Sam tingey wrote:
can i email questions to this address to get help with using R
Sarah Goslee replied;
Yes, but do read:
http://www.R-project.org/posting-guide.html
Dieter Menne thought:
Catch 42. When you are so good that you can create a reproducible example
without using R, you only
Christof Kluß wrote
mod - lme(A ~ -1 + B+C+D+E+F+G, random = ~1 | ...)
...
f - function(B,C,D,E,F,G) - {
return(i + b*B + c*C + d*D + e*E + f*F + g*G)
}
It looks like you are trying to compute contrasts the ugly way. Check
estimable in package gmodels or the vignette of the multcomp
I am trying to get segplot honor the groups parameter like barchart does. The
below give an incorrect display for segplot.
Any help?
Dieter
# seqplot bar coloring
library(latticeExtra)
d = data.frame(acid=letters[1:10],lwr=rnorm(10),
essential=rep(c(TRUE,FALSE),each=5))
d$upr =
Found it. Use level instead of groups.
# seqplot bar coloring
library(latticeExtra)
d = data.frame(acid=letters[1:10],lwr=rnorm(10),
essential=rep(c(TRUE,FALSE),each=5))
d$upr = d$lwr+1
# Works as expected
barchart(acid~lwr,data=d,
groups=essential,
chuck.01 wrote
datum - structure(list(Y = c(415.5, 3847.8325, 1942.83325,
1215.223,
950.142857325, 2399.585, 804.75, 579.5, 841.70825, 494.053571425
), X = c(1.081818182, 0.492727273, 0.756363636, 0.896363636,
1.518181818, 0.49917, 1.354545455, 1.61,
Dan Abner wrote:
I have been using the sink() function as follows:
x-rnorm(100)
sink(C:\\Users\\dan\\Desktop\\Current Events\\myhw.txt,
append=TRUE,split=TRUE)
m1-c(Mean=mean(x),SD=sd(x),Min=min(x),Max=max(x))
m1
sink()
===
Is it possible to create tabular style output very much
Marie Duarte wrote:
Is anybody able to recommend packages to provide GUI like behaviour to
interface with R that would facilitate, eg.
* Rotatable surface plots (similar to LiveGraphics3D for mathematica,
http://www.vis.uni-stuttgart.de/~kraus/LiveGraphics3D/examples/color_volumes.html
Gang Chen-4 wrote:
However, my problem is that the file generated
from a graph of fixed size is too large (in the order of 10MB) because of
many data points in multiple scatterplots. Any suggestions?
Generate pdf, open and save it in Adobe Acrobat which does a compression
when the setting
Antonio Rodriges wrote:
The idea is to grant access of remote users to R running on Linux. Users
must have ability to run their
R scripts but avoid corrupting the operating system.
Check RStudio.org
Dieter
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Andrew Winterman wrote:
I'm trying to use the xlsx package to read a series of excel spreadsheets
into R, but my code is failing at the first step.
I setwd into my the directory with the spreadsheets, and, as a test ask
for
the first one:
read.xlsx(file = Argentina Final.xls,
oaxacamatt wrote:
I am calculating two t-test values for each of many files then save it
to file calculate another set and append, repeat.
You did not tell use what you want to do with the data in the file. If you
just want a copy of the output, bracketing with sink(file) and sink() can be
marcel wrote:
I have a figure with a lattice plot and a basic plot. Is there a way to
select the color and line width of the surrounding boxes for each of
these? I could not find any documentation on this.
Thanks for providing a nice self-contained example. There was nothing wrong
Rosario Garcia Gil-2 wrote:
I have a problem on keeping the format when I export a matrix file with
the write.table() function.
When I import the data volcano from rgl package it looks like this in R:
data[1:5,]
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13]
christiaan pauw-2 wrote:
Hi Everybody
Is it possible to store a collection of variables of different types (like
named integers, matricies, data frames and two lists) all in one list and
save it and then simply load it again later and unpack the variables.
The easy way out is not to
Irene Prix wrote:
In a grouped Dotplot, is there any way to set the color of error bars to
be the same as the corresponding symbols?
...
require(lattice)
require(Hmisc)
data(barley)
Dotplot(variety~Cbind(yield, yield+2, yield-2)|year, groups=site,
data=barley)
Customizations of
Ram H. Sharma wrote:
I want to overlay lattice scatter plot: I do not know why the following
code
is not plotting subscripts ! Sorry if this question is too simple:
Working example shortened:
.panel.xyplot(x, y, pch=16, col = green4, ylim = c(0, 10))
Because they are out of
AriGold wrote:
Hi this is my first post. I am trying to run a simulation for a computer
playing Von Neumann poker and adjusting it's expectation of an opponent's
behavior according to how the opponent plays.
