be to
make vectors of row and columns coordinates. But it depends on what you
want to do with your data.
Regards
Petr
Thanks
From: Petr PIKAL petr.pi...@precheza.cz
To: azam jaafari azamjaaf...@yahoo.com
Cc: R-help r-help@r-project.org
Sent: Thursday, September 1, 2011 8:59 AM
=
as.vector(d$z[,ncol(d$z):1])))
It doesn't work and I think it is wrong.
Thanks
From: Petr PIKAL petr.pi...@precheza.cz
To: azam jaafari azamjaaf...@yahoo.com
Cc: R-help r-help@r-project.org
Sent: Thursday, September 1, 2011 10:22 AM
Subject: Re: [R] convert to grid file
Hi
Hi
Hi all,
I apologize for this probably stupid question, but I really can't figure
it
out.
I have a dataframe like this:
group - c(rep('A', 8), rep('B', 15), rep('C', 6))
time - c(rep(seq(1:4), 2), rep(seq(1:5), 3), rep(seq(1:3), 2))
value - runif (29, 1, 10)
dfx - data.frame (group,
something like:
When performing summary values for a data frame according to levels of a
factor you shall use syntax
ddply(.data, .variables, summarise, .fun, ...)
Regards
Petr
Best,
Ista
On Wed, Aug 31, 2011 at 7:13 AM, Petr PIKAL petr.pi...@precheza.cz
wrote:
Hi
Hi all,
I
Hi
Hi,
Does anyone know how to show zero frequencies variable levels with the
xtabs command? They show with the table(x,y) command but I need to apply
weight to frequency tables and I also need to cbind several tables
together, which implies that they all need to show the same number
Hi
Hi all,
I am reading previous posts and guidance on the 'reshape' package in
order
to solve the simple problem below. Thinking that this might be very
trivial for most of you, I thought there could be a fast solution coming
from you guys, and I´d be very thankful for that.
I have
Hi
Dear R-help readers,
I'm sure this problem has been answered but I can't find the solution.
I have two vectors
v1 - c(a,b)
v2 - c(1,2,3)
I want an easy way to produce every possible combination of v1, v2
elements
Ie I want to produce
c(a1,a2,a3, b1,b2,b3)
Another option is
Hi
or if Dan prefers data frame (which is also a list)
CInew2 -function(x,alpha){
data.frame(variable = deparse(substitute(x)), mean=mean(x), alpha = alpha)
}
CInew2(JOBSTAT, 0.05)
variable mean alpha
1 JOBSTAT 0.4567117 0.05
Regards
Petr
In this case you want to use a 'list'
Hi
Hi All,
I am a beginner in programming in r and please do forgive me if my
question
seems to be silly and sometimes not understandable.
1. we have a list of elements in a list say:
ls-list(N,E,E,N,P,E,M,Q,E,M)
2. We have an another list of tables in a list say:
n - list(M,
Hi
Thanks, Jim. quote='' works. And then I found a single quote in each of
these lines:
3262
10403
17544
24685
31826
38967
None of them near the position the table got truncated. Why is it?
And read.table is a great function. Is it possible for it to give a
warning
message when
Hi
I use this kind of output to excel if the table is not too big
write.table(tab, clipboard, sep = \t, row.names = F)
In excel sheet I press ctrl - V to copy from clipboard
Regards
Petr
Using write.table i would like to save data as an excel file to a
folder. I
am not too sure how to
Hi
On 26 August 2011 03:37, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
If you could, dput() them so we can see everything about them. You
also
might see if merge() gives you more expected behavior
Ok...
dput(a)
structure(c(7.6343, 7.6343, 7.5458, 7.4532, 7.404,
I was rather too quick
It has probably something to do with versions of zoo and xts
after updating to zoo 1.7.4 and xts 0.8.2 I got with your examples
merge(a,b)
ZWD.UGX SCHB.Close
2010-04-01 NA 28.02
2010-04-01 7.6343 NA
2010-04-02 7.6343 NA
2010-04-03
Hi
Hi there,
I have length data of an organism over the year and I want to make a
boxplot. I get the boxplot just fine but the months are all out of
order. In
the data set they are in order from Jan-Dec...how can I fix this
problem?
Probably months are either character or factor
Dear all,
How can I covert lm data to text in the form of y=ax+b, r2 and how do
I
calculate R-squared(r2)?
Thanks.
Code:
x=18:29
y=c(7.1,7,7.7,8.2,8.8,9.7,9.9,7.1,7.2,8.8,8.7,8.5)
res=lm(y~x)
I am not sure what do you mean by text. There are some lm extraction
functions for
Dear list,
I have problem that I cannot solve and would like to ask your opinion. I
tried to ask a few days ago already but got no answer and all my
attempts to
solve it by myself since then failed. Sorry for repeated posting! Here
the
problem broken down a bit.
My problem
Is there anything in R similar to spectogram command in matlab?
As I do not use matlab I can not know what spectogram does.
What is wrong with fft or spectrum functions?
Regards
Petr
On Tue, Aug 23, 2011 at 10:20 AM, Petr PIKAL petr.pi...@precheza.cz
wrote:
Hi
Hi all,
I am
Hi
Dear all,
I have a dataset of 3 categorical factors, the mean and the standard
deviation of each value. I want to use these values to plot a boxplot,
grouped by each of the 3 categorical factors (24 boxplots in total). I
don't have a clue on how to do the boxplot from mean and SD
Hi
as far as I understand your question it seems to me that
round(5*(1.4^(0:10)))
gives you your sequence
and
cumsum(round(5*(1.4^(0:10
gives you summary sequence.
Regards
Petr
I definitely used too much lines s of code because I still don't know
how to
do some staff.
but it
Hi
Dear All,
I am quite a newbie to R. Trying to learn it these days. Sorry for
asking
such a basic question, but could you kindly tell me how to map unique
string
values to integers in a data frame? I have a graph which has, most of
its,
vertices' attributes in a string format. I would
Hi
Hi all,
I am trying to do spectral analysis of a time series data. But I am not
sure
how to do it. Can anyone tell me if there are any package I can use to
do
the analysis using fast fourier transform?
Maybe ?fft or ?spectrum
Regards
Petr
Thanks in advance.
Cassie
Hi
Your code is rather baroque and it is difficult to see what is exactly
going on without having appropriate data. I does not consider your process
of reading data from Excel problematic.
Maybe the difference is in that
d- rnorm(whatever)
produces vector while
d- read.delim(clipboard,
Hi
r-help-boun...@r-project.org napsal dne 17.08.2011 21:07:43:
Dear Michael,
Thanks a lot for your reply and for your help.I was struggling so much
but
your suggestion showed me a path to the solution of my problem.I have
tried your code on my data frame step wise and it looks fine to
Hi
my qustion is if my miss value in my dataset is -
for example :
1 3 21 33 - 23 33 -
how can I plot or analysis this dataset ignoring the missing value ?
thanks
.
Use NA instead of - and things will get better
x-as.numeric(read.table(textConnection(1 3 21 33 -
Hi
look into the *apply series of functions. In your case
apply(name.of.your.data.frame,2,min)
or
apply(name.of.your.data.frame,2,max)
will do. You can also put any summary function to your liking instead of
min/max.
And summary has its own data frame method so simply
Hallo all
I try to find a way how to compare set of waiting times during different
periods. I tried learn something from queueing theory and used also R
search. There is plenty of ways but I need to find the easiest and quite
simple.
Here is a list with actual waiting times.
ml -
for comparison of two
or more sets with such long tailed distribution? - Trimmed mean?, Median?,
...
Thanks.
Regards
Petr
On Thu, Aug 18, 2011 at 7:49 AM, Petr PIKAL petr.pi...@precheza.cz
wrote:
Hallo all
I try to find a way how to compare set of waiting times during
different
periods. I
Hi
Dear list,
I'm trying to fit a chapman-richards equation to my data, only I
cannot interpret the parameters a, b and d. I know that the parameter
b denotes the asymptote, but for the others I couldn't figure out. But
No. d Is asymptote. You can easily check how the function behives by
.
Thank you for your time and an answer.
