You can use the lmList function in the nlme package to do several
seperate regressions, or use a model that allows for multiple
intercepts. Possibly Xvalues ~ 0 + log(Qvalues)*Tfac or Xvalues ~ 0 +
Tfac + log(Qvalues):Tfac (assuming Tfac is a factor).
On Tue, Oct 30, 2012 at 5:53 AM, Alex van der
First your response in the formula is a matrix which causes the lm
function to return an object of type 'mlm' for multivariate linear
model. Then when you run the stepAIC function it runs the addterm
function which looks for a method(function) to add terms to mlm
objects. However nobody has writt
Do you care about local topography/terrain? I think most of the
calculators/tables that are commonly used assume that you are at a
fairly flat place on the earth's surface, but that is not always true.
The area where my wife grew up had its longest day closer to the
equinox than the summer solsti
One possibility:
Estimate the center of the polygon with the mean of the x coords and
the mean of the y coords.
Calculate the angle of each point from that center point using the
atan2 function
sort the data by the angle calculated.
This will not be perfect if you have inlets and peninsulas, but
First of all, in the command par(xpd=F), what is the value of F? If
it is the default value of FALSE then that says to not plot anything
outside of the plot region, so any attempts to put a legend in the
outer margin will not plot anything. if F is TRUE (which is a recipe
for disaster) then you c
Another option would be to read the data using read.table or similar
to get the data into a data frame then use the xtabs function,
something like:
result <- xtabs( count ~ docID + wordID, data=mydf)
On Thu, Oct 18, 2012 at 6:44 AM, Rui Esteves wrote:
> Hi,
>
> I downloaded a dataset from UCI
You have a list of models, the coef and confint functions only work on
a single model, so you need to use lapply or sapply to get the
information from each model. Possibly something like (untested):
tableOfOddsRatios <- sapply( models, function(x) exp(c( coef(x)[2],
confint(x)[2,]) )
I included
Possible? Yes. (see fortune("Yoda"))
Automated using the legend function? No
Automated using another function? possbly somewhere in the 4,000+
packages on CRAN, but I don't know which.
It is doable with the basic tools. You could either find a part of
your graph with open area to put the legend i
Rui answered the main question by pointing out that you need z.test(m,
stdev=s(m)), or you could use z.test(m,,sd(m)), but I think the stdev=
approach is clearer. But you are really abusing the concept of z
tests in general (and the z.test function in particular) by using the
sd of the sample. If
It should be able to be done.
You would first need the data and be able to create the static version
of the plot. Then write a function that will create the static
version of the plot with some way (argument passed in) to add a
highlighted line.
Then it is just a matter of figuring out which lin
Duncan's answer is probably the easiest, but another alternative is to
use the tikz device instead of .eps files, then you can find the code
within the figure for the parts that you want to appear later and
enclose them in the beamer commands that will make them appear later.
Unfortunately this is
There are packages for big data analysis, which is best depends on
what you want to do. The High Performance Computing task view on CRAN
has a section on packages that deal with big data which gives some
more detail and may help you choose which package(s) to use.
On Wed, Oct 10, 2012 at 12:36 AM
I finally was able to compile/load it under windows 7. I had similar
problems to what you show below.
I set the MYSQL_HOME environmental variable through windows (start
button > control panel > System and Security > system > Advanced
System Settings > Environmental variables). I had to set it to
In addition to Bert's answer. If the 0 and/or 100 are hard boundaries
(you know that values cannot be outside those values) and you have
data points near one or both of the bounds, then the functions in the
logspline package may be of use.
On Tue, Oct 9, 2012 at 2:38 PM, Bert Gunter wrote:
> ??
The plot.new function is for base graphics and base and grid graphics
don't usually play well together. You probably want to use
grid.newpage function instead.
