gt;From: R-help On Behalf Of Avi Gross via R-help
> >Sent: Wednesday, September 15, 2021 1:23 AM
> >To: R-help@r-project.org
> >Subject: Re: \[R\] How to remove all rows that have a numeric in the first
> >(or any) column
> >
> >You are correct, Gregg, I am aware
>
>
>-Original Message-
>From: R-help On Behalf Of Avi Gross via R-help
>Sent: Wednesday, September 15, 2021 1:23 AM
>To: R-help@r-project.org
>Subject: Re: [R] How to remove all rows that have a numeric in the first (or
>any) column
>
>You are correct, Gregg, I a
handle them become better or at least better understood.
-Original Message-
From: R-help On Behalf Of Avi Gross via R-help
Sent: Wednesday, September 15, 2021 1:23 AM
To: R-help@r-project.org
Subject: Re: [R] How to remove all rows that have a numeric in the first (or
any) column
You are
Of course, the temporary columns for alphazoid and betazoid can trivially be
removed.
From: Andrew Simmons
Sent: Wednesday, September 15, 2021 12:44 AM
To: Avi Gross
Cc: Gregg Powell via R-help
Subject: Re: [R] How to remove all rows that have a numeric in the first (or
any) colum
> tibble [2 x 2] (S3: tbl_df/tbl/data.frame)
> $ alpha: int [1:2] 1 4
> $ beta :List of 2
> ..$ : chr "Hello"
> ..$ : chr "bye"
>
> So if you try variations on your code motivated by what I show, good luck.
> I am sure there are many better ways but I repe
2021 11:54 PM
To: Gregg Powell
Cc: Gregg Powell via R-help
Subject: Re: [R] How to remove all rows that have a numeric in the first (or
any) column
You cannot apply vectorized operators to list columns... you have to use a map
function like sapply or purrr::map_lgl to obtain a logical vector by r
:54 PM
To: Gregg Powell
Cc: Gregg Powell via R-help
Subject: Re: [R] How to remove all rows that have a numeric in the first (or
any) column
You cannot apply vectorized operators to list columns... you have to use a map
function like sapply or purrr::map_lgl to obtain a logical vector by r
You cannot apply vectorized operators to list columns... you have to use a map
function like sapply or purrr::map_lgl to obtain a logical vector by running
the function once for each list element:
sapply( VPN_Sheet1$HVA, is.numeric )
On September 14, 2021 8:38:35 PM PDT, Gregg Powell
wrote:
>
'is.numeric' is a function that returns whether its input is a numeric
vector. It looks like what you want to do is
VPN_Sheet1 <- VPN_Sheet1[!vapply(VPN_Sheet1$HVA, "is.numeric", NA), ]
instead of
VPN_Sheet1 <- VPN_Sheet1[!is.numeric(VPN_Sheet1$HVA), ]
I hope this helps, and see ?vapply if nece
On Wed, 15 Sep 2021 02:01:53 +
Gregg Powell via R-help wrote:
> > Stuck on this problem - How does one remove all rows in a dataframe
> > that have a numeric in the first (or any) column?
> >
>
> > Seems straight forward - but I'm having trouble.
> >
>
>
> I've attempted to used:
>
>
Here is the output:
> str(VPN_Sheet1$HVA)
List of 2174
$ : chr "Email: f...@fff.com"
$ : num 1
$ : chr "Eloisa Libas"
$ : chr "Percival Esquejo"
$ : chr "Louchelle Singh"
$ : num 2
$ : chr "Charisse Anne Tabarno, RN"
$ : chr "Sol Amor Mucoy"
$ : chr "Josan Moira Paler"
$ : num 3
An atomic column of data by design has exactly one mode, so if _any_ values are
non-numeric then the entire column will be non-numeric. What does
str(VPN_Sheet1$HVA)
tell you? It is likely either a factor or character data.
On September 14, 2021 7:01:53 PM PDT, Gregg Powell via R-help
wrote:
> Stuck on this problem - How does one remove all rows in a dataframe that have
> a numeric in the first (or any) column?
>
> Seems straight forward - but I'm having trouble.
>
I've attempted to used:
VPN_Sheet1 <- VPN_Sheet1[!is.numeric(VPN_Sheet1$HVA),]
and
VPN_Sheet1 <- VPN_Sheet1[!i
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