t;))
>> > return(px)
>> > }
>>
>> > and get nice results in the usual raw=FALSE case as well. Similar
>> stuff
>> > could be done in the multivariate cases.
>>
>> I don't have too much time for that now,
>> and I know that Bill
is:
> poly(x, degree = 2, raw=TRUE)
1 2
[1,] NA NA
[2,] 1 1
[3,] 2 4
[4,] 3 9
[5,] 4 16
[6,] 5 25
[7,] 6 36
[8,] 7 49
[9,] 8 64
[10,] 9 81
[11,] 10 100
attr(,"degree")
[1] 1 2
attr(,"class")
[1] "poly" "matrix"
Regards,
Liviu
>
> Bill Du
Dear all,
I'm a bit surprised by this behavior in poly:
x <- c(NA, 1:10)
poly(x, degree = 2, raw=TRUE)
## Error in poly(x, degree = 2, raw = TRUE) :
## missing values are not allowed in 'poly'
x^2
## [1] NA 1 4 9 16 25 36 49 64 81 100
As you can see, poly() will fail if the vector contains
On Sat, Feb 8, 2014 at 4:41 AM, Patrick Connolly
p_conno...@slingshot.co.nz wrote:
| Dear Don and Bert,
| Allow me to address some of your concerns below.
Which you do very clearly by positioning your responses underneath
what you're commenting on. That doesn't seem to be possible on SE.
In
Dear all,
On Sun, Feb 2, 2014 at 10:49 PM, Liviu Andronic landronim...@gmail.com wrote:
It seems that StackOverflow is officially proposing user-generated
content for download/mirroring:
http://blog.stackoverflow.com/2014/01/stack-exchange-cc-data-now-hosted-by-the-internet-archive/?cb=1
in comparison.
Kind regards,
Liviu
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 2/2/14 1:49 PM, Liviu Andronic landronim...@gmail.com wrote:
Dear Duncan,
I discovered something interesting wrt
, WA 98504-7600
Parcels:300 Desmond Drive, Lacey, WA 98503-1274
On Tue, 4 Feb 2014, Liviu Andronic wrote:
Dear Don and Bert,
Allow me to address some of your concerns below.
On Mon, Feb 3, 2014 at 9:56 PM, Bert Gunter gunter.ber...@gene.com
wrote:
I find SO's voting
Dear Duncan,
I discovered something interesting wrt to the licensing and mirroring
of user-contributed material on StackExchange. Please read below.
On Sun, Nov 24, 2013 at 9:00 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
I'm not aware of a discussion on this, but I would say no.
== 'agree'
-tgs
On Mon, Nov 25, 2013 at 4:24 AM, Liviu Andronic landronim...@gmail.com
wrote:
Dear all,
I am trying to convert the following data frame into a format more
useful for me:
library(HSAUR2, lib.loc=C:/Program Files/R/R-3.0.2/library)
Loading required package: tools
Dear all,
I am trying to convert the following data frame into a format more
useful for me:
library(HSAUR2, lib.loc=C:/Program Files/R/R-3.0.2/library)
Loading required package: tools
Attaching package: ‘HSAUR2’
The following object is masked _by_ ‘.GlobalEnv’:
womensrole
Dear Spencer,
In case you have similar questions you may want to ask them on
r-sig-teaching, which deals specifically with such topics.
Regards,
Liviu
On Sun, Nov 17, 2013 at 3:19 AM, Spencer Graves
spencer.gra...@prodsyse.com wrote:
Hello, All:
Would anyone recommend R for an
Dear all,
I know that reproducibility is a big concern for the R community, so
it may be interesting to some of the readers on this list that The
Economist recently ran a series of articles denouncing the alarming
number of shoddy and non-reproducible published papers:
Dear all,
Could someone please point me to the definitive list of valid
characters that are allowed in object names in R? I believe that the
following list covers them:
_.abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789
but I would like to make sure.
