y want a tibble that allows you
> to know what each row is for, consider one of many methods for saving the
> previous row names as a new column. I used that to take the data.frame
> version I made above and got:
>
> > temp <- as_tibble(result.df, rownames="rows")
I work with a list of crypto assets daily closing prices in a xts
class. Here is a limited example:
asset.xts.lst <- list(BTCUSDT = structure(c(26759.63, 26862, 26852.48, 27154.15,
27973.45), dim = c(5L, 1L), index = structure(c(1697068800, 1697155200,
1697241600, 1697328000, 1697414400), tzone =
Are you trying to test contrasts maybe? I would be surprised if
> the function for the statistical test you are trying to use does not
> deal with that already on its own.
>
> HTH,
> Ivan
>
>
> On 27/09/2023 13:01, arnaud gaboury wrote:
> > I have two data.frames:
>
I have two data.frames:
mydf1 <- structure(list(symbol = "ETHUSDT", cummulative_quote_qty =
1999.9122, side = "BUY", time = structure(1695656875.805, tzone = "", class
= c("POSIXct", "POSIXt"))), row.names = c(NA, -1L), class = c("data.table",
"data.frame"))
mydf2 <- structure(list(symbol =
I have a list of 9 lists called my.list. Each one of these 9 lists is
itself a list of 6 data.frames. Most of these data.frames have 0 rows and 0
columns.
I want to return all data.frames from the list with row numbers different
from 0.
I first created the following function:
non_empty_df <-
I need to download basic OHLCV (Open, High, Low, Close, Volume) in a
hourly format from various cryptocurrency exchanges.
There is the crypto package[0] but it has been removed from CRAN. Then
there is the coinmarketcapr[1] package on CRAN, but it is limited to a
paid service, coinmarketcap, which
Here is a sample of my data frame, obtained with read_csv2 from readr package.
myDf <- structure(list(X15 = c("30.09.2015", "05.10.2015", "30.09.2015",
"29.09.2015", "10.10.2015"), X16 = c("02.10.2015", "06.10.2015",
"01.10.2015", "01.10.2015", "13.10.2015"), X17 = c("Grains",
"Grains",
On Thu, Dec 10, 2015 at 12:54 PM, Duncan Murdoch <murdoch.dun...@gmail.com>
wrote:
> On 10/12/2015 6:12 AM, arnaud gaboury wrote:
>
>> Here is a sample of my data frame, obtained with read_csv2 from readr
>> package.
>>
>> myDf <- structure(list(X15 = c(
On Thu, Dec 10, 2015 at 1:47 PM, Giorgio Garziano <
giorgio.garzi...@ericsson.com> wrote:
> my_convert <- function(col) {
> v <- grep("[0-9]{2}.[0-9]{2}.[0-9]{4}", col);
> w <- grep("[0-9]+,[0-9]+", col)
> col2 <- col
> if (length(v) == length(col)){
> col2 <- as.Date(col,
I was doing some cleaning ony my linux machine and, among others, I
try to clean my R environment variables accordingly [0] and [1].
I am not really sure how to declare in a clean manner these startup variables.
Here is my setup:
1- my home folder
-$ ls ~/.config/R
env/ helper/ Renviron
I want to build R with an optimized BLAS library.
My OS: Fedora 22
Hardware: CPU op-mode(s): 32-bit, 64-bit Byte Order: Little Endian
CPU(s): 8 Thread(s) per core: 2 Vendor ID: GenuineIntel Model name:
Intel(R) Core(TM) i7-2600K CPU @ 3.40GHz
I am a little confused when it comes to choose a
#. rocks...1k
---
Sent from my phone. Please excuse my brevity.
On August 22, 2015 7:51:39 AM PDT, arnaud gaboury arnaud.gabo...@gmail.com
wrote:
I want to build R with an optimized BLAS library.
My OS: Fedora 22
Hardware: CPU op-mode
On Sun, Aug 16, 2015, 2:29 PM Swagato Chatterjee swagato1...@gmail.com
wrote:
Hello,
I have written a R script which runs a regression of a dataset and saves
the result in a csv file.
