Hi
Hi Michael and Sarah,
Thank you for offering help. I finally managed to construct an example
with all essentials of my problem:
x1-c(1,2,3,4)
x2-c(2,3,4,5)
x3-c(3,4,5,6)
x-rbind(x1,x2,x3)
time-c(1,3,9)
fit-function(xx,t,tcc){slope - coefficients(lm(log(xx) ~ 0 + t))[1]
You
What problem? Nabble is not available to all and here is not much to cook
from.
Nobody any solution for my problem??
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View this message in context:
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strsplit-missing-value-issue-tp4509065p4511668.html
Sent from the R help mailing list
On similar lines, how do I assign the position of the an occurence of a
value say 7 in a data vector to another data vector?
nFields
[1] 6 6 6 6 6 6 7 7 6 6 6 7 6 6 6 6
I need the output data vector showing occurence of 7 as:
[1] 7 8 12
which(nFields==7)
Regards
Petr
I tried
Hi
If you went through help page you probably could find it yourself in
shorter time then you spend writing email and waited for others to write
back.
see
?plot.stepfun
Dear all,
I would like to plot under the same plot
many curves like
mycdf-ecdf(runif(100))
plot(mycdf)
How do you run a regression in R?
By invoking appropriate function for regression.
??reggression
Regards
Petr
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Hi
See in text.
Dear Sir/Madam,
I'm getting a problem with a R-code which converts a data frame to a
matrix.
It first generate a (m^(n-m) * m) matrix A and then regenerate another
matrix B having less dimension than A which satisfy some condition. Now
I
wish to assign each row of B
Hi
Added a little more to my code (see below). It now automatically sets
the
name of the file. It also does a better job of spacing the text for
pattern and patient x line at the top of the graph.
I really like the way this looks now. I just need to figure out how to
loop through the
Hi
Hi Michael and Petr,
You both seem to have hit on the idea of splitting the TestData in order
to do by group processing. Trouble is that ggplot2 doesn't seem to like
lists very much.
When I run the code:
TempData - split(TestData, TestData$key_line)
TempData
for(temp in
Hi
Hi
Thank you Bert and Thomas for your help, I did what I wanted with this
code.
test-c(4,8,9,6,7)
barplot(test,density =20,angle=45)
But I want to cross the lines in each bar.
Maybe there is some other option in some add-on package but you can simply
add a second barplot
Hi
It is better instead of vague description of your file to use dput(t4) or
at least str(t4) for showing internals.
If I understand correctly your data frame will have columns eventXyear,
eventZyear... and qXayr. qXayr have values 73, 74, ... and you want to
change values in eventXyear to 1
Hi
Dear R users
I want change the entries in a matrix. I did a matrix
A=0 1 5
.3 0 0
0 .5 0
A1-A
A2-A*0.90
A2
12 3
1 0.00 0.90 4.5
2 0.27 0.00 0.0
3 0.00 0.45 0.0
I need replace elements one by one in a loop
I tried the
Hi
This is quite a CPu consuming process. My system got hung up for the
big file I have.
Within the for loop that you have suggested, can't I have a case
statement for different value of nfields to be read and specify what
format does the variable needs to be read?
something like
case
Hi
Dear all,
I have data in the following format :
X-axisY-axis
010%
0-20 20%
20-4030%
40-6040%
. and so on.
I want to plot a bar graph of the above. Also I would want to add a
trendline passing
Hi
Dear all I am having a vector with large length and I would like to ask
you if I can aggregate the values by constant sized windows. For example
for the following vector, I would like to take 30 points until the end
and find their mean.
myData-seq(1:10)
Hi
Hi everyone,
I need to see the source code of function
Does anybody know how can I find so.
Thanks a lot.
What function?
mean.default
function (x, trim = 0, na.rm = FALSE, ...)
{
if (!is.numeric(x) !is.complex(x) !is.logical(x)) {
warning(argument is not numeric or
Hi
Hello
I have this code for the count the occurrences between V_source and
V_destine, its can possible make the same, but in local the total the
occurrences to appear the mean or the minimum
Your question is rather cryptic and I am rather confused what you really
want.