Thank you,
Liviu
--
Do you
On Sat, Jul 27, 2013 at 3:08 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
Your question is a little ambiguous. All characters are allowed in object
names, but the parser will only recognize some of them if they are quoted in
backticks.
The ones it recognizes without the backticks are
Dear all,
How can I obtain the union of a list of logical values?
Consider the following:
x - head(iris)
x[,c(2,4)] - NA
x[c(2,4),] - NA
# x
# Sepal.Length Sepal.Width Petal.Length Petal.Width Species
# 1 5.1 NA 1.4 NA setosa
# 2 NA NA
On Mon, Jul 22, 2013 at 11:37 AM, Prof Brian Ripley
rip...@stats.ox.ac.uk wrote:
This really only makes sense for a list of logical vectors of the same
length. And by 'union' you seem to mean 'or'.
Indeed.
Two approaches
1) Make a logical matrix and use apply(m, 1, any)
Of course! I
Andronic
Sent: Thursday, June 06, 2013 8:00 AM
To: r-help@r-project.org Help
Subject: Re: [R] generate simple function with pre-defined constants
On Thu, Jun 6, 2013 at 4:48 PM, Liviu Andronic landronim...@gmail.com
wrote:
Dear all,
Given:
a - 2
b - 3
I'd like to obtain
Dear all,
Given:
a - 2
b - 3
I'd like to obtain the following function:
f - function(x) 2 + 3*x
but when I do this:
f - function(x) a + b*x
##f
##function(x) a + b*x
the 'a' and 'b' objects do not get evaluated to their constants. How
could I do that?
Thanks,
Liviu
--
Do you know how to
On Thu, Jun 6, 2013 at 4:48 PM, Liviu Andronic landronim...@gmail.com wrote:
Dear all,
Given:
a - 2
b - 3
I'd like to obtain the following function:
f - function(x) 2 + 3*x
but when I do this:
f - function(x) a + b*x
##f
##function(x) a + b*x
the 'a' and 'b' objects do not get
other attached packages:
[1] arrayhelpers_0.76-20120816 abind_1.4-0
[3] plyr_1.8 stringr_0.6.2
[5] reshape2_1.2.2
loaded via a namespace (and not attached):
[1] tools_3.0.0
- Original Message -
From: Liviu Andronic landronim...@gmail.com
To: r-help@r-project.org Help
On Thu, May 30, 2013 at 2:40 PM, Johnny Zhang johnny...@yahoo.com wrote:
I'd be very happy to change its name and welcome any input on another name.
Zhiyong
collect_rstats or RCollectStats or a variation thereof would do just fine.
My 2 cents,
Liviu
Hello,
I'm using ddply() in plyr and I notice that it has the habit of
re-ordering the levels of the '.variables' by which the splitting is
done. I'm concerned about correctly retrieving the original ordering.
Consider:
require(plyr)
x - iris[ order(iris$Species, decreasing=T), ]
head(x)
#
Dear all,
I encountered this strange behaviour with loops and lists. Consider this:
xl - list()
for(i in 5:7){##loop over numeric vector
xl[[i]] - rnorm(i)
}
xl
[[1]]
NULL
[[2]]
[1] -0.4448192 -1.3395014
[[3]]
[1] 1.3214195 -1.2968560 -0.6327795
The above lists contained a NULL element
On Sun, May 19, 2013 at 7:02 PM, peter dalgaard pda...@gmail.com wrote:
(The first example really had 2:3, not 5:7, right?)
Indeed. I simplified the example mid-email.
The essential bit is that to assign to the 2nd element of a list, it needs to
have at least two elements:
Thanks for the
(moving to r-help)
Dear all,
I think Paul is raising a useful question here: What is the
recommended workflow for creating a new function?
