Dear R users.
I would like to remove all object from my workspace except the function I have
defined. However, is I use rm(list = ls()) everything is cleared. I was
thinking to typeof to get information about objects, but I could not get it
working right.
Thank in advance,
Phil
Hi all.
How we evaluate a formula in R?
Ex.:
params - list(a = 2, b = 3)
x - seq(1,10, length.out = 100)
func1 - as.formula(y ~ a*x^2 + b*x)
##How to evaluate func1 using x and the params list
???
Thank you in advance,
Phil
[[alternative
Hi everyone, I have a formula like this:
f - as.formula(y ~ p0a * exp(-0.5 * ((x - p1a)/p2a)^2))
I would like to dynamically provide starting values for p0a, p1a, p2a. Is
there a way to do it?
#Params estimates
p - c(12, 10, 1)
# This is where I have difficulties
mystart - substitute(...)
Thank you!
Date: Wed, 3 Dec 2014 08:02:17 -0500
From: murdoch.dun...@gmail.com
To: pmassico...@hotmail.com; r-help@r-project.org
Subject: Re: [R] Substitute initial guesses of parameters in a function
On 03/12/2014 7:37 AM, philippe massicotte wrote:
Hi everyone, I have a formula like
Hi everyone.
I have a non-linear model specified as this (6 variables, a0, S, K, p0, p1, p2):
fit - nlsLM(formula = dat ~ a0 * exp(-S*(x - 250)) + K + ( C ) )
where C = (p0*exp(-0.5*((x-p1)/p2)^2))
The problem is that I do not know in advance how many component (C) I will have
in the model.
Hi all.
I'm ploting a raster and I can't find the proper way to move the legend. For
example,
r = raster(system.file(external/test.grd, package=raster))plot(r)
How can I put the legend at the desired position?
Thank in advance,Phil
[[alternative HTML
Thank you for reply.
If I'm not wrong, legend(...) will works for discrete elements. I'm not sure
hot to use it for a colorbar legend sur as the one in the example bellow.
Phil
Date: Mon, 2 Dec 2013 11:49:19 -0800
From: c...@witthoft.com
To: r-help@r-project.org
Subject: Re: [R] legend
Thank you, I'll try to work with lattice.
Regards,Phil
Date: Mon, 2 Dec 2013 12:06:50 -0800
From: c...@witthoft.com
To: r-help@r-project.org
Subject: Re: [R] legend position
It occurs to me that perhaps you're referring to the 'color bar' on the right
of the plot. AFAIK you cannot get at
Department of Anthropology
Texas AM University
College Station, TX 77840-4352
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of philippe
massicotte
Sent: Monday, December 2, 2013 1:22 PM
To: r-help@r-project.org
Subject: [R] legend
Hi everyone.
I have a list like this:
neutral_classes = list(A = 71:100, B = 46:70, C = 21:45, D = 0:20)
and I'm trying to return the letter of the named vector for with an integer
belong. For example, B if I use the value 50.
Any help would be greatly appreciated.
Regards,Phil
, length))]
# get one or more results with 'match':
names(neutralVec[match(c(50, 20, 10, -4), neutralVec)])
# result:
# [1] B D D NA
Pat
On 22/11/2013 16:58, philippe massicotte wrote:
Hi everyone.
I have a list like this:
neutral_classes = list(A = 71:100, B = 46:70, C = 21
On 22/11/2013 16:58, philippe massicotte wrote:
Hi everyone.
I have a list like this:
neutral_classes = list(A = 71:100, B = 46:70, C = 21:45, D = 0:20)
and I'm trying to return the letter of the named vector for with an
integer belong. For example, B if I use the value 50
Dear R users.
I'm trying to avoid using nested loops in the following code but I'm not sure
how to proceed. Any help would be greatly appreciated.
With regards,Phil
X = matrix(rnorm(100), 10, 10)
## Version with nested loopsresult = 0
for(m in 1:nrow(X)){ for(n in 1:ncol(X)){if(X[m,n] !=
Thank you for your answer. This is what I needed.
From: s.elli...@lgcgroup.com
To: r-help@r-project.org
Date: Fri, 4 Oct 2013 15:13:49 +0100
Subject: Re: [R] Trying to avoid nested loop
I'm trying to avoid using nested loops in the following code but I'm
not sure how to proceed. Any
Hi everyone.
I would like to know if it is possible to combine rasters in R to form a
collage.
For example, I would like to place 2 copies of the R logo side by side.
r = raster(system.file(external/rlogo.grd, package = raster))
After reading the help file (maybe I missed it) I did not
Look at colClasses in ?read.csv
Date: Thu, 5 Sep 2013 18:14:49 +0530
From: kiran4u2...@gmail.com
To: r-help@r-project.org
Subject: [R] Problem with converting F to FALSE
Hi,
I have a peculier problem in R-Project that is when my CSV file have one
column with all values as 'F' the
Hi everyone.
I'm currently translating some Matlab code into R. However, I realized that the
hsit function produce different results in both languages.
in Matlab, hist(1:10, 10) will produce 10 bins with a count of 1 in each, but
in R it will produce 9 classes with count of 2,1,1,1,1,1,1,1,1.
the only way to get exactly the number of breaks you want is to
specify the break intervals yourself.
David Carlson
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of philippe
massicotte
Sent: Wednesday
('name=GALX\\s*value=([^]+)'), replacement = \\1)
authenticatePage - postForm(authenticateURL, .params = list(Email = usr,
Passwd = psw, GALX = galx), curl = ch, .opts = list(verbose = F))
return(ch)
}
With regards,
Phil
--
Philippe Massicotte, Ph. D.
Stagiaire
Hi everyone.
I'm trying to create a graph where I could plot some lines on the right side.
Here an example:
layout(matrix(c(1,2), 1, 2, byrow = TRUE), widths=c(6,2), heights=c(1,1))
x = 1:100y = rnorm(x)+xplot(x,y)
reg = lm(y~x)abline(reg, col = red)
plot(1, type=n, axes=F, xlab=, ylab=, xlim =
Hi and thank you for your answer.
Sorry for the html post, here's the code: (you missed a break line between +x
and plot(...)
layout(matrix(c(1,2), 1, 2, byrow = TRUE), widths=c(6,2), heights=c(1,1))
x = 1:100
y = rnorm(x)+x
plot(x,y)
reg = lm(y~x)
abline(reg, col = red)
plot(1,
))
but the better way is to see xpd within ?par as described here:
https://stat.ethz.ch/pipermail/r-help/2009-July/206311.html
along with par()$mai to set the margins appropriately.
Sarah
On Tue, Mar 12, 2013 at 3:50 PM, philippe massicotte
pmassico...@hotmail.com wrote:
Hi and thank you for your answer
Hi everyone.
I have two data frames that contain the same variables but with different
number of observation.
I would like to know it was possible to combine the data so I can have
paired boxplot on the same figure.
For example,
df1 = data.frame(x = rnorm(100))
df1$type = ifelse(df1$x
Dear R users.
I'm new with layout and I can't figure how to teak my graphs.
I have the following code:
layout(matrix(c(1,2,3), 3, 1, byrow = TRUE), heights=c(0.3,0.3,0.6))
boxplot(rnorm(100), horizontal=TRUE, axes=FALSE)
boxplot(rnorm(100), horizontal=TRUE, axes=FALSE)
hist(rnorm(100))
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