Actually, let's set it
grid_new.l <- list(abcissa=c(-15.0,-14.5),ordinate=y)
to avoid out of bounds
On Tue, Dec 25, 2018 at 4:41 PM M P wrote:
> Thanks, Eric, for looking into that.
> The values are below and since I subset the new abcissa is smaller range
> grid_new.l <- list(
atted emails are not passed
> along.
>
>
>
> On Tue, Dec 25, 2018 at 4:13 AM M P wrote:
>
>> Hello,
>> I used commands below to obtain a surface, can plot it and all looks as
>> expected.
>> How do I evaluate values at new point. I tried as below but that produ
Hello,
I used commands below to obtain a surface, can plot it and all looks as
expected.
How do I evaluate values at new point. I tried as below but that produces
errors.
Thanks for suggestions/help.
x <- log(lambda)
y <- rh
z <- qext[,,2]
grid.l <- list(abcissa=x,ordinate=y)
xg <-
Hello,
It should be easu but I cannot figure out how to use apply function. I am
trying to replace negative values in an array with these values + 24.
Would appreciate help. Thanks,
Mark
shours - apply(fhours, function(x){if (x 0) x - x+24})
Error in match.fun(FUN) : argument FUN is missing,
Hello,
my series of dates look like
[1] 2012-05-30 18:30:00 UTC 2012-05-30 19:30:00 UTC
[3] 2012-05-30 20:30:00 UTC 2012-05-30 21:30:00 UTC
[5] 2012-05-30 22:30:00 UTC 2012-05-30 23:30:00 UTC
[7] 2012-05-31 00:30:00 UTC 2012-05-31 01:30:00 UTC
[9] 2012-05-31 02:30:00 UTC 2012-05-31
Thats works perfectly, thanks a lot,
Mark
On Thu, Dec 13, 2012 at 11:34 AM, arun smartpink...@yahoo.com wrote:
Hi,
Try this:
seq1-seq(from=as.POSIXct(2012-05-30
18:30:00,tz=UTC),to=as.POSIXct(2012-05-31 02:30:00,tz=UTC),by=1
hour)
seq2-seq(from=as.POSIXct(2012-05-31
Hello,
I have a problem writing a variable to an existing file.
Below is a part of my script and how it fails.
I can't find create.var.ncdf in help
Thanks for any help.
Mark
nc - open.ncdf(ncname, readunlim=FALSE, write=TRUE )
missing - 1.e+30
xdim - nc$dim[[west_east]]
ydim -
Hello,
I used correlogram from spatial package to determine correlation scale
for my data but just looking with bare eye it seems that the correlation
scale varies over the domain.
Can someone suggest what would the best way to handle that problem?
Thanks,
Mark
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Hello,
I'd like to check if my data can be well approximated with a function
(1+x/L) exp(-x/L)
and calculate the best value for L. Is there some package in R that would
simplify that task?
Thanks,
Mark
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