R prides itself for letting users to create and use home-brewed
functions: it's easy to maintain and re-use, doesn't clutter the
global environment with
On Wed, Apr 24, 2013 at 9:23 PM, Santosh santosh2...@gmail.com wrote:
Dear Rxperts,
Sorry if I am posting a really really dumb request.. I am new to subversion
and am trying to use subversion to download the tables package as suggested
by Duncan. I installed subversion client(from collabnet)
Dear Duncan,
On Wed, Apr 24, 2013 at 11:04 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
What I've done sometimes in debugging is to change that error to a
warning in the getNamespace() function, and add some tracing code to the
serialization code to print the names of objects as they
Dear all,
I am unable to understand how Hline() works in tabular(). I've read
the vignette and the help page, and here this example compiles
perfectly fine:
latex( tabular( Species + Hline() + 1
~ Heading()*mean*All(iris), data=iris) )
However, if I try it on my own data it fails.
Dear all,
I've bumped into the: Error in loadNamespace(name) : there is no
package called ‘R.utils’ error. I've already read a bit on this (
http://www.cybaea.net/Blogs/Data/A-warning-on-the-R-save-format.html )
but I have a follow-up question.
Given a workspace that automatically loads a package
Dear Duncan,
On Wed, Apr 24, 2013 at 4:57 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
What I've done sometimes in debugging is to change that error to a warning
in the getNamespace() function, and add some tracing code to the
serialization code to print the names of objects as they are
Dear Duncan,
On Wed, Apr 24, 2013 at 3:03 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
A better approach is to *never* save and load workspaces unless you know
exactly what is in them. Always reply no to the question about saving
your workspace (or set that as the default). If you
Dear David,
I'm having the exact same issue as Santosh, and looking at the fix
that you've provided it seems to me that results are slightly
different.
On Tue, Apr 23, 2013 at 4:40 AM, David Winsemius dwinsem...@comcast.net wrote:
b c
p a N mean sdmean sd
A
Dear David,
I'm once again facing the same issue as Santosh.
On Sat, Apr 20, 2013 at 12:15 AM, David Winsemius
dwinsem...@comcast.net wrote:
On Apr 19, 2013, at 2:03 PM, Santosh wrote:
Rounding was done to replicate the problem I faced in the original data
set...
I got an error every
On Tue, Apr 23, 2013 at 10:06 AM, David Winsemius
dwinsem...@comcast.net wrote:
On Apr 23, 2013, at 1:00 AM, David Winsemius wrote:
On Apr 23, 2013, at 12:53 AM, Liviu Andronic wrote:
Dear David,
I'm having the exact same issue as Santosh, and looking at the fix
that you've provided
Dear David,
On Tue, Apr 23, 2013 at 10:00 AM, David Winsemius
dwinsem...@comcast.net wrote:
tabular( (`p a`=interaction(a,p, drop=TRUE, sep= )) ~ (N = 1) + (b + c)*
(mean+sd),data=q)
b c
p a N mean sd mean sd
1 A 10 12.8 0.7888 52.1 8.020
3 A 10
Dear Duncan,
Thank you for your explanations.
On Tue, Apr 23, 2013 at 12:31 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
This isn't something that the package is designed to handle: if you say
p*a, it wants all combinations of p and a.
To your knowledge is there another 'complex tables'
Dear Duncan,
On Tue, Apr 23, 2013 at 2:13 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
I've done this now, in version 0.7.54 on R-forge. To leave out the rows
with N=0, you can select a subset of the table where N (the first column) is
non-zero:
tab -
...
# $ var2: num 4 3 3 3 4 4 3 3 3 3 ...
# - attr(*, label)= chr Some df label
A.K.
- Original Message -
From: arun smartpink...@yahoo.com
To: Liviu Andronic landronim...@gmail.com
Cc: R help r-help@r-project.org
Sent: Tuesday, April 16, 2013 2:40 PM
Subject: Re: [R
Dear Rui,
Thanks for the pointer.
On Tue, Apr 16, 2013 at 8:12 PM, Rui Barradas ruipbarra...@sapo.pt wrote:
setdiffDF2 - function(A, B){
f - function(X, Y)
!duplicated(rbind(Y, X))[nrow(Y) + 1:nrow(X)]
ix1 - f(A, B)
ix2 - f(B, A)
ix1 ix2
}
ix - setdiffDF2(Xe, Xf)
A.K.
