intense to select clusters.
I’m trying to do this as simply as possible while remaining loyal to the ranked
structure of the data.
Thanks, Simon Kiss
#Loadpackages
library(RCurl)
library(mlogit)
library(tidyr)
library(dplyr)
#URL where data is stored
dat.url-
'https
On Apr 2, 2015, at 6:30 PM, Jim Lemon drjimle...@gmail.com wrote:
Hi Simon,
How about this?
library(plotrix)
revlist-grep(i,names(df),fixed=TRUE)
df[,revlist]-sapply(df[,revlist],rescale,c(3,1))
Jim
On Fri, Apr 3, 2015 at 6:30 AM, Simon Kiss sjk...@gmail.com
mailto:sjk...@gmail.com
Hi there: I have a list of data frames with identical variable names. I’d
like to reverse scale the same variables in each data.frame.
I’d appreciate any one’s suggestions as to how to accomplish this. Right now,
I’m working with the code at the very bottom of my sample data.
Thanks, Simon
Hi there: normally I’m quite comfortable with as.Date(). But this data set is
causing problems.
The core of the data frame looks like the sample data frame below, but my
attempt to convert df$mydate to a date object returns only NA. Can anyone
provide a suggestion?
Thank you, Simon Kiss
that the latter actually
somehow calls the former. Am I reading this wrong? Can someone explain the
difference between the two functions?
Thanks.
Yours, Simon Kiss
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(mymelt, row~color, value.var=rank, fill=0)
#Compare
str(mydf)
str(d2)
head(mycast)
head(d4)
Again, I'm grateful for assistance. I can't understand what how my data-set
differs from David's sample data-set.
Simon Kiss
On Sep 4, 2014, at 2:35 PM, David L Carlson dcarl...@tamu.edu wrote:
I think we
4
4 42 4 0 3 1
5 53 4 2 0 1
6 64 3 2 0 1
David C
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of David L Carlson
Sent: Sunday, August 17, 2014 6:32 PM
To: Simon Kiss
Department of Anthropology
Texas AM University
College Station, TX 77840-4352
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Simon Kiss
Sent: Friday, July 25, 2014 2:34 PM
To: r-help@r-project.org
Subject: [R] Turn Rank Ordering
Hello:
I have data that looks like mydf, below. It is the results of a survey where
participants were to put a number of statements (in this case colours) in their
order of preference. In this case, the rank number is the variable, and the
factor level for each respondent is which colour they
message:
In mclapply(seq_len(n), do_one, mc.preschedule = mc.preschedule, :
all scheduled cores encountered errors in user code
Can anyone provide any guidance?
Thanks, Simon Kiss
*
Simon J. Kiss, PhD
Assistant Professor, Wilfrid Laurier University
73 George
Hello:
I have a .csv file that includes some character strings (open ended survey
responses) that includes some apostrophe. Using read.csv() the file reads in
just fine, except upon being read in the apostrophes are displayed with the
double-slash, i.e. 'I've' becomes 'I\\'ve'. I'd like to
..)/value))+facet_grid(~X2)
Thank you for your assistance!
Yours, Simon Kiss
*
Simon J. Kiss, PhD
Assistant Professor, Wilfrid Laurier University
73 George Street
Brantford, Ontario, Canada
N3T 2C9
__
R
.
Yours, simon Kiss
f - function (modelType, responseName, predictorNames, data, ..., envir =
parent.frame())
{
call - match.call()
call$formula - formula(envir = envir, paste(responseName, sep = ~ ,
paste0(`, predictorNames, `, collapse
!
Yours, Simon Kiss
On 2013-12-19, at 1:55 PM, Simon Kiss sjk...@gmail.com wrote:
Hello Bill, that is fantastic and it's quite a bit above what I could write.
Is there a way to make the model type an argument to the function so that you
can specify whether one is running glm, lm and such?
I tried
was not found
on this server. That’s all we know.
Has the search engine for the help archives moved?
Yours, Simon Kiss
*
Simon J. Kiss, PhD
Assistant Professor, Wilfrid Laurier University
73 George Street
Brantford, Ontario, Canada
N3T 2C9
# combine the model coefficients into a two-column matrix
do.call(rbind, lapply(modlist, coef))
You'd probably want to rename the second column since the slopes are
associated with different x variables.
