On 10/19/2010 11:47 AM, Rainer M Krug wrote:
>> x[n %% length(x)] gives you the same answer as rep(x, length.out=n)[n],
>> without having to create the longer vector.
>>
n %% length(x) may return 0 and in that case,
x[n %% length(x)] will not give the result you expect.
x[((n - 1) %% length(x
On Tue, Oct 19, 2010 at 11:30 AM, wrote:
> > x <- c(1, 2, 3)
> > n <- 10
> > ## so using the recycling rules, I would like to get from FUN(x, n)==1
> > ## I am doing:
> > xRecycled <- rep(x, length.out=n)[n]
> >
> > This works, but it seems to me that I am missing something really basic
> here
>
> x <- c(1, 2, 3)
> n <- 10
> ## so using the recycling rules, I would like to get from FUN(x, n)==1
> ## I am doing:
> xRecycled <- rep(x, length.out=n)[n]
>
> This works, but it seems to me that I am missing something really basic
here
> - is there more straightforward way of doing this?
x[n
Hi
I want to use R's recycling rule. At the moment I am using the following:
x <- c(1, 2, 3)
n <- 10
## so using the recycling rules, I would like to get from FUN(x, n)==1
## I am doing:
xRecycled <- rep(x, length.out=n)[n]
This works, but it seems to me that I am missing something really basic
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