mat - matrix(ncol = length(x), nrow = length(y))
for(i in 1:length(x)) { mat[,i] = y}
HTH,
Samuel
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of fernando.cabr...@nordea.com
Sent: 05 October 2011 17:11
To: r-help@r-project.org
Does file.exists answer to your question?
file.exists(.RData)
If you are not sure of the exact name of the file but know it contains
.RData, you can try:
List.files(directory,.RData)
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf
Hi,
I am manipulating xml objects using the package xml. With the version 2.10.1
this package included the function xmlToList that was converting the xml into a
list straight away.
This function seems to have gone when I moved to 2.13.0. Does someone has an
equivalent for it?
Thanks,
Yes, you can use:
eval(parse(text=c))
On the other hand I would not recommend to use c as a variable name as it is
the name of a very important function in the R language to aggregate data.
HTH,
Samuel
-Original Message-
From: r-help-boun...@r-project.org
Hello,
I was wondering if someone knows the formula used by the function lm to compute
the t-values.
I am trying to implement a linear regression myself. Assuming that I have K
variables, and N observations, the formula I am using is:
For the k-th variable, t-value= b_k/sigma_k
With
Exactly.
My formula holds only for k=1, this is how I generated it.
Do you have any references concerning the rather more careful algorithms?
Thanks,
Samuel
-Original Message-
From: peter dalgaard [mailto:pda...@gmail.com]
Sent: 01 August 2011 14:45
To: Samuel Le
Cc: r-h
Yes, that's what I was looking for.
Many thanks,
Samuel
-Original Message-
From: S Ellison [mailto:s.elli...@lgcgroup.com]
Sent: 01 August 2011 15:16
To: Samuel Le; r-h...@stat.math.ethz.ch
Subject: RE: formula used by R to compute the t-values in a linear regression
-Original
What about:
set.seed(1001)
total - 0
data - vector(list, 30)
for(i in 1:30) {
data[[i]] - runif(50)
}
set.seed(1001)
data[[23]] - runif(50)
HTH
Samuel
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Soyeon Kim
Sent: 09 June 2011
Dear all,
Is there a function in R to convert a matrix or a data.frame into an html table?
Many thanks,
Samuel
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE
Dear all,
I have a problem with the function lu to do LU decomposition: it seems that the
algorithm multiplies the matrix I input by a permutation matrix for efficiency
reasons -hence the sparse in the output. Does someone know whether it is
possible to specify not to use any permutation
To: Douglas Bates
Cc: Samuel Le; r-help@r-project.org
Subject: Re: [R] converting call objects into character
On Apr 3, 2011, at 1:22 PM, Douglas Bates wrote:
On Sun, Apr 3, 2011 at 11:42 AM, David Winsemius dwinsem...@comcast.net
wrote:
On Apr 3, 2011, at 12:14 PM, Samuel Le wrote:
Dear all
Dear all,
I would like to log the calls to my functions. I am trying to do this using the
function match.call():
fTest-function(x)
{
theCall-match.call()
print(theCall)
return(x)
}
fTest(2)
fTest(x = 2)
[1] 2
I can see theCall printed into the console, but I
Dear all,
I am trying the barplot command but some of the labels are disappearing as
there is not enough place on the graph to put them all.
Here is an example of code that doesn't show all the labels:
barplot(sort(runif(9,0,0.2),decreasing=TRUE),xlim=c(0,20),width=2,names.arg=c(first
Hello,
Make sure you have your file in your workspace directory (you can get it on
your R console with the command getwd()).
HTH,
Samuel
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of George Pantop
Sent: 08 February 2011 13:19
Hello,
Here is a quick suggestion:
F-function(i,j,a,b,c,d)
{
res-eval(parse(text=paste(f,i,j,(a,b,c,d),sep=)))
return(res)
}
HTH,
Samuel
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Alaios
Sent: 03 February
Hello,
Your problem is y=bX+epsilon
It can be transformed into: epsilon^2=(y-bX)^2
Standard (unconstrained) regressions are about minimizing the variance of
epsilon, ie (y-bX)^2.
In your case, you need to minimize again the quantity (y-bX)^2 with your
constraints on b=(b1,...,b5). Solve.QP
Hi,
You need to be careful with -Inf and Inf in R, I suppose they are some large
numbers arbitrarily chosen by R, but not infinite quantities. So the function
integrate can return errors if the function to integrate doesn't have
negligible values beyond those large numbers.
I ran the following
Dear all,
I am fitting a time series using the following command:
Ts.arima-arima(x,c(2,1,2)) where x is a time series.
What the function returns is perfectly fine but I was wondering if I could
access to the t-stat of the coefficients I got from the arima function.
Any help would be
Dear all,
I am fitting a time series using the following command:
Ts.arima-arima(x,c(2,1,2)) where x is a time series.
What the function returns is perfectly fine but I was wondering if I could
access to the t-stat of the coefficients I got from the arima function.
Any help would be
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