For row/column
Thanks Jim
For the first glance it seems to do what I want. I must go through it more
thoroughly.
Petr
On 03/13/2012 03:07 AM, Petr PIKAL wrote:
Dear all
with image I can plot only one set of values in one plot.
Do somebody have any insight how to put those 2 matrices into one
Hi
Hello
I am developing a small program that to calculate the maximum,
minimum
and average.
The data.frame v is
POS DIF
4 - 4 56
4 - 3 61
3 - 3 300
3 - 327
3 - 3 33
3 - 3 87
3 - 4 49
4 - 4 71
4 - 3 121
3 -
Hi
Using functions how would I go about do this question?
(I already have a mean defined for a function of x.)
Write a function called MyMean2. This function has two arguments, x and
nonzero, where nonzero has the default value TRUE. This function should
return the
(Previous
Dear all
with image I can plot only one set of values in one plot.
Do somebody have any insight how to put those 2 matrices into one picture
so that in one cell in image picture are both values from mat[1,1] and
mat2[1,1].
mat-matrix(1:4, 2,2)
mat2-matrix(4:1,2,2)
x -1:2
y -1:2
image(x, y,
Hi
you are coming from different language paradigm?
Although you did not provide your data I presume you have data frame
called data with columns SP, A1-A5
Your construction
data[1:n, A1]- data$A1 -1
seems to me rather strange and basically your cycle shall do
data[1:n, A4]- data$A4 -2
data[1:n, A5]- data$A5 -2}
else if(data$SP==3){
data[1:n, A1]-data$A1 -3
data[1:n, A2]-data$A2 -3
data[1:n, A3]-data$A3 -3
data[1:n, A4]-data$A4 -3
data[1:n, A5]-data$A5 -3}
}
-Tiff
9. maaliskuuta 2012 10.43 Petr PIKAL petr.pi...@precheza.cz
Hi
Hello,
the idea is to copy the d for df, with new results.
x-data.frame(name=x1,pos=4,age=20)
x-rbind(x,data.frame(name=x2,pos=5,age=20))
x-rbind(x,data.frame(name=x3,pos=6,age=21))
x-rbind(x,data.frame(name=x4,pos=7,age=24))
x-rbind(x,data.frame(name=x5,pos=8,age=27))
Hi
Dear All,
I have a data set with variables x1, x2, x3, ..., x20 and I want to
create z1, z2, z3, ..., z20 with the following formula:
z1 = 200 - x1
z2 = 200 - x2
z3 = 200 - x3
.
.
.
z20 = 200 - x20.
I tried using a for loop and its index as:
for (i in 1:20) {
z(i) =
Hi
Hello,
How is it possible to sort dates in R?
You mean sort? Or order? Something like:
dd -sample(Sys.Date()-1:10)
dd
[1] 2012-03-04 2012-03-05 2012-02-29 2012-03-01 2012-03-02
[6] 2012-03-08 2012-03-03 2012-02-28 2012-03-06 2012-03-07
sort(dd)
[1] 2012-02-28 2012-02-29 2012-03-01
Hi
I have only faint idea what was you problem as there is no context in you
message but maybe
remainder-MeanA[-mysample, ]
could work.
Regards
Petr
Hi, thank you but it does work for vectors and matrix but not
dataframes, it
gives me this message error:
MeanA -
Hi, thank you but it does work for vectors and matrix but not
dataframes, it
gives me this message error:
MeanA - read.csv(MeanAmf.csv,header=T)
mysample - MeanA[sample(1:nrow(MeanA), 20, replace=FALSE),]
Well, maybe slight correction
mysample - sample(1:nrow(MeanA), 20, replace=FALSE)
Hi
Dear All,
I have a problem in making a matrix from a data. I did a summary data
from a
big data frame using (ddply), the resulting table is like that:
Site.NoPlant.NameCover.Percentage
1XXX15
1YYY 20
2
Dear all.
