Re: [R] R2HTML giving NULL in output

2011-10-24 Thread L.A.
Just discovered It doesn't do this when run in the latest release Rcmdr, yet still does in JGR, RKward and R-Gui. Confusing. Thanks, L.A. -- View this message in context: http://r.789695.n4.nabble.com/R2HTML-giving-NULL-in-output-tp2309776p3934410.html Sent from the R help mailing list

Re: [R] R2HTML giving NULL in output

2011-10-19 Thread L.A.
Hey Guys, I'm having this same problem! I have searched and can't find anything. I'm guessing that it must be simple as nobody replied here, but I'm at a loss, Any help? L.A. R-2.13.2 XP 3 Ubuntu 11.10 -- View this message in context: http://r.789695.n4.nabble.com/R2HTML-giving-NULL

Re: [R] R2HTML giving NULL in output

2011-10-19 Thread L.A.
Thanks for the reply. Here is a sample. library(R2HTML) HTMLStart(outdir=Output, file=R2report, extension=html, echo=FALSE, HTMLframe=TRUE) HTML.title(Test Report 2011, HR=1) HTML.title(Test-Title:br Classification, HR=3) HTMLhr() HTMLStop() -- View this message in context:

[R] cbind or ?

2010-01-15 Thread L.A.
37255.72 117055.50 149314.00 196207.00 259288.60 Any suggestions? Thanks, L.A. Don't know if this helps: str(PARCELS) 'by' int [1:3(1d)] 9053 578 52 - attr(*, dimnames)=List of 1 ..$ Property: chr [1:3] UNSOLD SOLD SubSale - attr(*, call)= language by.default(data = ResImp[, ACCOUNTNO

Re: [R] R2HTML Report number format, or Better Way?

2010-01-04 Thread L.A.
29.69 I just want to format the R2HTML output to produce this: R outputParsalMC 9683 578 0.95 29.69 Thanks again to everyone. L.A. -- View this message in context: http://n4.nabble.com/R2HTML-Report-number-format-or-Better-Way-tp997787p998348.html Sent from the R help mailing

[R] R2HTML Report number format, or Better Way?

2010-01-03 Thread L.A.
this type of report? Thanks, L.A. R version 2.10.0 XP srtype-cbind(Par,Sal,Median,COD,PRD,LowerCI,UpperCI) srtype Par SalMedian COD PRD LowerCI UpperCI RES I 9683 578 0.9533 29.69 1.191 0.9382 0.9582 RES V4003 155 0.9763 16.51

Re: [R] R2HTML Report number format, or Better Way?

2010-01-03 Thread L.A.
? The actual data is 17000 rows and 31 columns. L.A. Par-by(Dataset[ , ACCOUNTNO], Dataset[TYPE], length) Sal-by(Dataset[ , ratio], Dataset[TYPE], length) PRD-with(Dataset, by(Dataset[ , prdb], TYPE, max)) COD-with(Dataset, by(Dataset[ , coda], TYPE, max)) LowerCI-with(Dataset, by(Dataset[ , LLCI

[R] NA or work around ??

2009-12-30 Thread L.A.
I've searched and tried several ideas (na.action. and other things), but I can't see to figure this out. I'm guessing this is so simple I'll feel foolish for asking, but here goes. Thanks, L.A. Dataset$Rcil=with(Dataset, ifelse(Rpr = .95, Dataset[,percentchgn], NA)) Dataset$LLCI-with(Dataset

Re: [R] An unprofessional message

2009-12-24 Thread L.A.
Well, a beginner just learning here, so ToYou-MERRY CHRISTMAS print(ToYou) L.A. -- View this message in context: http://n4.nabble.com/An-unprofessional-message-tp978419p978670.html Sent from the R help mailing list archive at Nabble.com

Re: [R] by function ??

2009-12-22 Thread L.A.
Thanks, but that produces what I think is an estimated interval. I really want to use the above formula. I just can't figure out how to get it to run by the LEAID. It does require 9 observations to produce an interval, but I was showing a sample. Thanks again. L.A. Matthew Dowle-3 wrote

Re: [R] by function ??

2009-12-21 Thread L.A.
(prb) Confidence=min(con) o= n -( c - 1) ch=ifelse (q = o , Dataset[,Ratio], 0) UpperCI=round(max(ch),digits=2) UpperCI I hope your not growing tired of my questions, I try reading all I can find, but I often can't seem understand it until I can actually see it in process. Thanks, L.A. -- View

Re: [R] by function ??

2009-12-12 Thread L.A.
. 6 8300 0.830 .0600 Thanks, L.A. Ista Zahn wrote: Hi, I think you want by(TestData[ , RATIO], LEAID, median) -Ista On Tue, Dec 8, 2009 at 8:36 PM, L.A. ro...@millect.com wrote: I'm just learning and this is probably very simple, but I'm stuck.   I'm trying

[R] by function ??

2009-12-08 Thread L.A.
I'm just learning and this is probably very simple, but I'm stuck. I'm trying to understand the by(). This works. by(TestData, LEAID, summary) But, This doesn't. by(TestData, LEAID, median(RATIO)) ERROR: could not find function FUN HELP! Thanks, LA -- View this message in context: