Hi,
I am interested in running sensitivity analysis (variance-based). But
instead of running Monte Carlo simulations in R, I already have my sample
data in two tables.
So how do I run Sobol on my own data then? Does that mean that the model =
null? And then to use tell()? I cannot find any exampl
Hello list,
I am trying to avoid "Rifying" some of my SAS code to generate ROC
plots, and the logistic.display() and lroc() functions in the epicalc
package do what I want. However, I must generate my logistic model
with bigglm because I have 1) limited hardware, 2) ~2.5 million rows,
and 4 categ
Hello R Experts,
How can I assign the name of a data frame with the argument of a
function? Specifically I am using RODBC to build local dataframes
from SAS datasets on a
remote server. I would like the local dataframe have the same name as
the source SAS dataset, and the function below is what
Thank you - zoo did exactly what I needed...
On Jan 20, 12:20 pm, Henrique Dallazuanna wrote:
> Try the zoo package:
>
> plot(as.yearqtr(time.val), inc, col = 'red', type = 'l')
>
>
>
> On Wed, Jan 20, 2010 at 3:41 PM, mah wrote:
> > I am tryi
I am trying to generate a line graph with quarterly time buckets (with
nice labels) on the x-axis. The first block of code below will
generate the graph with nicely formatted x-axis labels, but the
"type=" and "col=" options are not recognized when factors are used
for the x-axis.
The second bloc
If the desired end-state is a regression model and the appropriate
diagnostics, the Rcmdr package contains the necessary tools. Rcmdr is
available for many Linux distribuitons as well as for Windows, and it
is able to do much more than import-and-regress. I think the package
was built from Tcl/Tk
I am confuse by the results of the weights option for coxph. I
replicated each row three times from the help page for coxph in the
data frame test_freq. I had expected that the coefficients,
significance tests, and tests of non-proportionality would yield the
same results for the replicated and
Survfit returns an "Error in temp[, 1] : incorrect number of
dimensions" error message when I attempt to use newdata to validate my
models. The syntax I am using is "sfit <- survfit(mod1,
newdata=testd, individual=T)". The dataframe testd has two columns
and 39 rows (see below). The rows are th
s and then derive/extract what you need.
>
> --Matt
>
> Matt Austin
> Global Statistical Leader, denosumab PMO
> Biostatistics Director
> Amgen, Inc
>
>
>
> -Original Message-
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of mah
> Sent: Mo
t;
Mike
On Apr 7, 11:43 am, Roland Rau <[EMAIL PROTECTED]> wrote:
> Hi,
>
> just looked at it briefly and I don't know if it is the real cause for
> your problems. But 'data' as well as 'newdata' require a data.frame and
> not a list
I am unable to get the basehaz function to apply a proportional
hazards model to a new data frame. I replicated my specific situation
with the example for coxph in the help, where I changed the x value of
the first record from 0 to 1. Is there something incorrect in the
syntax that I am using? T
11 matches
Mail list logo