Now this dataset has to be edited periodically which is done in a server. I
need to run the R script in a
R 3.2.0 on Linux
library(tidyr)
playerStats - c(LVL 10, 5,671,448 AP l6,000,000 AP, Unique
Portals Visited 1,038,
XM Collected 15,327,123 XM, Hacks 14,268, Resonators Deployed 11,126,
Links Created 1,744, Control Fields Created 294, Mind Units
Captured 2,995,484
, arnaud gaboury
arnaud.gabo...@gmail.com wrote:
On Mon, Apr 20, 2015 at 9:10 AM, arnaud gaboury
arnaud.gabo...@gmail.com wrote:
R 3.2.0 on Linux
library(tidyr)
playerStats - c(LVL 10, 5,671,448 AP l6,000,000 AP, Unique
Portals Visited 1,038,
XM Collected
On Mon, Apr 20, 2015 at 9:10 AM, arnaud gaboury
arnaud.gabo...@gmail.com wrote:
R 3.2.0 on Linux
library(tidyr)
playerStats - c(LVL 10, 5,671,448 AP l6,000,000 AP, Unique
Portals Visited 1,038,
XM Collected 15,327,123 XM, Hacks 14,268, Resonators Deployed
, Apr 20, 2015 at 12:10 AM, arnaud gaboury arnaud.gabo...@gmail.com
wrote:
R 3.2.0 on Linux
library(tidyr)
playerStats - c(LVL 10, 5,671,448 AP l6,000,000 AP, Unique
Portals Visited 1,038,
XM Collected 15,327,123 XM, Hacks 14,268, Resonators Deployed
On Thu, Apr 16, 2015 at 3:25 PM, arnaud gaboury arnaud.gabo...@gmail.com
wrote:
On a Linux 64 bits, R.3.1.2, with tidyr() loaded.
gabx@hortensia [R] separate(rawStats, 'toto')
Error in dyn.load(file, DLLpath = DLLpath, ...) :
unable to load shared object
'/developement/language/r/library
On a Linux 64 bits, R.3.1.2, with tidyr() loaded.
gabx@hortensia [R] separate(rawStats, 'toto')
Error in dyn.load(file, DLLpath = DLLpath, ...) :
unable to load shared object
'/developement/language/r/library/stringi/libs/stringi.so':
libicui18n.so.54: cannot open shared object file: No such
On Tue, Apr 14, 2015 at 10:09 PM, John Sorkin
jsor...@grecc.umaryland.edu wrote:
I suggest that you investigate installing RStudio server on the Linux
Box. If you do this, you can logon to RStudio (on the Linux server), and
it will look exactly like RStudio running on a windows box. You may
On Tue, Apr 14, 2015 at 7:09 PM, Sarah Goslee sarah.gos...@gmail.com wrote:
Hi Michael,
On Tue, Apr 14, 2015 at 12:57 PM, Michael Haenlein
haenl...@escpeurope.eu wrote:
Dear all,
I am used to running R locally on my Windows-based PC. Since some of my
computations are taking a lot of
I have been searching for a while now, but can't put all pieces of the
puzzle together.
Goal : I want to replace all these kinds of patterns @U032FHV3S by
this @agreenmamba. In a more generic way, it is replacing 'id' by
user 'name'.
I have two df:
The first, 'history', is some message history
This is the wrong part of my code.