On Tue, Oct 9, 2012 at 1:26 PM, Ali Tofigh wrote:
> Hi,
>
> when using the grid package, I've come across this weird behaviour
> where a
Kokila,
Note that the quality of replies on this mailing list tend to
correlate with the quality of the questions. Follow the advice found
in the last 2 lines of this (and all) message and ask a better
question and you are more likely to get a better reply.
On Fri, Oct 5, 2012 at 5:53 AM, kokila
Others have shown barchart commands that include 0's. My guess (which
could be wrong, feel free to ignore this e-mail if so) is that your
problem is due to the way you are creating/summarizing the data before
the plotting command is used. R needs some way to know about what
bars you want, even if
See fortune("toad") for a bit more on this concept.
On Thu, Oct 4, 2012 at 3:19 PM, David Winsemius wrote:
>
> On Oct 4, 2012, at 8:57 AM, anto.r wrote:
>
>> Hi Michael
>>
>> thanks! That was the option if I kept it an array. The list format with $
>> sign since it leaves me feeling that the name
The most common case that I see that error is when someone fits their
model using syntax like:
fit <- lm( mydata$y ~ mydata$x )
instead of the preferred method:
fit <- lm( y ~ x, data=mydata )
The fix (if this is what you did and why you are getting the error) is
to not use the first way and in
So if you have both loaded in the same instance of R, how will R know
which version of lmer or other functions that you want to run?
It seems cleanest to me to have the 2 different instances of R running
like you do now. The other option would be to change all the names
(exported ones anyways) in
There is already support in the packaging system for a NEWS file which
can be accessed within R using the 'news' function. What would the
changelog that you are proposing contribute or contain beyond what the
NEWS file already does?
Creating and updating NEWS is not mandatory, but is encouraged.
You may find it easier to use the logspline density fits (logspline
package) rather than the kernel density estimators for this.
On Mon, Oct 1, 2012 at 7:46 AM, Eugene Kanshin wrote:
> Hello,
> I have a data x with normal (or very close to normal) distribution, I can
> plot a density distribution
Does your dataset have any missing data? (without a reproducible
example we can only guess).
If it does then you may be fitting the same model to different subsets
of the data between the 2 methods.
On Tue, Sep 25, 2012 at 9:03 AM, Maximilian Lklweryc
wrote:
> Hi,
> I want to make model selectio
Is GNI sorted? if not then the lines function plots the line segments
to the points in the order given and that would explain part of the
strangeness (the png file did not make it through). Are there gaps
between the GNI values? even if GNI is sorted, your code below will
just draw line segments
I expect that the coordinate system being set up and used by boxplot
is different from what you are expecting. See the ?boxplot and ?bxp
help pages for details. You may be able to have the boxplots drawn
where you expect by using the "at" argument (you may want to specify
"xlim" as well).
On Thu
I nominate Jim's answer below for the fortunes package.
On Wed, Sep 19, 2012 at 3:50 AM, Jim Lemon wrote:
> Sri krishna Devarayalu Balanagu wrote:
>>
>>
>> Suppose I want the output as "Trial and a sheet" without quotes
>> x=c("a", "b", "c")
>> print("Trial and x[1] sheet")
>>
>> Getting "Tr
In addition to Jessica's answers try
sprintf("Trial and %s sheet", x[1])
library(gsubfn)
fn$cat("Trial and `x[1]` sheet\n")
On Tue, Sep 18, 2012 at 8:42 AM, Jessica Streicher
wrote:
>> paste("Trial and",x[1],"sheet")
> [1] "Trial and a sheet"
>> cat("Trial and",x[1],"sheet")
> Trial and a sheet
Do you understand what you did (not the individual steps, but what the
overall process does)?
You simplified your model using things other than the AIC, if you go
back and look at the AIC at each step that you did you will probably
find that some of the intermediate steps actually had a slightly
h
I can confirm that I have this problem occasionally as well (windows 7
laptop), I see it more often when clicking the button in the GUI that
does the same as ctrl-R.