...
Debugging length programs is not what this list is supposed to do, but
Crock wrote:
i`m an absolute R-beginner and have a problem loading data from datasets.
For example, giving the command: load (Affairs), i get the message,
that there is an error in readChar and there cannot be made any
connection.
I tried to find out on introduction papers but wasn`t able
Menelaos Stavrinides-2 wrote:
I am analyzing a dataset on the effects of six pesticides on population
growth rate of a predatory mite. The response variable is the population
growth rate of the mite (ranges from negative to positive) and the
exploratory variable is a categorical variable
Bert Gunter wrote:
I would also address future questions of this sort to the
R-sig-mixed-models list, as this is not really an r-help kind of question.
That's a bit confusing, Bert. I always thought that that list was about
lme4/lmer development, it still says
notably lmer() related
Bansal, Vikas wrote:
I have two data frames
df
ChrPos CaseA CaseCCaseG CaseT
10 135349878 0.00 3.428571 0.00 20.571429
10 135349880 0.00 21.33 0.00 2.67
10 135349883 21.00 0.00 3.00 0.00
10
Daniel Adler wrote:
Initial Announcement: Package rdyncall released on CRAN. (Version 0.7.3)
The package was presented at the Use!R 2009 with the title
'An improved Foreign Function Interface for R' and is now available on
CRAN
and considered stable for a large range of R platforms.
Noah Silverman wrote:
I have several global variables that I want to change with a given
function. (The variable has a different value after the function is
called.)
Berend Hasselman wrote:
Maybe this helps
?`-`
It helps to get the job done, but the OP asked for best
I am trying to run inline/Rcpp under Windows 64. The RTools are installed on
a spaceless path D:\rtools.
Inlining pure c-code works perfectly. When I try the sample code for cpp in
the cxx Documentation, I get:
x86_64-w64-mingw32-g++.exe: C:/Program: No such file or directory
The path to the
DimmestLemming wrote:
hist(soloData$deaths)
I get the error, invalid number of 'breaks' .
Try
str(soloData$deaths)
or
head(soloData$deaths)
or
summary(soloData$Death)
There may be something wrong with you data.
Dieter
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DrCJones wrote:
hat I would like to do is fit an elipse to two lines of identity (at right
angles to each other), as indicated in the following figure:
http://imageshack.us/photo/my-images/30/poincareplotwip.png/
http://r-project.markmail.org/thread/kpg3ea665y2ud6cz
or, for a robust
Hi, Dirk,
Dirk Eddelbuettel wrote:
Thanks for your interest in Rcpp. We generally prefer questions about
Rcpp / RInside / ... on the rcpp-devel list.
I know that list, but I was not sure if Path-questions are part of devel.
Dirk Eddelbuettel wrote:
... presumably from installing R
xy wrote:
I have like 5.075e-12 , 3.207e-05, 7.438e-07 and 9.393e-08 *** , i dont
know what number they are
http://en.wikipedia.org/wiki/Floating_point
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jannis-2 wrote:
I am trying to figure out how much CPU time individual commands inside
one of my functions consume. Is it possible to obtain the CPU times of a
whole sequence of commands inside a function?
See the example under proc.time()
Dieter
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zcatav wrote:
If this isn't, a DOS version may be helpfull to run on Android under
dosbox.
Wow, a mind boggling bummer!
Dieter
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Jochen1980 wrote:
I am looking for an opportunity to make a KS-Test in my C/C++-app.
Unfortunately I am not able to find a lib or function in C or C++ which
does the job. For my other numerical stuff Gnu Scientific Library was
recommended to me. What to do now?
I read that there are
Wonjae Lee wrote:
strptime('20110101 0900',%Y%m%d %H%M)
[1] 2011-01-01 09:00:00
strptime('20110101 900',%Y%m%d %H%M)
[1] NA
If I have a 3-digit hour like '900', please show me how to convert it to
09:00:00.
d = c('20110101 900', '20110101 1900')
d1= gsub( (\\d\\d\\d)$, 0\\1,d)
David Scott-6 wrote:
I have been trying to read some data from an Excel workbook without
success.