idName=users[users$id %in% ext]
idname
1: U03AEKWTL agreenmamba
2: U032FHV3S poisonivy
3: U03AEKYL4 vairis
Best is to use:
idNames - users[pmatch(ext, users$id, duplicates.ok = T)]. This leave
me with an ordered and duplicate
On Thu, Feb 12, 2015 at 3:40 PM, arnaud gaboury
arnaud.gabo...@gmail.com wrote:
I have two df (and dt):
df1
structure(list(name = c(poisonivy, poisonivy, poisonivy,
poisonivy, poisonivy, poisonivy, poisonivy, poisonivy,
cruzecontrol, agreenmamba, agreenmamba, vairis, vairis,
vairis, vairis
On Thu, Feb 12, 2015 at 7:12 PM, arnaud gaboury
arnaud.gabo...@gmail.com wrote:
On Thu, Feb 12, 2015 at 3:40 PM, arnaud gaboury
arnaud.gabo...@gmail.com wrote:
I have two df (and dt):
df1
structure(list(name = c(poisonivy, poisonivy, poisonivy,
poisonivy, poisonivy, poisonivy, poisonivy
I am little lost between all the possibilities to apply a function to
a data.frame or data.table.
Here is mine:
structure(list(name = c(poisonivy, poisonivy, poisonivy,
poisonivy, poisonivy, poisonivy, poisonivy, poisonivy,
cruzecontrol, agreenmamba, agreenmamba, vairis, vairis,
vairis, vairis,
I have two df (and dt):
df1
structure(list(name = c(poisonivy, poisonivy, poisonivy,
poisonivy, poisonivy, poisonivy, poisonivy, poisonivy,
cruzecontrol, agreenmamba, agreenmamba, vairis, vairis,
vairis, vairis, vairis, vairis, xaeth), text = c(ok,
need items ?, i didn't submit pass codes for a
gabx@hortensia [R] sessionInfo()
R version 3.1.2 (2014-10-31)
Platform: x86_64-unknown-linux-gnu (64-bit)
locale:
[1] LC_CTYPE=en_US.UTF-8 LC_NUMERIC=C
LC_TIME=en_US.UTF-8LC_COLLATE=en_US.UTF-8
LC_MONETARY=en_US.UTF-8
[6] LC_MESSAGES=en_US.UTF-8LC_PAPER=en_US.UTF-8
On Thu, Oct 2, 2014 at 4:54 AM, Jason Eyerly teamtraders3...@gmail.com wrote:
A lot of excellent suggestions! Thank you everyone for the input. I’ve
purchased via Amazon:
A Beginner's Guide to R by Zuur
Data Manipulation with R by Spector
“Introductory Statistics with R.” by Peter Dalgaard
I got the benchmark script, which I've attached, from Texas Advanced
Computing Center. Here are my results (elapsed times, in secs):
Where can we get the benchmark script?
__
R-help@r-project.org mailing list
The best that I can see for R would be if someone were to post a how
to use MKL for compiling R type document.
I build R with MKL and ICC on my Archlinux box[1][2].
If I can help in anything, I will do it.
[1]https://wiki.archlinux.org/index.php/R
[2]https://aur.archlinux.org/packages/r-mkl/
On Thu, Aug 28, 2014 at 11:45 AM, Martin Spindler
spind...@mea.mpisoc.mpg.de wrote:
Dear all,
I would like to us openBLAS in R under Linux / Unix.
Which steps do I have to undertake? Does someone know a detailed
description? (I found some sources on the web, but none was really
helpful for
On Fri, Aug 22, 2014 at 2:03 PM, S Ellison s.elli...@lgcgroup.com wrote:
We are currently trying to migrate 3 users of R to a citrix based
environment, but are coming across major issues trying to install the
packages to the relevant image.
Please be more precised in your issue.
A directory is full of data.frames cache files. All these files have
the same pattern:
df.some_name.RData
my.cache.list - c(df.subject_test.RData, df.subject_train.RData,
df.y_test.RData,
df.y_train.RData)
I want to keep only the part inside the two points. After lots of
headache using grep()
R as.vector(sapply(my.cache.list, function(x)strsplit(x, \\.)[[1]][2]))
[1] subject_test subject_train y_testy_train
R gsub(df\\.(.*)\\.RData, \\1, my.cache.list)
[1] subject_test subject_train y_testy_train
Note that . will match any character, while \\. matches a
TY very much for your setdiffDF(). It does the job perfectly.