Here is my sessionInfo:
R version 2.15.1 (2012-06-22)
Platform: x86_64-pc-mingw32/x64 (64-bit)
locale:
[1] LC_COLLATE=English_Unit
Thanks for including an example that could be copied and pasted.
However TkPredict and Predict.Plot both need at least one numeric (not
factor) predictor. So I added another column called x that was just
1:5 to the sample data frame and included it in the model.
Here are a couple of approaches us
The symbols function allows you to place boxplot symbols at specified
x,y coordinates. Would that do what you want?
On Sat, Sep 8, 2012 at 8:14 AM, Zhang Qintao wrote:
> Hi, All,
>
> I am trying to use R to make the following type of boxplot while I couldn't
> find a way to do it.
>
> My dataset
Look at the staxlab function in the plotrix package.
On Thu, Sep 6, 2012 at 12:03 PM, David-Arnold wrote:
> All,
>
> I have:
>
> sales <- c(2300,900,155,102,42,10)
> names(sales) <- c("Christmas","Valentine's Day",
>"Mother's Day","Father's Day",
>"Thanksgiving","New Year'
I would be very surprised if the x value from locator matched the x
value in the data to the precision needed by ==, and what if 2 points
have the same x-value but different y-values, you would need to also
check the y's. With appropriate rounding this would work, but would
just be reinventing the
Look at the sprintf and paste functions (either one will do what you describe).
On Thu, Aug 30, 2012 at 7:49 AM, Andras Farkas wrote:
> Dear All,
>
> I have the following code set up:
>
> x <-2000
> y <-8
> z <-3
>
> I would need to use these numbers to show up in my plot title "mixed" with
> te
Others have mentioned assign and get, but generally when the answer to
a question is "assign" it means that you are asking the wrong question
(see fortune(236)).
This is actually FAQ 7.21, the most useful part of the answer in the
FAQ is the last few lines.
If you tell us more about what you are
Look at the TkListView function in the TeachingDemos package.
On Wed, Aug 22, 2012 at 1:30 PM, Michael wrote:
> Is there a data/variable explorer in R?
>
> Hi all,
>
> I am inspecting a complex variable which has lists inside lists...
>
> Is there a data-explorer that can help me view the structu
Using par(new=TRUE) will often cause more problems than it helps.
A better approach would be to use the twoord.plot function from the
plotrix package or to use the updateusr function from the
TeachingDemos package along with the lines function to add the lines
afterwards.
On Wed, Aug 22, 2012 at
I think the big unique thing about R is that it is both an interactive
environment and a programming language. A new user can start it,
enter some data, and compute same basic statics without ever
"programming". A more advanced user can write their own function to
automate common procedures or im
The akima package does interpolation and there are probably others as well.
You could also fit a parametric, semi-parametric, or local model to
the observed data and use the predicted values from the model for the
interpolations (see the loess function for one option that might work
well for you).
Perhaps the sprintf function is what you are looking for. It is one
way to insert information from a variable into a string. A couple of
other options are paste, paste0, and the gsubfn package, but I think
sprintf will be simplest for what you are asking.
On Thu, Aug 16, 2012 at 1:30 PM, Kenneth
The read.csv.sql function in the sqldf package may make this approach
quite simple.
On Thu, Aug 16, 2012 at 10:12 AM, jim holtman wrote:
> Why not put this into a database, and then you can easily extract the
> records you want specifying the record numbers. You play the one time
> expense of cr
s not plot the legend, but gives you the
information that you can use to create the legend yourself (and could
therefore move the pieces that you want moved).
On Wed, Aug 15, 2012 at 8:05 PM, Jinsong Zhao wrote:
> On 2012-08-16 0:22, Greg Snow wrote:
>>
>> You can use the grconv
A quick and simple way would be to fill both circles with a
semi-transparent color (does not work on all devices), then the
overlapping area will will show up as a different color/shade due to
the alpha blending. You might want to redraw the circles without fill
after the filled ones so that the 1
You can use the grconvertY function to find the position in the
current user coordinates that corresponds to the top of the device
area (instead of using locator).
