Subscribers,
For this example:
library(lattice)
testmatrix<-matrix(c(1,2,3,4,3,6,12,24),nrow=4,ncol=2)
testylabels<-c('w1','x1','y1','z1')
dotplot(testmatrix, scales=list(y=list(labels=testylabels), xlab=NULL))
legend('bottomright', 'legend', col=c('blue', 'pink'))
Error in strwidth(legend, unit
Subscribers,
What is my mistake with the following example:
library(lattice)
testmatrix<-matrix(c(1,2,3,4,3,6,12,24),nrow=4,ncol=2)
testylabels<-c('w1','x1','y1','z1')
dotplot(testmatrix, scales=list(y=list(testylabels)), xlab=NULL)
#testylabels not shown, instead 'D' 'C' 'B' 'A'
Thanks in adva
Subscribers,
A spreadsheet contains (what appears to a low aptitude mathematician!) a
recurrence equation:
cellb1=2cellc1=0.1 celld1=5
cella2=1/(k1*cellb1)cellb2=cellb1+cellc1+celld1 cellc2=cella2*cellb2
celld2=cellb2*k2
where k are constants.
Could someone p
On 2014-10-15 15:36, William Dunlap wrote:
Have you looked at recent entries in the system log files in /var/log,
especially /var/log/kern.log?
No such log file exist and other files in the directory do not make
reference to R and any general errors (e.g. internet access).
__
On 2014-10-15 09:13, Sven E. Templer wrote:
did you check the connection in R via for example:
head(readLines("http://cran.r-project.org/web/licenses/GPL-3";))
which should yield:
[1] "GNU GENERAL PUBLIC LICENSE"
[2] " Version 3, 29 June 2007"
[3] ""
[
On 2014-10-14 15:40, Sven E. Templer wrote:
Prevent graphic menues with:
options(menu.graphics = FALSE)
Same response after a pause: 'Killed'
or and define repositories:
options(repos = c(CRAN = "http://cran.r-project.org";))
Same response after a pause: 'Killed'
_
Subscribers,
A version of R is installed in a virtual machine, which has complete
internet access via the host.
The following error occurs when a package is selected:
install.packages([packagename], dependencies=TRUE)
--- Please select a CRAN mirror for use in this session ---
Killed
The err
Subscribers,
What is the correct syntax to apply the 'if else' conditional statement
to vector objects?
Example:
vectorx<-c(50,50,20,70)
vectory<-c(50,50,20,20)
vectorz<-function () {
if (vectorx>vectory)
vectorx
else vectorx<-0
}
vectorz()
Warning message:
In if (vec
On 2014-09-16 12:35, PIKAL Petr wrote:
So if result of menu is 0 (you did not choose anything) you can either
stay with 0, then switch does not return anything or add 1 and let
evaluate something meaningful specified in second and following
positions of switch command.
Thanks for your explana
On 2014-09-16 10:50, PIKAL Petr wrote:
switch(menu(c("List letters", "List LETTERS")) + 1,
cat("Nothing done\n"), letters, LETTERS)
why is the result changed if ' + 1,' removed?
Because +1 belongs to switch not to menu. You can translate above to:
The help pages ?switch, ?menu do no
On 2014-09-15 14:22, David L Carlson wrote:
I think switch() should work for you here, but it is not clear how
much flexibility you are trying to have (different tests based on the
first response; different tests based on first, then second response;
different tests based on each successive respo
On 2014-09-15 14:22, David L Carlson wrote:
I think switch() should work for you here, but it is not clear how
much flexibility you are trying to have (different tests based on the
first response; different tests based on first, then second response;
different tests based on each successive respo
Subscribers,
apply block of if statements with menu function
Subscribers,
For a menu:
menu(c('a','b','c','d'))
How to create a function that will apply to specific menu choice
objects? For example:
object1<-function (menuifchoices) {
menu1<-menu(c('a','b','c','d'))
if (menu1==1)
On 2014-09-10 10:45, PIKAL Petr wrote:
On 2014-09-08 15:47, William Dunlap wrote:
> d <- data.frame(Choices=c("One","Two","One","Three"), X=1:4)
> i <- 1 # possible output of menu(unique(d$Choices))
> d[ d$Choices[i] == d$Choices, ]
> # Choices X
> #1 One 1
> #3 One 3
>
> testd <- data
On 2014-09-08 15:47, William Dunlap wrote:
d <- data.frame(Choices=c("One","Two","One","Three"), X=1:4)
i <- 1 # possible output of menu(unique(d$Choices))
d[ d$Choices[i] == d$Choices, ]
# Choices X
#1 One 1
#3 One 3
testd <- data.frame(Choices=c("One","Two","One","Three"), X=1:4)
t
On Mon, 8 Sep 2014 07:55:23 -0700
William Dunlap wrote:
Again, feed the output of menu() directly into "[". Do not use
switch(). Bill Dunlap
The function was changed to:
testdataextract1<-function (testdata) {
selectionresult<-menu(c(unique(levels(testdata[,1]))),graphics=FALSE,title='Selec
On Sat, 6 Sep 2014 08:21:19 -0700
William Dunlap wrote:
>
testdataextract1<-switch(menu(c(unique(levels(testdata[,1]))),graphics=FALSE,title='Select
> something'))
The switch function does not work the way you are expecting it to.
Read help("switch") and read the introduction to R that comes
On 2014-09-05 09:40, r...@openmailbox.org wrote:
Subscribers,
Could someone please indicate correct terminology and relevant manual
sections to achieve the following conceptual workflow, to create a
script to select sequentially parts of a dataframe:
"Welcome to this R script program"
Select l
Subscribers,
Could someone please indicate correct terminology and relevant manual
sections to achieve the following conceptual workflow, to create a
script to select sequentially parts of a dataframe:
"Welcome to this R script program"
Select level number below of variable 'X'
[1]
[2]
[3]
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