I have a dataset, example of the data is shown below:
Grouped Data: drain_irr ~ irr | crop
Year decades crop irrisystem drain_irrirr
1310 1995-96 1990s Citrusvarious 0.400 9.021
1311 1995-96 1990s Citrus drip 0.541 6.468
1312 1995-96 1990s Citrus overhead
I have a dataset, example of the data is shown below:
Grouped Data: drain_irr ~ irr | crop
Year decades crop irrisystem drain_irrirr
1310 1995-96 1990s Citrusvarious 0.400 9.021
1311 1995-96 1990s Citrus drip 0.541 6.468
1312 1995-96 1990s Citrus
I have a dataset relating the effects of engineering works on the level of
salinity in a river before and after the works. I have modelled this using
linear mixed effects models to determine if the significance and level of the
response to the works. I am wanting to calculate the se of
Is there an equivalent package for mixed linear effects models developed using
the package nlme as there is for linear models?
Tschüß
Tony Meissner
Principal Scientist (Monitoring/Statistics)
Resource Monitoring
Science, Monitoring and Information Division
Department for Water
Imagine ©
*(ph)
OK, I thought I was being explicit enough, but here goes. The out of the first
five rows of mu dataframe is:
Time hour lev.morgan lev.lock2 lev.lock1 flow direction
velocity bearingvelcat
1 2009-07-06 15:00:00 15 3.266 3.274 3.240 1710.6180.28
4.352
OK, I thought I was being explicit enough, but here goes. The out of the first
five rows of mu dataframe is:
Time hour lev.morgan lev.lock2 lev.lock1 flow direction
velocity bearingvelcat
1 2009-07-06 15:00:00 15 3.266 3.274 3.240 1710.6180.28
4.352
I have a data frame (morgan) of hourly river flow, river levels and wind
direction and speed thus:
Time hour lev.morgan lev.lock2 lev.lock1 flow direction
velocity
1 2009-07-06 15:00:00 15 3.266 3.274 3.240 1710.6 180.282
4.352
2 2009-07-06 16:00:00
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From: Allan Engelhardt [mailto:all...@cybaea.com]
Sent: Thursday, 15 July 2010 3:09 PM
To: Meissner, Tony (DFW)
Cc: r-help@r-project.org
Subject: Re
I have a dataframe that contains time values in the form of -mm-dd hh:mm
i.e. 2010-07-14 13:00. When I convert this to numeric via tvec -
as.numeric(Time) I get a number that is in seconds. So far so good. When I
then divide the numeric value by the number of seconds in a day eg
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