Look at the "merge" argument to the legend function.
On Wed, Aug 15, 2012 at 10:04 AM, Jinsong Zhao wrote:
> Hi there,
>
> I draw a
The fill patterns date back to when the main way to get quality graphs
was using a pen plotter. Filling a rectangle with color using a pen
plotter took a long time and often resulted a soggy hole in the paper,
so the fill lines were preferred back then. Now with high resolution
screens and printe
Look at the leaps function in the leaps package. It will compute the
Cp statistic which is a function of AIC.
On Thu, Aug 9, 2012 at 7:28 AM, zel7223 wrote:
> Hi,
>
> I want to use four independent variables to predict the output of one
> dependent variable using a linear model lm. I want to com
Probably the best thing to do is create an environment within the
package that you can assign to and read from.
Somewhere in the source code for the package include a line like:
my.env <- new.env()
then within any functions defined after that line you can set
variables within the environment wit
You should not need to write them yourself. Look at the contr.poly function
along with the C function (Note uppercase C) or the contrasts function.
On Monday, July 23, 2012, Manzoni, GianMauro wrote:
> Dear all,
> I am quite new to R and I am having trouble writing the polynomial
> contrasts for
The EM algorithm does not impute missing data, rather it estimates
parameters when you have missing data (those parameters can then be
used to impute the missing values, but that is separate from the EM
algorithm).
If you create a dataset that has missing values imputed (a single
time) and then an
For reading data into R you should start with
http://cran.r-project.org/doc/manuals/R-data.html (or the local copy
that was installed with R on your machine).
For the example above the read.table function should be fine. If you
want to change the shape of the resulting data frame then look at the
There are functions that allow for the "plotting" of text and R
objects that could be used to plot to a bitmap. Look at the
'addtable2plot' function in the plotrix package and the textplot
function in the gplots package (look for alternative spellings if you
don't find them based on those exact sp
where that takes me.
>
> Paul
>
> --- On *Fri, 7/13/12, Greg Snow <538...@gmail.com>* wrote:
>
>
> From: Greg Snow <538...@gmail.com>
> Subject: Re: [R] Power analysis for Cox regression with a time-varying
> covariate
> To: "Paul Miller"
> Cc:
A permutation test may be appropriate:
1. compute the ratio of the 2 IQR values (or other comparison of interest)
2. combine the data from the 2 samples into 1 pool, then randomly
split into 2 groups (matching sample sizes of original) and compute
the ratio of the IQR values for the 2 new samples.
For something like this the best (and possibly only reasonable) option
is to use simulation. I have posted on the general steps for using
simulation for power studies in this list and elsewhere before, but
probably never with coxph.
The general steps still hold, but the complicated part here will
If you are going to be doing a lot of this then you might want to
consider using logspline density estimates (logspline package) instead
of kernel density estimates.
On Wed, Jul 11, 2012 at 8:33 AM, firdaus.janoos wrote:
> Hello,
>
> I wanted to know if there is a simple way of getting the invers
If you want something other than an arrow (or an arrow that looks
different from those produced by the arrows function) then look at the
my.symbols function in the TeachingDemos package.
On Mon, Jul 9, 2012 at 9:37 PM, Manish Gupta wrote:
> Hi,
> I am working on stacked bar plot and want to add m
You can use the locator function to retrieve the user coordinates of a
point that you click on in the plot, then use those points with
rasterImage to add the image. So replace the last 2 lines of
Michael's answer with something like:
> barplot(VADeaths, border = "dark blue")
> tmp <- locator(1)
>
You could read the .png (or some other formats) in then use the
rasterImage function to put that into the current plot.
