Re: [R] 2D and 3D graphing

as pwd is correct). Make sure to key "enter" after you >> paste or you >> will not get the last line of code. >> >> You will see a plot of 5 points (5,57,55,41,sum) which are all connected by >> lines. >> You can rotate the plot with left-click, pan t

Re: [R] 2D and 3D graphing

that with arbitrary scattered points. That is why the surface3d function interface is separate from the points3d function interface ... it uses a matrix to communicate adjacency for four points at a time. On March 23, 2020 7:54:04 PM PDT, EK Esawi via R-help wrote: > >Thank you Ista and LM

Re: [R] 2D and 3D graphing

at was in principle components so x, y, and z were in the same units. I can post a sample of the terminal input that I used if that would help. LMH Ek Esawi wrote: > Hi All-- > > I have been looking into 2D and 3D graphing packages. Based on what i > read, it seems that ggplot2 is the best and I

[R] 2D and 3D graphing

Hi All-- I have been looking into 2D and 3D graphing packages. Based on what i read, it seems that ggplot2 is the best and I like it too, but ggplot2 doesn't have 3D plotting capabilities. I read that other packages (plot_ly, rgl, rayshader) can be used with ggplot2 to create 3D charts, but not

Re: [R] Sequential Filtering of a Data Set

Hi If i understand your question correctly, it seems split or split date will do what you want. BOL--EK On Fri, Apr 26, 2019 at 10:51 AM Lorenzo Isella wrote: > > Dear All, > I must be drowning in a glass of water. > Consider the following data set > > tt2<-structure(list(year = c(2000, 2001,

Re: [R] Alternative to loops

ces<- sapply(MyDF$B, strsplit, split = " +") > > nm <- names(MyList) > > MyDF$C <- nm[sapply(choices, function(x)match(TRUE, > > sapply(MyList,function(tbl)any(x %in% tbl] > > MyDF$C > [1] "Y" "z" "X" NA NA > > Y

[R] Alternative to loops

Thank you. Sorry i forgot to turn off the html Below is a sample of my data. My original data frame has over 10,000 rows. I want to check each element on my data frame column B (MyDF$B) to see if it contains any element(s) of MYList. if os, change the value of MyDF$C to the name of the vector of

[R] Alternative to lops

Hi All-- Sorry i sent the one inadvertently Her is a sample of my data. A data frame (MyDF) and a list (MyList). My own data frame has over 10,000 rows. I want to find out which elements of MyDF$B contain any element(s) of MYList; then change MyDF$C to the name of the vector of the list that

[R] Alternative to loops

Hi All Her is a sample of my data. A data frame (MyDF) and a list (MyList). My own data frame has over 10,000 rows. I want to find out which elements of MyDF$B contain any element(s) of MYList; then change MyDF$C to the name of the vector of the list that has match. I solved this via loops and

Re: [R] Split a DF on Date column for each single year

> make the grouping column? > > On March 15, 2019 10:40:01 PM PDT, Ek Esawi wrote: > >Hi All— > > > >I have a data frame with over 13000 rows and 4 columns. A mini data > >frame is given at the bottom. I want to split the data frame into > >lists each corresponds

[R] Split a DF on Date column for each single year

Hi All— I have a data frame with over 13000 rows and 4 columns. A mini data frame is given at the bottom. I want to split the data frame into lists each corresponds to single year which ranges from 1990 to 2018). I wanted to use the split function, but it requires a vector of the same length as

Re: [R] Function doesn't work inside loop but works outside

Thank you Peter. That's a dumb question on my part! At least i should have known that i need an assignment statement. Thanks again--EK On Tue, Mar 5, 2019 at 11:36 AM peter dalgaard wrote: > > You need a print() around the gsub(...) when inside a loop. > > -pd > > > On 5 Ma

[R] Function doesn't work inside loop but works outside

Hi All, I am using xlsx package to extract and clean data from an Excel Workbook. I ran into a strange behavior that I don’t understand. The gsub doesn’t work inside the loop but does outside the loop as shown on my code.. Tried to Google for help but nothing came up. My code loads and reads

Re: [R] Remove cases with -Inf from a data frame

This is a similar versions of other answers. df[apply(apply(df,2,is.finite),1,sum)==4,] BOL---EK On Sat, Feb 16, 2019 at 10:07 AM AbouEl-Makarim Aboueissa wrote: > > Dear All: good morning > > > I have a log-transformed data frame with some *-Inf* data values. > > *my question: *how to remove

