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Bill Venables
http://www.cmis.csiro.au/bill.venables/
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of jimdare
Sent: Tuesday, 28 July 2009 8:10 AM
To: r-help@r-project.org
Subject: [R] Split rownames into factors
Hi,
I'm not an R expert, but I thought I'd give your question a shot anyway.
First, it looks like you're starting with a matrix, rather than a
list. Let's hope I guessed that right:
> m = matrix(c(324, 65, 543, 23, 54, 8765, 213, 43, 65))
> rownames(m) = c('X1Jan08', 'X1Jun08', 'X1Dec08', 'X2Jan
Hi Guys,
I was wondering how you would go about solving the following problem:
I have a list where the grouping information is in the row names.
Rowname [,1]
X1Jan08 324
X1Jun08 65
X1Dec08 543
X2Jan08 23
X2Jun08 54
X2Dec08 8765
X3Jan08 213
X3Jun08 43
X3Dec08 65
How can I create the f
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