I have some data and I seek the way to start their evaluation. The values
are from survey of different persons and their opinion about various
methods (metoda) and instrument (uzel). I am not sure where to start. I
would like to end with combination of method (metoda) and instrument
Hi
You can use this function to add arbitrary line to already plotted lattice
graph.
addLine- function(a=NULL, b=NULL, v = NULL, h = NULL, ..., once=F) {
tcL - trellis.currentLayout()
k-0
for(i in 1:nrow(tcL))
for(j in 1:ncol(tcL))
if (tcL[i,j] 0) {
k-k+1
trellis.focus(panel, j,
elements in
a lattice/trellis plot.
Kind regards,
Kimmo
08.03.2012 16:53, Petr PIKAL wrote:
Hi
You can use this function to add arbitrary line to already plotted
lattice
graph.
addLine- function(a=NULL, b=NULL, v = NULL, h = NULL, ..., once=F) {
tcL- trellis.currentLayout()
k-0
myself which is
not
I am not confused at all. At my side everything works as expected.
Regards
Petr
typical of me.
~Nicole
- Original Message -
From: Petr PIKAL petr.pi...@precheza.cz
To: Nicole Marie Ford nmf...@uwm.edu
Cc: r-help r-help@r-project.org
Sent: Wednesday, March
Hi
Good Morning
I have a small question regarding the function subset.
I am copying data from one table but I just want to collect data from a
user.
When do I take the view, presents the results I want.
The problem arises when can I make the tab. for RES_ID, introduces me to
zero
Hi
Good Day,
I have a small question, I think it is simple to solve,
I have a column with the following records
name
saucer
cup
tea
saucer
saucer
what is the quickest way to create a new column codes
1
1
3
1
1
Those numbers does not correspond to above mentioned
Hi
Just order your table output.
xx-sample(letters[1:5], 100, replace=T)
yy-table(xx)
barplot(yy[order(yy, decreasing=T)])
Regards
Petr
Hi,
I am working on categorical data with column as disease name(categaory).
My input data is
[1] Acute lymphoblastic leukemia (childhood)
Good Afternoon,
I have a small problem with the following code.
# The x.sub$Time[[1]] 2006-10-31 19:03:01 EST
# when put in variable star give-me
star-x.sub$Time[[1]]
print(star)
print(x.sub$Time[[1]])
[1] 1 36 32 -
do not understand why
Why what?
Without
Hi
wvs.a[,362]
Error: object 'wvs.a' not found
table(wvs.a[,362])
Error in table(wvs.a[, 362]) : object 'wvs.a' not found
norway - wvs.a[which(wvs.a[,362] == 2005), ]
Error: object 'wvs.a' not found
dim(norway)
Error: object 'norway' not found
I get errors with all your commands and have
'norway' which is in the
dataset
as variable 'v218'.
- Original Message -
From: Petr PIKAL petr.pi...@precheza.cz
To: Nicole Marie Ford nmf...@uwm.edu
Cc: r-help r-help@r-project.org
Sent: Tuesday, March 6, 2012 11:49:39 PM
Subject: Re: [R] pulling out 1 country and 1 wave
Hi
Here is my code:
##Centering predictors###
verbal.ability_C - verbal.ability - mean(verbal.ability)
children_C - children - mean(children)
age_C - age - mean(age)
education_C - education - mean(education)
work.from.home.frequency_C - work.from.home.frequency -
sizes differ?
Many thanks for your help.
Helena
From: Petr PIKAL [petr.pi...@precheza.cz]
Sent: Thursday, March 01, 2012 6:17 PM
To: Helena Chui
Cc: r-help@r-project.org; r-help-boun...@r-project.org
Subject: Re: [R] the problem about sample size
Hi
It is strange. I get completely different error.
dispersal[1] - if (any (relativenes[1] cost)) ((relativenes[1]-
cost)/(relativenes[1]- cost*cost)) else 0
Error: object 'relativenes' not found
for (i in 2: time){dispersal[i] - if (any (relativenes[i] cost))
((relativenes[i]-
Hi
Far from being an expert in this field I assume the answer is that it is
included in intercept term. It has something to do with contrasts
specification, but its usage is above my modelling knowledge.
You could try to see what
?contrasts
tells you.