[R] Create a new list from selected items in another list

Hi All-- I have a list which contain variables 0s at the end of each vector on the isit. I want to create a new list with only numbers > 0. It seems simple, but i tried several option, none of which worked. CCC <- list(A=c(1,2,3,0,0,0,0), B=c(2,3,4,5,0,0,0,0,0,0)) for (i in 1:length(CCC)) {

Re: [R] Combine recursive lists in a single list or data frame and write it to file

rting to a data frame. If > you can send some data (if it's not too big) I can test it and make > sure that it works, as it did every time for me. > > Jim > > On Thu, Dec 20, 2018 at 2:22 PM Ek Esawi wrote: > > > > Thank you Jim. I did use unlist with the recursive option whi

Re: [R] Combine recursive lists in a single list or data frame and write it to file

the levels or a nested list to convert it to a single level list. > > Jim > > On Thu, Dec 20, 2018 at 1:33 PM Ek Esawi wrote: > > > > Thank you Bert. I don't see how unlist will help. I want to combine > > them but keep the "rectangular structure",e.g. lis

Re: [R] Combine recursive lists in a single list or data frame and write it to file

ed, Dec 19, 2018 at 9:10 PM Bert Gunter wrote: > > Does ?unlist not help? Why not? > > Bert > > > On Wed, Dec 19, 2018, 5:13 PM Ek Esawi > >> Hi All— >> >> I am using the R tabulizer package to extract tables from pdf files. >> The output

[R] Combine recursive lists in a single list or data frame and write it to file

Hi All— I am using the R tabulizer package to extract tables from pdf files. The output is a set of lists of matrices. The package extracts tables and a lot of extra stuff which is nearly impossible to clean with RegEx. So, I want to clean it manually. To do so I need to (1) combine all lists in

Re: [R] Combine lists into a data frame or append them to a text file

quot;,"c")) > BB <- list(c=c(1,2,3,4,5),d=c("a","b","c","d","e")) > mylist <- c(AA,BB) > mydf > Jim > > On Mon, Dec 17, 2018 at 12:45 AM Ek Esawi wrote: > > > > Thank you Jim and Bert, > > > >

Re: [R] Combine lists into a data frame or append them to a text file

y(mylist,function(x) write.table(x,file = test.txt)) Show Traceback Error in (function (..., row.names = NULL, check.rows = FALSE, check.names = TRUE, : arguments imply differing number of rows: 4, 3 On Sun, Dec 16, 2018 at 8:45 AM Ek Esawi wrote: > > Thank you Jim and Bert, > > I trie

[R] Combine lists into a data frame or append them to a text file

Hi All, I have an R object that is made up of N number of lists which are all of different number of columns and rows. I want to combine the N lists into a single data frame or write (append) them into text file. I hope the question is clear and doesn’t require an example. I am hoping to

Re: [R] Remove specific rows from nested list of matrices

*\\s|^[0-9]x.*|.*[P-p]oints.*|.*\\sto\\s.*" To remove some unwanted entries, I used this formula. F <- lapply(G, function(x) lapply(x, function (y) lapply(y, function(z) gsub(S1,"",z Thanks again--EK On Fri, Nov 2, 2018 at 11:00 AM Ek Esawi wrote: > > Hi All, >

Re: [R] Remove specific rows from nested list of matrices

01/02", "01/02 01/02", Thanks again--EK On Fri, Nov 2, 2018 at 11:21 AM Jeff Newmiller wrote: > > Can you supply the output of > > dput(FF) > > ? > > On November 2, 2018 8:00:08 AM PDT, Ek Esawi wrote: > >Hi All, > > > >I have a list that

[R] Remove specific rows from nested list of matrices

Hi All, I have a list that is made up of nested lists, as shown below. I want to remove all rows in each sub-list that start with an empty space, that’s the first entry of a row is blank; for example, on [[1]][[1]][[1]] Remove row 4,on [[1]][[1]][[3]] remove row 5, on [[1]][[2]][[1]] remove row

Re: [R] remove text from nested list

ms screwy in the example you showed: For example, the > [[1]][[2]][[1]] component indicates a 2 x 5 matrix, but I see only 3 columns > of text. Am I missing something? > > Cheers, > Bert > > > > On Thu, Oct 25, 2018 at 6:04 PM Ek Esawi wrote: >> >> Hi All— >

[R] remove text from nested list

Hi All— I have a list that contains multiple sub-lists and each sub-list contains multiple sub(sub-lists), each of the sub(sub-lists) is made up of matrices of text. I want to replace some of the text in some parts in the matrices on the list. I tried gsub and stringr, str_remove, but nothing

