Hans W Borchers wrote:
>
> Let's see how many zeroes are there of the function sin(1/x) in the
> interval
> [0.1, 1.0]. Can you find out by plotting?
>
> In the 1-dimensional case the simplest approach is to split into
> subintervals
> small enough to contain at most one zero and search each o
Lorenzo Isella wrote:
>
> Hello,
> And sorry for the late reply.
> You see, my problem is that it is not known a priori whether I have one
> or two zeros of my function in the interval where I am considering it;
> on top of that, does BBsolve allow me to select an interval of variation
> of x
Lorenzo Isella wrote:
>
> Hello,
> And sorry for the late reply.
> You see, my problem is that it is not known a priori whether I have one
> or two zeros of my function in the interval where I am considering it;
> on top of that, does BBsolve allow me to select an interval of variation
> of x
Hello,
And sorry for the late reply.
You see, my problem is that it is not known a priori whether I have one
or two zeros of my function in the interval where I am considering it;
on top of that, does BBsolve allow me to select an interval of variation
of x?
Many thanks
Lorenzo
On 09/26/20
You may also try package nleqslv, which uses Newton or Broyden to solve a
system of nonlinear equations. It is an alternative to BB.
Without further information from your side, no additional information can be
provided.
/Berend
--
View this message in context:
http://r.789695.n4.nabble.com/Fi
Dear Lorenzo,
You could try the BB package:
# function we need the roots for
fn1 <- function(x, a) - x^2 + x + a
# plot
curve(fn1(x, a = 5), -4, 4)
abline(h=0, col = 2)
# searching the roots in (-4, 4)
# install.packages('BB')
require(BB)
BBsolve(par = c(-1, 1), fn = fn1, a = 5)
valu
Dear All,
I need to find the (possible multiple) zeros of a function f within an
interval. I gave uniroot a try, but it just returns one zero and I need
to provide it with an interval [a,b] such that f(a)f(b)<0.
Is there any function to find the multiple zeros of f in (a,b) without
constraints
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