[R] Sorting rows of a matrix independent of each other

Oh, this seemed so simple (and I'm sure the answer will be, as usual, so thanks in advance for enlightening me). I need to sort each row of a matrix independent of the others. For example, test - matrix(c(8,7,1,2,6,5,9,4,3),nrow=3) test [,1] [,2] [,3] [1,]829 [2,]76

Re: [R] Sorting rows of a matrix independent of each other

Got the answer: t(apply(test,1,sort)) I had played with the apply fn at one point, but noticed the results were not quite right. Wrapping it in t was the trick! Thanks! Now to use the nicely sorted rows in my real problem at hand... Cheers, Kev- -- View this message in context:

[R] Combining 2 arrays into a third array via a function

I'm completely stumped and seem to be going around for 2 days in the wrong circles. Here's what I have in 2 dataframes: dim(params.data); head(params.data, n=2) [1] 284 6 itema1a2 b1 b2 c 11 0.6671587 0.9588642 -3.5 -3.437961 0.2 22 1.1296298 1.4899307 -3.5