Dennis
On Tue, Dec 17, 2013 at 5:53 PM, Simon Kiss sjk...@gmail.com wrote:
I
coefficients into a two-column matrix
do.call(rbind, lapply(modlist, coef))
You'd probably want to rename the second column since the slopes are
associated with different x variables.
Dennis
On Tue, Dec 17, 2013 at 5:53 PM, Simon Kiss sjk...@gmail.com wrote:
I think I'm missing
I think I'm missing something. I have a data frame that looks below.
sample.df-data.frame(var1=rbinom(50, size=1, prob=0.5), var2=rbinom(50,
size=2, prob=0.5), var3=rbinom(50, size=3, prob=0.5), var4=rbinom(50, size=2,
prob=0.5), var5=rbinom(50, size=2, prob=0.5))
I'd like to run a series of
or h) are hypothesized to load
on one factor uncorrelated with the second factor, coded with a c (as in
cc.c.varname.c or i).
I used this for guidance http://vimeo.com/38941937
Yours, Simon Kiss
#Load Libraries
library(sem)
#Create Covariance Matrix
ff.cov -
structure(c(0.0925407885304659
the help documentation, that one really only has to use the
command biplot(mod) to get the plot.
Can someone please advise?
Yours, Simon Kiss
#Sample data
sample.data-data.frame(var1=sample(c(0,0.33, 0.66, 1), size=100,
replace=TRUE), var2=sample(c(0,0.33, 0.66, 1), size=100, replace=TRUE),
var3
in a line plot on a graph
where the x-axis is a series of dates twice as long as the time series itself?
The reason I'd like this is because I'd like to add a couple of other story
time series as well. They may appear at other points in time in the campaign as
well.
Thanks.
Simon Kiss
Hello:
I'm working with a 2-dimensional table that looks sort of like test below.
I'm trying to produce latex code that will add dimension names for both the
rows and the columns.
In using the following code, latex chokes when I include collabel='Vote' but
it's fine without it.
The code below
Hi there:
I'm having a weird problem with my startup procedure. R.app is reading an
unknown .Rprofile file.
First, I'm on a Mac Os 10.6.8 running R.app 2.15.0
On startup
getwd()
[1] /Users/simon
But: the contents of my .Rprofile file in my home directory when viewed with a
text editor are:
Hello: I need to create a six barplots from data that looks pretty close to
what appears below. There are two grouping variables (age and gender) and three
dependent variables for each grouping variables. I'm not really familiar with
trellis graphics, perhaps there is something that can do
NULL
I haven't seen this error reported anywhere in the R-list archives. Does
anyone have any suggestions?
Yours, Simon Kiss
P.S. The results of sessionInfo() are
R version 2.15.0 (2012-03-30)
Platform: x86_64-apple-darwin9.8.0/x86_64 (64-bit)
locale:
[1] en_CA.UTF-8/en_CA.UTF-8/en_CA.UTF-8/C
to someone unfamiliar with the tm package
as to how to go about creating a custom reader for this situation?
Yours truly,
Simon Kiss
Document 1 of 40
First Nation agrees not to block trains
Author: SHAWN BERRY Legislature Bureau
, at 4:44 PM, Milan Bouchet-Valat wrote:
Le mardi 08 janvier 2013 à 15:56 -0500, Simon Kiss a écrit :
Hello:
I have a series of newspaper articles from a Canadian newspaper
database (Canadian Newsstand) that look just like below.
I've read through this vignette
(http://cran.r-project.org/web
Hello:
I s there a way to use xtable with objects from the psych package, particularly
principal()?
Is there a difference between princomp and principal? xtable seems to play
better with princomp.
Thank you.
Yours, Simon Kiss
*
Simon J. Kiss, PhD
Assistant
something like:
mosaic(~var1+var2, labelling_args=list(varnames=c('newvar1', 'newvar2'))
Simon Kiss
*
Simon J. Kiss, PhD
Assistant Professor, Wilfrid Laurier University
73 George Street
Brantford, Ontario, Canada
__
R-help@r
. Calling
summary(mod1) on the real data does return information about the coefficients
and the model fitting.
I'm grateful for any help. I'm aware that the topic of non-integer successes
has been addressed before, but I could not find my answer to this question.
Yours, Simon Kiss
##str
, Simon Kiss
#Sample Data
mylist-list('1991-01-01'=data.frame(a=rep(5,5),
survey.date=rep(as.Date('1991-01-01', format='%Y-%m-%d'))),
'1979-01-01'=data.frame(aa=rep(5,5), survey.date=rep(as.Date('1979-01-01',
format='%Y-%m-%d'), 5)), '2001-01-01'=data.frame(c=rep(6,5),
survey.date=rep(as.Date('2001-01
to
be returned to two separate data frames.
Thank you.
Yours, Simon Kiss
#Sample data
mylist-list(df1=data.frame(a=seq(1,10,1), c=seq(1,109,1), q10=rep('favour',
10)), df2=data.frame(a=seq(1,10,1), b=seq(15,24,1), q14=rep('favour', 10)))
#The variables with different names that I need
Hello:
Forgive me, this is surely a simple question but I can't figure it out, having
consulted the help archives and Data Manipulation With R (Spector).
I have a list of 11 data frames with one common variable in each (prov). I'd
like to use lapply to go through and recode one particular level
),replace=TRUE, size=100),
var2=sample(c('a','b','c',NA),replace=TRUE,size=100))
df-subset(df, !is.na(var1) |!is.na(var2))
As you can see, if one variable has an NA, then the other variable has a valid
value, so how do I just combine the two variables into one?
Thank you for your assistance.
Simon
, 2012 at 5:03 PM, Simon Kiss sjk...@gmail.com wrote:
Hi there: I'm preparing a report in RStudio 0.96.330 on a Mac OS. I'm
running R 2.15.0
I understand from Ross Ihaka's document
(http://www.stat.auckland.ac.nz/~stat782/downloads/Sweave-customisation.pdf)
that you can modify the line
).
This works great for me for numeric output, but not for character vectors that
I have to print. The following is some sample code that illustrates my problem.
Is there a different way to format character vectors that are stored in R?
Yours, Simon Kiss
\documentclass{article}
\begin{document
the
web for tutorials, but I can't crack it. I'm aware that this is probably a
pretty basic question, but I need some help regardless. Yours, Simon Kiss
library(XML)
library(RCurl)
library(scrapeR)
library(RHTMLForms)
#Set URL
bus-c('http://www.brantford.ca/business/LocalBusinessCommunity/Pages
Hello:
The following code extracts the links to the daily transcripts of Canada's
House Of Commons. 'links' is a matrix of URLs (ncol=1), each of which points
to one day's transcripts.
If you inspect the code for scrape(links[1]), you will find that periodically
there appears an italicitze
Dear all:
Is there a way to add text to the margins or outer margins of a mosaic plot
using the vcd package? I understand the margins argument to mosaic, but I don't
know how to add text to that.
I'd like to add a caption to a plot. If possible, I'd like to know how to set
the font and size
Dear all,
I have a series of variables that looks roughly like the sample data below and
I'm trying to conduct a factor analysis. I've omitted cases with missing
values for the factor analysis, but now I'd like to use the scores on each
component as new variables in the *original* data set for
, Simon KIss
*
Simon J. Kiss, PhD
Assistant Professor, Wilfrid Laurier University
73 George Street
Brantford, Ontario, Canada
N3T 2C9
Cell: +1 905 746 7606
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman
names?
I'm grateful for your suggestions!
Simon Kiss
*
Simon J. Kiss, PhD
Assistant Professor, Wilfrid Laurier University
73 George Street
Brantford, Ontario, Canada
N3T 2C9
Cell: +1 905 746 7606
__
R-help@r-project.org
Thanks both! That solves ! You've made a very happy newbie!
Simon
On 2012-03-12, at 2:52 PM, Sarah Goslee wrote:
Hi Simon,
On Mon, Mar 12, 2012 at 2:37 PM, Simon Kiss sjk...@gmail.com wrote:
Hi: I'm sure this is a very easy problem. I've consulted Data Manipulation
With R and the R Book
/2010-September/253177.html) but the
result seemed to be ambiguous. Is there a work-around? Reproducible code and
sessioninfo are below. The OS is Mac OS 10.6.8.
Yours truly, Simon Kiss
install.packages(HSAUR)
library(HSAUR)
library(TeachingDemos)
data(Forbes2000, package=HSAUR)
#This is a test
and
individual specific variables are?