On Mon, Jul 9, 2012 at 8:25 PM, Jie Tang wrote:
> hi R-users
>Now I have a figure in emf or png or tiff format that have been drawn
> by other tool and I want to insert thi
Try the following:
library(TeachingDemos)
?TkPredict
fit.glm1 <- glm( Species=='virginica' ~ Sepal.Width+Sepal.Length,
data=iris, family=binomial)
TkPredict(fit.glm1)
(you may need to install the TeachingDemos package first if you don't
already have it installed)
You
Look at the Predict.Plot and TkPredict functions in the TeachingDemos
package. These will not plot all 11 dimensions at once, but will plot
2 of the dimensions conditioned on the others. You can then change
the conditioning to see relationships.
These use base rather than ggplot graphics.
On Th
A simple approach is to generate correlated normal data (mvrnorm
function in MASS package is one way), then use a cut-off to convert
them to binary.
On Wed, Jul 4, 2012 at 12:25 PM, Soyeon Kim wrote:
> Hi.
> I am trying to generate a correlated binary data set.
> I've tried to use mvtBinaryEP, bi
As has been mentioned, the windows GUI will not do this for you, but
here are some options.
You can save or copy the transcript file and load it into an R syntax
aware editor (e.g. emacs with ess and others) which will do the
coloring/formatting for you and may be able to print with the
coloring.
Instead of a loop you can use the replicate or lapply functions which
will create lists for you.
otherwise you can start with an empty list (mylist <- list() )
then add to the list in each iteration of the loop:
for(i in 1:10) {
mylist[[i]] <- myfunction(i)
}
On Sat, Jun 30, 2012 at 1:34
Here are examples of a histogram and a boxplot using rasterImage to
make the background:
bg <- matrix( c('#ff','#ff','#ff'), ncol=1 )
tmp <- hist(iris$Sepal.Width)
xylim <- par('usr')
rasterImage(bg, xylim[1], xylim[3], xylim[2], xylim[4])
plot(tmp, add=TRUE, lwd=3)
plot( Petal.Le
Look at the replicate function, it takes an expression (does not need
a function) and runs that expression the specified number of times.
Will that accomplish what you want without needing to worry about
substitute, quote, eval, etc.?
On Fri, Jun 29, 2012 at 11:36 AM, Jochen Voß wrote:
> [ please
In the R gui for windows you can turn off buffering with cntrl-w or
through one of the menus, but for more general solutions you should
look at:
?flush.console
?winProgressBar or ?tcltk::tkProgressBar or ?txtProgressBar
On Fri, Jun 29, 2012 at 1:01 AM, Spencer Graves
wrote:
> Hello, All:
>
>
>
Try: survfit(Surv(Time, 1-Status)~1)
On Wed, Jun 27, 2012 at 5:37 AM, niloo javan wrote:
>
>
> Hello
>
> In (survfit(Surv(Time,Status)~1))
>
> I want to have status=0 as Failure and status=1 as Censore.
>
> Changing above formula to (survfit(Surv(Time,Status)~0)) doesnot help!!
> What should i do
Here are 2 approaches:
Use logspline density estimates (logspline package) rather than kernel
density estimates, this can give you a function to pass to integrate
or other tools, the estimates may be a little different from the
kernel density estimates.
If you need to use kernel density estimates
You can use the 'my.symbols' and 'ms.arrows' functions in the
TeachingDemos package to plot arrows at given locations with specified
angles, lengths, and colors.
On Sat, Jun 16, 2012 at 5:16 AM, zoeita wrote:
> Hi,
>
> I have had a look around the forums and I can't seem to find anything that
> w
Or use 'fixed=TRUE' as an argument to grepl to avoid the regular
expression matching (but learning regular expressions will be a useful
tool in the long run).