- Original Message -
From: Liviu Andronic landronim...@gmail.com
To: arun smartpink...@yahoo.com
Cc: R help r-help@r-project.org
Sent: Friday, April 19, 2013 8:13 AM
Subject: Re: [R] avoid losing data.frame attributes on cbind()
Dear Arun,
On Tue, Apr 16, 2013 at 10:45
Dear all,
Consider the model below:
x - lm(mpg ~ cyl * disp * hp * drat, mtcars)
summary(x)
Call:
lm(formula = mpg ~ cyl * disp * hp * drat, data = mtcars)
Residuals:
Min 1Q Median 3Q Max
-3.5725 -0.6603 0.0108 1.1017 2.6956
Coefficients:
Estimate
On Wed, Apr 17, 2013 at 2:33 PM, Marc Schwartz marc_schwa...@me.com wrote:
If you only want up to say second order interactions:
summary(lm(mpg ~ (cyl + disp + hp + drat) ^ 2, data = mtcars))
This is what I was looking for. Thank you so much.
This is covered in ?formula
Indeed. I tried to
Dear all,
What is the quickest and most efficient way to diff two data frames,
so as to obtain a vector of indices (or logical) for rows/columns that
differ in the two data frames? For example,
Xe - head(mtcars)
Xf - head(mtcars)
Xf[2:4,3:5] - 55
all.equal(Xe, Xf)
[1] Component 3: Mean
Dear all,
How should I add several variables to a data frame without losing the
attributes of the df? Consider the following:
require(Hmisc)
Xa - iris
label(Xa, self=T) - Some df label
str(Xa)
'data.frame': 150 obs. of 5 variables:
$ Sepal.Length: num 5.1 4.9 4.7 4.6 5 5.4 4.6 5 4.4 4.9
Dear all,
Given the following vector:
(z - c('R project', 'hello world', 'something Else'))
[1] R project hello worldsomething Else
I know how to obtain all capitals or all lower case letters:
tolower(z)
[1] r project hello worldsomething else
toupper(z)
[1] R PROJECT
Something Else NANA
Any pointers how to work around that? Thanks,
Liviu
Henrik
On Apr 14, 2013 11:51 PM, Liviu Andronic landronim...@gmail.com wrote:
Dear all,
Given the following vector:
(z - c('R project', 'hello world', 'something Else'))
[1] R project hello world
Something Else NANA
Liviu
Regards,
Pascal
On 04/15/2013 03:50 PM, Liviu Andronic wrote:
Dear all,
Given the following vector:
(z - c('R project', 'hello world', 'something Else'))
[1] R project hello worldsomething Else
I know how to obtain all capitals or all lower case
On Mon, Apr 15, 2013 at 10:10 AM, Gergely Daróczi gerg...@snowl.net wrote:
Dear Liviu,
I have just updated tocamel to have a new argument, so the development
version of the package would produce:
tocamel(z, upper = TRUE, sep = ' ')
[1] R Project Hello WorldSomething Else
Thanks
On Mon, Apr 15, 2013 at 2:22 PM, Gergely Daróczi gerg...@snowl.net wrote:
I have added an extra check in the function for NA values before applying
`paste` at
https://github.com/Rapporter/rapport/compare/34ca6a35fb...a04abc8b21
Alex might not like it :)
Example:
tocamel(z, upper = TRUE,
On Thu, Apr 4, 2013 at 7:34 AM, ivo welch ivo.we...@anderson.ucla.edu wrote:
I wonder whether there is a complete list of all R commands (incl the
standard packages) somewhere, preferably each with its one-liner AND
categorization(s). the one-liner can be generated from the documentation.
Try
On Wed, Mar 13, 2013 at 1:02 AM, Santosh santosh2...@gmail.com wrote:
Dear Rxperts,
I am aware of Sweave that generates reports into a pdf, but do know of any
tools to generate to export to a MS Word document...
Is there a way to use R to generate and export report/publication quality
Dear all
I'd like to give RExcel a decent spin, mainly to take advantage of
Excel's data management facilities and automatic recalculations.