...
faults - sqlFetch(channel, sqtable = 'Data',
+colnames = FALSE, as.is = TRUE)
faults
[1] HY001 -1040 [Microsoft][ODBC Excel Driver] Too many fields defined.
[2]
adolfpf wrote:
How do I group my data in dolf the same way the data Orthodont are
grouped.
show(dolf)
distance age Subjectt Sex
16.83679 22.01 F1 F
26.63245 23.04 F1 F
3 11.58730 39.26 M2 M
I know that many sample in that excellent book use
DrCJones wrote:
But how can do 3 so that the bottom spans the width of the upper two:
[plot1 plot1]
[p l o t 3]
?layout
for standard graphics (plot..), but that's what you are referring to. For
trellis, you must use other methods.
Dieter
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R Help wrote:
I'm trying to plot nls profiles, but the plot.profile.nls function in
R doesn't seem to accept any plot.default variables.
Package nlstools has a few nice graphical display methods.
Dieter
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Dorien Herremans wrote:
Even if I use lm(), I get the following output:
summary(fit)
Df Sum Sq Mean Sq F valuePr(F)
nh11 324.0 323.99 139.13 2.2e-16 ***
nh21 723.1 723.12 310.53 2.2e-16 ***
nh31 1794.2 1794.21 770.49
Nilaya Sharma wrote:
I was trying to fit a mixed model in animal experiment but stuck at simple
point. The following similar example is from SAS mixed model pp 212.
genetic_evaluation - read.table(textConnection(
sire dam adg
1 1 2.24
1 1 1.85
...
5 2 2.58
5 2 2.56), header
helin_susam wrote:
x - rnorm(100)
y - rlnorm(100)
model - lm(y~x)
a - resid(model)
How I show the all area under the normal curve?
First, always try plot(model). It can never hurt. Too bad the plot you want
is not among the six contenders (?plot.lm).
To do it manually:
dorien wrote:
fit - lm((tos~nh1*nh2*nh3*randsize*aweights*tt1*tt2*tt3*iters*length,
data=expdata))
Error: unexpected ',' in fit -
lm((tos~nh1*nh2*nh3*randsize*aweights*tt1*tt2*tt3*iters*length,
Peter's point is the important one: too many interactions, and even with +
instead of * you
bellewong wrote:
The figure is posted at
http://www.mediafire.com/i/?08b9f4um43vxvw8
That type of plot that has descended on us like a beeswarm. Try the package
with that name.
Dieter
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baptiste auguie-5 wrote:
I wish to modify programmatically only a few factor levels, according
to a named list. I came up with this function..
.
It seems to work, but the original order of the levels is changed.
The split-and-unite policy you use makes it a bit difficult to
dorien wrote:
I calculate an anova test in the following way:
... aov example
I want to check the fit of the model with Rsquared
Try summary(lm(...)) instead.
Dieter
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Ian Renner wrote:
Hi,
I'm a novice with levelplot and need some assistance! Basically, I want a
window
which contains 6 levelplots of equal size presented in 3 columns and 2
rows.
...
Is there any way to concatenate levelplots from a factor vertically as
opposed
to horizontally?
jose romero-3 wrote:
For one thing, i am using google docs to host the R object file and google
docs has secure https URL's, which apparently cannot be handled by R's
url(). So my questions are these:
Try ?getURL in the RCurl package
Dieter
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Juraj17 wrote:
Do I have to write my own, or it exists yet? How name has it, or how can I
use it.
Try the R-function search. It return the function you are looking for as the
first match.
Dieter
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Bert Jacobs-2 wrote:
I would like to replace the last tree characters of the values of a
certain
column in a dataframe.
Besides the mentioned standard method: I found the subset of string
operations in Hadley Wickhams stringr package helpful. They have a much more
consistent interface
alaios wrote:
I am trying to learn lapply.
I would like, as a test case, to try the lapply alternative for the
Shadowlistlt;-array(data=NA,dim=c(dimx,dimy,dimmaps))
for (i in c(1:dimx)){
Shadowlist[,,i]lt;-i
}
---so I wrote the following---
returni lt;-function(i,ShadowMatrix)
Boris New wrote:
The problem is that the editor wants a formal test. So I guess that the
Vuong test should be ok...
I frequently note that it is the big boss who believes that the editor wants
a formal test.