On Tue, Jun 12, 2012 at 9:15 AM, Jeff Newmiller
wrote:
> ?grepl
>
> Note that this function uses regular expressions, in which certain cha
If you insert `\n` between each letter, then it should do what you
want with a single call to text or mtext. To expand on David's
example:
plot(1:10)
text(5,5, paste( strsplit(txvec, ''), collapse='\n') )
On Tue, Jun 12, 2012 at 10:16 AM, David Winsemius
wrote:
>
> On Jun 12, 2012, at 9:49 AM
Wow, even those of us who have been using S for more than 25 years
(and R since well before version 1.0) still have things to learn since
R keeps improving. So I stand corrected (well sit actually) on the
part about not keeping track of this sort of thing.
On Thu, Jun 7, 2012 at 3:04 AM, Duncan M
I think the problem is with fonts and encodings. The pdf device is
using a different font and/or encoding than the screen device and so
the non-ascii characters are looking different. If you can convince
the pdf driver to use the same font and encoding then the
symbols/characters in the plot shou
You can use the debug, fix, or edit functions to insert break points
into the version of the function in memory without needing to edit the
original source code.
On Tue, Jun 5, 2012 at 5:51 PM, Michael wrote:
> Thanks so much for your help!
>
> I'd like but however I couldn't provide the code sin
There are several ways that a function can come into being within R,
it can be sourced from a file like in your case, but it could also be
typed in by hand at the command prompt, or created by another
function, etc. So R does not in general keep links to the files from
which the file was generated
Well that answers the question as answer. So while you are working
within the system to get your company to change the policy you can use
rasterImage to add a gradient background to the plot, then use points
or lines or other functions to put the parts of interest back on top
of the gradient (if i
One thing to note is that there are more than one model that can be
called exponential. Two of the common ones are:
y = exp( a + b*x + error )
y = exp( a + b*x ) + error
The common way to fit the first is to take the log of both sides and
just fit a linear model with log(y), I expect (but am not
You could use the 'nls' function to fit a sine (or cosine) function to
the data.
On Fri, Jun 1, 2012 at 7:54 PM, Aaron Patterson
wrote:
> Hello! I'm collecting data on a refrigerator that I'm using to cure
> meat. Specifically I am collection humidity and temperature readings.
> The temperature
The short answer is "yes".
The question as answer is "what is wrong with your data that you feel
the need to hide/distort information and distract from the story of
the data?".
The hopefully thought provoking answer is "fortune(197)".
The answer to the question not asked that should have been is
What do you mean by prints? You can use capture.output to get what
would regularly be printed to the screen into a text vector, or use
dput to get a version of an object that could be read back into
another R session.
On Thu, May 31, 2012 at 2:10 PM, ivo welch wrote:
> dear R experts---is there
Are the x variables all the same? if so, you can give lm a matrix as
the y variable and it will compute all the different regressions for
each column in the y matrix. The summary function will then return a
list with the summary information for each of the regressions.
If the x variables are not
Did you look at the help page that Uwe directed you to? At least one
of the examples on that page demonstrates adding text to a barplot.
But before you do that you should read through the discussion here:
http://tolstoy.newcastle.edu.au/R/e2/help/07/08/22858.html on why you
might not want to add t
?do.call
On Thu, May 24, 2012 at 9:32 AM, Alexander Shenkin wrote:
> Hello Folks,
>
> Is there any way to pass a list into a function such that the function
> will use the list as its arguments? I haven't been able to figure that out.
>
> The background: I'm trying to build a function that will
The "do.call" function may be what you want, but it is not completely
clear. If that does not solve your problem then try giving us an
example of what your list looks like (the dput function can help) and
what you want your end result to look like.
On Thu, May 24, 2012 at 5:38 AM, Hans Thompson
I believe that what is happening is that when you try to edit the
entry widget any intermediate values get sent to the slider widget
which then checks to see if they are in the allowable range and if it
is not then it sets the value to either the minimum and maximum and
sends that back to the entry
This depends on what you mean by "distance between the 2 countries".
Do you want the shortest distance from a point on the border of each country?
The distance from the one capitol to the other?
Distance between centroids?
Weighted distance based on population distributions?
Etc.
