Please give me some help, many thanks.
I graphed a expected CDF line of a binomial distribution on a graph,
And I have some observed points (observed CDF) from 4 groups fall on the
smooth CDF line.
I cannot really get the legend I want
legend ('topleft', c('a, 'b', 'c', 'd', 'expected CDF'),
Thanks in advance!
A=c(1, 2,3)
B=c (9, 10, 11, 12)
I want to get C=c(1*9, 1*10, 1*11, 1*12, ., 3*9, 3*10, 3*11, 3*12)?
C is still a vector with 12 elements
Is there a way to do that?
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Dear R experts,
Can R make an usual dotplot just like Minitab and other softwares?
I have the following data, and can use dotchart to graph a dotplot:
y=c(2.873438152e-01, -8.732895642e-01,
4.579001889e-01, 1.047395204e+00,
8.491182299e-02 , -1.938007105e+00,
-1.273708343e+00,
Hello,
This may be a rare question. I am struggling to solve it. I really
appreciate any help or suggestions. Thanks a lot in advance!
I put my questions between the code to make it clear. The problem I have is:
I generated 10 data sets with 8 data for each set. Now I want to change the
number
Petr,
Thanks for your suggestions. It makes sense, since I don't know how to make
a matrix with different length of rows.
I have a concern for this problem. I actually deal with a much bigger
dataset e.g. 1000, and each dataset needs to change the number of data in it
according a vector which
Hello, I am frastruated with this graph, just cannot get what I need. Thank
you for any suggestions or help. I really appreciate it. I wrote the
following code, but there are 3 problems
1, the red line is added on the graph but without any marker on the y-axis.
I want to display the number
# [3,] 5 1
cov(cbind(a, b))
# a b
# a 9.333 -0.667
# b -0.667 2.333
HTH,
Jorge
On Thu, Dec 3, 2009 at 11:29 PM, aegea wrote:
Hello,
Sorry. It may be a stupid question.
I have two vectors
a-c(9,3,5)
b-c(3,4,1)
How can I get
Thanks a lot, Jorge. It works well!
On Fri, Dec 4, 2009 at 12:00 AM, Jorge Ivan Velez [via R]
ml-node+948277-873392...@n4.nabble.comml-node%2b948277-873392...@n4.nabble.com
wrote:
Hi aegea,
Here is one:
m - structure(c(6, 5, 20, 7, 8, 25, 14, 8, 9, 10, 11, 12, 13, 14,
1, 2, 3, 4, 5, 6
Hello,
I am working on seperate the matrix to two matrices but got trouble on doing
it. Please give me some suggestions on doing this. Thanks a lot!
My original matrix m is as follows for example,
[,1] [,2] [,3]
[1,]681
[2,]592
[3,]20 103
[4,]
Hello,
Sorry. It may be a stupid question.
I have two vectors
a-c(9,3,5)
b-c(3,4,1)
How can I get the variance-covariance matrix of these two vectors?
I tried cov(a,b), I got a number not a matrix.
I tried to transpose vector a and b as t(a) and t(b), it still cannot work.
Any suggestions?
Hello,
I have a question on export and import data. Thank you for any suggestions.
data 'simul' is generated as follows:
N - 20
n - N/2
nsets - 10
simul - matrix(0,nsets,N)
th- c(0,1, 1)
for(i in 1:nsets){
simul[i,] - rnorm(N,mean= rep(th[1:2],N/2),sd=th[3])
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