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On Jan 17, 2011, at 4:38 PM, André Dias wrote:
OK!!
So, the ideia is from the 1st matrix get the 2nd matrix
Pete Brecknock wrote:
>
> try ...
>
> new_m = m[c(2,7,8),c(1,4,6,7)]
>
> HTH
>
> Pete
>
Hi Pete,
I haven't understood what you wanted to say here. Can you explain please?
thanks
ADias
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OK!!
So, the ideia is from the 1st matrix get the 2nd matrix with the use of a
vector.
is it possible?
In the example I have a 10x10 matrix and I get from that one a second 4x3
matrix selected from a vector.
thanks
ADias
2011/1/17 David Winsemius
>
> On Jan 17, 2011, at 11:16 AM, ADias wrot
On Jan 17, 2011, at 11:16 AM, ADias wrote:
Hi,
yes it works perfectly.
I have another question:
Is there way of selecting with a vector the values I wish to take
out from a
matrix.
Example:
I have this matrix and I want to take out the numbers in bold and
get the
second matrix below
I believe you want to select a subset of rows and subset of columns of your
original matrix m.
If you had wanted only the first row of m, you could have used m[1,]
Alternatively, if you had wanted only the second column of m then you could
have used m[,2]
m[1,2] would give you the element at
Hi,
yes it works perfectly.
I have another question:
Is there way of selecting with a vector the values I wish to take out from a
matrix.
Example:
I have this matrix and I want to take out the numbers in bold and get the
second matrix below
>m
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,
try ...
new_m = m[c(2,7,8),c(1,4,6,7)]
HTH
Pete
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ADias wrote:
>
> Is there an expression to double the values of a matrix - without using a
> loop?
>
>
Why so complicated?
Dieter
> m = matrix(rep(1,20),nrow=4)
> m
[,1] [,2] [,3] [,4] [,5]
[1,]11111
[2,]11111
[3,]11111
[4,]
Hi,
Is there an expression to double the values of a matrix - without using a
loop?
What I need is this:
Suppose we have this matrix
> m
[,1] [,2] [,3]
[1,]7 174
[2,] 11 10 18
[3,] 15 19 18
and I want this matrix
[,1] [,2] [,3]
[1,] 112 102 115
typo ...
should have been
m = matrix(c(7,11,15,17,10,19,4,18,18), nrow = 3, ncol=3)
sum_m = sum(m)
new_m = sum_m-m
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If I have understood your question correctly, how about the following ...
m = matrix(c(7,11,15,17,10,19,4,18,18), nrow = 3, ncol=3)
sum_m = sum(m)
new_m = summ-m
HTH
Pete
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