Yours, Simon Kiss
l
*
Simon J. Kiss, PhD
Assistant Professor, Wilfrid Laurier University
73 George Street
Brantford, Ontario, Canada
N3T 2C9
Cell: +1 905 746 7606
__
R-help@r-project.org
(table(.y[sample(nrow(.y), 200), ]))$statistic)
}
hist(.z, xlab='Chi-Square Value', main=Chi-Squared Values From 100 different
samples asking\nabout gender and tea/coffee drinking)
abline(v=3.84, lty=2)
Thank you in advance,
Simon Kiss
*
Simon J. Kiss, PhD
Dear colleagues
I'm using data that looks like .test and .test1 below to draw two mosaic plots
with cell labelling (the row percentages from the tables).
When I take out the pop=FALSE commands in the mosaic commands and comment out
the two lines labelling the cells, then the plots are laid out
Dear colleagues
I'm using data that looks like .test and .test1 below to draw two mosaic plots
with cell labelling (the row percentages from the tables).
When I take out the pop=FALSE commands in the mosaic commands and comment out
the two lines labelling the cells, then the plots are laid out
appears to work just fine, although it doesn't
appear to contain the information I need (the URLs of the articles linked to on
this search page). Regardless, I'd still like to understand why htmlParse
doesn't work.
Thank you for any insight.
Yours,
Simon Kiss
myurl-c(http
option.
I'm running R 2.13 on Mac os 10.6 and the latest versions of XML and RCURL are
installed.
Yours, Simon Kiss
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org
be a way just to do
the comparison of means test between two subgroups of a factor, and not just on
all factor levels?
Using 2.13 on mac os 10.6 and the latest version of survey package.
Yours, Simon Kiss
*
Simon J. Kiss, PhD
Assistant Professor, Wilfrid Laurier
statistics as well, in R Commander.
Yours, Simon Kiss
*
Simon J. Kiss, PhD
Assistant Professor, Wilfrid Laurier University
73 George Street
Brantford, Ontario, Canada
N3T 2C9
Cell: +1 905 746 7606
__
R-help@r-project.org mailing
to in that instance.
Is there a solution within R Commander?
Yours, Simon Kiss
*
Simon J. Kiss, PhD
Assistant Professor, Wilfrid Laurier University
73 George Street
Brantford, Ontario, Canada
N3T 2C9
Cell: +1 905 746 7606
__
R-help
can imagine, this is quite laborious, having to restart.
I've looked through the help documentation and tried reinstalling tcltk prior
to opening up Rcommander, but that does not address the problem.
Any thoughts?
Yours, Simon Kiss
*
Simon J. Kiss, PhD
Assistant
John Fox
Sen. William McMaster Prof. of Social Statistics
Department of Sociology
McMaster University
Hamilton, Ontario, Canada
http://socserv.mcmaster.ca/jfox/
On Thu, 28 Jul 2011 13:40:11 -0400
Simon Kiss sjk...@gmail.com wrote:
Dear Colleagues,
I have recently installed R Commander on my
when working on a
test string
test-1:10
sapply(test, function(x) sum(1:x))
Any thoughts?
Simon Kiss
*
Simon J. Kiss, PhD
Assistant Professor, Wilfrid Laurier University
73 George Street
Brantford, Ontario, Canada
N3T 2C9
Cell: +1 905 746 7606
, but I don't know if there is an equivalent argument
in R.
Any thoughts.
Yours, Simon Kiss
*
Simon J. Kiss, PhD
Assistant Professor, Wilfrid Laurier University
73 George Street
Brantford, Ontario, Canada
N3T 2C9
Cell: +1 905 746 7606
Name \n \n Day Date, file =
clipboard)
## read data in, and only select the 4th line to pass to grep()
grep(pattern, x = readLines(clipboard)[4])
On Mon, Jul 11, 2011 at 9:31 AM, Simon Kiss sjk...@gmail.com wrote:
Dear colleagues,
I have a series of newspaper articles in a text file
:)
On Mon, Jul 11, 2011 at 10:25 AM, Simon Kiss sjk...@gmail.com wrote:
Hi Josh,
Sorry for the insufficient introduction. This might work, but I'm not sure.
The file that I have includes up to 100 documents (Document 1, Document 2,
Document 3Document 100) with the newspaper name following 4
Dear colleagues,
following John Fox' advice in this article
(http://cran.r-project.org/doc/contrib/Fox-Companion/appendix-cox-regression.pdf),
I'm trying to create a new data frame to examine the differential survival
curves from a combination of covariates.
These are derived from a Cox
for any suggestions.
