Knut Krueger r...@krueger-family.de wrote
I think this is more an general question to GLMs.
The result was better in all prior GLMs when I admitted the non
significant factors, but this is the first time that the result is worse
than before. What could be the reason for that?
Trafim rdapam...@gmail.com wrote
well, I definitely don't understand anything.
Why the hist function with freq=FALSE gives such a strange result???
R - c(-1.10, 0.79, -1.17, -0.53, -0.26, -0.22, 0.29, -0.26, -0.26, 0.39)
hist(R, freq=FALSE, breaks=10)
The total AREA has to equal 1, which
Good afternoon
Running R2.10.0 on Windows
I have a data frame that includes (among much else) a factor (In_2006) and a
continuous variable (math_3_4). I would like to find the 2 cases for In_2006 =
0 that are closest to each case where In_2006 = 1.
My data looks like
In_2006 math_3_4
David Winsemius dwinsem...@comcast.net wrote
On Dec 2, 2009, at 3:01 PM, Peter Flom wrote:
Good afternoon
Running R2.10.0 on Windows
I have a data frame that includes (among much else) a factor
(In_2006) and a continuous variable (math_3_4). I would like to
find the 2 cases
Thanks Chuck
I did not know about that MatchIt. I will check it out
Peter
-Original Message-
From: Chuck Cleland cclel...@optonline.net
Sent: Dec 2, 2009 3:47 PM
To: Peter Flom peterflomconsult...@mindspring.com
Cc: r help r-help@r-project.org
Subject: Re: [R] Finding cases in one
Arnab Maity arnab_ma...@isb.edu wrote
I like to call R from SAS. Could you please help me?
There are two methods that I know of:
1) Phil Rack has written a program called A Bridge to R see:
http://minequest.com/WordPress/?p=102
2) If you have SAS/IML licensed, you can link to R through
Please xcuse me for being slightly off-topic and cross-posting
I have a data set of schools, with scores for 4 years. The goal is to evaluate
the effect of an intervention on the scores, accounting for some covariates
which are not problematic. The chief problem is that the intervention could
Good morning
I just got a new computer with Windows 7. R works fine, but the editor I am
used to using RWinEdt does not. I did find one blog post on how to get
RWinEdt to work in Windows 7, but I could not get those instructions to work
either.
Is there a patch for RWinEdt?
If not, is
Good morning
I am learning about NLME and LME4, using Pinheiro and Bates and other materials
from Douglas Bates, but I have not seen anything on how to do variable
selection sensibly in this type of model.
In OLS regression, I frequently use the lasso, but googling did not reveal a
method for
David Winsemius dwinsem...@comcast.net wrote
I always assumed that the intercept was zero and the slope = unity.
y - rt(200, df = 5)
qqnorm(y); qqline(y, col = 2)
qqplot(y, rt(300, df = 5))
abline(0, 1, col=red)
Suppose you have the following
x - rnorm(500)
y - 500*(x + runif(500,
carol white wht_...@yahoo.com wrote
So the conclusion is that abline(0,1) should always be used and if it doesn't
go through the qqplot, the two distributions are not similar?
I think it depends what you mean by similar. E.g., if you mean are both of
these distributions (e.g.) normal? then
John Fox j...@mcmaster.ca wrote
I assumed that Carol wanted to compare the shapes of the distributions and
to adjust for differences in centre and spread. To put a line through the
quartiles or to base a line on the medians and IQRs is more robust than
using the means and sds.
Hi John
Indeed it
Peter Ehlers ehl...@ucalgary.ca wrote
That's not what qqline() does and for good reason - it treats
x and y asymmetrically.
But qqline() is a very simple function, using the quartiles
as also suggested by John. Here's a modified version that
should work for Carol:
qqline2 - function (x, y, ...)
Fran100681 franar...@hotmail.it wrote
just a simple question
How can I do to invert the sign of a number? (for example: -4 to 4, 2 to -2
and so on..)
I was looking for a specific function in R but I didn't found it...
thank you
Is there something wrong with *-1 ?
Peter
Peter L. Flom, PhD
Ravi Varadhan rvarad...@jhmi.edu wrote
I have heard this (i.e. only head-to-head comparisons are valid) and various
other folklores about AIC and BIC based model selection before, including
one that these information criteria are only applicable for comparing two
nested models.
Where has it
Paul Smith phh...@gmail.com wrote
Is there some way of drawing a boxplot, with R, when one does not have
the original continuous data, but only the data grouped in classes?
The function boxplot() can only deal with original data.