Nobody ever got fired for producing a p-value :-(
Dieter
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I am trying to pass a additional argument to texi2dvi, for example to use
the aux-directory. Looks like this is not possible via options:
options(texi2dvi='texi2dvi --tex-option=-aux-directory=auxdir')
texi2dvi(file = GBPL3.tex, pdf = TRUE)
#Error in system(paste(shQuote(texi2dvi), --version),
armstrwa wrote:
for(i in 1:length(gagehandles)){
dates-get(paste(gagehandles[i],_amsd,sep=))
Error in get(paste(gagehandles[i], _amsd, sep = )) :
variable names are limited to 256 bytes
It didn't have a problem with the variable names before, so I'm not sure
what's going on
After pondering all the pros and cons regarding the usefulness of a
rating/review system for R packages, don't you think it would make sense
to implement such a thing?
Or to look what is there, and how little it is filled:
http://crantastic.org/
Dieter
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Bert Gunter wrote:
You can't. R^2 has no (consistent, sensible) meaning for nonlinear models.
If you don't understand why not, get local help or do some reading.
There is no doubt that you are right, but Anna's question only shows that
she is sandwiched between reviewers/supervisors who
Michael Friendly wrote:
This is just the flexibility of R. I've just discovered a new class of
geometries based on
pi - 2.3
?Constants
This is a must-fortune.
Dieter
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Marlin Keith Cox wrote:
Thank you, but I need only the area under the llm colored. What if there
were two lm lines?
For the well-behaved case you could find the range to be colored with
range = which(diff(resid(llm)0)!=0)
Dieter
x=seq(0,5,len=100)
y=-(x-5)^2
llm-lm(y~x)
range =
Geoffrey Smith-3 wrote:
Hello, I was wondering if there was an easy way to calculate the rate of
change in a variable for an unbalanced panel data set. Below is a
detailed
description in R of what I am asking. Thank you. Geoff
A classic for mixed models, which simply does not know
John G. Bullock-2 wrote:
The strip argument to panel.xyplot seems to be ignored for single-panel
plots. Here is an example:
data(Chem97, package = mlmRev)
myStrip - function(...) { ltext(.5, .5, 'strip text') }
densityplot(~ gcsescore, data = Chem97, strip=myStrip)
The
Erin Hodgess-2 wrote:
Here is a little function that I put together:
fact1
function(x) {
n - ncol(x)
for(i in 1:n) {
if(mode(x[,i])==character)x[,i] - factor(x[,i])
}
return(x)
}
See
http://www.mail-archive.com/r-help@stat.math.ethz.ch/msg22459.html
for a more R-ish approach.
jannis-2 wrote:
is it somehow possible to retrieve the x and y coordinates of points in
a scatterplot after it has been plotted? identify() somehow seems to
manage this, so I was wondering whether it is possible?
locator might be the more basic function you are looking for.
Dieter
Jeff wrote:
I know Chi-squared test can be done with the frequency data by R function
chisq.test(), but I am not sure if it can be applied to the percentage
data ? The example of my data is as follow:
#
KSL MHL
Uwe Wolfram wrote:
I did fit an equation of the form 1 = f(x1,x2,x3) using a minimization
scheme. Now I want to compute the coefficient of determination. Normally
I would compute it as
r_square = 1- sserr/sstot with sserr = sum_i (y_i - f_i) and sstot =
sum_i (y_i - mean(y))
sserr
Marcel J. wrote:
Is there a way to manually costumize the color legend in an spplot() -
especially where to draw ticks and labels for the ticks?
spplot calls levelplot, so the documentation there gives some help. In
theory, the simplest approach would be to add a colorkey/ticknumber
surreyj wrote:
Now all the other demand literature reports the %/proportion of variance
accounted for (or R squared) as well as the parameter values and standard
error.
...
I had a chat to a supervisor and he suggested I post to here and see if
someone can give me a reference/references
mathijsdevaan wrote:
I have a DF like this:
DF = data.frame(read.table(textConnection(A B C
1 b1 1999 0.25
2 c1 1999 0.25
..
For each factor in A I want to sum the values of C for all years(Bn) prior
to the current year(Bi):
1 b1 1999 0.25 0
2 c1 1999 0.25 0.4
3
Elliot Joel Bernstein wrote:
I'm trying to use lattice graphics to produce some small plots for
inclusion in a LaTeX file. I want the LaTeX fonts to be used in the plots,
but to be scaled down to match the size of the plot.
I agree with Deepayan. With tikzdevice, tust try to get the
danielepippo wrote:
I'm building a matrix in R with a cycle for like this:
pp_ris2=matrix(NA,6,6)
for(i in 0:6){
.