Arnaud Gaboury
A2CT2 Ltd.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Petr Savicky
Sent: lundi 27 février 2012 20:41
To: r-help@r-project.org
Subject: Re: [R
= c(NA, 9L), class = data.frame)
As you can see, they have same column names.
My idea was to merge these two df when passing as argument not to take into
account duplicate rows, so I will get one df with rows which are not in both
df.
Is it possible? How to do it?
TY for any help.
Arnaud
I don't understand where is your problem. Are you looking for jaunty as a
package on R Crans?? Are you looking to install R package on your Ubuntu box?
As you know, Jaunty is no more supported by Ubuntu, so packets have been moved
in Archives.
Arnaud Gaboury
A2CT2 Ltd.
-Original
, 24.81, 1273.5, 1276.25), Nbr.Lots = c(-61, -61, 6, 40,
40, -1, -1, -1, 1, -61, -61, 5, 1, 40, 40, -1, -1, -1, 1)), .Names =
c(Product,
Price, Nbr.Lots), row.names = c(1, 2, 3, 4, 5,
6, 7, 8, 9, 11, 21, 31, 41, 61, 71, 51,
10, 81, 91), class = data.frame)
TY for your help
Arnaud Gaboury
A2CT2
dimension (I can add some
lines to deal with it, but again, seems very heavy).
I hoped I could find a better solution.
A2CT2 Ltd.
-Original Message-
From: jim holtman [mailto:jholt...@gmail.com]
Sent: lundi 27 février 2012 18:42
To: Arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R
.
TY for any help.
Trading
A2CT2 Ltd.
Arnaud Gaboury
A2CT2 Ltd.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented
TY Uwe,
So I will have to write a line for each condition? Right?
In fact I was trying to do something with apply in one line, but couldn't
achieve any result. In fact, all my transformation will be multiplying one
object by a specific number according to the value of df$x.
Arnaud Gaboury
this as result :
df
x y
1 AA 10 if df$x==AA, df$y-1*10
2 BB 50 if df$x==BB, df$y-2*25
3 CC 3 NOTHING
4 AA 40 if df$x==AA, df$y-4*10
5 DD 75 if df$x==DD, df$y-5*15
6 DD 90 if df$x==DD, df$y-6*15
Arnaud Gaboury
A2CT2 Ltd.
-Original Message
clear enough, and YES I have tried many workarounds myself before
posting. Feel free to ignore my post if you think I am lazy and disrespectful
to the list.
Arnaud Gaboury
A2CT2 Ltd.
-Original Message-
From: Uwe Ligges [mailto:lig...@statistik.tu-dortmund.de]
Sent: vendredi 24 février
, 14L, 15L, 16L, 17L, 18L,
19L, 8L, 9L, 10L, 11L, 12L, 20L, 21L, 22L, 23L, 35L, 36L, 37L,
38L, 39L, 40L, 41L, 42L, 31L, 32L, 24L, 25L, 26L, 27L, 28L, 29L,
30L, 2L, 3L, 1L, 33L, 34L), class = data.frame)
Have a good weekend.
Arnaud Gaboury
A2CT2 Ltd.
Trade: +41 22 849 88 63
Fax: +41 22 849 88
WORKING
Now day 2 with df2:
df2 - data.frame(x = c(AA,AA,BB,BB,BB,CC,DD,DD), y = 1:8)
df2$y - df2$y * mult[as.character(df2$x)]
df2
x y
1 AA 2
2 AA 4
3 BB 15
4 BB 20
5 BB 25
6 CC 6
7 DD 14
8 DD 16
WORKING
Ty both of you and have a good weekend.
Arnaud Gaboury
A2CT2 Ltd
the openJDK path in your
environment.
Hope this help.
Arnaud Gaboury
A2CT2 Ltd.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of John Kane
Sent: vendredi 24 février 2012 19:32
To: r-help@r-project.org
Subject: [R] install
TY Elai for your answer. One solution has been given earlier in this list by
Sarah Goslee and William Dunlap.
Arnaud Gaboury
A2CT2 Ltd.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of ilai
Sent: vendredi 24 février 2012 20:14
and renamed it Nbr.Lots. This line works.
