Dear R help list,
I was just wondering whether there is a way to cluster the documentation files
of data sets in the package documentation index file, so that common prefixes
such as dat... are not necessary.
Best wishes,
Alrik
Dr.
]
Gesendet: Samstag, 13. Juli 2013 19:57
An: William Dunlap
Cc: mailman, r-help; Thiem Alrik
Betreff: Re: [R] Test for column equality across matrices
I tried it on a slightly bigger dataset:
A1 - matrix(t(expand.grid(1:90, 15, 16)), nrow = 3)
B1 - combn(90, 3)
which(is.element(columnsOf(B1
Dear list,
I have a matrix M.1 (30x2) into which I would like to paste another matrix M.2
(10x2) three times. However, the columns get flipped in every odd-numbered
recycle run. How can I avoid this behavior?
M.1 - matrix(numeric(30*2), ncol = 2)
M.2 - t(combn(1:5, 2))
M.1[, 1:2] - M.2
Many
Dear list,
I have two matrices
A - matrix(t(expand.grid(c(1,2,3,4,5), 15, 16)), nrow = 3)
B - combn(16, 3)
Now I would like to exclude all columns from the 560 columns in B which are
identical to any 1 of the 6 columns in A. How could I do this?
Many thanks and best wishes,
Alrik
Dear mailing list,
how can I identify all those rows of matrix B which fulfill some condition
based on another matrix A? More precisely,
A - matrix(c(1, 1, 0, 1, -9, 1, -9, 1, 0, 0, 1, 1, 0, -9, 1, 0, -9, 0, 1, 1,
1, -9, 1, 1, 1), ncol = 5, byrow = TRUE)
B -
Dear mailing list,
I would like to use the optim() command in order to maximize the logged
likelihood of the following function, where p is the parameter of interest and
should be constrained between 0 and positive infinity.
y = 1/2 * ((te - x)/(te - tc))^p
x and y are given by
x - c(5.18,
Dear mailing list,
Why does the following code produce numerical results for x.pos.l, but NaNs for
x.neg.l?
x.pos - function(tau.e, tau.c){
tau.e + ((-tau.e^3 + 3*tau.e^2*tau.c -
3*tau.e*tau.c^2 + tau.c^3)^(1/3))/(2*2^(1/3))
}
(x.pos.l - x.pos(1, 2))
x.neg - function(tau.c, tau.i){
Dear Mailing List Members,
the problem I've been grappling with für quite some time now is the following:
I have a 100 rows x 200 columns matrix.
data.set - matrix(rnorm(2, 100, 200))
Now I would like to get a vector of length 100 which collects the values from
the following procedure:
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