However I cannot use this Windows-only solution on the platform of my
choice, Linux.
Alternatively I've been considering the cross-platform ROOo, the
On Sun, Nov 25, 2012 at 2:38 PM, John Kane jrkrid...@inbox.com wrote:
Can you supply a link for ROOo ? I don't see it anywhere.
Oh, sorry. I thought it was obvious:
http://rcom.univie.ac.at/download.html#ROOo
Also what do you mean OpenOffice is deprecated?
Do you mean in terms of using it
On Fri, Nov 23, 2012 at 6:44 AM, wampeh wam...@gmail.com wrote:
How do I get gvarbrowser to display only data.frame named, say atab1 or
atab2 or atab*?
Also, how do I turn off the selection pull down box?
Two remarks. If you hope to get an answer it would be a good idea to
CC John Verzani,
On Thu, Aug 30, 2012 at 12:50 AM, Yihui Xie x...@yihui.name wrote:
Do you know what environments are allowed inside \subfloat{}? The
No, not really. From what I can tell, \subfloat{} is provided by the
`subfig' package. Here's what their docs have to say about
compatibility with verbatim and
,
Yihui
--
Yihui Xie xieyi...@gmail.com
Phone: 515-294-2465 Web: http://yihui.name
Department of Statistics, Iowa State University
2215 Snedecor Hall, Ames, IA
On Wed, Aug 29, 2012 at 3:30 PM, Liviu Andronic landronim...@gmail.com
wrote:
Hey Yihui
On Wed, Aug 29, 2012 at 6:17 PM, Yihui
On Tue, Aug 28, 2012 at 9:05 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
On 28/08/2012 2:16 PM, Liviu Andronic wrote:
I came up with a modified version of the above:
print_noattr - function(x, keep.some=T, ...){
if(keep.some) xa - attributes(x)[c('names', 'row.names', 'class
Dear all
Are LaTeX \subfloat{} commands incompatible with Sweave code? I cannot
get the following code to compile properly:
\begin{table}
\subfloat[asdfa]{=
2+2
@
}
\caption{asdf}
\end{table}
If I replace the Sweave chunk with a random string or a table, the
compilation works fine. Any ideas
On Wed, Aug 29, 2012 at 1:34 PM, Steve Lianoglou
mailinglist.honey...@gmail.com wrote:
This isn't exactly what you want, but I'm using kintr and building and
saving my figures in the their own chunks then just inlining the
path to the generated figure in the \subloat{..}. Things are working
Dear all
I was wondering what old hacks on this list were thinking about the
shiny new wind map, which The Economist describes as breathtaking
for its elegance and rich data presentation. [1]
What do you think of it? And of authors' other graphs? Can something
similar be done in R?
Regards
Hey Yihui
On Wed, Aug 29, 2012 at 6:17 PM, Yihui Xie x...@yihui.name wrote:
Yes that is one possible solution, but the filename is hard-coded
somehow. The key to this problem is a missing new line before =,
which was addressed in
https://github.com/downloads/yihui/knitr/knitr-subfloats.pdf
Dear all
Suppose the object below:
require(Hmisc)
require(plyr)
x - dlply(iris, .(Species), describe)
How can I print the object without displaying the attributes? I
inspected ?print and ?print.default with no luck.
x
$setosa
x[, Sepal.Length]
n missing uniqueMean .05 .10
On Tue, Aug 28, 2012 at 7:34 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
Assign a class to the object, and write a print method for it.
For example, this doesn't quite do what you want, but it's a start:
print.noattributes - function(x, ...) {
attributes(x) - NULL
print(x)
}
On Tue, Aug 7, 2012 at 10:26 PM, Marc Schwartz marc_schwa...@me.com wrote:
since there are alpha-numerics present, whereas the first option will:
grepl([^[:alnum:]], ab%)
[1] TRUE
So, use the first option.
And I should start reading more carefully. The above works fine for me.
