I often find myself making lists similar to this
list(var1=var1, var2=var2)
It doesn't seem list has an option, to make it use the name of the
variable as name in the list.
Is there another function that does this?
--
Med venlig hilsen
Rune Schjellerup Philosof
Ph.d-stipendiat
)
$a
[1] 1
$b
[1] 2
On Fri, Mar 12, 2010 at 5:28 PM, Rune Schjellerup Philosof
rphilo...@health.sdu.dk wrote:
I often find myself making lists similar to this
list(var1=var1, var2=var2)
It doesn't seem list has an option, to make it use the name of the
variable as name
debugging a pain.
Erich Neuwirth wrote:
If thats what you want, why don't you do
list(a=1, b=2)
On 3/12/2010 10:45 AM, Rune Schjellerup Philosof wrote:
No, I mean this:
a - 1
b - 2
list(a=a, b=b)
I just find it anoying, that I have to type the names of the variables
twice.
I would
[mailto:r-help-boun...@r-project.org] På
vegne af Rune Schjellerup Philosof
Sendt: 12. marts 2010 10:46
Til: Linlin Yan
Cc: r-help@r-project.org
Emne: Re: [R] Creating named lists
No, I mean this:
a - 1
b - 2
list(a=a, b=b)
I just find it anoying, that I have to type the names
How come the k is 3 in all of this output?
I expected it to be equal to r.
tmp3 - lapply(1:3, function(k) function(r) print(paste(r, - r | k
-, k)))
for (i in 1:3) { tmp3[[i]](i) }
[1] 1 - r | k - 3
[1] 2 - r | k - 3
[1] 3 - r | k - 3
--
Med venlig hilsen
Rune Schjellerup Philosof
Ph.d
I need to use a red-black tree, which package provides that data structure?
--
Best regards
Rune Schjellerup Philosof
Ph.d-stipendiat, Forskningsenheden for Biostatistik
Telefon: 6550 3607
E-mail: rphilo...@health.sdu.dk
Adresse: J.B. Winsløwsvej 9, 5000 Odense C
SYDDANSK UNIVERSITET
of 'a' from 'first' is
returned?
--
Regards
Rune Schjellerup Philosof
Ph.d.-studerende, Statistik, IST, SDU
Telefon: 6550 3607
E-mail: rphilo...@health.sdu.dk
Adresse: J.B. Winsløwsvej 9, 5000 Odense C
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Peter Dalgaard skrev:
Rune Schjellerup Philosof wrote:
Hi
I want to use a function (update) that in its body uses
eval(call, parent.frame())
I would like to use this function in a function that does not contain
the variables referred to in 'call'. Those variables are instead
-on-write on the memory inherited from
the master.
So my question is:
How do I allow the child threads to work on the variables base and
smooth as shared memory, so that I don't have to use sendMaster or
similar functions that copy the results?
--
Med venlig hilsen
Rune Schjellerup Philosof
on the rhs, so it should be allowed to
have NAs in the lhs, according to help(Extract).
What am I missing?
I can see no ambiguite as to what the result of those commands should be
(j == c(2,2,NA)).
--
Med venlig hilsen
Rune Schjellerup Philosof
Videnskabelig Assistent, Statistik, SDU
Telefon: 6550
On the splinefun help page it refers to the interpSpline function from
the splines package.
What are the differences in the results, other than splinefun returns a
function and with interpSpline you use predict.
The only difference from the help pages seems to be the deriv option of
splinefun, are
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