
eventi.c-c(10, 5, 7, 6)
n.c-c(11, 34, 25, 20)
eventi.a-c(2, 7, 6, 5)
n.a-c(11, 35, 25, 15)
dfs-rma(yi, vi,
Am 01.04.2011 11:24, schrieb Yan Jiao:
Dear R users,
I'm trying to add a regression line on my boxplots (something
like:boxplot(c(1:3),c(4:6),c(5:8))) But I can't see it. Please help
!!! It's not a April fool's joke!!!
Your sample data does not make any sense (at least to me). I would do it
Am 31.03.2011 19:31, schrieb array chip:
Hi, I am stuck on this: how to specify a match pattern that means not
to include abc?
I tried:
grep(^(abc), hello, value=T) should return hello.
grep([^(abc)], hello, value=T)
[1] hello
HTH,
Bernd
__
Am 31.03.2011 21:06, schrieb array chip:
Ok then this code didn't do what I wanted. I want not including
'arg' before '.symptom', not individual letters of arg, but rather
as a word.
Bill Dunlap suggested using invert=T, it works for single 1
condition, but not for 2 conditions here: not
Am 30.03.2011 09:15, schrieb Christopher Desjardins:
Hi,
I am trying to write a loop to recode my data from -999 to NA in R. What's
the most efficient way to do this? Below is what I'm presently doing, which
is inefficient. Thanks,
Chris
dat0- read.table(time1.dat)
colnames(dat0)- c(e1dq,
Am 24.03.2011 11:28, schrieb Arnau Mir:
Hello.
Somebody knows how to write in R all the permutations of a given set?
For example, is the set is {a,b,c} I want the following:
a,b,c
a,c,b
b,c,a
b,a,c
c,a,b
c,b,a
library(gregmisc)
permutations(3, 3, letters[1:3])
gives
[,1] [,2] [,3]
[1,]
Am 04.08.2010 06:21, schrieb Jeffry Madura:
[...]
Can anyone explain to me what is going on here? The frame code in
latex is
\begin{frame}{fragile} \frametitle{Numbers} \textbf{Numbers} can be
represented in a variety of different formats. For example the number
$1.2345\times 10^5$ is
Am 02.07.2010 08:10, schrieb Wincent:
Dear all,
I try to show a subset of coefficients in my presentation. It seems
that a standard table is not a good way to go. I found figure 9
(page 9) in this file (
Am 14.05.2010 12:10, schrieb arnaud Gaboury:
Dear group,
Here is an object:
z -
c(LSCPos100415.csv, LSCPos100416.csv, LSCPos100419.csv,
LSCPos100420.csv, LSCPos100421.csv, LSCPos100422.csv,
LSCPos100423.csv,
LSCPos100426.csv, LSCPos100427.csv, LSCPos100428.csv,
LSCPos100429.csv,
Am 11.05.2010 10:37, schrieb arnaud Gaboury:
Dear group,
Here is my df :
df3 -
structure(list(DESCRIPTION = c(COPPER May/10, COTTON NO.2 Jul/10,
CRUDE OIL miNY May/10, GOLD Jun/10, ROBUSTA COFFEE (10) Jul/10,
SOYBEANS Jul/10, SUGAR NO.11 Jul/10, SUGAR NO.11 May/10,
WHEAT Jul/10, SPCL
ONKELINX, Thierry schrieb:
Dear Bernd,
Omitting the NA values from the dataset will work.
ggplot(aes(x = x, color = g), data = na.omit(mydf)) + geom_density()
Dear Thierry,
thanks for your reply! Of course, regarding my little toy example
na.omit() perfectly works. However, my real data
Sebastian Stegmann schrieb:
[...]
The R packages meta and rmeta are, as far as I can see, set up for
analysis with effect sizes for differences (i.e. comparison of the
means/odds-ratios of experimental and control group).
Only the function metagen from the meta-package looks like it would
markle...@verizon.net schrieb:
Thanks Petr because I sent Bernd a solution offline but yours is MUCH
NICER. it's not worth showing you because it was pretty ugly.
Dear Mark Petr,
Thank your very much! I like both solutions. Petr's is the more obvious
one but Mark's solution is good for
Dear all (Hadley, Thierry :-),
I was wondering how to force ggplot/qplot(... geom=histogram) to plot
proportions (or %) instead of counts/densities.
Thanks for your help,
Bernd
__
R-help@r-project.org mailing list
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library(lattice)
## works as expected
xyplot(1~1, key = list(text = list(c(Maenner
## works as expected
xyplot(1~1, key = list(text = list(c(Maenner))), xlab = M\344nner)
## gives an error
xyplot(1~1, key = list(text = list(c(M\344nner
Is
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Bernd Weiss schrieb:
| library(lattice)
|
| ## works as expected
| xyplot(1~1, key = list(text = list(c(Maenner
|
| ## works as expected
| xyplot(1~1, key = list(text = list(c(Maenner))), xlab = M\344nner)
|
| ## gives an error
| xyplot(1~1, key
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Prof Brian Ripley schrieb:
[...]
| It works correctly for me in CP1252 with R-patched, and gives an error
| in 2.7.0 (and works in 2.6.2). I think it was fixed as side effect of
|
| oRare string width calculations in package grid were not
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skestin schrieb:
| I suppose it's very simple but I can't find the way to generate a
sequence of
| characters, e.g. from a to z.
| Could you please help me with this?
?letters
letters
HTH,
B.
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Dear all,
is this a bug?
as.numeric(FALSE)
[1] 0
library(Matrix)
Loading required package: lattice
as.numeric(FALSE)
Error in UseMethod(as.double) : no applicable method for as.double
Regards,
Bernd
version
_
platform i386-pc-mingw32
arch i386
os
Bernd Weiss schrieb:
Dear all,
is this a bug?
as.numeric(FALSE)
[1] 0
library(Matrix)
Loading required package: lattice
as.numeric(FALSE)
Error in UseMethod(as.double) : no applicable method for as.double
After doing a complette reinstallation (uninstalling R, deleting all
Megh Dal schrieb:
Dear all,
I have following codes:
colnames(data) = c(var, var, var)
i = c(1,2,3)
Now I want construct a for loop starting from 1 to 3 to give the new names
of columns for dataframe data like below
colnames(data)
c(var1, var2, var3)
Definitely I could do this
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