Best regards
Petr
On Thu, Aug 18, 2011 at 8:52 AM, Petr PIKAL petr.pi...@precheza.cz
wrote:
Hallo Jim
Thank you and see within text.
jim holtman jholt...@gmail.com napsal dne 18.08.2011 14:09:11:
I am not sure why you say that lapply(ml, mean
Hi
Here's an example of relevel used to relevel and combine groups
InsectSprays2-InsectSprays
levels(InsectSprays2$spray)
levels(InsectSprays2$spray)-list(new1=c(A,C),YEPS=c(B,D,E),LASTLY=F)
levels(InsectSprays2$spray)
InsectSprays2
So for you try...
levels (Data1$Site) -
Hi
In the following data.frame there are 6 columns, but 7 are written to
the CSV file.
install.packages(pmlr)
library(pmlr)
data(enzymes)
write.table(enzymes, sep=,, eol=\n,file=albert.csv)
see row.names option in ?write.table
Regards
Petr
Hi
In Excel, make sure that your data has a format that corresponds to an R
data frame (first row with column names, consistent column size and data
type).
Export your .XLS worksheet as .CSV file (mydata.csv).
In R, read it into a data frame with
read.csv( mydata.csv )
Another
Hi
Hi R help,
I am trying to determine how nls() generates a function based on the
self-starting SSlogis and what the formula for the function would be.
I've scoured the help site, and other literature to try and figure
this out but I still am unsure if I am correct in what I am coming up
Hi
Dear List,
I like to assign names to vectors in a loop.
Here is a short example:
DMUs -
as.data.frame(matrix(c(b,c,d,a,e,h,i,f,g,j,k,l),ncol
=7, nrow=10))
colnames(DMUs) - v_DMUs - c(a,b,c,d,e,f,g)
for (i in v_DMUs)
assign(paste(eff_val,i,sep=.),abs(rnorm(10)))
Now I like to
about how your function works? How is the input data
structured?
What is vysledek? (the response variable?)
I was surprised to see very few posts about GRR on the R-help website,
and
packages. Any help you can offer is appreciated.
[R] Odp: GRR - Best methods in R
Petr
Hi
I did save workspace and when I load it, I can see the variables,
using ls().
But I cannot see the commands from the program I saved. How to do
that?
Perhaps you can check .Rhistory file.
Regards
Petr
__
R-help@r-project.org mailing list
Hi
Are you sure about sine fit? Seems to me that logistics would be better
fit-nls(dat ~ SSlogis(x, Asym, xmid,scal), data = dat.df, start =
list(Asym=90, xmid = 75, scal = -6))
plot(dat.df)
lines(dat.df$x[complete.cases(dat.df)], predict(fit))
Regards
Petr
Hello, I'm trying to generate
Hi
Hi all
I want to use function of is.list and is.data.frame in if-else
statement,
but I get a trouble. To replicate this trouble, I run codes like that:
set.seed(123)
x - rnorm(100)
x - data.frame(matrix(x, 10, 10))
class(x)
[1] data.frame
is.list(x)
[1] TRUE
Hi
Hello,
I am having some fun dealing with dates and times. My input is a excel
csv
file with two columns with data in the following format:
date time
25-Jun-1961 04:00:00
i.e. day - month - year hour:min:sec
I would
Hi
Hi,
I have 334 records, with two columns:
Column (1): Resolution Column (2): Number of images with a specific
resolution
How can I make a scatter plot in R with this data? Is there a way to
*import
If you have your data in two column data frame you can just
plot(your.data.frame)
My version of R is not silent:
Neither mine
library(akima)
Error in library(akima) : there is no package called ‘akima’
Regards
Petr
setwd(/notHere)
Error in base::setwd(dir) : cannot change working directory
library(notHere)
Error in library(notHere) : there is no package called
Hi
Dearl all,
I have to fit a function
y = f(x1, x2)
to data experiemntal data describing the measured behavior of y.
x1 and x2 are the independent variables.
Could you suggest me wich R package can I use for this purpose?
?nls
?lm
?loess
?glm
And there are plenty more if you do
you should look to
?nls or maybe ?optim
Regards
Petr
Paola.
