Re: [R] Fitting linear models

2009-04-21 Thread Vemuri, Aparna
the same result as before. Bert: This is not homework. But I will remember to do my research before posting here. Aparna -Original Message- From: David Winsemius [mailto:dwinsem...@comcast.net] Sent: Monday, April 20, 2009 5:35 PM To: Vemuri, Aparna Cc: r-help@r-project.org Subject: Re: [R

Re: [R] Fitting linear models

2009-04-21 Thread Vemuri, Aparna
The variables are all in separate vectors. -Original Message- From: Dimitri Liakhovitski [mailto:ld7...@gmail.com] Sent: Tuesday, April 21, 2009 8:26 AM To: Vemuri, Aparna Cc: David Winsemius; r-help@r-project.org Subject: Re: [R] Fitting linear models Aparna, I should have been more

Re: [R] Fitting linear models

2009-04-21 Thread Vemuri, Aparna
Yes, they are all of the same length. -Original Message- From: Dimitri Liakhovitski [mailto:ld7...@gmail.com] Sent: Tuesday, April 21, 2009 8:32 AM To: Vemuri, Aparna Cc: r-help@r-project.org Subject: Re: [R] Fitting linear models Are they of the same length? On Tue, Apr 21, 2009 at 11

Re: [R] Fitting linear models

2009-04-21 Thread Vemuri, Aparna
of the variables to have coefficients in the regression equation or a at least a consistent result, irrespective of the order of input information. -Original Message- From: David Winsemius [mailto:dwinsem...@comcast.net] Sent: Tuesday, April 21, 2009 8:38 AM To: Vemuri, Aparna Cc: r-help@r-project.org

Re: [R] Fitting linear models

2009-04-21 Thread Vemuri, Aparna
9:02 AM To: Vemuri, Aparna Cc: r-help@r-project.org; David Winsemius Subject: Re: [R] Fitting linear models I am not sure what the problem is. I found no errors: data-read.csv(file.choose()) # I had to change your file extension to .csv first dim(data) names(data) lapply(data,function(x){sum

Re: [R] Fitting linear models

2009-04-21 Thread Vemuri, Aparna
...@gmail.com] Sent: Tuesday, April 21, 2009 9:31 AM To: Vemuri, Aparna Subject: Re: [R] Fitting linear models Aparna, why are your IVs so highly intercorrelated? It's not a good sign... On Tue, Apr 21, 2009 at 12:29 PM, Dimitri Liakhovitski ld7...@gmail.com wrote: But if the multicollinearity is so

[R] Fitting linear models

2009-04-20 Thread Vemuri, Aparna
I am not sure if this is an R-users question, but since most of you here are statisticians, I decided to give it a shot. I am using the lm() function in R to fit a dependent variable to a set of 3 to 5 independent variables. For this, I used the following commands:

Re: [R] Controlling widths in write.fwf()

2009-04-15 Thread Vemuri, Aparna
Duncan I tried writeLines. But I need to print about 23 lines and it is really slow. Thanks Aparna -Original Message- From: Duncan Murdoch [mailto:murd...@stats.uwo.ca] Sent: Tuesday, April 14, 2009 4:34 PM To: Vemuri, Aparna Cc: r-help@r-project.org Subject: Re: [R] Controlling

Re: [R] Controlling widths in write.fwf()

2009-04-15 Thread Vemuri, Aparna
I was trying to format and write each line while looping over the entire matrix; which made it terribly slow. Without the loop, it works fine. Thanks Duncan. -Original Message- From: Duncan Murdoch [mailto:murd...@stats.uwo.ca] Sent: Wednesday, April 15, 2009 10:04 AM To: Vemuri, Aparna

[R] Controlling widths in write.fwf()

2009-04-14 Thread Vemuri, Aparna
Is there a way to handle the widths of values being written to a file using wrtite.fwf() ? For example, I used read.fwf(file, width.vector) to read a file. After making the necessary data manipulation, I want to write the data to a new file in the same width.vector format. Is there a way to

Re: [R] Controlling widths in write.fwf()

2009-04-14 Thread Vemuri, Aparna
[mailto:morse.bren...@gmail.com] Sent: Tuesday, April 14, 2009 5:35 PM To: Vemuri, Aparna Cc: r-help@r-project.org Subject: Re: [R] Controlling widths in write.fwf() Hi Aparna, you could always use the write.table function and set sep=. This will put all of your data into a sort of fixed-width column

[R] Large 3d array manipulation

2009-02-27 Thread Vemuri, Aparna
I have a large 3 dimensional array of size (243,246,768) The first dimension is Rows, second is columns and the third is Time. So for each row and column, I want to calculate the mean of time steps 1:8, 2:9, 3:10 and so on and assign the values to a new array. For this I am using the following

Re: [R] Tables in legend

2009-02-09 Thread Vemuri, Aparna
any ideas on how to do this. -Original Message- From: jim holtman [mailto:jholt...@gmail.com] Sent: Friday, February 06, 2009 4:52 PM To: Vemuri, Aparna Cc: r-help@r-project.org Subject: Re: [R] Tables in legend This will probably do what you need: plot(1) x - 1:10 # numbers

[R] Tables in legend

2009-02-06 Thread Vemuri, Aparna
I need to create a legend for a simple scatter plot in the following format. This is Blah1 number1 number2 This is Blah2 number3 number4 . . . This is Blah6 number11number12 I looked up these help pages and found the following solution. lStr-c(Blah1, Blah2,Blah6, number 1,

[R] Boxplots by variable

2009-02-02 Thread Vemuri, Aparna
Dear R users, I have a matrix final which looks like this: final oSO4 oNO3 mSO4 mNO3 [1,] 3.3728 0.2110 1.9517421 1.01883602 [2,] 0.8249 0.0697 1.5970292 0.11368781 [3,] 0.2636 0.1004 0.6012445 0.24356332 [4,] 8.0072 0.3443 6.1016998 3.63207149 [5,] 13.5079