[R] rdcomclient issue - member not found when using borders

uot;") Cell2<-paste(letters[grep(substring(Cell,1,1),letters)+1], as.integer(substring(Cell,2))+nrow(Data),sep="") MyCell=paste(Cell1,":",Cell2,sep="") B3R[["Formula"]] <- paste("=sum(",MyCell,")",sep="")

[R] Obtaining name of data frame used in a function argument

I'm writing a function that can take a data.frame as an argument. I'd like to be able to obtain the name of the data.frame and print it out within the function. My current function looks like this: examineIt<-function(x) { print(nrow(x)) print(x[ceiling(runif(10)*nrow(x)),]) print(summary(x)

Re: [R] generating multiple sequences in subsets of data

ius [mailto:dwinsem...@comcast.net] Sent: Thursday, August 27, 2009 12:48 PM To: Jason Baucom Cc: Henrique Dallazuanna; r-help@r-project.org; Steven Few Subject: Re: [R] generating multiple sequences in subsets of data On Aug 27, 2009, at 11:58 AM, Jason Baucom wrote: > I got this to work. T

Re: [R] generating multiple sequences in subsets of data

iteria. I'm surprised it's bringing my computer to its knees. I'm running about 1M rows now, but doing other operations such as merges or adding new columns/rows seems fine. -Original Message- From: David Winsemius [mailto:dwinsem...@comcast.net] Sent: Thursday, August 2

Re: [R] generating multiple sequences in subsets of data

9 32313 FALSE1 1042414 FALSE2 Jason From: Henrique Dallazuanna [mailto:www...@gmail.com] Sent: Thursday, August 27, 2009 11:02 AM To: Jason Baucom Cc: r-help@r-project.org; Steven Few Subject: Re: [R] gener

Re: [R] generating multiple sequences in subsets of data

reaches 3. This way we can have two unique sequences for each row2, assuming of course the threshold is reached. Jason From: Henrique Dallazuanna [mailto:www...@gmail.com] Sent: Thursday, August 27, 2009 11:02 AM To: Jason Baucom Cc: r-help@r-project.org; Steven

[R] generating multiple sequences in subsets of data

ike row3<-sequence(nrow(unique(stuff$row2))) that actually works :-) Here is the for loop that functions properly for row3: stuff$row3<-c(1) for (i in 2:nrow(stuff)) { if ( stuff$row2[i] == stuff$row2[i-1]) { stuff$row3[i] = stuff$row3[i-1]+1}} Thanks! Jason Baucom Ateb, Inc. 919