Hi Faradj,
Yes, the function expects at least three values for each country. Glad
it worked.
Jim
On Tue, May 29, 2018 at 10:53 PM, Faradj Koliev wrote:
> Dear Jim,
>
> wow! It worked! Thanks a lot.
>
> I did as you suggested and it worked well with the real data. Although it
> gave me this
Dear Jim,
wow! It worked! Thanks a lot.
I did as you suggested and it worked well with the real data. Although it gave
me this error: Error in if (!is.na(x$Y[i])) { : argument is of length zero. For
some reason the X1 produced less observations than it is in the data. But it's
not a big
Hi Faradj,
What a problem! I think I have worked it out, but only because the
result is the one you said you wanted.
# the sample data frame is named fkdf
Y2Xby3<-function(x) {
nrows<-dim(x)[1]
X<-rep(0,nrows)
for(i in 1:(nrows-2)) {
if(!is.na(x$Y[i])) {
if(x$Y[i] == 1 &&
I was not able to decipher your meaning, and your failure to garner a
response so far may mean that others may have had similar difficultes. You
might therefore try providing providing a **small reproducible** example of
X's and Y's that show what you have and what you want to end up with to
Hi everyone,
I am trying to generate a conditional dummy variable ”X" with the following
rules
set X=1 if Y is =1, two years prior to the NA. [0,0,NA].
For example, if the pattern for Y is 0,0,NA then the X variable is =0 for all
the two years prior to the NA. If the pattern for Y is
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