On Fri, Aug 5, 2011 at 2:55 PM, Petr PIKAL petr.pi...@precheza.cz
wrote:
Hi
Dearl all,
I have to fit a function
y = f(x1, x2)
to data experiemntal data describing the measured behavior of y.
x1 and x2
Hi
r-help-boun...@r-project.org napsal dne 05.08.2011 15:21:34:
khadeeja ismail haj...@yahoo.com
Odeslal: r-help-boun...@r-project.org
My version of R is not silent:
setwd(/notHere)
Error in base::setwd(dir) : cannot change working directory
library(is notHere)
Error in
Hi
r-help-boun...@r-project.org napsal dne 04.08.2011 14:56:09:
a217 aj...@case.edu
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04.08.2011 14:56
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[R] Counting rows given conditional
Hello,
I have an input file that contains multiple
Hi
Hello,
I have a big data.frame, a piece of it as follows.
a b c d
1 58009 2010-11-02 0 NA
2 114761 NA 1 2008-11-05
3 184440 NA 1 2009-12-08
4 189372 NA 0 NA
5 105286
Hi
another possibility is to use logical values properties
(x 0)*x
[1] -3 -2 -1 0 0 0 0
Regards
Petr
In addition to what David said:
On Mon, Aug 1, 2011 at 6:57 PM, zoe_zhang 1987.zhan...@gmail.com
wrote:
Dear All,
Sorry to bother
I want to write a function in R using if
Hi
Hi!
The sample below should give you what you want:
M = matrix(runif(100), 10, 10)
sd(as.numeric(M))
So the as.numeric command is the key. It transforms the matrix to a 1D
vector. Or alternatively without using as.numeric:
M = matrix(runif(100), 10, 10)
M
dim(M) = 100
or
Hi
Hi,
I have some simple statistics to calculate for a large
number of variables.
I created a simple function to apply to variables.
I would like the variable name to be placed automatically.
I tried the following function but is not working.
desc = function(x){
Hi
Hi,
I have a dataframe that I imported from a .txt file by:
skogTemp - read.delim2(Skogaryd_shoot_data.txt, header=TRUE,
fill=TRUE)
and the data are factors, how can avoid factors from the beginning?
Although
the file contains both characters and numbers.
You have got an answer
Hi
Dear All
I would like to produce interaction boxplots and this seems to work:
par(mfrow=c(2,2))
A=sample(rnorm(50,50,10))
B=sample(rnorm(50,100,10))
Test=merge(A,B,by=0)#by=0 where 0 is the row.names
TreatA=(gl(2,50,100,labels=c(High,Low)))
Hi
Re: [R] Big data and column correspondence problem
Daniel, thanks for the answer.
I will try to make myself i little bit clearer. Doing step by step I
would
have (using a loop trough the lines of 'A'):
I am not sure if you are successful in your clarifying.
1. AA[1] is 4. As so, I
Hi
r-help-boun...@r-project.org napsal dne 25.07.2011 05:23:51:
Re: [R] Problem with random number simulation
Hi,
I was just hoping someone could try running the program to see if they
get
any output. This is independent research. I just need to run this
simulation to see how a
Hi
[R] How to merge a matrix and a dataframe with different types of
columns
Hi,
I hope someone can help here. I have been scratching my head for many
hours, trying to find out how to merge two datasets that were created by
different means. The initial miniMarket contains dates
Hi
[R] Using t tests
Dear Sir,
I am doing some work on a population of patients. About half of them are
admitted into hospital with albumin levels less than 33. The other half
have
albumin levels greater than 33, so I stratify them into 2 groups, x and
y
respectively.
I
Hi
Hi,
I am reading payment data like so
2010-01-01,100.00
2010-01-04,100.00
...
2011-01-01,200.00
2011-01-07,100.00
and plot it aggregated per month like so
library(zoo)
df - read.csv(daily.csv, colClasses=c(d=Date,s=numeric))
z - zoo(df$s, df$d)
z.mo - aggregate(z,
, beside=T, col=1:2)
Or you could look at ggplot2 package.
Regards
Petr
In SQL something like GROUP BY MONTH, YEAR as opposed to GROUP BY
YEAR, MONTH.
greetings, el
on 2011-07-07 11:08 Petr PIKAL said the following:
[...]
