Hello,
I am having trouble figuring out how to convert a Day of Year integer
back into a Date format. For example I have the following:
date -
c('2008-01-01','2008-01-02','2008-01-03','2008-01-04','2008-01-05','2008-01-06','2008-01-07',
There may very well be a better solution, but this works.
format(strptime(dayofyear, format=%j), format=%m-%d)
On Tue, Mar 27, 2012 at 11:12 AM, Sam Albers tonightstheni...@gmail.comwrote:
Hello,
I am having trouble figuring out how to convert a Day of Year integer
back into a Date format.
On 27/03/2012 19:30, Justin Haynes wrote:
There may very well be a better solution, but this works.
format(strptime(dayofyear, format=%j), format=%m-%d)
The answer depends on the year (think leap years), so I think you need
strptime(paste(2008, dayofyear), format=%Y %j)
Probably a better
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