Regards
Petr
you can
Hello,
I’m
Hi
my favourite would be
test$v[which(test$pattern==1)]-NA
Regards
Petr
Hi,
On Mar 1, 2012, at 12:38 PM, Sarah Goslee wrote:
Hi,
On Thu, Mar 1, 2012 at 11:11 AM, mails mails00...@gmail.com wrote:
Hello,
consider the following data.frame:
test - data.frame(n =
Hi
Hi,
I am trying to run two Non-Gaussian regressions: logistic and probit. I
am
receiving two different errors when I try to run these regressions and I
am
not sure what they mean or how to fix my syntax.
Here is the logistic regression error:
Error in family$linkfun(mustart) :
Hi
Hi Petr!
Thank you for responding to my post.
I checked out all my variables in the way you suggested and they are all
in
integer form, but here are many missing values in some of my vectors,
denoted with NA.
So, they are in the correct form, I am just wondering if there is
[[2]]
NULL
[[3]]
NULL
[[4]]
NULL
[1] 3.897434
Any suggestions. Thanks for all the help. :)
Regards
Aparna
On Tue, Feb 28, 2012 at 11:01 PM, Petr PIKAL petr.pi...@precheza.cz
wrote:
Hi
Difficult to without knowing what objects you are operating your
functions
Hi
Hi, there,
I run into the same sample size error in JM. Have you found the solution
for
the error?
What error?
Petr
Many thanks,
Helena
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View this message in context: http://r.789695.n4.nabble.com/the-problem-
about-sample-size-tp1592855p4434009.html
Sent from the R help
Hi
Dear who may concern,
I am sending you this email to ask if I could have someone help me to
write this script I am interested in.
I am requesting the script for performing variance-stabilizing
normalizations on the R language. Could you please help me on that?
If I am asking a wrong
Hi
Difficult to without knowing what objects you are operating your
functions.
I get
test.functional.t(1:10,1:10,3,4)
Error in res.em1$eta : $ operator is invalid for atomic vectors
moderated.functional.t(1:10)
Error in testStatistics[numerator, ] : incorrect number of dimensions
And
Hi
My algorithm as follows;
y - c(1,1,1,0,0,1,0,1,0,0)
x - c(1,0,0,1,1,0,0,1,1,0)
n - length(x)
t - matrix(cbind(y,x), ncol=2)
Do not use t, it is a function for transposing matrix and after you
redefine it you can get nasty surprise in future.
tt - cbind(y,x)
is enough
z = x+y
Hi
Your mail is quite messy. what is ***? How your data are structured?
str(your.data)
Please submit part of your data by
dput(your.data)
and show what the output shall be.
Regards
Petr
Actually, what I really want to do is that,
annual productivity data(2011)
firts date
Hi
SORRY!
The data in MyTable are tagsets of photos, like this:
V1 V2 V3 V4 V5 V6V7 V8
230green nailpolish barrym 0 00 00
231 ny green brooklyn cleanup clean gowanus volunteer gcc
232
Hi
Dear all,
Newbie: What is the fastest way to combine all columns of a matrix to
one
column?
If mm is your matrix use
dim(mm) -NULL
Regards
Petr
--
View this message in context: http://r.789695.n4.nabble.com/What-is-the-
you plain vector
dim(mm) - c(rows, columns)
gives you now matrix with specified number of rows and columns. You can
put columns to 1 and in that case you will get one column matrix.
Please provide some toy example what do you really want.
Regards
Petr
thanks again
On 2/27/12, Petr
Hi
Hi,
The parentheses are in the wrong places in the two if() statements.
Look here:
(length(table(x)1))
^^
(length(table(x)==1))
^ ^
In both cases you're checking whether
the length of the comparison (table(x) 1) or
Hi
Hi,
why my script iss always generating the same graph?when I change the
parameters and the name of text file?
library(MASS)
dados-read.table(inverno.txt,header=FALSE)
vento50-fitdistr(dados[[1]],densfun=weibull)
png(filename=invernoRG.png,width=800,height=600)
hist(dados[[1]],
Hi
[R] How do I save the current session?
savehistory() gives me the option of saving the executable lines only.
I'd
like to save everything.
Using save is not enough?