It's not clear how the data are, now. What are the classes? Are
Frank E Harrell Jr f.harr...@vanderbilt.edu wrote
Ben Bolker wrote:
Allan.Y wrote:
Hi everyone,
I am wondering if there exists a stepwise regression function for the
Bayesian regression model. I tried googling, but I couldn't find
anything. I know step function exists for regular
Good afternoon
Using R 2.9.2 on a machine running Windows XP
I have a longitudinal data set, with data on schools and their test scores over
a four year period. I have centered year, and run the following
m1.mod1 - lme(fixed = math_1 ~ I(year-2007.5)*TFC_,
data = long,
Hello
Running R2.9.2 on Windows XP
I am puzzled by the performance of LME in situations where there are missing
data. As I understand it, one of the strengths of this sort of model is how
well it deals with missing data, yet lme requires nonmissing data.
Thus,
m1.mod1 - lme(fixed =
I wrote
I am puzzled by the performance of LME in situations where there are
missing data. As I
understand it, one of the strengths of this sort of model is how well it
deals with missing
data, yet lme requires nonmissing data.
Mark Difford replied
You are confusing missing data with
Good morning
I recently shifted to digest mode; I get the digest each day (sometimes two in
a day) and when I open the first file
it opens as a text file with a list of topics; but then it is hard to find the
right message. In a list of 100 or so links,
counting to find link number 53 or
Dieter Menne wrote:
IF TYPE='TRUCK' and count=12 THEN VEHICLES=TRUCK+((CAR+BIKE)/2.2);
vehicles - ifelse(TYPE=='TRUCK' count=12, TRUCK+((CAR+BIKE)/2.2), NA)
Read both versions to an audience, and you will have to admit that this is
one of the cases where SAS is superior.
And Peter
Carlos J. Gil Bellosta c...@datanalytics.com wrote
I had a conversation with a guy working in a business intelligence
department at a major Spanish bank. They rely on recursive partitioning
methods to rank customers according to certain criteria.
They use both SAS EM and Salford Systems' CART.
Patrick Burns pbu...@pburns.seanet.com wrote
Proposal
That a new mailing list be established
that pertains exclusively to R documentation.
The purpose of the list would be to discuss
weak sections of the documentation and
establish fixes for those weak spots.
Pro
If it works, there would be
to faxing)
Peter Flom peterflomconsult...@mindspring.com 6/14/2009 7:05 AM
Patrick Burns pbu...@pburns.seanet.com wrote
Proposal
That a new mailing list be established
that pertains exclusively to R documentation.
The purpose of the list would be to discuss
weak sections of the documentation
I certainly don't have anything against the WIKI, but I think that the
documentation
is where the action is, especially for newbies. It's the natural first step
when you want to learn about a function or when you get an error message you
don't understand.
Peter
Peter L. Flom, PhD
Well, suppose I wanted to suggest changes to some documentation, or write an
alternate help file for some function. Where would I put it?
Let's say I type, in R, ?median. Now suppose I have suggestions. If I look at
http://wiki.r-project.org/rwiki/doku.php?id=idx=rdoc:base
I don't see the
Werner Wernersen pensterfuz...@yahoo.de wrote
Hi,
I am trying to specify a multinomial logit model using the multinom function
from the nnet package. Now I add another independent variable and it halves
the AIC as given by summary(multinom()). But when I call Anova(multinom())
from the car
Lindsay Banin l.bani...@leeds.ac.uk wrote
Hi there,
I am looking to compare nonlinear mixed effects models that have different
nonlinear functions (different types of growth curve)embedded. Most of the
literature I can find focuses on comparing nested models with likelihood
ratios and AIC. Is
Christophe Genolini cgeno...@u-paris10.fr wrote
Thanks for yours answers. So if I understand:
- Trajectories are continuous, the other are discrete.
- The difference between time series and longitudinal is that time
series are made at regular time whereas longitudinal are not ?
- Repeated
Jean-Paul Kibambe Lubamba jean-paul.kiba...@uclouvain.be wrote
I have two questions:
I am computing a linear regression model with 0 as Intercept.
Well, I would like the sum of my predicted values be equal to a constant
and therefore analyze if my coefficients are significatively different
charles78 hu...@hotmail.com wrote
I have a stupid question on how to get the real p-values for wilcox.test and
correlation. the minmun can be reached is 2.2E-16 using the R version
2.6.2. I do not think it is the R version causing this but other issues.
Any help is highly appreciated.
Can I
Dieter Menne dieter.me...@menne-biomed.de wrote
Technically a good point, but I found it helpful for starters who want to
avoid the inferno of what's attached now? not to use it at all.
My suggestion is to use with() instead because it has a higher locality.
I know, many of the examples use
utkarshsinghal utkarsh.sing...@global-analytics.com wrote
Hi all,
I am performing a stepwise regression by running the step function on an
lm object. Now I want to save the intermediate iterations. I know the
argument trace=T will print it on the console, but I rather want to assign
it to
Wacek Kusnierczyk waclaw.marcin.kusnierc...@idi.ntnu.no wrote
Seriously? You think:
lapply(1:n, rnorm, 0, 1)
is 'clearer' than:
x=list()
for(i in 1:n){
x[[i]]=rnorm(i,0,1)
}
for beginners?