What I would like is changing the col names in the same line, thus avoiding
another line with
colnames(exportfile)-c(Contract,Price,Nbr.Lots)
Is there a possibility to change my col names in the same line?
TY
Arnaud Gaboury
A2CT2 Ltd
, but with an Error.
Why?
TY for any help
Arnaud Gaboury
A2CT2 Ltd.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self
TY much.
Works for me.
Arnaud Gaboury
A2CT2 Ltd.
-Original Message-
From: R. Michael Weylandt [mailto:michael.weyla...@gmail.com]
Sent: jeudi 9 février 2012 17:47
To: Arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] ifelse
cat() returns a null value so it's problematic
package: MASS
Loading required package: nnet
YOU DID A GOOD JOB,SEND EMAIL
Last line is the supposed result of my function, so it ok.
How to get rid of the first two lines, only for esthetic purpose?
TY for your time.
Arnaud Gaboury
A2CT2 Ltd.
__
R
TY for your answer, but here what i did :
#load needed lybrary
suppressPackageStartupMessages(library(plyr))
suppressPackageStartupMessages(library(car))
library(plyr)
library(car)
But I still get :
Loading required package: MASS
Loading required package: nnet
Arnaud Gaboury
A2CT2 Ltd
Ah, I feel stupid!
OK, it works for me.
TY for your help
Arnaud Gaboury
A2CT2 Ltd.
-Original Message-
From: Sarah Goslee [mailto:sarah.gos...@gmail.com]
Sent: jeudi 9 février 2012 20:02
To: Arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] loading packages in a function
names1-recode(df$names,'BO'='BOO';'CL'='CLR';'C'='CC')
df1-data.frame(names1,price)
df1
names1 price
1BOO10
2 CC25
3CLR20
TY for the tip.
Any possibility to write this in one single line?
Arnaud Gaboury
A2CT2 Ltd.
-Original Message-
From: Berend Hasselman
.
All numbers are in fact 2.1/4, 2.1/2, 2.3/4.
How can I tell R 2.2 is 2.25, 2.4 is 2.50 and 2.6 is 2.75 ?
TY for any help.
Arnaud Gaboury
A2CT2 Ltd.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
TY Jim,
It do the trick.
I was trying to play without success with the format() options.
No simplest way so?
Arnaud Gaboury
A2CT2 Ltd.
-Original Message-
From: jim holtman [mailto:jholt...@gmail.com]
Sent: mercredi 8 février 2012 15:36
To: Arnaud Gaboury
Cc: r-help@r-project.org
David,
You are not far indeed, as I trade commodities, and prices are the ones from
grain market: Corn, wheat and Soybeans.
They are quoted in 1/4, and my trading platform displays them in 2,4,6 and my
statements are in 25,50,75.
TY
Arnaud Gaboury
A2CT2 Ltd.
-Original Message
Thanks so much Peter. You are the man.
Easy way and working for me.
Arnaud Gaboury
A2CT2 Ltd.
-Original Message-
From: peter dalgaard [mailto:pda...@gmail.com]
Sent: mercredi 8 février 2012 16:15
To: David Reiner
Cc: Arnaud Gaboury; jim holtman; r-help@r-project.org
Subject: Re: [R
But my df is bigger indeed with other elements.
I was thinking using replace(), but can't get any clean result ( NA or all
elements replaced with only one), neither with sapply().
TY for any help, and sorry for the n00b question.
Arnaud Gaboury
A2CT2 Ltd
As you can see, BO has been replaced by BOO, but with a warning!
Arnaud Gaboury
A2CT2 Ltd.
Trade: +41 22 849 88 63
Fax: +41 22 849 88 66
arnaud.gabo...@a2ct2.com
This email and any files transmitted with it are confidential and intended
solely for the use of the individual or entity
I used in fact recode() from epilcac package, not the one you mentioned!
Arnaud Gaboury
A2CT2 Ltd.