How do I get the monthly aggregated payments in different
Hi
divide and conquer
Split your data frame to required portions
dat-as.data.frame(cbind(rnorm(1:12),rnorm(1:12)))
dat.s-split(dat, rep(1:4, each=3))
apply lm to each portion
sapply(dat.s, function(x) coef(lm(V2~V1, x)))
1 2 3 4
(Intercept)
Hi
r-help-boun...@r-project.org napsal dne 01.07.2011 14:32:31:
B Marktplaats gm.spam2...@gmail.com
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[R] defining new variable
Hello,
I'm new to R and I'm trying to define new
Hi
r-help-boun...@r-project.org napsal dne 29.06.2011 11:38:17:
Ida Dolciotti ida.dolcio...@ufz.de
Hello everybody,
I have drawn a line in a x y plot that links the minimum and maximum
points in the plot
plot(xx,yy)
a=max(yy)
b=min(yy)
lines(c(xx[yy==a],xx[yy==b]),c(a,b))
Hi
r-help-boun...@r-project.org napsal dne 28.06.2011 02:45:01:
Right. You forgot the comma!
If you want to resolve this rather cryptic advice see
?[
Regards
Petr
--
David.
On Jun 27, 2011, at 7:10 PM, Nanami wrote:
it's a table; I read it from a file; I've tried to make it
Hi
Dear expeRts,
I have two questions concerning data frames:
(1) How can I apply the class function to each component in a
data.frame?
As you can see below, applying class to each column is not the right
approach; applying it to each component seems bulky.
(2) After transforming the
Dear expeRts,
I have two questions concerning data frames:
(1) How can I apply the class function to each component in a
data.frame?
As you can see below, applying class to each column is not the right
approach; applying it to each component seems bulky.
(2) After transforming the
Hi
r-help-boun...@r-project.org napsal dne 24.06.2011 16:51:27:
Thanks for your reply, but that is not quite what I am looking for...I
do not
want to add up all the values in the row, I want to get the number of
columns in each row that meet the criteria and then get that as a
Hi
Hi Dimitris,
Thanks for your reply. But this is not exactly what i am after. I want
to
find the probes that falls into certain regions. In your solution it
will
ignore the second probe if it falls into the same region as the first
one.
Is there any vector trickb uilt in R to find
Hi
Thank you for all your help! I did not know to use when searching for
help, as ?mean, etc, had always worked for me in the past.
It makes perfect sense why 'else' was causing me the trouble the way I
was
using it. I think it was working in my other code, despite the same
format,
Hi
Hi,
I have a matrix (pwdiff in the example below) with ~48 rows and 780
columns.
For each row, I want to get the percentage of columns that have an
absolute
value above a certain threshold t. I then want to allocate that
percentage
to matrix 'perc' in the corresponding row.
Hi
r-help-boun...@r-project.org napsal dne 22.06.2011 20:40:39:
On 6/22/2011 1:34 PM, Sarah Goslee wrote:
On Wed, Jun 22, 2011 at 2:28 PM, David Winsemius
dwinsem...@comcast.net wrote:
On Jun 22, 2011, at 2:03 PM, Sarah Goslee wrote:
Hi,
On Wed, Jun 22, 2011 at 11:40 AM,
Hi
r-help-boun...@r-project.org napsal dne 19.06.2011 20:45:04:
Hi:
It's just an extra step:
y - list(list(c(1,5),c(2,3,4)), list(c(1, 3, 4), c(5, 7)))
lapply(seq_len(length(y)), function(i) lapply(y[[i]], min))
[[1]]
[[1]][[1]]
[1] 1
[[1]][[2]]
[1] 2
[[2]]
[[2]][[1]]
[1] 1
Hi
I am using the following command to replace all the missing values and
assorted typos in a dataframe with NA:
mydata[mydata80]=NA
The problem is that the first column contains values which should be
more than 80, so really I want to do it just for
mydata[,2:length(mydata)]
I
Hi
Hi,
If you truly have an array, this is option that should be much faster
than a loop:
index - which(is.na(dat))
dat[index] - dat[index - 1]
the only catch is that when there previous value is NA, you may have
to go through the process a few times to get them all. One way to
Hi
Dear R users,
I am using package alphahull version 0.2-0 with R-2.13.0. Here is my
problem.