R is not like c, indexing starts with 1.
Dieter
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Kari-4 wrote:
I've created a 3d scatterplot, and had no problems labeling the points.
However, I've been really struggling to change the color of the points
based
on a factor (see 'group' below). Is such a thing possible?
Its always polite to make the example self-running by adding
JESSICA wrote:
I have a text file stored in notepad:
DATE TIME Q
2004-11-01233311 1
2004-11-01234227 1
...
I run
x-read.table(C:/R/Sample.txt,header=T)
then get a table
...
I am trying to
strptime(x$TIME,%H%M%S)
and get :
Steven Cordwell wrote:
However, transforming z into a matrix with two rows, where both rows are
the same as z above does seem to be a workaround.
z - matrix(c(z,z),2,length(z),byrow=TRUE)
y - c(0.25,0.75)
Bogaso wrote:
Vect - c(12.234, 234.5675, 1.5)
Now I want a string vector like:
changedVec - c(012.234, 234.568, 001.500)
sprintf(%06.3f, c(12.234, 234.5675, 1.5))
Dieter
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Shige Song wrote:
Dear All,
I am trying to recode a variable using the functions provided by
memisc package. Actually I am following the examples on page 9-10 of
the vignette:
--
d.fig - within(d.fig,{
sev -
wanfairos wrote:
Dear members;
I have one problem to display my simulated data. Basically, I've generated
a set of rnorm (std.norm.mat)and rnbinom (gen.data) data to test on the
performance of FE Poisson model estimates
... Long self-contained example shorted
wanfairos wrote:
Dear members;
I have one problem to display my simulated data. Basically, I've generated
a set of rnorm (std.norm.mat)and rnbinom (gen.data) data to test on the
performance of FE Poisson model estimates
... Long self-contained example shorted
wanfairos wrote:
I have one problem to display my simulated data. Basically, I've generated
a set of rnorm (std.norm.mat)and rnbinom (gen.data) data to test on the
performance of FE Poisson model estimates
... Long self-contained example shorted
my.data-rep(,sim.size)
for(i in
wanfairos wrote:
I have one problem to display my simulated data. Basically, I've generated
a set of rnorm (std.norm.mat)and rnbinom (gen.data) data to test on the
performance of FE Poisson model estimates
... Long self-contained example shorted
my.data-rep(,sim.size)
for(i in
Dear latticists,
Getting legend and graph line types synchronized has been a challenge in
lattice; the last example below that works looks ridiculously ugly for such
a simple job, I am sure there is a more elegant solution.
When trying this out, I found a feature which I found confusing: why are
BSanders wrote:
.
lin[i] = lm(reservesub[,3]~ reservesub[,i+3])
For which I'm given 15 warning messages which say :
1: In lin[i] = lm(reservesub[, 3] ~ reservesub[, i + 3]) :
number of items to replace is not a multiple of replacement length
lin = list()
for(i in 1:15){
veepsirtt wrote:
corr - cor(s1,s2)
Error in cor(s1, s2) : incompatible dimensions
Check lenghts of your series.
cor(c(1,2),c(1,2,3))
#Error in cor(c(1, 2), c(1, 2, 3)) : incompatible dimensions
Dieter
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zerfetzen wrote:
Is it possible in Sweave to put \Sexpr{} inside ? This is a bad
example, but here goes:
results=hide
Age - 5
@
x - \Sexpr{Age}
@
...
It's good to have a simplified example, but your's is so much simplified
that it is difficult to understand. I know I had
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__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
plsc wrote:
I analysed my data with lme and after that I spent a lot of time for
mean separation of treatments (post hoc). But still I couldnât make
through it. This is my data set and R scripts I tried.
3 level3 var4361261
plsc wrote:
I analysed my data with lme and after that I spent a lot of time for
mean separation of treatments (post hoc). But still I couldnât make
through it. This is my data set and R scripts I tried.
3 level3 var4361261
ADias wrote:
Is there an expression to double the values of a matrix - without using a
loop?
Why so complicated?
Dieter
m = matrix(rep(1,20),nrow=4)
m
[,1] [,2] [,3] [,4] [,5]
[1,]11111
[2,]11111
[3,]11111
[4,]1
Fabrice Tourre wrote:
How to plot as the coordinate as in my attachment? I want to trim the
coordinate and one of plot as the figure in attachment. Does any one
have such example?
http://markmail.org/message/3jn2sqoep36ckswb
(for a lattice-lookalike)
and package
plotrix
Dieter
--
Thomas Jensen-6 wrote:
... data set ...