-Original Message-
From: Arnaud Gaboury
Sent: mardi 7 février 2012 20:25
To: Jorge I Velez
Cc: r-help@r-project.org; Arnaud Gaboury
Subject: RE: [R] replace elements of a data frame
I
Dear list,
here are my two data frames:
av -
structure(list(DESCRIPTION = c(COFFEE C Sep/10, COPPER Sep/10,
CORN Dec/10, CRUDE OIL miNY Sep/10, GOLD Aug/10, HENRY HUB
NATURAL GAS Sep/10,
PALLADIUM Sep/10, SILVER Sep/10, SOYBEANS Nov/10, SPCL HIGH
GRADE ZINC USD,
SUGAR NO.11 Oct/10, WHEAT
/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
**
Arnaud Gaboury
Mobile: +41 79 392 79 56
BBM: 255B488F
Dear group,
Here is a list of elements :
l -
c(100415, 100416, 100419, 100420, 100421, 100422,
100423, 100426, 100427, 100428, 100429, 100430, 100503,
100504, 100505, 100506, 100507, 100510, 100511, 100512,
100513, 100514, 100517, 100518, 100519, 100520, 100521,
100524, 100525, 100526,
The correct line is :
l[(which(100420==l)-1):which(100420==l)]
[1] 100419 100420
-Original Message-
From: arnaud Gaboury [mailto:arnaud.gabo...@gmail.com]
Sent: Wednesday, June 02, 2010 9:41 AM
To: r-help@r-project.org
Cc: 'arnaud Gaboury'
Subject: which function
Dear group
I do really think it is a very good idea.
TY
-Original Message-
From: h.wick...@gmail.com [mailto:h.wick...@gmail.com] On Behalf Of
Hadley Wickham
Sent: Wednesday, June 02, 2010 3:31 PM
To: arnaud Gaboury
Cc: Peter Ehlers; r-help@r-project.org; Prof Brian Ripley
Subject: Re: [R
Dear group,
Here is my environment:
ls()
[1] DailyPL100419 DailyPL100420 DailyPL100421 ddi
l PLglobal Pos100416 Pos100419 Pos100420
Pos100421 position
[13] resultsel Trad100416Trad100419
Trad100420Trad100421trade
With
Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Wednesday, June 02, 2010 4:48 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] bind select data frames
Hello,
Does this do what you are looking for?
output - NULL
for(i in paste(DailyPL, sel, sep=)[-1
-Original Message-
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Wednesday, June 02, 2010 4:48 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] bind select data frames
Hello,
Does this do what you are looking for?
output - NULL
for(i in paste
= ), envir =
.GlobalEnv), :
unused argument(s) (row.names = NULL)
Why this error?
TY for your help
-Original Message-
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Wednesday, June 02, 2010 5:08 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] bind
Here we go :
dd-data.frame(do.call(rbind,
mget(paste(DailyPL,sel[-1],sep=),envir=.GlobalEnv)),row.names=NULL)
TY so much Joshua and Jorge.
-Original Message-
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Wednesday, June 02, 2010 5:11 PM
To: arnaud Gaboury
Cc: r-help@r
Jorge,
Your line works and give the desired result. Now I need to be able to work
with i instead of 100419..., as I need to be able to change these numbers.