Yours, Simon Kiss
**dataset
ff-runif(10, 0.85, 1)
ff-cbind(ff, 1-ff)
gg-runif(10, 0.85, 1)
gg-cbind(gg, 1-ff)
hh-runif(10, 0.86, 1)
hh-cbind(hh, 1-hh)
ii-runif(10, 0.92, 1)
ii-cbind(ii, 1-ii)
jj-runif(10,0.76, 1)
jj-cbind(jj, 1-jj)
r-list(ff, gg, hh,ii, jj
Dear colleagues, working with the data frame below, trying to reverse two
variables I the error message below.
i searched through the help list but could not find any postings which could
help me solve the situation. I tried attaching and detaching the data frame to
no avail.
Yours, Simon Kiss
(weight_test) contains no
What am I missing?
Yours, Simon Kiss
P.S. The code is only reproducible if the data set is downloadable. I'm nt sure
ces-read.spss(file.choose(), to.data.frame=TRUE, use.value.labels=FALSE)
missing_data-subset(ces1, !is.na(ces08_NATWGT))
weight_test-svydesign(id=~0
of minimization points ... 51
Number of estimation points . 101
Pilot Bandwidth . 0.25
Smoothing Bandwidth . 1.27
Minimum IMSE 6716.9
Can anyone provide any advice?
Yours, Simon Kiss
'data.frame': 147 obs. of 7 variables:
$ state : Factor w/ 50
of values
of two variables?
Yours, Simon Kiss
str(bpa)
'data.frame': 150 obs. of 5 variables:
$ State : Factor w/ 50 levels Alabama,Alaska,..: 1 2 3 4 5 6 7 8 9 10 ...
$ year: num 2008 2008 2008 2008 2008 ...
$ ban : num 0 0 0 0 0 0 0 0 0 0 ...
$ partisan: Factor w/ 3 levels
arbitrary ranges.
I also tried converting the dates to numeric and using histogram to try to get
the data, but that doesn't work either. Cut appears to accept an arbitrary
range, but I could only get it to produce NAs.
Any suggestions? Yours, Simon Kiss
mydata-list(x=seq(as.Date(2007-05-01), as.Date
) :
element 1 is empty;
the part of the args list of 'is.character' being evaluated was:
(file)
Does anyone have any suggestions?
Yours, Simon Kiss
*
Simon J. Kiss, PhD
Assistant Professor, Wilfrid Laurier University
73 George Street
Brantford, Ontario, Canada
the data look like?
On Mon, Jan 17, 2011 at 11:47 AM, Simon Kiss simonjk...@yahoo.ca wrote:
Hello,
I'm trying to read in 50 text filess with dates as content to create a list
of tables.
a is the list of filenames that need to be read in.
The following command returns the following
readLines worked great Jim, thanks!
Simon Kiss
On 2011-01-17, at 7:44 PM, jim holtman wrote:
It sounds like you want to use 'readLines' and not 'read.table'
x - readLines(textConnection(January 11, 2009
+ January 11, 2009
+ October 19, 2008
+ October 13, 2008
+ August 16, 2008
+ June 19
and see if I can get it to loop through.
Yours, Simon Kiss
On 2011-01-17, at 7:44 PM, jim holtman wrote:
It sounds like you want to use 'readLines' and not 'read.table'
x - readLines(textConnection(January 11, 2009
+ January 11, 2009
+ October 19, 2008
+ October 13, 2008
+ August 16, 2008
. Is it necessary to create a new object via barplot
and then quote that in the x,y coordinates of text?
Like I said, the code works great, but I'm trying to actually understand the
rationale behind the elements so I can apply it in future.
Yours, Simon Kiss
#Reproducible Code
mydat-data.frame
,
Simon Kiss
x1-rnorm(500)
plot(x1)
test-seq(1987, 2002, by=1)
test_2-seq(2003, 2006, by=1)
test-format(c(test, test_2), width=5)
mtext(test, side=1, line=2)
*
Simon J. Kiss, PhD
Assistant Professor, Wilfrid Laurier University
73 George Street
Brantford, Ontario
the numbers for one year, where I'd like to be able to get a
string of numbers for several years.But, on the upside, grep appears to do the
trick in terms of selecting rows.
Can any one suggest a solution?
Yours truly,
Simon Kiss
#This is the reproducible code to set-up all the data frames
.
I also tried this:
as.numeric(as.character(test[16,c(2:5)] and that also changed the
values from what they originally were.
I'm grateful for any suggestions.
