Hi there,
Is this what you want?
your.number=5.43
# For a vector
x=c(1,2,4,3,2,5,6,7,5.42,6)
which.min(abs(x-your.number))
[1] 9
# For a matrix
set.seed(123)
X=matrix(rpois(100,4.5),ncol=10)
apply(X,2,function(x) which.min(abs(x-your.number)))
[1] 9 3 2 3 2 5 1 2 2 2
HTH,
Jorge
On Wed, Ju
-
Von: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Im
Auftrag von R_Learner
Gesendet: Wednesday, July 09, 2008 11:28 AM
An: r-help@r-project.org
Betreff: [R] Find the closest value in a list or matrix
I have a long list of numbers [3.4,5.4,3.67,], and I basically want to
find the index of the
: Wednesday, July 09, 2008 11:28 AM
An: r-help@r-project.org
Betreff: [R] Find the closest value in a list or matrix
I have a long list of numbers [3.4,5.4,3.67,], and I basically want to
find the index of the number closest to this number that I have, let's say
5.43. How would I do this wi
Try this:
which.min(abs(x - 5.43))
where x is your vector of numbers.
On Wed, Jul 9, 2008 at 12:28 PM, R_Learner <[EMAIL PROTECTED]> wrote:
>
> I have a long list of numbers [3.4,5.4,3.67,], and I basically want to
> find the index of the number closest to this number that I have, let's sa
I have a long list of numbers [3.4,5.4,3.67,], and I basically want to
find the index of the number closest to this number that I have, let's say
5.43. How would I do this without writing a for loop (I have to do this many
times for several lists)? Is there a "lookup" function in R?
Thanks!
5 matches
Mail list logo