TY for your help
From: Jorge Ivan Velez [mailto:jorgeivanve...@gmail.com]
Sent: Wednesday, June 02, 2010 5:09 PM
To: arnaud Gaboury
Cc
Dear group,
Here is the kind of data.frame I obtain every day with my function :
futures -
structure(list(DESCRIPTION = c(CORN Jul/10, CORN Jul/10,
CORN Jul/10, CORN Jul/10, CORN Jul/10, LIVE CATTLE Aug/10,
LIVE CATTLE Aug/10, SUGAR NO.11 Jul/10, SUGAR NO.11 Jul/10,
SUGAR NO.11 Jul/10, SUGAR
To: arnaud Gaboury
Subject: Re: [R] data frame manipulation with zero rows
On Tue, 1 Jun 2010, arnaud Gaboury wrote:
Dear group,
Here is the kind of data.frame I obtain every day with my function :
futures -
structure(list(DESCRIPTION = c(CORN Jul/10, CORN Jul/10,
CORN Jul/10
Dear group,
Here is my data frame:
futures -
structure(list(DESCRIPTION = c(CORN Jul/10, CORN Jul/10,
CORN Jul/10, CORN Jul/10, CORN Jul/10, LIVE CATTLE Aug/10,
LIVE CATTLE Aug/10, SUGAR NO.11 Jul/10, SUGAR NO.11 Jul/10,
SUGAR NO.11 Jul/10, SUGAR NO.11 Jul/10, SUGAR NO.11 Jul/10
),
...@uni-bremen.de]
Sent: Tuesday, June 01, 2010 11:38 AM
To: arnaud Gaboury
Subject: Re: [R] data frame manipulation ddply
Hi Arnaud,
maybe aggregate can help:
PosFut - aggregate(futures$QUANTITY, list(DESCRIPTION =
futures$DESCRIPTION,
SETTLEMENT
It is indeed ddply() from package plyr.
-Original Message-
From: Prof Brian Ripley [mailto:rip...@stats.ox.ac.uk]
Sent: Tuesday, June 01, 2010 12:24 PM
To: Peter Ehlers
Cc: arnaud Gaboury; r-help@r-project.org
Subject: Re: [R] data frame manipulation with zero rows
On Tue, 1
Dear group,
Here is my df (obtained with a read.csv2()):
df -
structure(list(DESCRIPTION = c(COTTON NO.2 Jul/10, COTTON NO.2 Jul/10,
PALLADIUM Jun/10, PALLADIUM Jun/10, SUGAR NO.11 Jul/10,
SUGAR NO.11 Jul/10), CREATED.DATE = c(13/05/2010, 13/05/2010,
14/05/2010, 14/05/2010, 10/05/2010,
TY for the tip. The lower case is in fact the culprit.
-Original Message-
From: Erik Iverson [mailto:er...@ccbr.umn.edu]
Sent: Tuesday, June 01, 2010 6:05 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] as.date
Where does the problem comes from?? Maybe from
Maybe not the cleanest way, but I create a fake data frame with one row so
ddply() is happy!!
if (nrow(futures)==0) futures-data.frame(...)
-Original Message-
From: Peter Ehlers [mailto:ehl...@ucalgary.ca]
Sent: Tuesday, June 01, 2010 12:07 PM
To: arnaud Gaboury
Cc: 'Prof
Thank you for the answer.
Is there any way to combine if() and switch() in one line? In my case,
something like :
if(trade$Trade.Status==DEL)switch(.)
I would like to avoid the loop .
From: Joris Meys [mailto:jorism...@gmail.com]
Sent: Wednesday, May 26, 2010 9:15 PM
To: arnaud Gaboury
Dear group,
Here is my df :
trades -
structure(list(Trade.Status = c(DEL, INS, INS), Instrument.Long.Name =
c(SUGAR NO.11,
CORN, CORN), Delivery.Prompt.Date = c(Jul/10, Jul/10,
Jul/10), Buy.Sell..Cleared. = c(Sell, Buy, Buy), Volume = c(1L,
2L, 1L), Price = c(15.2500, 368., 368.5000),
.
NULL
That's certainly not what I want.
From: Joris Meys [mailto:jorism...@gmail.com]
Sent: Thursday, May 27, 2010 8:43 AM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] data frame manipulation change elements meeting criteria
The loop is due to the switch statement
..sum.
NULL
That's certainly not what I want.