Regards
Petr
[[alternative HTML version deleted]]
__
Hi
If you want to have more than 6 line types you had either to use colours
or to follow last part of lty advice from par and go to section Line
types. In that case you can not simúply use lty 1,2,...,n but you have to
prespecify line types in some character vector and choose from that
Hi
This is copy paste from my session:
xyz-as.vector(c(ls(),as.matrix(lapply(ls(),class
dim(xyz)-c(length(xyz)/2,2)
allobj-function(){
+ xyz-as.vector(c(ls(),as.matrix(lapply(ls(),class;
+ dim(xyz)-c(length(xyz)/2,2);
+ return(xyz)
+ }
xyz
[,1] [,2]
Hi
apply probably does not understand you function. I do not want to go too
deeply into it but I noticed few issues in it. See inline
Dear ALL
I have this function in R:
func_LN - function(data){
med_ge - matrix(c(rep(NA,nrow(data)*ncol(data))), nrow = nrow(data),
Hi
hi,
i am using R for first time. i am trying to do T-test for a sample set
with
three variables. i attached my data set as CSV file.
but when i do t.test(data$Day.1,data$Day.2,var.equal=T) i get this
following error. Can anyone please help e identify the problem.
Error in if
Hi
Hi, I am working under R2.11.1 Windows.
Rather old one, consider upgrading
I work with a set of parameters which is save under a vector. I think it
is
easier to understand, which parameter is called in the vector by naming
all
vector elements. For example, we have a vector which the
Hi
Hello everybody!
Let's assume I have the following factor with it's levels:
a-factor(c(2,3,3,2,4,2,3,2,2,2,3,2,3))
mydata-data.frame(a)
When I plot the vector a using
barplot(table(mydata$a)
unfortunately the value 1 does not
show up, as it does not appear in my data.
But
Hi
Hi,
Is there a way to check which value in a vector is nearest to a given
value?
so for example I have vector x:
x - c(1, 6, 12, 28, 33)
and I would like to get the position of the element of x that is nearest
to 14
(in this case the third element).
Easy. Smallest difference
Hi
Thank you a lot for answering so fast!
but..what do you mean by example?
I 've mentioned above the loop I used and I also show how the file looks
like
I do not see any loop. I do not archive all posts from R help, only those
with interesting answers :-) and if you do not keep the
Hi
now you omitted data, but never mind :-)
My loop is the following
counter = 0
for (i in 1:nrow(y))
{
for (j in 1:ncol(y))
{
if (y[i,j]==Func_0005634) {
counter = counter + 1 }
if(y[i,j]==Func_0005737){
counter = counter + 1 }
if(y[i,j]==Func_0005515){
Hi
Dear R-helpers,
I have got a vector which looks like the following:
apkz - c(1,2,3,4,5,6,1,1,2,1,2,3,4)
now I am trying to find a way to automatically create several vectors,
each starting with the number 1, namely:
First vector
1 2 3 4 5 6
Second vector
1
Hi
as.logical(rowSums(apply(Data, 2, diff)0))
here is another option.
Regards
Petr
Hi all
For the data below, I would like to return a logical value indicating
differences in the data.
#Create data
Data..-data.frame(a=rep(1,10),b=c(rep(1,9),2),c=c(rep(1,8),2,2))
a b c
1 1 1
Hi
Honestly thank you for the prompt responding
and you are right I will tellyou what I want to do
and not the way ..since I dont know much from R
I have a txt with Proteins
Prot_10035 Func_0005874 Func_0016787 Func_0003774
Func_0006898
Func_0005856 Func_0005525
Hi
For such tasks I would use merge
merge(u, v, by.x=name, by.y = enter, all.x=TRUE)
If you do not want coe column anymore you can easily get rid of it.
Regards
Petr
Hi Valerie
One way would be to use the match function.
# Your Data
u =data.frame(coe=c(0,0,0,0,0,0,0,0),
Hi
Can you be more specific? What else do you want?
x-table(sample(letters[1:5], 100, replace=TRUE))
x
a b c d e
20 14 23 23 20
as.numeric(x)
[1] 20 14 23 23 20
y-as.numeric(x)
Regards
Petr
i want to retrieve count for each freq of given summary from table()
e.g. A
cout,B count
Hi
Hello,
I have a matrix of 17 rows and 20 columns. I want to replicate this
matrix
20 times, but I only want to replicate the rows. How do I do that?