Firstly, using 'lapply' introduces a function (lapply) that doesn't
have an intuitive
I wrote
As a beginner, I agree the for loop is much clearer to me.
Wacek Kusnierczyk waclaw.marcin.kusnierc...@idi.ntnu.no replied
well, that's quite likely. especially given that typical courses in
programming, afaik, include for looping but not necessarily functional
stuff -- are
steve_fried...@nps.gov wrote
I have encountered a situation with regards to plotting barcharts with
associated error bars. My search for clues on how to accomplish this
turned up some interesting information. Basically, I found that including
error bars with barplots is not desirable and hence
Simon Pickett simon.pick...@bto.org wrote
My institute uses SAS religiously, I am the only R heathen.
I have resisted learning to use SAS because I dont see the point after years
of using R and I like being able to do everything using one program.
However, my colleagues maintain that SAS is
Steve Murray smurray...@hotmail.com wrote
I'm attempting to insert a legend into a line graph. I've sorted out the
positioning, but I'm unable to display the sample line and associated colour
to go within the legend box. Instead, under the variable names, the numbers 1,
2, 2, 3 are displayed
Steve Murray smurray...@hotmail.com wrote
I have a data frame of the nature:
I am hoping to plot columns 2 and 3 against Latitude. I understand that you
have to do this by plotting one column at a time, so I have been starting by
attempting the following, but receiving errors:
I'm
Dieter Menne dieter.me...@menne-biomed.de wrote
I noted the and was misleading. Read: Good journals like Lancet,
New English and many British Journal of XXX really help you to do
better.
I am one of the statistical editors for PLoS Medicine, and I try to help
people do better; often, the
carol white wht_...@yahoo.com wrote
Consider a vector of 100 elements (attached files). then,
truehist(b)
lines(density(b[20:50]))
How is it possible to have density plots of all subsets like b[20:50] within
histogram (without exceeding the max of historgram on y axis)?
I didn't open your
drmh douglasrmhol...@googlemail.com wrote
Hello again,
In my situation, I have three variables: pretest, posttest, and cohesion.
I want to work out the correlation between postest and cohesion.
cor(cohesion, posttest) gives you this.
I looked at multiple sets of data and created ANOVA
Robin Williams wrote
Is there any facility in R to perform a stepwise process on a model,
which will remove any highly-correlated explanatory variables? I am told
there is in SPSS. I have a large number of variables (some correlated),
which I would like to just chuck in to a model and perform
Hello
I wrote a simple program to modify a boxplot:
gdsbox - function(indvar){
boxplot(indvar~gds3lev,
main = paste('Boxplot of', substitute(indvar), for GDS groups),
names = c('1', '3', '4, 5, 6'))
}
If I attach the dataframe gdsgraph, this works fine. However, I've been warned
Hello
I have created a graph using the following commands:
startBReP3O1T - diffs$BReP3O1T - diffs$diff_BReP3O1T
endBReP3O1T - diffs$BReP3O1T
x - seq(47,89, length = 10)
ymin - min(min(startBReP3O1T), min(endBReP3O1T))
ymax - max(max(startBReP3O1T), max(endBReP3O1T))
y - seq(ymin, ymax, length
Hello again
I recently downloaded the gcl package, which computes a fuzzy rules or tree
classifier from data. It is very interesting and is giving good results.
However, rather than return a list, it returns a function. Per the example in
the documentation:
library(gcl)
library(datasets)
Dear r-help
I am trying to run LDA on a training data set, and test it on another data set
with the same variables. I found examples using crossvalidation, and using
training and testing data sets set up with sample, but not when they are
preassigned.
Here is what I tried
# FIRST SET UP A
Hello
Using R 2.7.0 on Windows.
I am running a linear discriminant analysis as follows
discrim1 - lda(normvar~ mafmahal+ mrfmahal+ mffmahal+ bafmahal+ brfmahal+
cofmahal+ bmfmahal+ cfmahal+ fractmahal+ antmahal+ absmifmahal+
absifmahal, subset = train)
prediction - predict(discrim1,
I wrote (in part)
I am running a linear discriminant analysis as follows
discrim1 - lda(normvar~ mafmahal+ mrfmahal+ mffmahal+ bafmahal+ brfmahal+
cofmahal+ bmfmahal+ cfmahal+ fractmahal+ antmahal+ absmifmahal+
absifmahal, subset = train)
prediction - predict(discrim1,
I wrote
Hello
Using R 2.7.0 on Windows.
I am running a linear discriminant analysis as follows
discrim1 - lda(normvar~ mafmahal+ mrfmahal+ mffmahal+ bafmahal+ brfmahal+
cofmahal+ bmfmahal+ cfmahal+ fractmahal+ antmahal+ absmifmahal+
absifmahal, subset = train)
prediction -
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