I ended up
On Mon, Aug 6, 2012 at 7:35 PM, Marc Schwartz marc_schwa...@me.com wrote:
is.letter - function(x) grepl([[:alpha:]], x)
is.number - function(x) grepl([[:digit:]], x)
Quick follow-up question.
I'm always reluctant to create functions that would resemble the
method of a function (here, is() ),
Hello
On Fri, Jul 27, 2012 at 6:54 AM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
Much easier than you think:
x - c(1L, 9000L)
sprintf(%05i,x)
For anyone interested, I came up with a small wrapper for the above:
add.lead - function(x, width=max(nchar(x))){
On Mon, Aug 6, 2012 at 5:27 PM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
On Mon, Aug 6, 2012 at 9:53 AM, Liviu Andronic landronim...@gmail.com wrote:
On Mon, Aug 6, 2012 at 4:48 PM, Liviu Andronic landronim...@gmail.com
wrote:
string, something that I find strange. At best NA
On Mon, Aug 6, 2012 at 7:35 PM, Marc Schwartz marc_schwa...@me.com wrote:
is.letter - function(x) grepl([[:alpha:]], x)
is.number - function(x) grepl([[:digit:]], x)
Another follow-up. To test for (non-)alphanumeric one would do the following:
x - c(letters, 1:26, '+', '-', '%^')
x[1:10] -
On Tue, Aug 7, 2012 at 10:18 PM, Marc Schwartz marc_schwa...@me.com wrote:
That will get you values where punctuation characters are used, but there may
be other non-alphanumeric characters in the vector. There may be ASCII
control codes, tabs, newlines, CR, LF, spaces, etc. which would not
On Tue, Aug 7, 2012 at 10:48 PM, David Winsemius dwinsem...@comcast.net wrote:
On Aug 7, 2012, at 3:55 AM, Liviu Andronic wrote:
For anyone interested, I came up with a small wrapper for the above:
add.lead - function(x, width=max(nchar(x))){
sprintf(paste('%0', width, 'i', sep=''), x
Dear all
I'm a bit surprised by the results output from nzchar(). The help page
says: nzchar is a fast way to find out if elements of a character
vector are *non-empty strings*. (my emphasis. However, if you do
x - c(letters, NA, '')
nzchar(x)
[1] TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE
On Mon, Aug 6, 2012 at 4:48 PM, Liviu Andronic landronim...@gmail.com wrote:
string, something that I find strange. At best NA is the equivalent of
an empty string. In this sense, if you Hmisc::describe() the vector
you get, as I would expect, that in the context of character vectors
NA
Dear all
I'm pretty sure that I'm approaching the problem in a wrong way.
Suppose the following character vector:
(x[1:10] - paste(x[1:10], sample(1:10, 10), sep=''))
[1] a10 b7 c2 d3 e6 f1 g5 h8 i9 j4
x
[1] a10 b7 c2 d3 e6 f1 g5 h8 i9 j4 k
l m n
[15] o p q r s t
TRUE TRUE TRUE TRUE TRUE TRUE
TRUE TRUE TRUE TRUE
[52] TRUE
I need to have TRUE when an element contains a letter, and FALSE when
an element contains only numbers. The above returns TRUE for the
entire vector.
