Yet another way which returns the row and column of the items you want
rc - which(t(x[,-c(1,ncol(x))]),arr.ind=TRUE) #this identifies the rows and
columns but is one column off
rc[,1] - rc[,1] +1 #this adjusts the columns
colnames(rc) - c(col,row)
rc #show them
Bill
On Jun 6, 2014, at
R 3.1.0
OS X
Colleagues
I have an array (I am using T/F rather than TRUE/FALSE for convenience) that
could have patterns like:
c(T, T, T, F, F, F, T, F, T, T, T) ## T at either end, a
single T in the middle
c(F, F, F, F, F, T, F, F, T, T, T) ## T at
Not sure if this is better than your brute force and you may be able
to simplify it...
notStart = function(x)
{
n = length(x)
i0 = which(x);
n0 = length(i0);
i0!=c(1:n)[1:n0];
}
notStartNorEnd = function(x) { which(x)[notStart(x) rev(notStart(rev(x)))] }
notStartNorEnd(c(F, F, F))
Here is my solution.
falses - which(!x)
first.false - head(falses, 1)
last.false - tail(falses, 1)
which(x[first.false:last.false]) + first.false - 1
Best regards,
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie
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