sort
of solution, but looking at your elegant solution, I want to find the best
way.
Again, I greatly appreciate your help.
Regards,
Brijesh
-Original Message-
From: Joshua Ulrich [mailto:josh.m.ulr...@gmail.com]
Sent: Thursday, August 22, 2013 9:10 AM
To: Brijesh Gulati
Cc: R-Help
Hi:
I have a financial series data. For instance, one can take YHOO from the
quantmod package.
library(quantmod)
getSymbols(YHOO)
As you can see this series has date along with close prices. I want to do a
cross-sectional analysis of the time series and want to see if there are any
seasonal
Hello, I have a data.frame with repeating rows and corresponding value. For
instance, z will be an example of that.
x = c(a,a, a, b,b,b)
y = c(1.0, 1.2, 1.1, 1.01, 1.03, 1.0)
z = as.data.frame(cbind(x,y))
z
xy
1 a1
2 a 1.2
3 a 1.1
4 b 1.01
5 b 1.03
6 b1
-Original Message-
From: arun [mailto:smartpink...@yahoo.com]
Sent: Sunday, August 04, 2013 1:30 PM
To: Brijesh Gulati
Cc: R help
Subject: Re: [R] question: data.frame data conversion
#actually, this would be more compact
data.frame(split(z[,-1],z$x))
A.K.
- Original Message -
From
[mailto:ruipbarra...@sapo.pt]
Sent: Sunday, August 04, 2013 1:57 PM
To: Brijesh Gulati
Cc: r-help@r-project.org
Subject: Re: [R] question: data.frame data conversion
Hello,
First of all, do _not_ create a data frame with
as.data.frame(cbind(...))
Instead, use
z = data.frame(x, y)
As for your question
Hi: I am using termstrc package and not sure if TODAY field (govbonds
dataset) is today's date or the settlement date for the bonds. Although the
name suggests that it should be today's date, but how the formula is setup
indicates that it should be settlement date. Please help and thanks in
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