Re: [R] Reorder file names read by list.files function

will try it and see. Thank you all. EK On Tue, Oct 9, 2018 at 9:44 AM Ek Esawi wrote: > > Hi All-- > > I used base R list.file function to read files from a directory. The > file names are months (April, August, etc). That's the system reads > them in alphabetical order., but i want

Re: [R] Reorder file names read by list.files function

untested) > FNs <- sort(match(sub("\\.PDF", "", basename(file.names)), month.name)) > > Bill Dunlap > TIBCO Software > wdunlap tibco.com > > On Tue, Oct 9, 2018 at 1:38 PM, Ek Esawi wrote: >> >> Hi again, >> >> I worked with

Re: [R] Reorder file names read by list.files function

fnames[ match( sub("\\.PDF", "", fnames ), month.name ) ] > > > On October 9, 2018 6:44:21 AM PDT, Ek Esawi wrote: > >Hi All-- > > > >I used base R list.file function to read files from a directory. The > >file names are months (April, August, et

Re: [R] Reorder file names read by list.files function

t;.PDF",full.names = TRUE) > file.names <- str_remove(file.names,"\\s[0-9][0-9]") > FNs <- sort(match(sub("\\.PDF", "", file.names), month.name)) > FNs1 <- paste0(month.name[FNs],".","PDF") > A <- lapply(FNs1, function(i

[R] Reorder file names read by list.files function

Hi All-- I used base R list.file function to read files from a directory. The file names are months (April, August, etc). That's the system reads them in alphabetical order., but i want to reordered them in calendar order (January, February, ...December).. I thought i might be able to do it via

Re: [R] From for loop to lappy?

t; 925-423-1062 > Lab cell 925-724-7509 > > > > On 10/1/18, 3:32 PM, "R-help on behalf of Ek Esawi" > wrote: > > Hi All— > > I am using Tabulizer to extract tables from PDF files. Tabulizer > creates a list of matrices for each set of tab

[R] From for loop to lappy?

Hi All— I am using Tabulizer to extract tables from PDF files. Tabulizer creates a list of matrices for each set of tables in each document. My code, below, works well. Then i thought i would use lapply instead of for loop since it is a little faster and more compact, but i kept getting an error

Re: [R] error "The system cannot find the file specified..."

Thank you Bert and Rui. Everything mentioned on your posts was OK with the exception of a typo in my original post where [a] was instead [[a]]. I stumbled one something that stated if i delete the sub-directory and create it it again might work. In my case once that was done, it worked. Thanks

[R] error "The system cannot find the file specified..."

Hi All, I am using the R Tabulizer package to extract tables from a set of pdf files. Tabulizer creates a list of data frames; each corresponds to a table in a file. My aim is to create a list of lists, one for each file.i have 8 files The code below kept giving me the error "Error in

Re: [R] Aggregate over multiple and unequal column length data frames

Thank you again Pikal and Bert. Using lapply, as Bert suggested, was the first thing that i thought of dealing with this question and was mentioned in my original posting. I just did not know how to implement it to get the results/form i want. Below is what i did but could not get it to give me

Re: [R] Aggregate over multiple and unequal column length data frames

ta.frames myself but most probably they would be > different from yours and also the result would not be necessary the same as > you expect. > > You should post those data frames as output from dput(data) and show us real > desired result from those example data frames. > > Cheer

[R] Aggregate over multiple and unequal column length data frames

Hi All-- I have generated several 2 column data frames with variable length. The data frames have the same column names and variable types. I was trying to aggregate over the 2nd column for all the date frames, but could not figure out how. I thought i could make them all of equal length then

Re: [R] substr gives empty output

The reason you get "" is, as stated on the previous response and on the documentation of substr function, the function "When extracting, if start is larger than the string length then "" is returned.". This is what happens on your function. HTH EK On Sun, Jan 21, 2018 at 3:59 AM, Luigi Marongiu

Re: [R] Replace NAs in split lists

Thank you all. Now everything works. Happy 2018 and beyond EK On Sun, Jan 7, 2018 at 10:13 PM, Ek Esawi <esaw...@gmail.com> wrote: > Hi all-- > > I stumbled on this problem online. I did not like the solution given > there which was a long UDF. I thought why cannot split and l/s

Re: [R] Replace NAs in split lists

e posting in HTML so your code is mangled. Can you > post plain text and use the reprex package to make sure it produces the > errorin a clean R session? > -- > Sent from my phone. Please excuse my brevity. > > On January 8, 2018 8:03:45 AM PST, Ek Esawi <esaw...@gmail.com> w