Replicate index.
x-matrix(1:4, 2,2)
x[rep(1:2, 20),]
Regards
Petr
Kind regards / Met vriendelijke groet / Med venlig hilsen,
Dr.
Hi
[R] iterating through for loop
how to iterate two elements each through for loop?
e.g. x-c(1,2,4,7,34,6)
y-c(3,5,6,9,34,7)
for(z in x){
print(paste(z,y)) }
i want both element of vector iterate serially with same position
Not sure what the result shall be. but
paste(x,y)
and
Hi
Thanks to Berend and the others,
I've found a solution which works fine for my problem.
I have not only 2 vectors, but also 4.
Question is, if q1 and q2 is equal to w1 and w2.
The computational time is very short, also for large data.
q1 - c(9,5,1,5)
q2 - c(9,2,1,5)
w1 -
Hi
Hello,
I know this has been covered on here before, but as a complete novice, I
need a little more guidance. I would like to produce boxplots with the
whiskers extending to the 10 and 90th percentiles. I found this code:
myboxplot.stats - function (x, coef = NULL, do.conf = TRUE,
Hi
I did not see any response and actually I can not offer any ready made
solution too. For such problems there could be various solutions from
cycles to *apply, reshape or plyr options.
However for anybody to start with it would be nice to get rather more
clear description together with
Hi
Dear All,
I have data set which includes details of locations e.g latitude,
longitude
, time.
I would like to compare two different data sets ( sampling in space and
time).
the e.g data sets are as follows
t_lat
[1] -90.00 -86.17 -82.34 -78.51 -74.68 -70.85 -67.02 -63.19
odstraněna uživatelem Petr PIKAL/CTCAP]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained
Hi
Error in data.frame(, check.names = FALSE)
Hi Petr,
I have added for loop for previous code. Some error is coming as “error
in data.frame(, check.names = FALSE): arguments has different counts
of rows: 0, 18” for the following code.
Can you please help?
Probably
Hi
I new in R programming language.
I have some time data
time
[1] 2005-01-03 05:11:39 UTC 2005-01-03 06:36:02 UTC 2005-01-03
06:36:55 UTC
[4] 2005-01-03 06:37:00 UTC 2005-01-03 06:38:04 UTC 2005-01-03
06:38:04 UTC
[7] 2005-01-03 06:38:04 UTC 2005-01-03 06:38:04 UTC 2005-01-03
Huh
If you spend only 10 seconds inspecting one plot you will need about 150
hours for that task. I would recommend to reconsider this issue for your
own sanity.
Anyway you can save them either to separate files or in multi page PDF
document although I do not know if there is some limit in
Hi
You shall at least read what others wrote you about your code.
here is a quote from what I wrote you yesterday and what stays valid for
today too.
Also be aware that all levels of a factor are preserved in a subset
unless you specifically strip the unused levels. Therefore there is a
, and forced to true if file is a pipe.
Regards
Petr
Best regards,
Khodakarim
On Fri, Jan 20, 2012 at 11:57 AM, Petr PIKAL petr.pi...@precheza.cz
wrote:
Huh
If you spend only 10 seconds inspecting one plot you will need about 150
hours for that task. I would recommend to reconsider this issue
Hi
Hello,
this is a very simple question:
How can I find out if a word is part of a list of words
like:
a - word1
b - word4
vector - c(word1,word2,word3)
I tried it with match(a,vector)
but this gives the position of the word.
Perhaps
a %in% vector
Regards
Petr
I am not
on a single page. (Note that with
50k
plots you'll want layout() and multiple pages.)
Michael
On Jan 20, 2012, at 6:46 AM, Petr PIKAL petr.pi...@precheza.cz wrote:
Thank you very much,
but in *.pdf I can see 1 plot, may I ask you another question?
How can see more than one
Hi
Hi all,
Small problem in generating the line charts.