The data set has in total 27 countries for the years 1999 to 2008, but
with unbalanced panels.
I want to be able to estimate a model and do forecasting for each
country in the data set. I have been looking into the YourCast package
from
Bill.Venables wrote:
...
If you want to fit a multistratum model, such as a repeated measures
model, you need to use aov.
...Or lme in nlme / lmer in lme4.
Dieter
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anord wrote:
I'm trying to make multiple comparisons for an lme-object.
...
My final model takes the following form:
feedings ~ treat + year + data^2, random = ~1|site,data=feed.df
...
==
feedings sex site treat year date^2
1.8877888 M 838 H 2009 81
Jeroen Ooms wrote:
What is the most efficient method of parsing a dataframe-like structure
that has been json encoded in record-based format rather than vector
based. For example a structure like this:
[ {name:joe, gender:male, age:41}, {name:anna,
gender:female, age:23} ]
RJSONIO
John Kane-2 wrote:
# Can anyone suggest why this works
datafilename -
http://personality-project.org/r/datasets/maps.mixx.epi.bfi.data;
person.data - read.table(datafilename,header=TRUE)
# but this does not?
dd -
Henrique Dallazuanna wrote:
With the ssl.verifypeer = FALSE argument it works:
x = getBinaryURL(dd, ssl.verifypeer = FALSE)
Thank, good to know. It's only in the examples of ..., but is looks like a
parameter important enough to be included in the docs of getBinaryURL.
Digging
mhofert wrote:
trellis.device(pdf, width = 5, height = 5)
print(xyplot(0 ~ 0, main = This title is not 'centered' for the human's
eye, scales = list(alternating = c(1,1), tck = c(1,0
dev.off()
... the title does not seem to be centered for the human's eye [although
it is centered
Axolotl9250 wrote:
...
resampled_ecoli = sample(ecoli, 500, replace=T)
coefs = (coef(lm(MIC. ~ 1 + Challenge + Cleaner + Replicate,
data=resampled_ecoli)))
sd(coefs)
...
Below a simplified and self-consistent version of your code, and some
changes
Dieter
# resample
d =
Az Ha wrote:
I have a set of data where two groups of animals walk around in an
environment and I have calculated the percentages of the area covered by
them. Each group covers different area, for example the arithmetic mean is
35% and 23% with n=40 and 29 respectively.
...
Should i use
Lei wrote:
I have been playing with lme fitting different kinds of model. I am
puzzled by the estimates associated with $modelStruct and I have no idea
what they are?
e.g if I fit a random intercept model using the following
fit.0-lme(y~time,random=list(subject=pdIdent(~1)))
The
mathijsdevaan wrote:
I have a postgresql and a mysql database and I would like to combine the
info from two different tables in R. Both databases contain a table with
three columns: project_name, release_id and release_date. So each project
output could be released multiple times (I am
Robert Ruser wrote:
x - seq(20, 100, by=15)
ety - rep( Effect on treatment group, times=length(x))
barplot(x, names.arg=ety, las=1, horiz=TRUE)
Labels are not visible. But trial and error method with the second mar
argument I get what I want.
Standard graphics has fallen a bit out of
venik wrote:
I am trying in vain to find the bioDist package.
More generally, where can I find a lit of packages and their location? I
thought CRAN will have it, but I had no luck with bioDist.
Google bioDist, second hit (maybe another one, depending on your language
settings).
D
--
David Winsemius wrote:
Here's my latest guess at what you may want:
pdf(file=multpage.pdf)
xyplot(val~time|subj + comp, data=dt,type=l,
layout=c(3,5, 3),
skip=rep(c(rep(FALSE,13), TRUE, TRUE), 3) )
dev.off()
Not really, but skip was the right idea. I added
Dear latticists,
I would like to spread a lattice conditioned plot over multiple pages,
keeping the same layout as if I had only one page as shown in the code
below.
My workaround is to divide the dataframe into subset that fit on one page,
but the code is ugly.
Is there a build-in way to
djmuseR wrote:
If I read your intention correctly, you need a third element in layout = .
df - data.frame(month = rep(month.abb, each = 20),
time = rep(1:20, 12),
y = rnorm(240))
xyplot(y ~ time | month, data = df, layout = c(2, 2, 3))
This
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