Re: [R] Replace NAs in split lists

Please excuse my brevity. >> >> On January 7, 2018 7:35:59 PM PST, Ek Esawi <esaw...@gmail.com> wrote: >>> >>> I just came up with a solution right after i posted the question, but >>> i figured there must be a better and shorter one.than my solu

Re: [R] Replace NAs in split lists

I just came up with a solution right after i posted the question, but i figured there must be a better and shorter one.than my solution sdf1[[1]][1,4]<-lapplyresults[[1]] sdf1[[2]][1,4]<-lapplyresults[[2]] EK On Sun, Jan 7, 2018 at 10:13 PM, Ek Esawi <esaw...@gmail.com> wrote: >

[R] Replace NAs in split lists

Hi all-- I stumbled on this problem online. I did not like the solution given there which was a long UDF. I thought why cannot split and l/s apply work here. My aim is to split the data frame, use l/sapply, make changes on the split lists and combine the split lists to new data frame with the

Re: [R] Help with script

Hi Pablo, Rui's suggestion is probably the best and easiest. In addition to Eric's, i think the apply functions will work well here too. Best of luck, EK On Thu, Dec 28, 2017 at 7:03 PM, PABLO ORTIZ PINEDA wrote: > Hello there. Happy new year for everyone! > > I need

Re: [R] match and new columns

Hi Val— Here is something similar to what Bill suggested. wainb <- which(tdat$A %in% tdat$B) tdat[c(length(tdat$D)-1,length(tdat$D)),c("D","E")] <- tdat[wainb,c("B","C")] HTH EK On Wed, Dec 13, 2017 at 4:36 PM, Val wrote: > Hi all, > > I have a data frame > tdat <-

Re: [R] Remove

HI-- How about this one. It produces the desired result. If you have more conditions, you can put them in a matrix/DF form and subset as suggested by one of the previous suggestion. DM[(DM$GR=="A"$x>=15$x<=30)|(DM$GR=="B"$x>=40$x<=50)|(DM $GR=="C"$x>=60$x<=70),] EK On Sat, Dec 9, 2017 at 5:00

Re: [R] trying to find the multiple combinations...

As Burt and Jeff stated that there is an infinite set of solutions. If you are interested in a particular solution, such as getting 15.0078, you can easily achieve that by trial and error; that is fix 1 or 2 variables and change the the rest till you get the desired solution. I tried that and came

Re: [R] Dynamic reference, right-hand side of function

Hi Love, I am not sure if I understand your question and it will help if you provided a sample data frame, sample of your code and sample of your output and the output you desire. Having said that, I think you could use cbind to join all datasets into a matrix and use the apply family of

Re: [R] assign NA to rows by test on multiple columns of a data frame

of luck EK a <- grep("_flag",colnames(mydf)) b <- mydf[,a]==0 c <- mydf[,a-1] c[b] <- NA mydf[,a-1] <- c mydf A A_flag B B_flag 1 8 10 5 12 2 NA 0 6 9 3 10 1 NA 0 4 NA 0 1 5 5 5 2 NA 0 On Wed, Nov 22, 2017 a

Re: [R] assign NA to rows by test on multiple columns of a data frame

OPS, Sorry i did not read the post carfully. Mine will not work if you have zeros on columns A and B.. But you could modify it to work for specific columns i believe. EK On Wed, Nov 22, 2017 at 8:37 AM, Ek Esawi <esaw...@gmail.com> wrote: > Hi *Massimo,* > > *Try this.* > &

Re: [R] assign NA to rows by test on multiple columns of a data frame

Hi *Massimo,* *Try this.* *a <- mydf==0mydf[a] <- NAHTHEK* On Wed, Nov 22, 2017 at 5:34 AM, Massimo Bressan < massimo.bres...@arpa.veneto.it> wrote: > > > Given this data frame (a simplified, essential reproducible example) > > > > > A<-c(8,7,10,1,5) > > A_flag<-c(10,0,1,0,2) > >

Re: [R] Count non-zero values in excluding NA Values

What was suggested by Eric and Rui works well, but here is a short and may be simpler answer provided your data is similar what Eric posted. It should work for your l data too. aa <- is.na(data)|data==0 nrow(data)-colSums(aa) EK On Sun, Oct 29, 2017 at 6:25 AM, Engin YILMAZ

Re: [R] Count non-zero values in excluding NA Values

Since i could not see your data, the easiest thing comes to mind is court values excluding NAs, is something like this sum(!is.na(x)) Best of luck--EK On Sun, Oct 29, 2017 at 6:25 AM, Engin YILMAZ wrote: > Dear R Staff > > You can see my data.csv file in the annex. > > I