From: Joris Meys [mailto:jorism...@gmail.com]
Sent: Thursday, May 27, 2010 8:43 AM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] data frame manipulation change elements meeting criteria
The loop is due to the switch statement
, Instrument.Long.Name,
Delivery.Prompt.Date, Buy.Sell..Cleared., Volume, Price,
Net.Charges..sum.), row.names = c(NA, 3L), class = data.frame)
From: Joris Meys [mailto:jorism...@gmail.com]
Sent: Thursday, May 27, 2010 10:38 AM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] data frame
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] data frame manipulation change elements meeting criteria
Off course. You put in a matrix to sapply, but sapply is for vectors. You
want to apply the switch command on every entry of the vector
trades$Buy.Sell..Cleared for which trades
,
Instrument.Long.Name, Delivery.Prompt.Date, Buy.Sell..Cleared.,
Volume, Price, Net.Charges..sum.), row.names = c(NA, 3L), class =
data.frame)
From: Joris Meys [mailto:jorism...@gmail.com]
Sent: Thursday, May 27, 2010 10:38 AM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] data frame
: Thursday, May 27, 2010 2:34 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] switch function
try this:
toBuy - trades$Trade.Status == DEL trades$Buy.Sell..Cleared. ==
Sell
toSell - trades$Trade.Status == DEL trades$Buy.Sell..Cleared. ==
Buy
x - trades # make a copy
Dear group,
Here is my function:
#return the daily PL for day y
PLDaily-function(x,y)
{
#find elements in my directory with LSCPos in the name, keep the numeric
part in the name and
#create a list
l-gsub(\\D,,dir()[grep(LSCPos,dir())])
#select in the list the desired elements
help is appreciated
***
Arnaud Gaboury
Mobile: +41 79 392 79 56
BBM: 255B488F
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting
Oops, forgot to give a subject
-Original Message-
From: arnaud Gaboury [mailto:arnaud.gabo...@gmail.com]
Sent: Wednesday, May 26, 2010 2:31 PM
To: r-help@r-project.org
Cc: 'arnaud Gaboury'
Subject:
Dear group,
Here is my data frame:
dput(u)
structure(list(DESCRIPTION
element different from zero).
From: Joris Meys [mailto:jorism...@gmail.com]
Sent: Wednesday, May 26, 2010 2:48 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] (no subject)
What exactly are you trying to do? If you want to know which position is
wrong, try :
if (sum(u$POSITION
Dear group,
Here is my df :
trade -
structure(list(Trade.Status = c(DEL, INS, INS), Instrument.Long.Name =
c(SUGAR NO.11,
CORN, CORN), Delivery.Prompt.Date = c(Jul/10, Jul/10,
Jul/10), Buy.Sell..Cleared. = c(Sell, Buy, Buy), Volume = c(1L,
2L, 1L), Price = c(15.2500, 368., 368.5000),
Dear group,
I have a function, let's call it myfun, wich give me a list of result:
R1,R2,R3...
There is a loop in this function to get my results. Here is the structure of
my function:
Myfun-function()
{
For (i in X ){
---instructions-
Ri
{
{
All Results (R1,R2...) are
,] DailyPL100416 DailyPL100419 DailyPL100420
That's not what I want! I expect DF to be a data.frame binded by row.
I suspect there is an issue with get() or assign(), or something like that.
Any help is appreciated.
-Original Message-
From: arnaud Gaboury [mailto:arnaud.gabo...@gmail.com
Maybe is there a neater solution, but the function mget() does the trick. So
until further advice, I will work with your solution.
Thank you
-Original Message-
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Monday, May 24, 2010 5:07 PM
To: arnaud Gaboury
Cc: r-help@r
Do you think there is a way to add somewhere the argument row.names=NULL ? Or
should I have to write another line to remove the row.names?
-Original Message-
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Monday, May 24, 2010 5:07 PM
To: arnaud Gaboury
Cc: r-help@r
Dear group,
Here is my environment after I run a function, myfun()
myfun()
ls()
[1] allconavprix16 DailyPL100416 DailyPL100419
DailyPL100420 l llmyl PL
PLdaily PLglobal PLmonthly
[13] Pos100415 Pos100416 Pos100419
Thank you so much. You are totally right.
-Original Message-
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Monday, May 24, 2010 6:33 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] writing function
My guess is that either ls(), called inside grep
1 - 100 of 150 matches
Mail list logo