Regards
Liviu
On Mon, Aug 6, 2012 at 9:25 AM, Liviu Andronic landronim...@gmail.com
On Mon, Aug 6, 2012 at 7:35 PM, Marc Schwartz marc_schwa...@me.com wrote:
is.letter - function(x) grepl([[:alpha:]], x)
is.number - function(x) grepl([[:digit:]], x)
This does exactly what I wanted:
x
[1] a10 b8 c9 d2 e3 f4 g1 h7 i6 j5 k
l m n
[15] o p q r s t u v
On Mon, Jul 30, 2012 at 6:00 PM, jim holtman jholt...@gmail.com wrote:
try this:
(x - rep(letters,2))
[1] a b c d e f g h i j k l m n o p
q r s t u v w
[24] x y z a b c d e f g h i j k l m
n o p q r s t
[47] u v w x y z
values - c(aa, a, b, NA, d, zz)
repl - c(aa, A, B, NA, D, zz)
Dear all
I've got stuck when trying to replace values in a vector by selecting
replacements from a replacement table. I'm trying to use only base
functions. Here's a dummy example:
(x - rep(letters,2))
[1] a b c d e f g h i j k l m n o p
q r s t u v
[23] w x y z a b c d e f g h i j k l
m n o p q
On Mon, Jul 30, 2012 at 6:00 PM, jim holtman jholt...@gmail.com wrote:
try this:
indx - match(x, repl.tab[, 1], nomatch = 0)
x[indx != 0] - repl.tab[indx, 2]
x
[1] A B c D e f g h i j k l m n o p
q r s t u v w
[24] x y z A B c D e f g h i j k l m
n o p q r s t
[47] u v w x y z
This is
On Wed, Jul 18, 2012 at 12:30 AM, Kjetil Halvorsen
kjetilbrinchmannhalvor...@gmail.com wrote:
Venables Ripley:
Modern Applied Statistics with S (fourth Edition)
[..]
On Sat, Jul 14, 2012 at 4:01 PM, Larry White ljw1...@gmail.com wrote:
I'm looking for a single book that provides a deep, yet
On Fri, Jul 13, 2012 at 9:25 PM, Silje Nord silje.nordg...@gmail.com wrote:
Is there a function similar to excel's hlookup in R ?
Try match(). I think it provides hlookup() functionality.
Liviu
__
R-help@r-project.org mailing list
On Tue, Jul 10, 2012 at 4:53 PM, Peter Ehlers ehl...@ucalgary.ca wrote:
Both this and Liviu's original solution destroy the
factor nature of 'Species' (which may not matter, of
course). How about
(.xb - iris[ iris$Species=='zz', ])
.xb - .xb[1, ] # this probably shouldn't work, but it
On Wed, Jul 11, 2012 at 9:56 PM, William Dunlap wdun...@tibco.com wrote:
Why does one want to replace a zero-row data.frame
with a one-row data.frame of NA's? Unless this is for
an external program that cannot handle zero-row inputs,
this suggests that there is an unnecessary limitation
Dear all
Is there a simpler method to achieve the following: When I obtain an
empty data.frame after subsetting, I need for it to contain one line
of NAs. Here's a dummy example:
(.xb - iris[ iris$Species=='zz', ])
[1] Sepal.Length Sepal.Width Petal.Length Petal.Width Species
0 rows (or
Dear all
I have a 'character' vector containing mixed formats (thanks Excel!)
and I'd like to translate it into a default %Y-%m-%d Date vector.
x - c(1/3/2005, 13/04/2004, 2/5/2005, 2/5/2005, 7/5/2007,
22/04/2004, 21/04/2005, 20080430, 13/05/2003, 20080529,
NA, NA, 19/05/1999,
On Thu, Jun 21, 2012 at 2:48 PM, Liviu Andronic landronim...@gmail.com wrote:
The culprit is likely that the 'x' vector is 'character' throughout,
but I'm not sure how to work around. For example, I couldn't figure
how to create an empty 'Date' vector. Regards
I think I managed to crack
Dear Özgür
On Wed, Jun 20, 2012 at 7:37 AM, Özgür Asar oa...@metu.edu.tr wrote:
Why do you prefer robust methods in the example of Noor and why you need
exact normality here?
The idea is that when you do hypothesis testing to check whether a
given distribution is normal, the results are
On Tue, Jun 19, 2012 at 12:42 PM, Özgür Asar oa...@metu.edu.tr wrote:
Following a straight line indicates less evidence towards non-normality. But
QQ-Plot is an exploratory tool.
You can confirm your ideas obtained from the QQ-Plot via noramlity tests
such as Shapiro-Wilk test.