Yours, Simon Kiss
*
Simon J. Kiss, PhD
Assistant Professor, Wilfrid Laurier University
73 George
the mean score of z for NDP managers, Conservative
managers and Liberal managers and then for a few other configurations.
Ive played around with aggregate, tapply and by, but I can't get it to
work.
Cordially,
Simon Kiss
mydata=data.frame(cbind(x,y,z))
mydata$x=as.factor(sample(c(labourers
?
Yours, Simon Kiss
*
Simon J. Kiss, PhD
SSHRC and DAAD Post-Doctoral Fellow
John F. Kennedy Institute of North America Studies
Free University of Berlin
Lansstraße 7-9
14195 Berlin, Germany
Cell: +49 (0)1525-300-2812,
Web: http://www.jfki.fu-berlin.de/index.html
, row.names=FALSE)
Thanks a lot.
Simon Kiss
On 29-Jun-10, at 9:21 PM, Gabor Grothendieck wrote:
On Tue, Jun 29, 2010 at 6:22 AM, Simon Kiss sjk...@gmail.com wrote:
Dear colleagues, particularly academic ones,
So I'm creating a Microsoft Word template for myself so that every
time I
teach a new
Dear colleagues, particularly academic ones,
So I'm creating a Microsoft Word template for myself so that every
time I teach a new course, I don't have to enter in the dates manually
for each class session.
I'd like to use an R script that can generate an irregular series of
dates starting
Dear colleagues,
I have extracted the dates of several news stories from a newspaper
data base to chart coverage trends of an issue over time. They are in
a data frame that looks just like one generated by the reproducible
code below.
I can already generate a histogram of the dates with
that are either
5, 10, 15 or 20. My idea is then to add the two, average them and use
that value as an index of economic egalitarianism?
Yes / no? Suggestions?
I am an R user and I hope that a purely statistical question is not
especially misplaced.
Yours truly,
Simon Kiss
Dear colleagues,
I want to calculate the value of x2 based on the value of x1. x1 is a
factor with three separate levels. I want to make sure that missing
values remain as NA in X2, but non-missing values take on a value of
either 0 or 1 dependending on the value in x1.
This is the code I'm
.
I've looked through; all the variables included in the two models are
identical save for the DV. And the DV's in both models are ordered
factors.
Is any one familiar with this problem in effects plots?
Yours, Simon Kiss
quartz()
jpeg(filename=test.jpeg, type=c(quartz))
plot(effect
,
labeling=labeling_values(value_type=c(residuals), suppress=0)
then I do get the residuals printed, but the labels are unattractive.
How do I combine labeling_borders and labeling_values commands in one
command.
Yours, Simon Kiss
On 12-May-10, at 2:42 PM, Jim Lemon wrote:
On 05/12
I'm working with the following code below to generate a
how do I set the h,c, and l values such that the significant, positive
residuals appear different on a grayscale printer from significant
grayscale residuals. The challenge as I see it is that one can only
distinguish the positive and
Hello all,
I'm having difficulty getting one particular variable into R from SPSS
v. 16.0 for mac. R version is 2.10.1. I saved the relevant variables
from SPSS into a .csv file and then read them into R. All the
variables worked fine, except for one (enviro_spending). In the SPSS
file
data set, but
get precisely the same error at precisely the same location in the
command, i.e. the second colon.
As far as I can tell I have the most up-to-date version of car
installed.
Any suggestions?
Yours, Simon Kiss
*
Simon J. Kiss, PhD
SSHRC and DAAD
like this.
x5
1 4.2
2 7.8 (4.2 +3.6)
3 10.5 (4.2+3.6+2.7)
308 =na
So the last number in the vector x5 should be 100, as these are all
percentages.
Any suggestions? Yours truly,
simon Kiss
*
Simon J. Kiss, PhD
SSHRC and DAAD Post-Doctoral Fellow
John F
because
av.plots brings up an interactive menu that does not appear to allow
for that.
If any one can help, it would be appreciated!
Yours,
Simon Kiss
*
Simon J. Kiss, PhD
SSHRC and DAAD Post-Doctoral Fellow
John F. Kennedy Institute of North America Studies
Free
screen; I'd like to make them full screen to identify points
in a dense scatterplot.
Thank you for any suggestions. Yours, Simon Kiss
*
Simon J. Kiss, PhD
SSHRC and DAAD Post-Doctoral Fellow
John F. Kennedy Institute of North America Studies
Free University of Berlin
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