I have produced a 2-D plot of points and need to draw convex hulls
around
some subsets of these points. So I just need to add the convex hulls to
the already existing plot. That is why I
Hi
r-help-boun...@r-project.org napsal dne 14.06.2011 18:28:42:
Andreas Betz ab...@portola.com
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[R] problems with plots in loop (corrected Email)
Dear helpers,
In an
Hi
r-help-boun...@r-project.org napsal dne 13.06.2011 05:21:23:
Re: [R] automatically generate the output name of my for loops
?paste
something like...
paste (group, i, sep=_)
I believe that better idea is to use list, with which you can work further
much more efficiently.
lll-
Hi
[R] How do I make proper use of the by() function?
Dear list,
I have a function that uses values from two vectors and spits out one
new
vector based on all the values of the two original vectors, and with
the
same length as them.
Ok, I would now like to be able to apply that
Hi
r-help-boun...@r-project.org napsal dne 13.06.2011 17:19:39:
Patrizio Frederic frederic.patri...@gmail.com
On Mon, Jun 13, 2011 at 4:45 PM, Barry Rowlingson
b.rowling...@lancaster.ac.uk wrote:
On Mon, Jun 13, 2011 at 11:06 AM, Aparna aparna.sampat...@gmail.com
wrote:
Hi All
I am
Hi
r-help-boun...@r-project.org napsal dne 13.06.2011 17:35:29:
jiliguala jiligu...@mail.com
really thanks for helping.
i just did just like what Petr Pikal said,
but it appeared some error like this:
There were 50 or more warnings (use warnings() to see the first 50):
Warning
Hi
r-help-boun...@r-project.org napsal dne 13.06.2011 17:59:03:
Ben Ganzfried ben.ganzfr...@gmail.com
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[R] log2() and -min() very quick question
I'm looking over good-code a
Hi
[R] what is the mistake?? the coding still not function. no result
display
#lda.r
#
#Author:Amsha Nahid, Jairus Bowne, Gerard Murray
#Purpose:Perform Linear Discriminant Analysis (LDA)
#
#Input:Data matrix as specified in Data-matrix-format.pdf
#
Hi
[R] How to subset based on column name that is a number ?
Hi,
I have a data frame with column names 1, 2, 3, ... and I'd like to
extract
a subset based on the values in the first column. None of the methods I
tried
worked (below).
x - subset(dframe, 1 = = My Text)
x -
Hi
r-help-boun...@r-project.org napsal dne 01.06.2011 21:10:23:
Filipe Leme Botelho filipe.bote...@vpar.com.br
Odeslal: r-help-boun...@r-project.org
RES: [R] Recode numbers
I think this is proper.
a - c(1, 2, 3, 3, 4, 4, 5, 6, 1, 2, 2, 3, 1, 2, 1, 2, 3, 3, 4, 5, 1, 2,
3, 4)
b -
Hi
[R] Problem using read.xls - Everything converted to factors
Hallo,
I would like to use to read.xls function from the gdata package to read
data from Microsoft Excel files but I experienced a problem: For example
I used the following code:
Hi
Dear all,
I have a matrix X which consists of 2 columns. I would like to convert
this
matrix into a list where every entry of the list consists of a single
row of
the matrix.
e.g.
split(mat, 1:nrow(mat))
Regards
Petr
Does anyone have a suggestions how to manage this?
Hi
Without reproducible example or some code I wonder if anybody can give you
some advice.
As a wild guess do you use if function correctly i.e. input is length one
logical vector ?
And maybe you do not need loop at all
Regards
Petr
[R] while loop problems
Hi , i am trying to get this
Hi
[R] load seven files (named by date) at a time
Hello,
I'm trying to load a weeks worth of files that are each named by the
date they were creaded (e.g., 20110601.RData), starting with the day
before today so if today is June 1, I would like to load 20110525-
20110531. The script
Hi
r-help-boun...@r-project.org napsal dne 28.05.2011 20:12:33:
Salil Sharma sali...@gmail.com
Odeslal: r-help-boun...@r-project.org
Dear Sir,
I have data, coming from tests, consisting of 300 values. Is there a way
in
R with which I can confirm this data to 68-95-99.8 rule or
Hi
r-help-boun...@r-project.org napsal dne 09.05.2011 16:07:27:
Nilza BARROS nilzabar...@gmail.com
Odeslal: r-help-boun...@r-project.org
09.05.2011 16:07
Dear R users,
I am reading data from a file where there are some missing that are
represented by -.00.