Do you want grea
The tkexamp function in the TeachingDemos package can be used to
create a tcltk based GUI for your own functions.
On Fri, May 18, 2012 at 5:45 PM, Noah Silverman wrote:
> Hello,
>
> I need to design a fairly simple front-end for someone to use an R script
> system that I've built. My thought wa
There are a couple of options.
First if you want the mean to equal 7, then that means the sum must
equal 21 and therefore you can let optim only play with 2 of the
variables, then set the 3rd to be 21-s1-s2.
If you want the mean to be greater than 7 then just put in a test, if
the mean is less th
?contr.sum
On Fri, May 11, 2012 at 8:13 AM, Rosario Garcia Gil
wrote:
> Hello
>
> It is possible to set up an lm() model where none of the categories of the
> categorical independent variable need to be used as references, I mean use
> the total mean instead.
>
> Thanks
> /R
> _
The phrase "doesn't work" does not do much to help us help you, see:
https://stat.ethz.ch/pipermail/r-help/2012-April/311074.html
Also if you don't tell us what you have tried (and how the results
differed from what you want) then we have no way of knowing if you
have already tried our first sugge
A couple of things that I did not see mentioned by the others:
Generally statistics plots work better in .png files than in .jpg
files due to the type of compression each uses (detailed image plots
and some surface plots may be the exception), though that may be out
of your control (some journals
t 2:52 PM, Greg Snow <538...@gmail.com> wrote:
>> Jeff, there are also many times that people are told not to post HTML,
>> so this case would be a bit of a Catch 22. Also some of us (well me
>> at least, I expect others have as well) have experienced this already
>> a
Jeff, there are also many times that people are told not to post HTML,
so this case would be a bit of a Catch 22. Also some of us (well me
at least, I expect others have as well) have experienced this already
and fully understand what is being discussed without needing an
example (and for this cas
ferent from 1.0, right?
>
> If I may ask one more question: could I use the offset to test if the slope
> of 0.56 is different from yet another value, e.g., 0.5?
>
> Much appreciated.
>
> Many thanks, Mark Na
>
>
>
>
>
> On Wed, Apr 25, 2012 at 3:27 PM, Greg Snow <538
Look at the 'addtable2plot' function in the 'plotrix' package or the
'textplot' function in the 'gplots' package.
On Thu, Apr 26, 2012 at 7:26 AM, statquant2 wrote:
> Hello,
> I would like to be able to plot an array on a plot, something like:
> |arg1 | arg2 | arg3
> val1| 0.9 | 1.1
mistakes of others (or others to learn from
my mistakes).
On Wed, Apr 25, 2012 at 5:31 PM, David Winsemius wrote:
>
> On Apr 25, 2012, at 6:02 PM, Greg Snow wrote:
>
>> I believe that fortune(312) applies here. As my current version of
>> fortunes does not show this I am gu
Sorry I took so long getting back to this, but the paying job needs to
take priority.
The regular expression "(? wrote:
> Hi Greg,
>
> This is quite helpful. Not so good yet with regular expressions in general or
> Perl-like regular expressions. Found the help page though, and think I was
> able
The phrase "does not work" is not very helpful, it can mean quit a few
things including:
* Your computer exploded.
* No explosion, but smoke is pouring out the back and microsoft's
"NoSmoke" utility is not compatible with your power supply.
* The computer stopped working.
* The computer sits aroun
You could also use the grconvertX function to convert from the middle
of the plotting region (from='npc') to user coordinates (to='user'),
or many other combinations.
On Wed, Apr 25, 2012 at 5:53 AM, Ramon Ovelar wrote:
> Many many thanks for the tip and for authoring this function!
>
> The final
is a magical shortcut and like
any other magic if used
incorrectly is likely to do the programmatic equivalent of turning
yourself into a toad.
—Greg Snow (in response to a user that wanted to access a column whose name is
stored in y via x$y rather than x[[y]])
R-help (February 2012)
On Tue, Apr 24
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