Re: [R] Problem Subsetting Rows that Have NA's

z <- x[x[,2]==0&!is.na(x[,2]),] seems to work and get you what you want, but doesn't answer your question, z <- x[x[,2]==0&!is.na(x[,2]),] Best of luck, EK On Tue, Oct 24, 2017 at 3:05 PM, BooBoo wrote: > This has every appearance of being a bug. If it is not a bug,

Re: [R] nested loop

I would try fininterval as well. It should do what you have asked provided that you take care of the issue Ulrik pointed out. Best of luck--EK On Fri, Sep 8, 2017 at 6:15 AM, Hemant Sain wrote: > i have a vector containing values ranging from 0 to 24 > i want to create

[R] Identyfing rows with specific conditions revisited

Allaisone 1 allaisone1 at hotmail.com Mon May 22 02:10:10 CEST 2017 Hi All— I am curious as to whether there is a vectorized solution using base R functions, instead of looping and if statements, to the problem below. I have seen several posts that address a similar question which generally ask

[R] Fill in empty spaces modified

Thank you so much Jim. I forgot to state that i was hoping to get it without loops if possible. Thanks again, EK [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see

[R] Fill in empty spaces modified

Hi All— I was looking at a posting from June-17. I managed to solve it. However, when I changed the example in the posting, my solution will work only once at a time which was mentioned by Jim Lemon on his response to the original posting. This means that my solution will have to be repeated as

[R] How to replace match words whith colum name of data frame?Hi--

Hi-- concept_df$NewCol <- ""; kw <- "acid|ph"; bb <- grepl(kw,concept_df$concept) concept_df[dd,2] <- "chemical" The is a bit late but it accomplish the same with base R. Good luck--EK PS.. my email doesn't accept reply [[alternative HTML version deleted]]

[R] Counting with multiple criteria using data table

I have a data.table which is shown below. I want to count combinations of columns on i and count on j with by. A few examples are given below the table. I want to: all months to show on the output including those that they have zero value I want the three statements combined in on if possible

Re: [R] nested for loop with data table

concept is the first step. > > Perhaps look closely at [1], or Google for data table aggregation yourself? > > [1] https://www.r-bloggers.com/efficient-aggregation-and- > more-using-data-table/amp/ > -- > Sent from my phone. Please excuse my brevity. > > On May 3, 201

Re: [R] nested for loop with data table

July 23 10: 10 orange F70 May 7 11: 11 black A77 June 11 12: 12 green B87April 33 13: 13 black A79 August 9 14: 14 green A68 December 14 15: 15 black C90 January 31 16: 16 green D79 January 11 17: 17

[R] nested for loop with data table

I have a huge data file; a sample is listed below. I am using the package data table to process the file and I am stuck on one issue and need some feedback. I used fread to create a data table. Then I divided the data table (named File1) into 10 general subsets using common table commands such as:

[R] Data.table vs dplr handling multiple variables

Hi All— I am often working with large datasets with multiple variables (integer, decimal, string, complex, date, and time) that require processing, cleaning, etc. I am relatively new to R and I would like to get some input on the following issue: I am trying to figure out which R-package(s) is

Re: [R] Reading and converting time data via read.table

Thank you Jeff and Don. As I stated on my original posting that I am relatively new to R. After a few weeks of searching and reading I have come to the same point that Don made which is base R doesn’t have a class for time only. I explored the chron and lubridate packages and even looked at Ecfun

Re: [R] Reading and converting time data via read.table

Thanks for the responses i received from David and Spencer. As for the package Ecfun, i looked at it briefly, but it's long and i am new to R; so this just adds to my confusion. David suggested the sub function which i will try and see what i get.i s As i said earlier i have no problems reading

Re: [R] Reading and converting time data via read.table

Thanks Petr! I am still unable to come up with a conversion formula/trick to convert my time data to POSIXlt which then can be used in read.table. Below are again a few lines from my file. Since as you see there are several columns of time data ONLY (no date), I am hoping that there is a way to

Re: [R] Reading and converting time data via read.table

Thanks Jim! The problem is not date data. The problem is time. I figured out that I can use chron library and then use this expression times(paste0(t2, ":00")) because my time data are not h:m:s, only h;m. The problem I am trying to figure out is how to implement [times(paste0(t2, ":00"))] on

[R] Reading and converting time data via read.table

Hi All-- I am relatively new to R. I am reading a csv file via read.table (MyFile). The data types in the file are date, string, integer, and time. I was able to read all the data and manipulated correctly except time, e.g., 12:30. I used as.Date to convert date and string and integer were