Since I didn't get an answer to this question, I'm rephrasing my question in
simpler terms:
I have a dataframe and I want to split it based on the levels of one of its
columns, and apply a function to each section of the data. Output of the
function may be drawing a plot, returning a value,
Merik,
You did get an answer to the question, and it's even included in the material
below.
What doesn't work for you in Ista's suggestion?
id- c(1,1,1,1,1,2,2,2,3,3,3)
month - c(1, 1, 2, 3, 6, 2, 3, 6, 1, 3, 5)
value - c(10, 12, 11, 14, 16, 12, 10, 8, 14, 11, 15)
dat.tmp - data.frame(id,
On Tue, Jul 26, 2011 at 10:12 AM, Ista Zahn iz...@psych.rochester.edu
wrote:
OK, easy enough:
dat.tmp - data.frame(id, month, value)
my.plot - function(dat) {print(dat[, c(id, value)])}
by(dat.tmp, id, my.plot)
Excellent. The output of that last line is:
* id value
1 110
2 112
3
Hi Merik,
Please keep the mailing list copied.
On Tue, Jul 26, 2011 at 6:44 AM, Merik Nanish merik.nan...@gmail.com wrote:
You can convert my data into a dataframe simply by dat - data.frame(id,
month, value). That doesn't help though.
Can you be more specific? What is the problem you are
Hello,
Here are three vectors to give context to my question below:
*id- c(1,1,1,1,1,2,2,2,3,3,3))
month - c(1, 1, 2, 3, 6, 2, 3, 6, 1, 3, 5)
value - c(10, 12, 11, 14, 16, 12, 10, 8, 14, 11, 15)*
and I want to plot value over month separately for each id. Before I
can do that, I need to
Hi Merik,
by() works most easily with data.frames. Is this what you are after?
my.plot - function(dat) { print(dat$value);
print(dat$month[dat$id==dat$value]) }
by(dat.tmp, id, my.plot)
Best,
Ista
On Mon, Jul 25, 2011 at 9:19 PM, Merik Nanish merik.nan...@gmail.com wrote:
Hello,
Here are
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