Hmm, some
On Tue, May 29, 2012 at 8:30 AM, stefan23 stefan.vo...@uni-konstanz.de wrote:
He folks,
I want to use quantile regression for doing a test of symmetrie of a
distribution. Following Buchinsky I want to test, whether the square of \tau
= \beta(p)+\beta(1-p)-2*\beta(0.5) (\beta(\tau) is the
On Tue, May 22, 2012 at 9:01 AM, jiangxijixzy jiangxiji...@163.com wrote:
The function I wrote can run well with the small data, but with the large
data, the function runs very very slowly. How can I correct it? Thank you
very much. My function as below:
I guess this is a classic loops vs
On Tue, May 22, 2012 at 11:22 AM, Vincy Pyne vincy_p...@yahoo.ca wrote:
Thanks a lot for pointing out such a silly mistake from my side. I was simply
wondering how come I am not getting such a simple mean.
To avoid such mistakes it would help to first store your data in a vector.
x-c(16,18)
On Mon, May 21, 2012 at 10:29 PM, Alexander Shenkin ashen...@ufl.edu wrote:
So, I think it will be better if I can somehow generate the tables as
images. Is there any way to generate tables as images in separate files
in Sweave? Or, is there another tree up which I should be barking?
Hmm,
On Tue, May 22, 2012 at 3:24 PM, Alexander Shenkin ashen...@ufl.edu wrote:
If I understand it correctly, odfWeave doesn't have a path backwards
from the odf doc back to the original odfWeave doc (which is the main
restriction of all these Sweave/knitr/etc solutions in my use case).
Please
Dear Richard
On Tue, May 22, 2012 at 3:20 PM, Richard M. Heiberger r...@temple.edu wrote:
mydata - data.frame(
row.names=c(group1, group2, group3, group4, group5),
males=c(20,30,45,12,5),
females=c(35,23,32,8,5))
## make a pyramid Likert chart
as.pyramidLikert(likert(mydata),
, May 22, 2012 at 9:44 AM, Liviu Andronic landronim...@gmail.com
wrote:
Dear Richard
On Tue, May 22, 2012 at 3:20 PM, Richard M. Heiberger r...@temple.edu
wrote:
mydata - data.frame(
row.names=c(group1, group2, group3, group4, group5),
males=c(20,30,45,12,5),
females=c
On Sat, May 19, 2012 at 9:31 AM, peter dalgaard pda...@gmail.com wrote:
Best practice is a bit contentious, but several people have found that the
tcltk package offers a path of low resistance.
Additionally check gWidgets.
Liviu
__
On Tue, May 8, 2012 at 12:14 PM, Apoorva Gupta apoorva.ni...@gmail.com wrote:
I have checked that. It allows me to get the t-1, t-2 value but not the t+1
value.
Is there any other way of achieving this other than using the plm package?
It would be easier to help if you provided a minimal
On Mon, May 7, 2012 at 3:21 PM, Apoorva Gupta apoorva.ni...@gmail.com wrote:
Dear R users,
I am working with panel data and I want the difference of a variable with
its t+1 value.
Could you tell me if such a function exists in the plm package?
Perhaps diff() or lag(). See the plm vignette.
Dear all
I'd like to make a beeping sound in R, but alarm() doesn't beep? I
checked ?alarm but I couldn't find any pointers to system
configuration. Any ideas?
Regards
Liviu
sessionInfo()
R version 2.14.2 (2012-02-29)
Platform: x86_64-pc-linux-gnu (64-bit)
locale:
[1] LC_CTYPE=en_US.UTF-8
On Sat, May 5, 2012 at 8:34 PM, David Winsemius dwinsem...@comcast.net wrote:
Is there a command you could call with system()?
Yes. Something like:
system(play /tmp/02Canon.mp3)
works jsut fine. But I was curious about alarm().
Liviu
__
Dear Rainer
On Wed, Apr 25, 2012 at 5:34 PM, Rainer Schuermann
rainer.schuerm...@gmx.net wrote:
chunk_name_1,eval=FALSE,echo=FALSE=
I like the 'eval=FALSE' trick.
SweaveInput( setup.Rnw )
and from here, I can suse the named chunks almost like function calls, as you
you describe below.
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