[R] Using Foreach for downloading data

Hi! I have this code which is working formula <- function(x){ return(x) } For( x in names) { x5 <- rbind(x5,formula(x)) } Now, I want to convert this code to parallel processing, so i am using foreach function foreach(x=names, .packages="checkpoint"

[R] using foreach function with gtrendsR

I have this code which is working library("checkpoint") library("gtrendsR") library("doParallel") cl<-makeCluster(4) registerDoParallel(cl) gconnect(usr = "em...@gmail.com", psw = "password", verbose = FALSE) names <- c("apple","shit", "android", "rocks") formula <- function(x){ x0 <-

Re: [R] Need help with lm function on MAC OS X. R version - 3.2.0

, samarvir singh samarvir1...@gmail.com wrote: I Have a data frame named BSE and CP is my independent variable and here;s the error I get if I try to run an lm function any idea whats wrong P.S - all my data is in numeric except company which is a factor. I have 2700 row and 450 variable

[R] Need help with lm function on MAC OS X. R version - 3.2.0

I Have a data frame named BSE and CP is my independent variable and here;s the error I get if I try to run an lm function any idea whats wrong P.S - all my data is in numeric except company which is a factor. I have 2700 row and 450 variable P.P.S - I have no missing data, I have 0 in Empty

[R] Selecting cell values with XLSX package

Hello, I am working with some 2700 files in .xlsx format Like the one attached below I want to transform all tabular data to a single row as shown below in example or in attachment so that all data can be used as a variable. and replicate all to make a single csv file which has all the data

[R] Can't load CARET package, on Mac OS X (latest), on R version 3.1.2 (2014-10-31)

I installed CARET package, but when I try to load CARET. I see this error. Please help. thank you install.packages(caret) trying URL ' http://cran.rstudio.com/bin/macosx/mavericks/contrib/3.1/caret_6.0-41.tgz' Content type 'application/x-gzip' length 3997718 bytes (3.8 Mb) opened URL

Re: [R] how to Subset based on partial matching of columns?

it hard to copy and paste. Alternatively, don't post in HTML, because it screws up your code. On Wed, Apr 8, 2015 at 8:57 PM, samarvir singh samarvir1...@gmail.com wrote: So I have a list that contains certain characters as shown below `list - c(MY,GM+ ,TY,RS,LG)` That's a character vector

[R] how to Subset based on partial matching of columns?

So I have a list that contains certain characters as shown below `list - c(MY,GM+ ,TY,RS,LG)` And I have a variable named CODE in the data frame as follows `code - c(MY GM+, ,LGTY, RS,TY)` 'x - c(1:5) `df - data.frame(x,code)` df x code 1 MY GM+ 2 3 LGTY 4 RS 5 TY

[R] How to subset data, by sorting names alphabetically.

hello, I am cleaning some large data with 4 million observation and 7 variable. Of the 7 variables , 1 is name/string I want to subset data, which have same name Example- Name var1 var2 var3 var4 var5 var6 aa- - - - -- ab bd ac ad af ba bd aa av i want