I am using the
Hi
Re: [R] Setting NA to blank
I asked because I thought it'd solve an issue I had. I was actually
being
quite rash in asking this question and for that, I apologize.
I wanted to know because I was attempting to create a heatmap where the
NA
values would not be shown while all the
Hi
r-help-boun...@r-project.org napsal dne 05.05.2011 14:16:04:
Joel joda2...@student.uu.se
Odeslal: r-help-boun...@r-project.org
05.05.2011 14:16
Hi all R users
Ive got a file that contains diffrent settings in the manor of:
What file, what is its structure, is it some R object
to select the setting?
Petr Pikal wrote:
What file, what is its structure, is it some R object or separate
file?
What did you try and what went wrong?
Regards
Petr
Just a normal textfile nothing fancy
Ive tried diffrent kind of ways of useing my OS witch is linux by the
system
Hi
r-help-boun...@r-project.org napsal dne 04.05.2011 12:44:04:
TheSavageSam jujok...@jyu.fi
Odeslal: r-help-boun...@r-project.org
Hello!
I have had some problems lately with use of R at home and school. At my
home
laptop (Ubuntu linux 64bit R-2.12.0) R works just fine. But when I
Hi
r-help-boun...@r-project.org napsal dne 04.05.2011 22:26:59:
Erik Iverson er...@ccbr.umn.edu
Odeslal: r-help-boun...@r-project.org
04.05.2011 22:26
Komu
Dan Abner dan.abne...@gmail.com
Ultimately, I would like for this to be 1 conponent in a larger
function
that will
Hi
r-help-boun...@r-project.org napsal dne 28.04.2011 16:16:16:
ivan i.pet...@gmail.com
Odeslal: r-help-boun...@r-project.org
28.04.2011 16:16
Komu
r-help@r-project.org
Kopie
Předmět
[R] for loop with global variables
Hi,
is there a possibility to use global variables
Hi
r-help-boun...@r-project.org napsal dne 28.04.2011 16:59:26:
ivan i.pet...@gmail.com
Odeslal: r-help-boun...@r-project.org
28.04.2011 16:59
Komu
jim holtman jholt...@gmail.com
Kopie
r-help@r-project.org
Předmět
Re: [R] for loop with global variables
Hi,
thank you
Hi
Something like
paste(output, i, sep = .)
shall work
You could consult FAQ
7.34 How can I save the result of each iteration in a loop into a separate
file
Regards
Petr
r-help-boun...@r-project.org napsal dne 28.04.2011 17:17:48:
Petr PIKAL petr.pi...@precheza.cz
Odeslal: r-help-boun
Hi
x - matrix(rnorm(1e6), 1000,1000)
y - matrix(rnorm(1e6), 1000,1000)
identical(x,y)
[1] FALSE
The response is almost instant.
In case you are not satisfied with the unspecific answer be more specific
with your question.
Regards
Petr
r-help-boun...@r-project.org napsal dne 27.04.2011
Hi
r-help-boun...@r-project.org napsal dne 27.04.2011 13:30:13:
Hi there,
this is probably simple but I can't seem to figure it out by myself...
I have two dataframes (df.1 and df.2):
df.1 - data.frame(year=factor(rep(1:3,3)), level=rep(letters[1:3],3),
number=c(11:19))
df.2 -
Hi
If I understand correctly you maybe could read a file without header,
discard last column, read first line of a file and put it as column names.
read.delim(textConnection(infile), header=F, skip=1)
scan(textConnection(infile), nlines=1, sep=\t, what=c(,))
Regards
Petr
Hi
d-data.frame(matrix(c(ww,ww,xx,yy,ww,yy,xx,yy,NA),
ncol=3, byrow=TRUE))
Change character value NA to missing value NA
d[d[,3]==NA,3]-NA
If you want drop any unused levels of a factor just use
factor(d[,3])
[1] xx yy NA
Levels: xx yy
Regards
Petr
r-help-boun...@r-project.org napsal
Hi
r-help-boun...@r-project.org napsal dne 22.04.2011 09:19:19:
Hello R,
I would like to plot continuos function (e.g. y=x^2) without creating a
sequence for x.
Is there a possibility to somehow specify the range - x belongs to
-100,100?
Something like
curve(x^2, -100,100)
Maybe this
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