Question: Legend for the first graph is coming wrong., for second graph
correctly. Please fix the legend postion at the down of graph.
Plesae give me the solution.
Thank you
Devarayalu
Orange1 - structure(list(REFID
Hi
Hello all,
It might be a simple question, but I cannot find the solution, as I do
not
know which subjects I should search on. So, much thanks for he/she we
can
help me.
I am creating a function and would like to place a formula in the
function,
without it being executed
Hi
Hi,
I am creating a function and ran into the problem of selecting a column
from a dataset. It seems as though the $ function (as in
data$columnname)
does not apply in the function. In simplified version:
This works:
testf2-function(data,columnnumber){print(data[,columnnumber])}
Hi
addLine- function(a=NULL, b=NULL, v = NULL, h = NULL, ..., once=F) {
tcL - trellis.currentLayout()
k-0
for(i in 1:nrow(tcL))
for(j in 1:ncol(tcL))
if (tcL[i,j] 0) {
k-k+1
trellis.focus(panel, j, i, highlight = FALSE)
if (once) panel.abline(a=a[k], b=b[k], v=v[k], h=h[k], ...)
Hi
Hi,
I have a list of unique patient IDs which I want to run against a
dataframe
of unique patient IDs with dates. There are multiple date instances
against
unique IDs. The end result I wish is that I have a list of IDs (which
are
unique) with the latest date. I have begun with using
Hi
Dear R help listers,
I am trying to replicate results in Gelman and Hill's book (Chapter 3
in regressions and multilevel models). Below I estimated two models
(chp3.1 and chp3.3 in R codes) with the same data and dependent
variable but different independent variables. I have been using
Hi
It seems to me quite like a homework for which the policy of this list is
not to respond.
But far from being an expert in statistics I only express my opinion. It
seems to me that your height variable behaves like a two level factor and
the 190 value points to rather suspicious value in
Hi
Dear R users,
I have some trivial query.
I have a string, I want to remove space from the string.
For eg.
Input:
a - Remove space
Output required:
Removespace
It seems to be simple. Even myself with very poor knowledge of regexpr can
suggest solution.
gsub( , , a)
Hi
what do you want to achieve?
Hi Justin,
it still does not work.
All points become red.
I use this skript with your modifications:
TOC_NI-read.csv2(C:/Users/hilliges/Desktop/Master/Daten/Statistik/TOC-NI.csv,
sep=;, dec=,, encoding=UTF-8)
I forgot to post it to r help.
Petr
Hi
Hi Petr,
thanks for your answer.
First of all it's not homework I am a student and need to analyse cancer
data using linear models.
I looked into that topic since a week now and still struggling in
interpreting some of the R output that is why
Hi
Dear group,
I am trying to prepare a NONMEM friendly dataset for population PK
analysis. My patient IDs are 10 digit long and NONMEM is losing precison
and rouding the last couple of digits. I need to generate unique
Patient
IDs fromt he current 10-digit IDs. Ihave total 250
Hi
Hello-
I have rather a messy SPSS file which I have imported to R, I've dput'd
some of the columns at the end of this message. I wish to get rid of all
the labels and have numeric values using as.numeric. The funny thing is
it works like this:
as.numeric(mydata[,2]) # generates
Hi
Hello all
I'm new to R and am experiencing a problem with a categorical variable.
All
the data of this variable are Low, High, or NA. When I put
summary(x$y), it gives me the number of High, Low, and NA entries.
However,
when I try to subset by writing x$y==Low or x$y==High, R
Hi
[R] question about rev
Hi,all:
I have a vector,and wanna get the opposite value via rev function.
a
[1] FALSE FALSE TRUE TRUE TRUE
rev(a)
[1] TRUE TRUE TRUE FALSE FALSE
I don't know why the 3rd TRUE has not been reversed,while all other
values are reversed?
Hi
Hi,
A simple question I hope. I wish to add a single vertical line to a plot
with several density plots.
Here is a simplified example.
thedata - data.frame(x1=rnorm(100,1,1),x2=rnorm(100,3,1)) #create data
thedata.m-melt(thedata)
densityplot(~value, thedata.m,
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